Suppose you pay a dollar to roll two dice. if you roll 5 or a 6 you Get your dollar back +2 more just like it the goal will be to find the amount of money you can expect to win or lose if you play this game 100 times. How many times would you win? how many times would you lose?

Answer:

Step-by-step explanation:

Given the sequence [tex]a_n = \frac{9+14n^{2} }{n+15n^{2} }[/tex]

To find the limit of the sequence, we will first divide the numerator and the denominator through by the highest power of n which is n² as shown;

[tex]\lim_{n \to \infty} \frac{9/n^{2} +14n^{2}/n^{2} }{n/n^{2} +15n^{2}/n^{2} }\\ \lim_{n \to \infty} \frac{9/n^{2} +14 }{1/n +15n^{2}/n^{2 }}\\[/tex]

As [tex]n[/tex] tends to [tex]\infty[/tex], [tex]\frac{a}{n}[/tex] tends to zero where n is any constant, The limit of tyhe sequence as n tends to infinity becomes;

[tex]= \frac{9/\infty+14 }{1/\infty+15 }\\= \frac{0+14}{0+15} \\= 14/15\\[/tex]

Therefore [tex]\lim_{n \to \infty} \frac{9+14n^{2} }{n+15n^{2} } = 14/15[/tex]

Since the limit of the sequence gave a finite number , the sequence converges.

Note that the only case when the sequence diverges id when the limit of the sequence is infinite

Answer:

8 is in the hundreds place as well as in the tens place.

Step-by-step explanation:

We use the base 10 system. 880 would represent eight hundred and eighty. So our 0 would be the ones place, 8 in the tens place, and 8 also in the hundreds place.

Answer:

A

Step-by-step explanation:

Given the equality y > -½, it means the values of y is greater than -½.

The values of y would range from 0 upwards. I.e. 0, ½, 1, 1½, 2. . .

Thus, when graphed on a number line, the circle that appears like "o" would start from -½, and the "o" would not be full or shaded to indicate that -½ is not included in the values of y, which are greater than -½. Since the values of y are greater than -½ the direction of the arrow that indicates values of y would point towards our far right, to indicate the values included as y.

Therefore, the graph that indicates the inequality y > ½ is A

Answer:

A

Step-by-step explanation:

Answer:

8 and 4/9 i think... i am sorry if i am wrong

Step-by-step explanation:

Answer:

0.15 or 15%

Step-by-step explanation:

If the price of a stock rose 3/4 on a point, it means that 1x became 1,75x (x + 3/4x). X is the price of the stock here.

To calculate how much the price went up each day on average, we will create exponential equation.

x = price of the stock

y = average daily change

[tex]x*y^{4} =1.75x[/tex]  divide by x

[tex]y^{4} = 1.75[/tex]

We will calculate it using logarithms.

y = 1.15016, rounded to 1.15

We see that the stock goes up 0.15 points every day.If we multiply it by 100%, we get 15%

Answer:

For this case we have the following confidence interval given:

[tex] 0.345 \leq p \leq 0.895 [/tex]

And for this case we want to find the estimated proportion like this:

[tex]\hat p= \frac{0.345 +0.895}{2}= 0.62[/tex]

And the margin of error for this case would be given by:

[tex] ME= \frac{0.895-0.345}{2}= 0.275[/tex]

Step-by-step explanation:

For this case we have the following confidence interval given:

[tex] 0.345 \leq p \leq 0.895 [/tex]

And for this case we want to find the estimated proportion like this:

[tex]\hat p= \frac{0.345 +0.895}{2}= 0.62[/tex]

And the margin of error for this case would be given by:

[tex] ME= \frac{0.895-0.345}{2}= 0.275[/tex]

Answer:

ok I am tellin6 to you

Step-by-step explanation:

ok I will tell to you

Answer:

a) Calculate the probability that at least one of them suffers from arachnophobia.

x = number of students suffering from arachnophobia

= P(x ≥ 1)

= 1 - P(x = 0)

= 1 - [0.05⁰ x (1 - 0.05)¹¹⁻⁰ ]

= 1 - (0.95)¹¹

= 0.4311999 = 0.4312

b) Calculate the probability that exactly 2 of them suffer from arachnophobia? 0.08666

=  P(x = 2)

=  (¹¹₂) x (0.05)² x (0.95)⁹

where ¹¹₂ = 11! / (2!9!) = (11 x 10) / (2 x 1) = 55

= 55 x 0.0025 x 0.630249409 = 0.086659293 = 0.0867

c) Calculate the probability that at most 1 of them suffers from arachnophobia?

