If both electron affinity and heat of sublimation are smaller, then MX would be less stable.
M²⁺ + X⁻(g) → MX(s), + Lattice energy
Therefore, from the given thermodynamic cycle,
Lattice enthalpy = -100-800 = -900kJ/mol
Lattice enthalpy MX = -900kJ/mol
Enthalpy of the formation of MX is given as follows:
M(s) + 1/2X₂(g) --------->M(g) + 1/2 X₂(g)
Enthalpy of formation = +250 kJ
M(g) + 1/2X₂(g) → M(g) +X(g)
Enthalpy of formation = +350 kJ
M (g) + X(g) ------> M²⁺(g), + X(g)
Enthalpy of formation = +400 kJ
M²⁺ (g) + X(g) 24→ M²⁺(g), + X(g)
Enthalpy of formation = +200kJ
M²⁺(g), + X⁻(g)→ MX(s)
Enthalpy of formation= +900kJ.
Enthalpy of formation of MX = 250 +350 +406-200-900 = -100 kJ
Therefore, Enthalpy of formation of MX = -100 kJ
Since electron affinities are the heat released while the heat of sublimation is the heat absorbed then if electron affinity decreases while the heat of sublimation, increases then the overall enthalpy of formation of MX will be less negative. Hence in that case MX would be less stable.
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what is the concentration (m) of sodium ions in 4.57 l of a 1.25 m na3pna3p solution?
The sodium ion molarity in 4.57 L of a 0.847 M Na3P Nh 3 P solution is thus 2.54 M.
What effects does sodium have on the body?A little quantity of sodium is needed by the human body to convey nerve impulses, contract or relax muscles, and keep the right ratio of water and minerals. We are thought to require 500 mg of salt everyday for these essential processes.
BriefingOne way to write an equation is:
Na₃P → 3Na⁺ + P⁻³
The molar mass divided by the mass in L gives the concentration (M):
C = n / V
We may determine the number pf moles of Na3P by using the concentration provided by the issue, and by using that value, we can get the molar mass of Na+:
4.57 L * 2.35 M = 10.7395 mol Na₃P
10.7395 mol Na₃P * = 32.2185 mol Na⁺.
Concentration of Na⁺ = mol Na⁺ / V
[Na⁺] = 32.2185 mol Na⁺ / 4.57 L = 7.05 M
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which reaction is the formation reaction for cao(s) ? in other words, which equation has a δH∘rxn value equal to the δH∘f value for cao(s) 2ca(s) o2(g)⟶2cao(s) ca(s) 12o2(g)⟶cao(s) cao(s)⟶ca(s) 12o2(g) ca2 (aq) o2−(aq)⟶cao(s) 2cao(s)⟶2ca(s) o2(g)
The reaction Ca(s) + 1/2O₂(g) ⇒CaO(s) in which ΔH⁰rxn value equal to the ΔH⁰f value for cao(s).
In above reaction
calcium and oxygen react to form calcium oxide. In this reaction one mole of calcium oxide solid formed so the enthalpy change during this is reaction is considered as enthalpy of formation.
The enthalpy change that takes place when 1 mole of a substance is created from its component elements in their standard states is known as the standard enthalpy of formation.
Hence, one mole of cao is formed from a constituent atom from their elemental state is the enthalpy of formation.
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of the following, which are characteristics of weak electrolytes? (select all that apply) select all that apply: they produce a low concentration of ions when dissolved in water. they are soluble in water. they exhibit no conductivity. they exhibit low conductivity.
Answer:A and C
Explanation:
They produce a low concentration of ions when dissolved in water, they are soluble in water and they exhibit low conductivity are characteristics of weak electrolytes.
Electrolytes are substances that release ions when they are dissolved in water. Among them, salts, bases, and acids can all be categorised. These solutions transmit electricity because the positive and negative ions, referred to as cations and anions, respectively, are mobile. For instance, diluted sulfuric acid, which contains both negative sulphate ions and positive hydrogen ions (H+, a cation), serves as the electrolyte in a lead-acid automotive battery (SO42-, an anion).
Ionic compounds, such as ionic salts, that separate into cations and anions when dissolved, or covalent substances that chemically react with water to produce ions, are examples of electrolytes (such as acids and bases). Compounds referred to as nonelectrolytes do not produce ions when dissolved in water.
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an aqueous solution is: any liquid with another compound dissolved in it. an ionic compound with water dissolved in it. water with a molecular compound dissolved in it. water with another compound dissolved in it. None of the above
Aqueous solutions have various uses because they participate in various processes, creating a wide variety of substances that tend to dissolve in water.
