The constant of proportionality between the number of animals(a) at a zoo and the number of employees(e) that work there is 9/2.

The Constant Of Proportionality Between The Number Of Animals(a) At A Zoo And The Number Of Employees(e)

Answers

Answer 1

Step-by-step explanation:

i think the answer is 1/9


Related Questions

Create a bucket by rotating around the y axis the curve y=5 ln(x-2) from y=0 to y=4. If this bucket contains a liquid with density 760 kg/m3 filled to a height of 3 meters, find the work required to pump the liquid out of this bucket (over the top edge). Use 9.8 m/s2 for gravity.

Answers

Answer:

The work will be "1909212.015 J". The further explanation is given below.

Step-by-step explanation:

The given values are:

Liquid's density

= 760 kg/m³

Height

= 3 meters

Gravity

g = 3.8 m/s²

Value of y is:

y = 5 log (x-2)

y = 0

y = 4

As we know,

⇒  [tex]\Delta V=\pi r^2 \Delta y[/tex]

⇒  [tex]y =5log(x-2)[/tex]

⇒  [tex]\frac{y}{5} =log (x-2)[/tex]

⇒  [tex]e^{\frac{y}{5}}=(x-2)[/tex]

⇒  [tex]x=e^{\frac{y}{5}}+2[/tex]

Now,

[tex]\Delta F=ma[/tex]

      [tex]=760 \pi (e^{\frac{y}{5}}+2)^2(9.8)\Delta y[/tex]

So that,

⇒  [tex]\Delta W = \Delta F.distance[/tex]

            [tex]=\Delta F(4-y)[/tex]

The required work will be:

⇒  [tex]W=760\times 9.8 \pi \int_{3}^{0}(e^{\frac{y}{5}}+2)^2 (\Delta-y)dy[/tex]

         [tex]=760\times 9.8 \pi[{-20(y-9)^{e^{\frac{y}{5}}}-2(y-8)y}][/tex]

         [tex]=760\times 9.8 \pi[81.455][/tex]

         [tex]=1909212.015 \ J[/tex]

An electrical engineer wishes to compare the mean lifetimes of two types of transistors in an application involving high-temperature performance. A sample of 60 transistors of type A were tested and were found to have a mean lifetime of 1827 hours and a standard deviation of 168 hours. A sample of 180 transistors of type B were tested and were found to have a mean lifetime of 1658 hours and a standard deviation of 225 hours. Find a 95% confidence interval for the difference between the mean lifetimes of the two types of transistors.

Answers

Answer:

(115.2642, 222.7358).

Step-by-step explanation:

Given data:

type A: n_1=60, xbar_1=1827, s_1=168

type B: n_2=180, xbar_2=1658, s_2=225

n_1 = sample size 1, n_2= sample size 2

xbar_1, xbar_2 are mean life of sample 1 and 2 respectively. Similarly, s_1 and s_2 are standard deviation of 1,2.

a=0.05, |Z(0.025)|=1.96 (from the  standard normal table)

So 95% CI is

(xbar_1 -xbar_2) ± Z×√[s1^2/n1 + s2^2/n2]

=(1827-1658) ± 1.96×sqrt(168^2/60 + 225^2/180)

= (115.2642, 222.7358).

find the value of x

m<2= x + 122​

Answers

Answer:

x= -14

Step-by-step explanation:

Please see attached picture for full solution.

Nadine mixes a juice solution that is made from 3 gallons of an 80% juice solution and 1 gallon of a 20% juice solution. What is the percent concentration of the final solution?

Answers

Answer:

65%

Step-by-step explanation:

Nadine mixes a juice solution that is made from 3 gallons of an 80% juice solution and 1 gallon of a 20% juice solution. What is the percent concentration of the final solution?

3 gallons of 80% juice solution contains this amount of juice:

80% * 3 gal = 0.8 * 3 gal = 2.4 gal

1 gallon of 20% juice solution contains this amount of juice:

20% * 1 gal = 0.2 * 1 gal = 0.2 gal

The total amount of juice in the final juice solution is

2.4 gal + 0.2 gal = 2.6 gal

The total amount of juice solution made is 3 gal + 1 gal = 4 gal

The 4 gal juice solution contains 2.6 gallons of juice.

2.6 gallons is what percent of 4 gallons?

2.6/4 * 100% = 0.65 * 100% = 65%

Answer: 65%

Answer:

65% i got the answer right on the question

Step-by-step explanation:

Find the simplest pattern and insert the missing term(s) of each sequence. 33, 39, 51, 57, 69, 84, ____

Answers

Answer:

  87

Step-by-step explanation:

Such "find a pattern" problems can always be answered a number of ways.