P(x ≤ 1)

= P(x = 0) + P(x = 1)    

= [(¹¹₀) x 0.05⁰ x 0.95¹¹] + [(¹¹₁) x 0.05¹ x 0.95¹⁰]

= (1 x 1 x 0.5688) + (11 x 0.05 x 0.598736939) = 0.5688 + 0.3293 = 0.8981

Answer:

ADB = Major Arc

arc measure = 310

Step-by-step explanation:

major arc measure = 360 - 50 = 310

Answer:

it would be 3/5*4/1

Step-by-step explanation:

To divide you multiply the first number by the reciprocal of the second number. Check and you'll see that the answer is the same. Hope this helps!

Answer:

The answer is 3/5 x 4/1

Step-by-step explanation:

20%

Here's a tip: Always start percentage calculating with dividing the current number by 10.

Answer:

6.09 * 10 ^-3

Step-by-step explanation:

We want one non zero digit to the left of the decimal

Move the decimal 3 places to the right

6.09

The exponent is 3 and it is negative since we move to the right

6.09 * 10 ^-3

Answer:

6.09(10⁻³)

Step-by-step explanation:

Step 1: Put number into proper scientific decimal form

6.09

Step 2: Figure out how many decimals places it moves

Since it moves to the left 3, our exponent would be -3

Answer: True

Step-by-step explanation: Taking the triangle from the left and moving it to the right creates a rectangle. From there just do 12.8×4.5.

Answer:

Option 2

Step-by-step explanation:

The average temperature in January is -1 degrees celsius. Last year, it was 1 degrees celsius higher than the average.

-1 + 1 = 0

Answer:

The second answer.

Step-by-step explanation:

The average temp. is -1C.

'was 1C warmer' = +1

-1+1=0

Answer:

9 mile trip

Step-by-step explanation:

$15 + $15 = $30

$15 + $9 = $24

$15 + $25 = $40

$15 + $12 = $27

$30 > $25

$24 < $25

$40 > $25

$27 > $25

Answer:

The first answer.

Step-by-step explanation:

The first answer.

What was the temperature of the air?

'was 2C warmer than the surface of the ice'

warmer than= +2c

Temp. of ice=-2c

-2c+2c=0

Answer:

Option 1

Step-by-step explanation:

The temp. was -2 degrees celsius.

The temp. got 2 degrees celsius warmer.

-2 + 2 = 0

What is your question?

Answer:

yeah what's your question?

Answer:

the slope of A'B' = 3

A'B' passes through point O

Step-by-step explanation:

A dilation with scale factor 3 gives the effect of stretching the line AB three times longer. As dilation does not change the direction of the line, the slope will stay the same. If point O lies on AB and is the center of dilation, then the point O must also lie on A'B'

The required black space in the statement "The slope of AB is 3. The slope of A1 B1 is___. A1 B1 _____ through point O". is filled by 3 and passes.

Given that,
To Select the correct answer from each drop-down menu. AB is dilated by a scale factor of 3 to form A 1 B1. Point O, which lies on AB, is the center of dilation. The slope of AB is 3. The slope of A1 B1 is___. A1 B1 _____ through point O.

The scale factor is defined as the ratio of modified change in length to the original length.

Here, is o is the center of the line AB and slope of line AB is 3 than the line dilated with scale factor 3 A1B1 has also a scale factor of 3 because Position of dilation is center 0 thus dilation did not get any orientation.
And the center of dilation is O so line A1B1 passes through O.

Thus, the required black space in the statement "The slope of AB is 3. The slope of A1 B1 is___. A1 B1 _____ through point O". is filled by 3 and passes.