Example of aqueous solutionsBlood is a good example of important aqueous solutions, because its solubility allows life to be sustained.
Blood is an aqueous solution made up of salts and proteins (plasma), in which erythrocytes or red blood cells, white blood cells or leukocytes are found, and the functions that these components fulfill are important for life.
Other examples of aqueous solutions:
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The temperature at 9 p.m. was -4 degrees Fahrenheit, which is one-third of the temperature at midnight. What was the temperature at midnight? Write an equation that could represent this situation.
Temperature at midnight would be -12 degrees Fahrenheit and is determined using the equation that represents this situation i.e., T/3 = -4.
In mathematics, an equation is a representation of a formula or statement that illustrated an equality relationship of two expressions. The expressions are connected with an equals sign. Solving an equation containing variables involves calculating values of the variables that make the equality true. The variables for which the equation has to be solved are also called unknowns, and the values of the unknowns that satisfy the equality are called solutions of the equation.
Based on the information provided, as the temperature at 9am is -4 and it is the 1/3 of the temperature at midnight T, the equation would be:
1/3* Midnight temperature = 9am temperature
1/3*T = -4 or T/3 = -4
Solving the equation,
T = 3*-4 = -12.
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What is the change in the cell voltage when the ion concentrations in the anode half-cell are increased by a factor of 10?.
The change in the cell voltage when the ion concentrations in the anode half-cell are increased by a factor of 10 is decreased by 0.030 V.
The electrochemical cell has both species the Fe²⁺ and Ag⁺ at 1 M concentration . the cell potential is given the standardbred cell potential E°.
at anode if the concentration increased by 10 then:
ΔE = -(R T / nF ) ln Q
now the reactions are :
at anode : Fe ---> Fe²⁺ + 2e
at cathode : 2 ( Ag⁺ + e ---> Ag)
overall : Fe + 2Ag⁺ ----> Fe²⁺ + 2Ag
Q = [Fe²⁺ ] / [Ag⁺]²
now, n = 2 , the change in cell potential is given as:
ΔE = ( -RT / nF ) ln [Fe²⁺ ] / [Ag⁺]²
[Fe²⁺ ] = 10 M
ΔE = -(8.314 × 298 ) / 2 × 96485 ln [10] / [1]
ΔE = - 0.030 V
Thus, the cell potential at anode half cell will decreased by 0.030 V.
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question mode multiple choice question calculate the enthalpy change when 1.75 moles of diethyl ether changes from the liquid to the gas phase if δhovap
the enthalpy change when 1.75 moles of diethyl ether changes from the liquid to the gas phase is ΔH= 47.775 KJ
What is enthalpy?
Enthalpy is an energy-like attribute or state function; it has the dimensions of energy (and so is measured in joules or ergs), and its value is controlled wholly by the system's temperature, pressure, and composition, rather than its history.
What is enthalpy with example?
This Enthalpy is equal to the sum of the internal energy of such a system with the constant. You must realise that the forms of energy fluctuate, while Enthalpy remains constant. For example, when water freezes into ice, some energy is used in the process, which is referred to as Enthalpy.
Here ΔH°vap for die ethyle ether = 27.3 KJ/mol
The enthalpy change when 1.75moles of die ethyle ether charges from the liquid to the gas phase will be,
ΔH = (27.3 × 1.75)KJ
ΔH= 47.775 KJ
Hence47.775 KJ is a correct answer.
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classify each of the compounds as soluble or not soluble: potassium carbonate chromium(iii) iodide iron(ii) nitrate
potassium carbonate is not soluble, chromium is soluble in water, iodide iron soluble in ether alcohol and ammonia and nitrate is soluble in water.
With the chemical formula K2CO3, potassium carbonate is an inorganic substance. It is a white salt that may be dissolved in water. It is effervescent and frequently manifests as a wet or soggy solid. Glass and soap manufacture are the two main industries that utilise potassium carbonate. For the creation of glass and soap, potassium carbonate is frequently utilised.
Common nitrate ingredients in explosives and fertilisers. Water is a solvent for almost all inorganic nitrates. Bismuth oxynitrate is one type of insoluble nitrate. Similar to NO, nitrate has physiological effects on the body in a variety of systemic activities, such as lowering blood pressure, preventing platelet aggregation, and protecting blood vessels [3, 37].
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Double Replacement Worksheet
Write the formula unit equation for this reaction occurring in water: Potassium sulfate and barium chloride is mixed to form potassium chloride and barium sulfate.
