Answer:
Its either B or A
Explanation:
A 2 kg marble moving at 4 mi./s collides into a 1 kg marble at rest. After collision, the 2 kg marble speed decreased to 2 mi./s. Calculate the velocity and speed of the 1 kg marble immediately after colliding.
Please show work and please help me as fast as possible because this is time
Please help as soon as possible please
Please I’m begging
Answer:
[tex]2\sqrt{6}[/tex] [tex]\frac{mi}{s}[/tex]
Explanation:
Assuming there is no waste of energy:
[tex]K_{1} = K_{2}\\\frac{1}{2}m_{1}v_{1_{1}}^{2} + \frac{1}{2}m_{2}v_{2_{1}}^2 = \frac{1}{2}m_{1}v_{1_{2}}^{2} + \frac{1}{2}m_{2}v_{2_{2}}^2\\\\=> m_{1}v_{1_{1}}^{2} + m_{2}v_{2_{1}}^2 = m_{1}v_{1_{2}}^{2} + m_{2}v_{2_{2}}^2\\\\m_{1} = 2 kg, m_{2} = 1 kg, v_{1_{1}} = 4 \frac{mi}{s} , v_{2_{1}} = 0\\=> 32 = 8 + v_{2_{2}}^{2} => v_{2_{2}} = 2\sqrt{6} \frac{mi}{s}[/tex]
The common version of Newton’s second law of motion, EF= ma, is actually a special case that is true only when an objects _____ is constant.
-Mass
-Momentum
-Force
-Velocity
Answer:
A
Explanation:
only is true when the objects mass is constant
Answer:
A.
Explanation:
When the mass is constant. Newton's second law will work perfectly.
Fun fact you probably won't need to know this, but the original formula that Newton derived was F=change in momentum divided by change in time. Momentum will account for a change in mass. The schooling system lies to you all the time especially in physics.
Radar tells an air traffic controller that a jet is slowing as it nears the
airport. Which might represent the jet's velocity?
A. 700 h/km
B. 700 km
C. 700 km/hr
D. 700 km/h west
Choice-D is the only velocity on the list.
(It has a speed and a direction.)
The jet's velocity might be represented by 700 km/h west. Hence, option (D) is correct.
What is velocity?The rate at which a body's displacement changes in relation to time is known as its velocity. Velocity is a vector quantity with both magnitude and direction. SI unit of velocity is meter/second.
In this question, 700 h/km, 700 km have different unit that of velocity. So, option (A) and option (B) is not correct. . 700 km/hr has same unit that of velocity. But it does not has direction. So, option (C) is also incorrect. 700 km/h west has the same unit of velocity with define direction. So, option (D) is correct.
Hence option (D) is correct answer.
Learn more about velocity here:
https://brainly.com/question/18084516
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A negative charge of -0.00067 C and a positive charge of 0.00096 C are separated by 0.7 m. What is the force between the two charges?
Answer:
-11,813.87N
Explanation:
According to coulombs law, the Force between the two charges is expressed as;
F = kq1q2/d²
k is the coulombs constant = 9*10⁹kg⋅m³⋅s⁻²⋅C⁻².
q1 = -0.00067 C
q2 = 0.00096 C
d = 0.7m
Substitute into the formula:
F = 9*10^9 * -0.00067 * 0.00096/0.7²
F = 9*10⁹*-6.7*10⁻⁴*9.6*10⁻⁴/0.49
F = -578.88*10⁹⁻⁸/0.49
F = -578.88*10/0.49
F = -5788.8/0.49
F = -11,813.87N
Hence the force between the two charges is -11,813.87N
A wagon, initially traveling at a constant 8.2 m/s, starts going down a hill that creates an acceleration of 9.0 m/s2. What is the wagon's velocity 6.6 s after it starts accelerating down the hill?
Answer:
67.6m/s
Explanation:
Given parameters:
Initial velocity = 8.2m/s
Acceleration = 9.0m/s²
Time = 6.6s
Unknown:
Final velocity = ?
Solution:
To solve this problem, we use the expression below:
Acceleration = [tex]\frac{v - u }{t}[/tex]
v is the final velocity
u is the initial velocity
t is the time taken
9 = [tex]\frac{v - 8.2}{6.6}[/tex]
v - 8.2 = 59.4
v = 59.4 + 8.2 = 67.6m/s
Please help me
27. A 20 kg object is at rest. A 6 N force pulls to the right on
the object for 10 seconds.
A) Find the impulse on the object.
B) Find the final momentum of the object.
C) What is its final velocity?
Answer:
a. 60 N*s
b. 60 (kg*m)/s
c. 3 m/s
Explanation:
Givens:
m = 20 kg
v_i = 0 m/s
t = 10 s
F = 6 N
a) Impulse:
I = F*t
I = 6 N*10 s
I = 60 N*s
b) Momentum:
p = v*m
F = m(a)
a = F/m
a = 6 N/20 kg
a = 0.3m/s^2
a = (v_f -v_i)/t
v_f = (0.3 m/s^2)*10 s
v_f = 3.0 m/s
p = 3 m/s*20 kg
p = 60 (kg*m)/s
c. Final velocity
a = (v_f -v_i)/t
v_f = (0.3 m/s^2)*10 s
v_f = 3.0 m/s
The impulse, momentum and final velocity can all be obtained from Newton's second law.
Let us recall that the impulse is obtained as the product of force and time.
Impulse = Force × time
Impulse = 6 N × 10 s = 60 Ns
From Newton's second law of motion;
F.t = mv - mu
Since the object was initially at rest;
F.t = mv
Hence, the final velocity of the object is 60 Kgms-1
The final velocity is obtained from;
F.t = mv
v = F.t/m
v = 6 × 10/20
v = 3 m/s
Learn more about impulse and momentum: https://brainly.com/question/904448
its urgent plssss help me :(
Answer:
(4) The particle travels with a constant velocity until t0 and then comes to rest.
Explanation:
Uniform rectilinear motion is defined as the motion of a particle in a straight line with constant velocity, that is, there is no change in velocity over time.
And this can be determined by means of the following equation:
[tex]x=x_{o}+v*(t-t_{o})[/tex]
where:
x = final point [m]
xo = initial point [m]
v = velocity (slope) [m/s]
t = final time [s]
to = initial time [s]
So the slope in the graph gives the constant velocity
[tex]v=\frac{x-x_{o}}{t-t_{o}}[/tex]
Therefore, after the time to there is no displacement, that is the particle comes to rest.
In the figure shown, if angle i increases slightly, angler will
angle of
reflection
angle of
incidence
a. remain the same
Oc. increase
Ob disappear
O d. decrease
Answer:
Explanation:
According to law of reflection of light ,
angle of incidence = angle of reflection
angle of incidence = i
angle of reflection = r
when angle of incidence increases to i₁ and angle of reflection becomes r₁
According to law of reflection,
i₁ = r₁
i₁ - i = r₁ - r
increase in angle of incidence = increase in angle of reflection .
So angle of reflection also increases .