Learn more about line Scale factors here:

https://brainly.com/question/22312172

#SPJ2

Answer:

a. [tex]N(1)=2600[/tex]

b. [tex]N'(a) = 470/a[/tex]

c. N(a) has no maximum value, max N'(a) = 470 (when a = 1)

d. lim a→[infinity] N′(a) = 0

Step-by-step explanation:

a.

the variable 'a' is the amount spent in thousands of dollars, so $1,000 is equivalent to a = 1. Then, we have that:

[tex]N(1)=2600 + 470ln(1)[/tex]

[tex]N(1)=2600 + 470*0[/tex]

[tex]N(1)=2600[/tex]

b.

To find the derivative of N(a), we need to know that the derivative of ln(x) is equal (1/x), and the derivative of a constant is zero. Then, we have:

[tex]N'(a) = 2600' + (470ln(a))'[/tex]

[tex]N'(a) = 0 + 470*(1/a)[/tex]

[tex]N'(a) = 470/a[/tex]

c.

The value of 'ln(a)' increases as the value of 'a' increases from 1 to infinity, so there isn't a maximum value for N(a).

The maximum value of N'(a) is when the value of a is the lower possible, because 'a' is in the denominator, so the maximum value of N'(a) is 470, when a = 1.

d.

When the value of 'a' increases, the fraction '470/a' decreases towards zero, so the limit of N'(a) when 'a' tends to infinity is zero.

Answer:

S is the volume of the small cup, M the volume of the medium cup and L the volume of the large cup:

2*S + 2*M + 4*L = 160oz

2*S + 6*M + 1*L = 160oz

5*S + 1*M + 3*L = 160oz.

First, we must isolate one of the variables, for this we can use the first two equations and get:

2*S + 2*M + 4*L = 160oz = 2*S + 6*M + 1*L

We can cancel 2*S in both sides:

2*M + 4*L = 6*M + 1*L

now each side must have only one variable:

4*L - 1*L = 6*M - 2*M

3*L = 4*M

L = (4/3)*M.

now we can replace it in the equations and get :

2*S + 2*M + 4*(4/3)*M = 160oz

2*S + 6*M + (4/3)*M = 160oz

5*S + 1*M + 4M = 160oz.

simplifing them we have:

2*S + (22/3)*M +  = 160oz

2*S + (22/3)*M  = 160oz

5*S + 5*M  = 160oz.

(the first and second equation are equal because we used those to get the relation of M and L, so we now have only two equations):

2*S + (22/3)*M  = 160oz

5*S + 5*M  = 160oz.

We can take the second equation and simplify it:

S + M = 160oz/5 = 32oz

S = 32oz - M

Now we can replace it in the first equation and solve it for M

2*S + (22/3)*M = 2*(32oz - M) + (22/3)*M = 160oz

62oz - 2*M + (22/3)*M = 160oz

-(6/3)*M + (22/3)*M = 98oz

(18/3)*M = 98oz

M = (3/18)*98oz = 16.33 oz

Then:

L = (4/3)*M =(4/3)*16.33oz = 21.78 oz

and:

S = 32oz - M = 32oz - 16.33oz = 15.67oz

Answer:

343 cm3

Step-by-step explanation:

Answer:

side(s) =7cm

volume (v)=l^3

or, v = 7^3

therefore the volume is 343cm^3.

hope its what you are searching for..

Answer:

D. 66

Step-by-step explanation:

Well if AD is 100 and AC is 34 that leaves CD so we can just subtraction 34 from 100 and get 66.

Answer:

D. 66

Step-by-step explanation:

AD = 100

AC = 34

The whole line is 100. A part of the line is 34. The other part will be 66.

100 - 34 = 66

Answer:

C. Approaches 35

Step-by-step explanation:

If we graph the expression, we see that we have an asymptote at y = 35.

Answer:

21/5

Step-by-step explanation:

if a/b = c, then b=a/c

in other words:

divide -7/25 by -1/15 to get the answer

It also helps to use the fact that a/b / c/d = a/b * d/c

-7/25 / -1/15 = -7/25 * -15/1

= 105 / 25

= 21 / 5

Answer:

[tex]4 \frac{1}{5} [/tex]

Step-by-step explanation:

[tex] \frac{ - 7}{25} \div x = \frac{ - 1}{15} [/tex]

[tex]x = \frac{ - 7}{25} \div \frac{ - 1}{15} [/tex]

[tex] = \frac{7}{25} \times \frac{15}{1} [/tex]

[tex] = \frac{21}{5} = 4 \frac{1}{5} [/tex]

Answer:

0.015 radians per second.