1. KSO4 (aq) + BaCl (aq) → KCl (aq) + BaSO4 (s)
2. K2SO4 (s) + BaCl2 (s) → 2KCl (aq) + BaSO4 (s)
3. 2 K3SO4 (aq) + 3 BaCl2 (s) → 6 KCl (aq) + 2 Ba3(SO4)2 (s)
4. K2SO4 (aq) + BaCl2 (aq) → 2 KCl (aq) + BaSO4 (s)
5. K2SO4 (aq) + BaCl2 (s) → 2 KCl (aq) + BaSO4 (s)
6. 2 K3SO4 (aq) + 3 BaCl2 (aq) → 6 KCl (aq) + 2 Ba3(SO4)2 (s)
The formula unit for the equation when potassium sulfate and barium chloride are mixed to form potassium chloride and barium sulfate would be: [tex]K_2SO_4 (aq)+ BaCl_2 (aq) --- > 2KCl (aq) + BaSO_4 (s)[/tex]. Option 4.
Chemical equation of reactionsThe chemical equation of reactions can be derived from the chemical formula of each participating species of the reaction. Thus, when potassium sulfate and barium chloride are mixed to form potassium chloride and barium sulfate, the chemical equation can be derived as follows:
Chemical formula of potassium sulfate = [tex]K_2SO_4[/tex]
Chemical formula of barium chloride = [tex]BaCl_2[/tex]
Chemical formula of potassium chloride = [tex]KCl[/tex]
Chemical formula of barium sulfate = [tex]BaSO_4[/tex]
The reaction is a double decomposition reaction and can also be a precipitation reaction because one of the salts formed, barium sulfate is an insoluble salt.
The overall equation of the reaction, can thus, be written as [tex]K_2SO_4 (aq)+ BaCl_2 (aq) --- > 2KCl (aq) + BaSO_4 (s)[/tex]
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What happens to the temperature of a mixture of ice and liquid water as heat is applied at a constant rate?.
Until all of the ice has melted, the mixture's temperature doesn't change at all; after that, it starts to rise steadily.
How does chemistry define temperature?The average energy of every molecules and atoms in a substance is what chemists refer to as the substance's temperature. The kinetic energy of a substance's constituent particles varies.
What does temperature define?Temperature is a unit used to represent hotness or coolness on any of a number of scales, including F and Celsius. According to temperature, heat energy will naturally move from a hotter (body with a warmer pressure) to a colder (body with a temperature lower) .
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A sample of propane gas has a volume of 35. 3-l at 315 k and 922 torr. What is the number of moles of propane gas?.
The propane gas test has a volume at 35.3 l at 315 k 922 torr, and there are 37.1 moles if propane gas in total.
What is propane used for?Its main uses include heating homes and water, preparing and storing food, drying clothes, and powering agricultural and industrial machines. Gas is used as a raw material in the chemical industry for the manufacturing of polymers and other compounds. Liquefied natural gases (LPG), often known as propane, is a commonly utilized fuel that is produced domestically. Use of propane as a car fuel alone increases energy security, makes on-site refueling more affordable, and reduces air pollution and the environmental effects of vehicles.
Briefing:
We begin by assuming the gas is in fact an ideal gas in order to find a solution. the ideal gas's PV version;
PV = nRT
=(922/760) x 35.3/315
=1 x V2 /273
V2 = 37.1L
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Please help me on this
And I will give brainliest
The reducing agent belongs in the left (oxidation) circle of the given Venn diagram. Therefore, option (1) is correct.
What is a reducing agent?A substance that loses its electrons to other substances in a redox reaction and gets oxidized to a higher valence state is known as a reducing agent.
A reducing agent can be described as one of the reactants of an oxidation-reduction reaction that can reduce the other reactant by donating its electrons to the reactant.
If the reducing agent does not give away its electrons to other substances in a reaction, then the reduction cannot occur. For example, in the following chemical reaction;
[tex]H_2(g) + F_2(g) \longrightarrow 2HF(g)[/tex]
Hydrogen gas acts as a reducing agent because it gives out its electrons to fluorine, which permits fluorine to be reduced.
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How many milliliters of 0. 110 m hcl are needed to titrate each of the following solutions to the equivalence point?.
The volume of HCl needed is 4.12 mL
The dilution or neutralization reaction equation is as follows: n1*M1*V1= n2*M2*V2 where,
n1, M1, and V1 are the acid's molarity and volume.
n2, M2, and V2 stand for the basal n-factor, molarity, and volume
Given:
n₁=1
M₁=0.110M
n₂ =1
M₂=0.00950M
V₂= 50.0mL
To find: V₁=?
