Suppose the coefficient of static friction is 0.55 rather than 0.61. is the weight of the pail and sand necessary to start the pumpkin moving in this case greater than, less than or equal to 11 N? calculate the required weight.

Answers

Answer 1

The weight of the pail and sand necessary to start the pumpkin moving in this case is less than 11 N.

What is the force of friction acting the pumpkin?

The force of friction acting on the pumpkin depends on the weight of the pumpkin and the coefficient of static friction.

F = μW

where;

μ is the coefficient of static frictionW is the weight of the pumpkin

The weight of the pumpkin is calculated as follows;

W = mg

where;

m is the mass of the pumpkin = 1.8 kgg is acceleration due to gravity

W = 1.8 kg  x  9.8 m/s²

W = 17.64 N

The static friction force preventing the pumpkin from moving is calculated as follows;

F = μW

F = 0.55 x 17.64 N

F = 9.7 N

Thus, the minimum force required to move the pumpkin is 9.7 N which is less than 11 N.

Learn more about static friction force here: https://brainly.com/question/13680415

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The complete question is blow:

Suppose the coefficient of static friction is 0.55 rather than 0.61. is the weight of the pail and sand necessary to start the pumpkin moving in this case greater than, less than or equal to 11 N? calculate the required weight. mass of the pumpkin is 1.8 kg.


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Answers

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Answers

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Answer:

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Answers

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Answers

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Answers

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