Step-by-step explanation:

They tell us that at the moment the speed would be 6 ft / s, that is, dx / dt = 6 and those who ask us is dθ / dt.

Which we can calculate in the following way:

θ = arc sin 100/200 = pi / 6

Then we have the following equation of the attached image:

x / 100 = cot θ

we derive and we are left:

(1/100) * dx / dt = - (csc ^ 2) * θ * dθ / dt

dθ / dt = 0.01 * dx / dt / (- csc ^ 2 θ)

dθ / dt = 0.01 * 6 / (- csc ^ 2 pi / 6)

dθ / dt = 0.06 / (-2) ^ 2

dθ / dt = -0.015

So there is a decreasing at 0.015 radians per second.

The horizontal distance and the height of the kite are illustration of rates.

The angle is decreasing at a rate of 0.24 radian per second

The given parameters are:

[tex]\mathbf{Height =y= 100ft}[/tex]

[tex]\mathbf{Speed =\frac{dx}{dt}= 6fts^{-1}}[/tex]

[tex]\mathbf{Length = 200}[/tex]

See attachment for illustration

Calculate the angle using the following sine ratio

[tex]\mathbf{sin(\theta) = \frac{100}{200}}[/tex]

[tex]\mathbf{sin(\theta) = \frac{1}{2}}[/tex]

The horizontal displacement (x) is calculated using the following tangent ratio:

[tex]\mathbf{tan(\theta) = \frac{100}{x}}[/tex]

Take inverse of both sides

[tex]\mathbf{cot(\theta) = \frac{x}{100}}[/tex]

[tex]\mathbf{cot(\theta) = \frac{1}{100}x}[/tex]

Differentiate both sides with respect to time (t)

[tex]\mathbf{-csc^2(\theta) \cdot \frac{d\theta}{dt} = \frac{1}{100} \cdot \frac{dx}{dt}}[/tex]

Substitute known values

[tex]\mathbf{-csc^2(\theta) \cdot \frac{d\theta}{dt} = \frac{1}{100} \cdot 6}[/tex]

[tex]\mathbf{-csc^2(\theta) \cdot \frac{d\theta}{dt} = \frac{6}{100}}[/tex]

Recall that:

[tex]\mathbf{sin(\theta) = \frac{1}{2}}[/tex]

Take inverse of both sides

[tex]\mathbf{csc(\theta) = 2}[/tex]

Square both sides

[tex]\mathbf{csc^2(\theta) = 4}[/tex]

Substitute [tex]\mathbf{csc^2(\theta) = 4}[/tex] in [tex]\mathbf{-csc^2(\theta) \cdot \frac{d\theta}{dt} = \frac{6}{100}}[/tex]

[tex]\mathbf{-4 \cdot \frac{d\theta}{dt} = \frac{6}{100}}[/tex]

Divide both sides by -4

[tex]\mathbf{\frac{d\theta}{dt} = -\frac{24}{100}}[/tex]

[tex]\mathbf{\frac{d\theta}{dt} = -0.24}[/tex]

Hence, the angle is decreasing at a rate of 0.24 radian per second

Read more about rates at:

https://brainly.com/question/6672465

Answer:1.P(exactly 2 kids are girls)=3/8

2. P(at least 1 is boy)=7/8

Step-by-step explanation:

1.P(exactly 2 kids are girls)=N(outcomes with 2 girls) /Total number of outcomes.

All possible outcomes are ggb,gbg, bgg, gbb, bgb, bbg, ggg, bbb - total 8

Outcomes where are exactly 2 girls are:

ggb,gbg, bgg - total 3 outcomes

So P(exactly 2 are girls)=3/8

2. P(at least 1 is boy)=Number of outcomes , where are at least 1 boy (1,2 or all 3 kids are boys)/ Total number of outcomes

All possible outcomes are ggb,gbg, bgg, gbb, bgb, bbg, ggg, bbb - total 8

Outcomes, where at least 1 kid is boy: ggb,gbg, bgg, gbb, bgb, bbg, bbb - total  7

P(at least 1 is boy)=7/8

Answer:D

Step-by-step explanation: