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Answer:

Because in correspondence to the same distance from a mass, the gravitational acceleration is the same for all the bodies. It doesn't depend on the mass of the objects.

why did my answer get deleted??

oh yeah i put a link on there- oopsies.

I wont this time!

I got 30!

Answer:

Explanation:

The sun is much closer than the other stars

Answer: The Rasalas's solar mass is 1.50 times that of our star, the Sun. The Sun's Mass is 1,989,100,000,000,000,000,000 billion kg.

Explanation:

Answer:

The Rasalas's solar mass is 1.50 times that of our star, the Sun. The Sun's Mass is 1,989,100,000,000,000,000,000 billion kg. which to calculate using this website is too large. To give idea of size, the Sun is 99.86% the mass of the solar system.

Explanation:

Hi there!

I. Only momentum is conserved.

An inelastic collision means that there is a LOSS in the KINETIC ENERGY of the system.

However, momentum is ALWAYS conserved for every type of collision unless there is an external force acting on the system.

Answer:   biogeochemical process

Explanation:

Answer:

This is the answer that I got.

Explanation:

Hope it is right.

Answer:

It's going to be a single displacement reaction

So we'll get ZnSO4 + Cu for the following reaction Zn + CuSO4

Equation:

Zn + CuSO4 ------> Cu + ZnSO4

Answer:

100

Explanation:

Displacement is the shortest line between the starting point and the ending point

so , the starting point is "A"

,the ending point is "C"

so "AC" = AB - CB = 300 - 200 = "100"

Answer:

  4/3 m/s

Explanation:

Assuming momentum is conserved, the sum of products of mass and speed before the collision is the same as after:

  (2000 kg)(4 m/s) +(4000 kg)(0 m/s) = (2000 +4000 kg)(Vt)

  Vt = (8000 kg·m/s)/(6000 kg) = 4/3 m/s

The speed of the combined objects after the collision is 4/3 m/s.

Answer:

Momentum Packet Answer KEY - Science Online

YOU WILL SEE THE PDF

Answer:speed difference

Explanation:

Answer:

The magnitude of its acceleration is 1.6 m/s^2.

Hope you could get an idea from here.

Doubt clarification - use comment section.

Answer: false

Explanation:

Answer:

B- Correlation

Explanation:

Answer:

correlation

Explanation:

To solve the problem it is necessary to apply the concepts of Torque and equilibrium.

The Torque is defined as:

Where

F= Force

d = Distance

In this particular case, the force is caused by the weight of both children.

In turn, when there is equilibrium, the two torques must be equal therefore

Replacing with our values

Re-arrange to find  

Therefore the distance that the second kid should sit to balance the see-saw is 1.8m from the pivot.

Answer:

Muscle memory is found in many everyday activities that become automatic and improve with practice, such as riding bicycles, driving motor vehicles, playing ball sports, typing on keyboards, entering PINs, playing musical instruments, poker, martial arts, and dancing.

Explanation:

Answer:

Explanation:

The concept of a new strong nuclear force was introduced. In 1935, the first theory for this new force was developed by the Japanese physicist Hideki Yukawa, who suggested that the nucleons would exchange particles between each other and this mechanism would create the force.

Answer:

Explanation:

We know that the pressure can be calculated in the following way:

p = d·g·h

with d being the density of the water, g the gravitational acceleration and h the depth.

Also d of the water = 1000 kg/m^3 circa and g = 9.8 m/s^2 circa

117,500 Pa = 1000kg/m³ · 9.8m/s² · h

Therefore h = 11,9 m

Answer:

a solid made of liquid solution

Explanation:

a trumpet for example has intrcuite valves , the only way to do this is by creating a liquid form of the metal to be able to create the solid formed instrument.

Answer:

a solid made of liquid solution

Explanation:

domne

From conservation of energy, the height he will reach when he has gravitational potential energy 250J is 0.42 meters approximately

The given weight of Elliot is 600 N

From conservation of energy, the total mechanical energy of Elliot must have been converted to elastic potential energy. Then, the elastic potential energy from the spring was later converted to maximum potential energy P.E of Elliot.

P.E = mgh

where mg = Weight = 600

To find the height Elliot will reach, substitute all necessary parameters into the equation above.

250 = 600h

Make h the subject of the formula

h = 250/600

h = 0.4167 meters

Therefore, the height he will reach when he has gravitational potential energy 250J is 0.42 meters approximately

Learn more about energy here: https://brainly.com/question/24116470

Answer:

Approximately [tex]5.11 \times 10^{-19}\; {\rm J}[/tex].

Explanation:

Since the result needs to be accurate to three significant figures, keep at least four significant figures in the calculations.

Look up the Rydberg constant for hydrogen: [tex]R_{\text{H}} \approx 1.0968\times 10^{7}\; {\rm m^{-1}[/tex].

Look up the speed of light in vacuum: [tex]c \approx 2.9979 \times 10^{8}\; {\rm m \cdot s^{-1}}[/tex].