Here, the alternating pattern (6, 12, 6, 12, ...) of first differences doesn't seem to hold. However, the first differences of alternate terms does seem to be constant: 33, 51, 69 all have a common difference of 18.

The next term in that sequence is 69+18 = 87.

___

The other terms seem to have increasing differences:

  57 -39 = 18

  84 -57 = 27

If that pattern continues, then the second missing term will be 84 +36 = 120.

___

So, one way to extend the sequence is ...

  33, 39, 51, 57, 69, 84, 87, 120, 105, 165, ...

The rule is that the sequence alternates a linear sequence and a quadratic one.

A​ student's course grade is based on one midterm that counts as 1010​% of his final​ grade, one class project that counts as 1515​% of his final​ grade, a set of homework assignments that counts as 4040​% of his final​ grade, and a final exam that counts as 3535​% of his final grade. His midterm score is 6767​, his project score is 8888​, his homework score is 9191​, and his final exam score is 7272. What is his overall final​ score? What letter grade did he earn​ (A, B,​ C, D, or​ F)? Assume that a mean of 90 or above is an​ A, a mean of at least 80 but less than 90 is a​ B, and so on.

Answers

Answer:

His overall final​ score is 81.5

He earned a B

Step-by-step explanation:

To find his overall grade, we multiply each of his grades by it's weight.

Grades:

67 on the midterm, which counts for 10% = 0.1

88 on the project, which counts for 15% = 0.15

91 on homework assignements, which counts for 40% = 0.4

72 on the final exam, which counts for 35% = 0.35.

What is his overall final​ score?

67*0.1 + 88*0.15 + 91*0.4 + 72*0.35 = 81.5

His overall final​ score is 81.5

At least 80 and less than 90 has a letter grade of B. 81.5 is in this range. So he earned a B

What is the slope of the line on the graph below? On a coordinate plane, a line goes through points (negative 2, negative 3), (negative 1, negative 1), (0, 1) and (1, 3). –One-half One-half 1 2 plz

Answers

Answer:

slope = 2

Step-by-step explanation:

All four points lie on the same line.

Taking the first and fourth points, the slope can be found by the formula

slope, m = (y2-y1)/(x2-x1) = (3- -3) / (1- -2) = 6/3 =2

See attached diagram.

Answer:

2

Step-by-step explanation:

edge 2020

16. How much money will I need to have at retirement so I can withdraw $60,000 a year for 20 years from an account earning 8% compounded annually? a. How much do you need in your account at the beginning b. How much total money will you pull out of the account? c. How much of that money is interest?

Answers

Answer:

starting balance: $636,215.95total withdrawals: $1,200,000interest withdrawn: $563,784.05

Step-by-step explanation:

a) If we assume the annual withdrawals are at the beginning of the year, we can use the formula for an annuity due to compute the necessary savings.

The principal P that must be invested at rate r for n annual withdrawals of amount A is ...

  P = A(1+r)(1 -(1 +r)^-n)/r

  P = $60,000(1.08)(1 -1.08^-20)/0.08 = $636,215.95

__

b) 20 withdrawals of $60,000 each total ...

  20×$60,000 = $1,200,000

__

c) The excess over the amount deposited is interest:

  $1,200,000 -636,215.95 = $563,784.05

HELP WITH THESE QUESTIONS!!

Answers

That is the answer ,check by ur self

Twelve percent of the population is left handed. Approximate the probability that there are at least 20 left-handers in a school of 200 students. State your assumptions.

Answers

Answer:

Step-by-step explanation:

We would assume a binomial distribution for the handedness of the population. Let x be a random variable representing the type of handedness in the population. The probability of success, p is that a randomly chosen person is left handed only. Then probability of failure is that a chosen person is not left handed only(right handed only or both).

p = 12/100 = 0.12

number of success, x = 20

n = 200

the probability that there are at least 20 left-handers is expressed as P(x ≥ 20)

From the binomial probability calculator,

P(x ≥ 20) = 0.84

4x+1/15=2x/10 PLEASE HELP

Answers

Answer:

[tex]x=-1[/tex]

Step-by-step explanation:

Cross multiply.

10(4x + 1) = 15(2x)

Expand brackets.

40x + 10 = 30x

Add -30x and 10 on both sides.

40x - 30x = -10

10x = -10

Divide both sides by 10.

10/10x = -10/10

x = -1

50 random teenagers were asked how many hours a day they use their phone. They spent an average of 7 hours a day with a standard deviation of 1.3. Based on the results, what is the margin of error for the true mean number of hours a teenager spends on their phone?your margin of error on a 95% confidence level, round your answer to the nearest tenth

Answers

Answer:

The margin of error for the true mean number of hours a teenager spends on their phone is of 0.4 hours a day.

Step-by-step explanation:

We have the standard deviation of the saple, so we use the t-distribution to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 50 - 1 = 49

95% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 49 degrees of freedom(y-axis) and a confidence level of [tex]1 - \frac{1 - 0.95}{2} = 0.975[/tex]. So we have T = 2

The margin of error is:

[tex]M = T\frac{s}{\sqrt{n}} = 2\frac{1.3}{\sqrt{50}} = 0.4[/tex]

In which s is the standard deviation of the sample and n is the size of the sample.

The margin of error for the true mean number of hours a teenager spends on their phone is of 0.4 hours a day.

A school district performed a study to find the main causes leading to its students dropping out of school. Thirty cases were analyzed, and a primary cause was assigned to each case. The causes included unexcused absences (U), illness (I), family problems (F), and other causes (O). The results for the thirty cases are listed below:

U U U I F O O U I F F O U I I F I I O U I F F U U I I O F U

Required:
Construct a table summarizing the frequency distribution of the primary causes leading to student dropout.

Answers

Answer:

See below for the table.

Step-by-step explanation:

The results for the thirty cases are listed below:

U U U I F O O U I F F O U I I F I I O U I F F U U I I O F U

The table summarizing the frequency distribution of the primary causes leading to student dropout is:

[tex]\left|\begin{array}{c|c}$Cause&$Frequency\\----------&----\\\\$Unexcused absences (U)&9\\$Illness (I)&9\\$Family problems (F)&7\\$Other causes (O)&5\\-----------&---\\$Total&30\end{array}\right|[/tex]

What is the measure of x?​

Answers

Answer:

x= 9 inches

Step-by-step explanation:

Hello

I can help you with this.

in this case, we have two similar triangles, let's see

Step 1

identify the rigth triangles.

1) the first triangle has these dimensions

hypotenuse( remember, the longest side)= unknown=H

adjacent side(the horizontal)=6 +x

opposite side(the vertical)=10

2) the second triangle has these dimensions

hypotenuse( remember, the longest side)= unknown=h

adjacent side(the horizontal)=6

opposite side(the vertical)=4.

As these triangles keep the same proportion and in both cases we know the length of the legs, we can establish a relationship

Step 2

establish a relationship

let's compare the opposite side and the adjacent side

triangle 1 (the bigger)

[tex]proportion= \frac{opposite\ side}{adjacent\ side}\\proportion= \frac{10}{6+x}[/tex]

Triangle 2

[tex]proportion= \frac{opposite\ side}{adjacent\ side}\\proportion= \frac{4}{6}\\proportion=\frac{2}{3}[/tex]

were the proportions are equal, so

[tex]\frac{10}{6+x}=\frac{2}{3}[/tex]

at this point, just isolate x to find its value

Step 3

isolate x

[tex]\frac{10}{6+x}=\frac{2}{3}\\multiply\ both\ sides\ by\ 3\\\frac{10*3}{6+x}=\frac{2*3}{3}\\\frac{30}{6+x} =2\\\\Multiply\ both\ sides\ by (6+x)\\\frac{30(6+X)}{6+x} =2(6+x)\\30=12+2x\\30-12=2x\\18=2x\\so\\x=\frac{18}{2} \\x=9[/tex]

remember the units of measure ( Inches)

x= 9 inches

I really hope it helps, have a nice day.

Tanya can wash a car and vacuum its interior in 2 hours. Pat needs 5 hours to do this same job. If Tanya and Pat work together, how many hours will it take them to clean a car??

Answers

Answer:

It will take 1.43 hours for them to clean the car.

Step-by-step explanation:

The together rate is the sum of each separate rate.

In this problem:

Together rate: 1/x

Tanya's rate: 1/2

Pat's rate: 1/5

Together rate = Tanya's rate + Pat's rate

[tex]\frac{1}{x} = \frac{1}{2} + \frac{1}{5}[/tex]

[tex]\frac{1}{x} = \frac{5 + 2}{10}[/tex]

[tex]\frac{1}{x} = \frac{7}{10}[/tex]

[tex]7x = 10[/tex]

[tex]x = \frac{10}{7}[/tex]

[tex]x = 1.43[/tex]

It will take 1.43 hours for them to clean the car.