On substituting the values:
n₁*M₁*V₁= n₂*M₂*V₂
1*0.110*V₁=1*0.00905*50
V₁=4.12mL
Hence, the volume of HCl needed is 4.12 mL
The quantity of space that matter takes up is measured in terms of volume. A physical material with mass and room to move about is said to be matter. The usual volume measurement in physical sciences like chemistry is in cubic meters (m3). Volume is equal to mass times density, hence you can calculate it by dividing mass by density. Assure that throughout the calculations, the units are maintained.
In essence, the shape's area and height are multiplied to determine the volume. Volume = Base Area x Height
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in their experiment you epoxidized r-carvone. the epoxidation could have occurred at the double bond in the ring or at the double bond outside the ring. which product was actually formed
The product that was formed in the experiment is an epoxide that was formed at the double bond outside the ring.
This can be determined by looking at the structure of the product, which contains an oxygen atom connected to two carbon atoms with a double bond outside the ring.
The reaction that occurred in the experiment is known as an epoxidation reaction, which occurs when an alkene (in this case, the double bond outside the ring) is reacted with an oxidizing agent (such as a peroxide or an organic hydroperoxide).
In the reaction, the double bond of the alkene is broken and replaced with an oxygen atom, forming an epoxide. The reaction is typically catalyzed with a metal-based catalyst, such as a transition metal, which helps to facilitate the reaction.
In the case of the epoxidation of r-carvone, the epoxide was formed at the double bond outside the ring because the reactant (the double bond) was located outside the ring. Since the double bond inside the ring is not easily accessible to the reagents, the epoxidation reaction preferentially occurred at the double bond outside the ring.
Therefore, the product that was formed in the experiment is an epoxide that was formed at the double bond outside the ring. The image attached explains the reaction.
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A electrolytic cell is set up as was done in this experiment but with a different metal. An average current of 144.2 mA is delivered for 16 minutes and 39 seconds. The cathode gains 0.1427 g in mass. If there are two moles of electrons transferred per mole of the metal, what is the molar mass of the metal?
If there are two moles of electrons transferred per mole of the metal, 191.1g/mol will be the molar mass of the metal.
Since formula for faraday's law of electrons is,
Since m = 0.1427g,
L=144.2
= 144.2 *(1A/1000mA)
= 0.1442,
t = 16min39
= 16min*(60/1min)
= 999 second
Z = 2e-mol
by substituting all the values in faraday's law of electrons formula,
0.1427 g = (0.1442*999*M*1/96485*2)
molar mass M = (0.1427g*96485*2/0.1442*999*1)
M = 191.1538 g/mol = 191.1g/mol
Therefore molar mass of metal will be 191.1g/mol.
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Nuclear decay occurs according to first-order kinetics. How long will it take for a sample of radon-218 to decay from 99 grams to 0. 50 grams? the half-life of radon-218 is 35 milliseconds.
In 2.6*10² ms, a sample of radon-218 will deteriorate from 99 grams to 0.50 grams. The half-life of radon-218 is 35 milliseconds.
How crucial is nuclear power? What is a good nuclear example?The only significant, carbon-free energy resource that the nation can extensively expand to produce significant amounts of power is nuclear energy. When fossil fuels are burned to produce the same number of electricity, nuclear power plants avoid producing a sizable amount of emissions. One of the best instances of nuclear fusion seems to be the sun. Helium is created when hydrogen nuclei combine inside the sun, producing thermal energy which warms the Earth..
Briefing:t = 2.303/R log A₀/A
Hence, R = 0.693/t/2
t = 2.303/0.693*35 log 99/0.5
t = 267ms
= 2.6*10² ms
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helium gas effuses through a porous container 8.25 times faster than an unknown gas. estimate the molar mass of the unknown gas.
Ideal gas law is valid only for ideal gas not for vanderwaal gas. To solve such, we need to know the relation between rate of effusion and molar mass of gases. Therefore, the molar mass of unknown gas is 285.7g/mol.
What is ideal gas equation?Ideal gas equation is the mathematical expression that relates pressure volume and temperature.
Mathematically the relation between rate of effusion of gases and their molar masses can be given as:
rate of effusion of unknown gas/rate of effusion of helium gas=√molar mass of helium gas/molar mass of particular gas
rate of effusion of helium= 8.25×rate of effusion of unknown gas
Substituting all the given values we get
rate of effusion of unknown gas÷ 8.25×rate of effusion of unknown gas=√4 g/mol÷ molar mass of unknown gas
1÷ 8.25=√44 g/mol÷ molar mass of unknown gas
squaring both side
0.014=4 g/mol÷ molar mass of unknown gas
mass of unknown gas=285.7g/mol
Therefore, the molar mass of unknown gas is 285.7g/mol
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the number average molecular weight of polypropylene is 1500000 g/mol. compute the degree of polymerization
the number average molecular weight of polypropylene is 1500000 g/mol, the Degree of Polymerization = 35 648
Moleculer weight of polypropylene = 1500000g/mal To calculate Degree of Polymerization First we know the monomer of Polymer.