Look up Planck's constant: [tex]h \approx 6.6261 \times 10^{-34}\; {\rm J \cdot s}[/tex].

Apply the Rydberg formula to find the wavelength [tex]\lambda[/tex] (in vacuum) of the photon in question:

[tex]\begin{aligned}\frac{1}{\lambda} &= R_{\text{H}} \, \left(\frac{1}{{n_{1}}^{2}} - \frac{1}{{n_{2}}^{2}}\right)\end{aligned}[/tex].

The frequency of that photon would be:

[tex]\begin{aligned}f &= \frac{c}{\lambda}\end{aligned}[/tex].

Combine this expression with the Rydberg formula to find the frequency of this photon:

[tex]\begin{aligned}f &= \frac{c}{\lambda} \\ &= c\, \left(\frac{1}{\lambda}\right) \\ &= c\, \left(R_{\text{H}}\, \left(\frac{1}{{n_{1}}^{2}} - \frac{1}{{n_{2}}^{2}}\right)\right) \\ &\approx (2.9979 \times 10^{8}\; {\rm m \cdot s^{-1}}) \\ &\quad \times (1.0968 \times 10^{7}\; {\rm m^{-1}}) \times \left(\frac{1}{2^{2}} - \frac{1}{8^{2}}\right)\\ &\approx 7.7065 \times 10^{14}\; {\rm s^{-1}} \end{aligned}[/tex].

Apply the Einstein-Planck equation to find the energy of this photon:

[tex]\begin{aligned}E &= h\, f \\ &\approx (6.6261 \times 10^{-34}\; {\rm J \cdot s}) \times (7.7065 \times 10^{14}\; {\rm s^{-1}) \\ &\approx 5.11 \times 10^{-19}\; {\rm J}\end{aligned}[/tex].

(Rounded to three significant figures.)

When the mass of the cylinder increases from 3. 0 kg to 6. 0 kg, the amount of heat generated in the system increases by a factor of 2.

The given parameters:

The amount of heat generated in the system is calculated as follows;

Q = mcΔT

where;

If we keep every other parameters constant and change the mass from 3.0 kg to 6.0 kg, the increase in the heat generated is calculated as follows;

[tex]Q_1 = 3c \Delta T\\\\Q_2 = 6c\Delta T\\\\Q_2 = 2(3c \Delta T)\\\\Q_2 = 2Q_1[/tex]

Thus, when the mass of the cylinder increases from 3. 0 kg to 6. 0 kg, the amount of heat generated in the system increases by a factor of 2.

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Answer:

because of the gravity of the earth

Answer:

Explanation:

hope this helps

The maximum speed of the bucket can experience before the rope snaps if A 3.4-kg bucket of water is attached to a 1.0-m rope. The bucket is swung in a circle at a speed of 10.0-m/s is 10.85 m / s.

Force is the influence of either pull or pushes in the body. Basically, gravitation forces, nuclear forces, and friction forces are the types of forces. For e.g. when the wall is hit by a hand then a force is exerted by the hand on the wall as well as the wall also exerts a force on the hand. There are different laws given to Newton to understand force.

Newton is a unit of force used by physicists that is part of the International System (SI). The force required to move a body weighing one kilogram one meter per second is known as a newton.

Given:

The mass of the bucket, m = 3.4 kg,

The length of the rope, r = 1 m,

The speed of the bucket, v = 10 m / s,

The force of the rope, F = 400 N,

Calculate the maximum speed by the formula given below,

[tex]F_c = mv^2 / r[/tex]

400 = 3.4 v² / 1

v² = 400 / 3.4

v² = 117.6

v = 10.85 m / s

Therefore, the maximum speed of the bucket can experience before the rope snaps if A 3.4-kg bucket of water is attached to a 1.0-m rope. The bucket is swung in a circle at a speed of 10.0-m/s is 10.85 m / s.

To know more about Force:

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The car is accelerating at 3 m/s² in the positive direction (to the right). By Newton's second law, the net force on the car in this direction is

∑ F = F[a] - F[f] - F[air] = ma

3100 N - 200 N - F[air] = (650 kg) (3 m/s²)

Solve for F[air] :

F[air] = 3100 N - 200 N - (650 kg) (3 m/s²)

F[air] = 3100 N - 200 N - 1950 N

F[air] = 950 N

[tex]\text{Given that,}\\\\\text{Mass}~ m = 68 ~\text{g} = 68 \times 10^{-3}~ \text{kg}\\\\\text{Volume}~ V = 80 ~ \text{cm}^3 = 80 \times 10^{-6}~ \text{m}^3 = 8\times 10^{-5}~ \text{m}^3\\\\\\\text{Density} ~\rho = \dfrac mV = \dfrac{68\times 10^{-3}}{8 \times 10^{-5}} = 8.5 \times 10^2 = 850 ~ \text{kg}~\text{m}^{-3}[/tex]