The volume of a cantaloupe is approximated by Upper V equals four thirds pi font size decreased by 5 r cubed . The radius is growing at the rate of 0.5 cm divided by week​, at a time when the radius is 6.4 cm. How fast is the volume changing at that​ moment?

Answers

Answer:

308.67 cm ^ 3 / week

Step-by-step explanation:

A cantaloupe is approximately a sphere, therefore its approximate volume would be:

V = (4/3) * pi * (r ^ 3)

They tell us that dr / dt 0.5 cm / week and the radius is 6.4 cm

if we derive the formula from the volume we are left with:

dV / dt = (4/3) * pi * d / dr [(r ^ 3)]

dV / dt = (4/3) * pi * 3 * (r ^ 2) * dr / dt

dV / dt = 4 * pi * (r ^ 2) * dr / dt

we replace all the values and we are left with:

dV / dt = 4 * 3.14 * (6.4 ^ 2) * 0.6

dV / dt = 308.67

Therefore the volume is changing at a rate of 308.67 cm ^ 3 / week

y = 3x + 4, what is y when x is 1, 2, and 3?

Answers

Answer:

When x is 1, y=7

When x is 2, y=10

When x is 3, y= 13

Step-by-step explanation: Plug in each number for x and solve

Answer:

If x=1, y=7

If x=2, y=10

If x=3, y=13

Step-by-step explanation:

For every equation substitute x in y = 3x + 4, with the value you want.

For example the first one says when x=1, so simply substitute x with 1 in y = 3x + 4.

So it'll look something like this:

y = 3(1) + 4.

Simply solve the equation from there, and you'll get y=7, and we know that x is already equal to 1.

So if x=1, then y=7

A softball pitcher has a 0.626 probability of throwing a strike for each curve ball pitch. If the softball pitcher throws 30 curve balls, what is the probability that no more than 16 of them are strikes

Answers

Answer:

19.49% probability that no more than 16 of them are strikes

Step-by-step explanation:

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

[tex]E(X) = np[/tex]

The standard deviation of the binomial distribution is:

[tex]\sqrt{V(X)} = \sqrt{np(1-p)}[/tex]

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that [tex]\mu = E(X)[/tex], [tex]\sigma = \sqrt{V(X)}[/tex].

In this problem, we have that:

[tex]n = 30, p = 0.626[/tex]

So

[tex]\mu = E(X) = np = 30*0.626 = 18.78[/tex]

[tex]\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{30*0.626*(1-0.626)} = 2.65[/tex]

What is the probability that no more than 16 of them are strikes

Using continuity correction, this is [tex]P(X \leq 16 + 0.5) = P(X \leq 16.5)[/tex], which is the pvalue of Z when X = 16.5. So

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{16.5 - 18.78}{2.65}[/tex]

[tex]Z = -0.86[/tex]

[tex]Z = -0.86[/tex] has a pvalue of 0.1949

19.49% probability that no more than 16 of them are strikes

The amount of soda a dispensing machine pours into a 12-ounce can of soda follows a normal distribution with a mean of 12.45 ounces and a standard deviation of 0.30 ounce. Each can holds a maximum of 12.75 ounces of soda. Every can that has more than 12.75 ounces of soda poured into it causes a spill and the can must go through a special cleaning process before it can be sold. What is the probability that a randomly selected can will need to go through this process?

Answers

Answer:

0.1587

Step-by-step explanation:

According to the situation, the solution and the data provided is as follows

mean = 12.45 ounces

Standard deviation = 0.30 ounces

maximum = 12.75 ounces

More than ounces of soda = 12.75

Based on the above information, the probability is

[tex]Z=\frac{X-\mu }{\sigma } \\\\Z=\frac{12.75-12.45 }{0.30 } \\\\\Z=\frac{0.30 }{0.30 } \\\\Z= 1 \\\\P(X> 12.75)=1-P(X< 12.75) \\\\\P(X> 12.75)=1-P(Z< 1) \\\\[/tex]

As we know that

P(Z<1) = 0.8413

So,

P (X > 12.75) = 1 - 0.8413

= 0.1587

Refer to the figure and find the volume generated by rotating the given region about the specified line. ℛ1 about AB

Answers

Answer:

I guess that the area we care about is the yellow area, delimited by the functions.

f(x) = 8*(x)^(1/4)

and the line with the slope s= 8/1 = 8 (as the line goes through the points (0,0) and (1, 8)).

g(x) = 8*x

then we want tofind the area between x = 0 and x = 1, of f(x) - g(x)

then we have:

[tex]I = \int\limits^1_0 {f(x)} \, dx = \int\limits^1_0 {8*\sqrt[4]{x} )} \, dx = (8*(4/5)*\sqrt[4]{1^5} - 8*(4/5)*\sqrt[4]{0^5}) = 6.4[/tex]

now, for the area under the g(x) we have:

[tex]I2 = \int\limits^1_0 {g(x)} \, dx = \int\limits^1_0 {8x} \, dx = (8/2)*1^2 - (8/2)*0^2 = 4.[/tex]

then I - I2 = 6.4 - 4 = 2.4

The yellow area is 2.4

And then, if we rotate this about the line AB, the volume will be:

B = 2*pi*2.4 = 2*3.14*2.4 = 15.075

The figure will be something like a half spheroid, with a hole in the shape of a cone inside of it.

In a certain online dating service, participants are given a 4-statement survey to determine their compatibility with other participants. Based on the questionnaire, each participant is notified if they are compatible with another participant. Each question is multiple choice with the possible responses of "Agree" or "Disagree," and these are assigned the numbers 1 or −1, respectively. Participant’s responses to the survey are encoded as a vector in R4, where coordinates correspond to their answers to each question. Here are the questions:

Answers

The question is incomplete. Here is the complete question.

In a certain online dating service, participants are given a 4-statement survey to determine their compatibility with other participants. Based on the questionnaire, each particpant is notified if they are compatible with another participant. Each question is multiple choice with the possible responses of "Agree" or "Disagree", and these are assigned the numbers 1 or -1, respectively. pArticipnat's responses to the survey are encoded as a vector in R4, where coordinates coreespond to their answers to each question. Here are the questions:

Question #1: I prefer outdoor activities, rather than indoor activities.

Question #2: I prefer going out to eat in restaurants, rahter than cooking at home.

Question #3: I prefer texting, rather than talking on the phone.

Question #4: I prefer living in a small town, rather than in a big city.

Here are the results for the questionaire, with a group of 5 participants:

                        Question1     Question2   Question3       Question4

participant A           1                      1                   -1                      -1

participant B           -1                     1                    1                       1

participant C           -1                    -1                    1                       1

participant D           1                     -1                   -1                      -1

participant E            1                    -1                    1                       1

Two participants are considered to be "compatible" with each other if the angle between their compatibility vectors is 60° or less. Participants are considered to be "incompatible" if the angle between their compatibility vectors is 120° or larger. For angles between 60° or 120°, pairs of participants are warned that they "may or may not be compatible".

(a) Which pairs of paricipants are compatible?

(b) Which pairs of participants are incompatible?

(c) How would this method of testing compatibility change if the questionnaire also allowed the answer "Neutral", which would correspond to the number zero in a participant's vector? Would this be better than only

allowing  "Agree" or "Disagree"? Could anything go wrong if we allowed "Neutral" as an answer?

Answer: (a) Participants A and D; B and C; C and E.

(b) Participants A and B; A and C; A and E; B and D; C and D;

Step-by-step explanation: Vectors in R4 are vectors in a 4 dimensional space and are determined by 4 numbers.

Vectors form angles between themselves and can be found by the following formula:

cos α = [tex]\frac{A.B}{||A||.||B||}[/tex]

which means that the cosine of the angle between two vectors is equal the dot product of these vectors divided by the product of their magnitude.

For the compatibility test, find the angle between vectors:

1) The vectors magnitude:

Magnitude of a vector is given by:

||x|| = [tex]\sqrt{x_{i}^{2} + x_{j}^{2}}[/tex]

Since all the vectors have value 1, they have the same magnitude:

||A|| = [tex]\sqrt{1^{2} + 1^{2} + (-1)^{2} + (-1)^{2}}[/tex] = 2

||A|| = ||B|| = ||C|| = ||D|| = ||E|| = 2

2) The dot product of vectors:

A·B = 1(-1) + 1(1) + (-1)1 + (-1)1 = -2

cos [tex]\alpha_{1}[/tex] = [tex]\frac{-2}{4}[/tex] = [tex]\frac{-1}{2}[/tex]

The angle that has cosine equal -1/2 is 120°, so incompatible

A·C = 1(-1) + 1(-1) + (-1)1 + (-1)1 = -4

cos [tex]\alpha _{2}[/tex] = -1

Angle = 180° --------> incompatible

A·D = 1(1) + 1(-1) + (-1)(-1) + (-1)(-1) = 2

cos [tex]\alpha _{3}[/tex] = 1/2

Angle = 60° ---------> COMPATIBLE

A·E = 1.1 + 1(-1) + (-1)1 + (-1)1 = -2

cos [tex]\alpha_{4}[/tex] = -1/2

Angle = 120° --------> incompatible

B·C = (-1)(-1) + 1(-1) + 1.1 + 1.1 = 2

cos [tex]\alpha _{5}[/tex] = 1/2

Angle = 60° -------------> COMPATIBLE

B·D = (-1)1 + 1(-1) + 1(-1) + 1(-1) = -4

cos[tex]\alpha_{6}[/tex] = -1

Angle = 180° -----------> incompatible

B·E = (-1)1 + 1(-1) + 1.1 + 1.1 = 0

cos[tex]\alpha _{7}[/tex] = 0

Angle = 90° -------------> may or may not

C·D = (-1)1 + (-1)(-1) + 1(-1) + 1(-1) = -2

cos[tex]\alpha_{8} =[/tex] -1/2

Angle = 120° ---------------> Incompatible

C·E = (-1)1 + (-1)(-1) + 1.1 + 1.1 = 2

cos [tex]\alpha_{9}[/tex] = 1/2

Angle = 60° ---------------> COMPATIBLE

D·E = 1.1 + (-1)(-1) + (-1)1 + (-1)1 = 0

cos [tex]\alpha_{10}[/tex] = 0

Angle = 90° -----------------> may or may not

(c) Adding zero (0) as a component of the vectors would have to change the method of compatibility because, to determine the angle, it is necessary to calculate the magnitude of a vector and if it is a zero vector, the magnitude is zero and there is no division by zero. So, unless the service change the method, adding zero is not a good option.

The Jones family and the Connor family both bought the same boxed package of sugar cubes at the store, in which the cubes were arranged in 5 layers. After drinking of 61 cups of tea, the Joneses found that they were out of sugar. The Connors' sugar box was enough to last them through 88 cups of tea. Both families put either 2 or 3 pieces of sugar per cup. How many sugar cubes were in the box?

Answers

Answer:

180

Step-by-step explanation:

At the beggining, it says they are stacked in 5 layers which means the number of cubes is divisible by 5.

If the number of cubes equals x:

The least amount of sugar cubes the Jones family could have used is [tex]61*2[/tex] which equals 122. The most they couldve used is [tex]61*3[/tex] which equals 183.

Based on the information from the Jones family, x is between 122 and 183.

Based on the information from the Connor's, x is between 176 and 264.

Based on the information from both, x is between 176 and 183. The only number that is divisible by 5 between those numbers is 180 cubes.

Please answer this correctly

Answers

Answer:

12.5

Step-by-step explanation:

This is the answer!

Answer:

50%

Step-by-step explanation:

Total Cards = 4

6 or even cards = 2

P( 6 or even) = 2/4

=> 1/2

In %age:

50%

Crane Company reports the following for the month of June.

Date
Explanation
Units
Unit Cost
Total Cost
June 1 Inventory 150 $4 $600
12 Purchase 450 5 2,250
23 Purchase 400 6 2,400
30 Inventory 80

Assume a sale of 500 units occurred on June 15 for a selling price of $7 and a sale of 420 units on June 27 for $8.

Calculate cost of goods available for sale.

Calculate Moving-Average unit cost for June 1, 12, 15, 23 & 27. (Round answers to 3 decimal places, e.g. 2.525.)

Answers

Answer:

Crane Company

June Financial Reports

a) Cost of goods available for sale = $5,250

b) Moving-Average unit cost for:

i) June 1:  = $5

ii)        12:  = $4.75

iii)       15: = $4.75

iv)      23:  = $5.75

v)       27:  = $5.25

Step-by-step explanation:

a) Calculations:

Date     Explanation   Units     Unit Cost    Total Cost   Moving Average Cost

June 1 Inventory          150        $4                $600         $4.000

      12 Purchase         450          5               2,250            4.750

      15 Sale                 500          7                      3,500     4.750

     23 Purchase         400          6               2,400            5.750

     27 Sale                 420          8                      3,360     5.250

     30 Inventory           80

Cost of goods available for sale = Cost of Beginning Inventory + Cost of Purchases = $5,250 + ($600 + 2,250 + 2,400)

b) Moving-Average unit cost for:

i) June 1: Cost of goods available/Units of goods available = $5 ($600/150)

ii)        12: Cost  of goods available/Units of goods available = $4.75 ($600 + 2,250/600)

iii)       15: Cost  of goods available/Units of goods available = $4.75 ($475/100)

iv)      23: Cost of goods available/Units of goods available = $5.75 ($475 + 2,400)/500

v)       27: Cost of goods available/Units of goods available = $5.25 ($420/80)

The diagram shows the first four patterns of a sequence. Find an expression for the numbers of squares in the nth pattern of the sequence.

Answers

Answer:

n^2+3

Step-by-step explanation:

As we can see in the diagram

1st pattern consists from 1 square 1x1 +3 squares 1x1 each

2nd pattern consists from 1 square 2x2 +3 squares 1x1 each

3-rd pattern consists from 1 square 3x3 +3 squares 1x1 each

4-th pattern consists from 1 square 4x4 + 3 squares 1x1  each

We can to continue :

5-th pattern consists from 1 square 5x5+3 squares 1x1 each

So the nth    pattern consists from 1 square nxn+3 squares 1x1 each

Or total amount of 1x1 squares in nth pattern N= n^2+3

The expression for the numbers of squares in the nth pattern of the sequence is  [tex]n^{2} +3[/tex].

What is nth term of a sequence?

"The nth term of a sequence is a formula that enables us to find any term in the sequence. We can make a sequence using the nth term by substituting different values for the term number(n) into it."

From the given diagram

We can see that every term is made up with a square which side is n and three small square side is 1.

So,

1st term is 1 × 1 + 3 = 4

2nd term is 2 × 2 + 3 = 4

3rd term is  3 × 3 + 3 = 12

4th term is 4 × 4 + 3 = 19

So, nth term is [tex]n^{2} +3[/tex]

Hence, The expression for the numbers of squares in the nth pattern of the sequence is  [tex]n^{2} +3[/tex].

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4. Parking fees at IIUM are RM 5.00 for IIUM students and RM 7.50 for non-IIUM students. At the
end of each day, the total number of vehicles parked that day and the gross receipts for the day are
recorded, but the number of vehicles in each category is not. The following table contains the relevant
information for a recent 4-day period:
Day
Vehicles Parked
Gross Receipts
Monday
1,200
RM 7,125
Tuesday
1.550
RM 9,825
Wednesday Thursday
1.740
1,400
RM 11,100 RM 8,650
(a) How many vehicles in each category used the IIUM parking facilities on Wednesday? (1 point]
(b) If 1,200 vehicles are parked in one day, is it possible to take in gross receipts of RM 10,000?
Explain. [1 point]
(c) Describe all possible gross receipts on a day when 1,200 vehicles are parked. [1 point]
(3 points)​

Answers

Answer:

(a) 780 students and 960 non-students  

(b) No. The maximum revenue is RM9000 from 1200 non-students.

(c). Revenue is maximum of RM9000 at 1200 non-students, decreasing by RM2.50 per student to a minimum of RM6000 at 1200 students

Step-by-step explanation:

 Let x = IIUM students and

and  y = non-IIUM students

You have two conditions

(a)          x +         y = total vehicles parked

(b) 5.00x + 7.50y = total gross receipts

(a) Wednesday

From your table,  

       x +          y = 1740

5.00x + 7.70y = RM11 100  

Solve the simultaneous equations

[tex]\begin{array}{rrcrl}(1) & x + y & = &1740&\\(2) & 5.00x + 7.50y & = & 11 100\\(3)& 5.00x + 5.00y & = & 8700 & \text{Multiplied (1) by 5}\\&2.50 y & = &2400 &\text{Subtracted (3) from (2)}\\(4)&y& = &\mathbf{960} &\text{Divided each side by 2.50}\\& x +960& = &1740& \text{Substituted (4) into (1)}\\& x& = &\mathbf{780}& \\\end{array}\\\text{There are $\large \boxed{\textbf{780 students and 960 non-students}}$}[/tex]

(b) Can 1200 vehicles bring in RM10000?

No. Even if all the cars were from non-students, the most you could get is  

1200 × 7.50 = RM9000

(c) Possible combinations for 1200 vehicles  

Revenue = 5.00x + 7.50y = 5.00x + 7.50(1200 -x) = 5.00x + 9000 - 7.50x =  

Revenue = 9000 - 2.50x

The maximum revenue of RM9000 occurs when there are no student cars and 1200 non-student cars.

For each student car that enters and displaces a non-student, the revenue drops by RM2.50.

Finally. when there are 1200 student cars and no non-students, the revenue has dropped to a minimum of RM6000.  

Lisa surveyed 60 students at her school and found that 0.85 of the students she surveyed said their favorite class is math. Another 15% of the students she surveyed reported that their favorite class is science. How many more students in the survey prefer math over science?

Answers

Answer:

42

Step-by-step explanation:

Number of students whose favorite class is Math:

60*0.85=51

Number of students whose favorite class is Science:

15% is equal to 0.15.

60*0.15=9

Subtract number of students who like science from number of students who like math.

51-9=42

42 more students in the survey prefer math over science.

Answer:

42

Step-by-step explanation:

85% math

15% science

Subtract

85-15 = 70

The difference is 70 %

70% of 60 students

.70 * 60 = 42

There is a 42 student difference

Answer in POINT-SLOPE FORM:
Complete the point-slope equation of the line through (1,3) and (5,1) Use exact numbers!

Answers

Answer:

y - 3 = (1/2)(x - 1)

Step-by-step explanation:

As we go from (1, 3) to (5, 1), we see that x (the run) increases by 4 and y (the rise) decreases by 2.  Hence, the slope is m = rise / run = 2/4, or m = 1/2.

Then the desired point slope equation is  y - 3 = (1/2)(x - 1).

The table below shows the distance a car travels and the amount of gasoline left in the tank of the car. Distance Traveled and Gas Left in Tank Distance Traveled (in miles) 0 90 180 270 Amount of Gas Left in Tank (in gallons) 15 12 9 6 PLZ HELP How many gallons of gasoline does the car have left after it has traveled 330 miles? 2 4 6 8

Answers

Answer:

b: 4

Step-by-step explanation:

i took the test on edge 2020

The gallons of gasoline the car has left after it has traveled 330 miles is 4 gallons so option (B) will be correct.

How to form an equation?

Determine the known quantities and designate the unknown quantity as a variable while trying to set up or construct a linear equation to fit a real-world application.

In other words, an equation is a set of variables that are constrained through a situation or case.

Given the table of the number of miles and gallons.

If we take two points of the number of miles and gallons.

Then,

1 st point = ( 0 ,15 )

2 nd point = ( 90 , 12)

Now since the relation is linear which can be seen by data.

So,

Linear equation joining points 1st and 2nd is

y - 15 = [(12-15)/(90-0)](x - 0)

y - 15 = -x/30

y = (450 - x)/30

So,

At x = 330 miles

y = (450 - 330 )/30

y = 4 gallons

Hence "The gallons of gasoline the car has left after it has traveled 330 miles is 4 gallons".

For more about the equation,

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An airline charges the following baggage fees: $25 for the first bag and $35 for the second. Suppose 51% of passengers have no checked luggage, 33% have one piece of checked luggage and 16% have two pieces. We suppose a negligible portion of people check more than two bags.

Required:
a. Build a probability model, compute the average revenue per passenger, and compute the corresponding standard deviation.
b. About how much revenue should the airline expect for a flight of 120 passengers? With what standard deviation? Note any assumptions you make and if you think they are justified.

Answers

Answer:

The average revenue per passenger is about $13.85

μ = $13.85

The corresponding standard deviation is $14.51

σ = $14.51

The airline should expect revenue of $1,662 with a standard deviation of $14.51 for a flight of 120 passengers.

Expected revenue = $1,662 ± 14.51

Step-by-step explanation:

An airline charges the following baggage fees:

$25 for the first bag and $35 for the second

Suppose 51% of passengers have no checked luggage,

P(0) = 0.51

33% have one piece of checked luggage and 16% have two pieces.

P(1) = 0.33

P(2) = 0.16

a. Build a probability model, compute the average revenue per passenger, and compute the corresponding standard deviation.

The average revenue per passenger is given by

μ = 0×P(0) + 25×P(1) + 35×P(2)

μ = 0×0.51 + 25×0.33 + 35×0.16

μ = 0 + 8.25 + 5.6

μ = $13.85

Therefore, the average revenue per passenger is about $13.85

The corresponding standard deviation is given by

σ = √σ²

Where σ² is the variance and is given by

σ² = (0 - 13.85)²×0.51 + (25 - 13.85)²×0.33 + (35 - 13.85)²×0.16

σ² = 97.83 + 41.03 + 71.57

σ² = 210.43

So,

σ = √210.43

σ = $14.51

Therefore, the corresponding standard deviation is $14.51

b. About how much revenue should the airline expect for a flight of 120 passengers? With what standard deviation?

For 120 passengers,

Expected revenue = 120×$13.85

Expected revenue = $1,662 ± 14.51

Therefore, the airline should expect revenue of $1,662 with a standard deviation of $14.51 for a flight of 120 passengers.

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