Step-1 Polypropylene Polymer made by
Propylene monomer
CH3-CH=CH₂ → Propylene mallar mass of propylene = 42-078 8/mal
molar mass of Propylene = 12.01 x 3 + 6x1-608
A 36.03 + 6·048 Malay mass Propylene = 42.078 8/mal.
Step- Polymerisation Begrore = (Molar Mass of) Polymer
molar mass of monomer
= 1500000/42.078
= 35648
Degree of Polymerization = 35 648
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- Quick Check
Which atom has one as both the atomic mass and atomic number?
Nitrogen
Hydrogen
a
Helium
Oxygen
Answer:
Explanation:
Hydrogen
how many grams of ni are formed from 58.5 g of ni2o3 ? 2ni2o3(s)⟶4ni(s) 3o2(g) step 1: show the strategy for solving this problem.
The grams of ni are formed from 58.5 g of ni2o3 is 41.2 g.
The mole, mol, is the unit of amount of substance inside the global gadget of units. the amount quantity of the substance is a degree of how many fundamental entities of a given substance are in an object or pattern. The mole is described as containing precisely 6.02214076×10²³ primary entities.
Calculation:-
2ni2o3(s)⟶4ni(s)
The molar mass of 2ni2o3 = 2(2×57 + 3 × 16)
= 324 g
324 g of ni2o3 produces 228 g of Ni
Therefore, 58.5 g of ni2o3 will produce = 228 / 324 × 58.5
= 41.2 g
All chemistry is pervaded with the aid of the mole definition. on account that most quantitative chemical calculations are centered on the mole, for the have a look at chemistry, the expertise of the mole is vital. Information of how the mole applies to mass, a variety of entities.
Mole is defined as the amount of the substance containing an equally wide variety of discrete entities (atoms, molecules, ions, etc) as there are atoms in a pattern of natural 12C weighing precisely 12g. The wide variety of particles present in one mole of any substance =Avogadro variety=6.
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what is the predominant intermolecular force in h2nnh2? group of answer choices ionic bonding dipole-dipole attraction london-dispersion forces ion-dipole attraction hydrogen bonding
The predominant intermolecular force in H₂NNH₂ is hydrogen bonding.
Hydrogen bonding intermolecular forces are present in compounds which have at least one hydrogen atom directly bonded to either nitrogen, oxygen or fluorine atom.
Hydrogen bonding is the strongest intermolecular force of attraction.
In hydrazine there are 4 hydrogen atoms bonded directly to two nitrogen atoms. Hence, hydrazine has hydrogen bonding intermolecular force present.
Use of hydrazine
Hydrazine is used as a corrosion inhibitor in cooling water reactor. It is also used in the process of electrolytic plating of metals on plastic and glass. One of the main use of hydrazine is in the manufacturing of agricultural chemicals.
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the volume of a sample of hydrogen gas was decreased from 12.35 l12.35 l to 5.64 l5.64 l at constant temperature. if the final pressure exerted by the hydrogen gas sample was 5.00 atm,5.00 atm, what pressure did the hydrogen gas exert before its volume was decreased?
2.2834 atm of pressure is initially present before the volume of the gas was reduced.
Assuming the condition to be an ideal behavior, the gas sample should satisfy the Boyle's law, which states that
PV = constant when temperature is held constant.
It can be said that, the pressure the gas exerts is inversely related to the volume of the airtight container. Therefore,
P₁V₁ = P₂V₂
On rearranging,
P₁ = (P₂V₂)/V₁
We know that V₁ is 12.35L and V₂ is 5.64L P₂ is 5 atm. On substituting we get,
P₁ = (5x5.64)/12.35
P1₁ = 28.2/12.35
P₁ = 2.2834 atm
Therefore the initial pressure would be 2.2834 atm when the volume of the gas is reduced from 12.34L to 5.64L.
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What caused the rate of discovery of elements to increase after 1700
Determine the correct name for the compound, c3h8. In organic chemistry, this is referred to as propane.
Tricarbon octahydride is the correct name for the compound C3H8.
C3H8 is an example of a covalent compound. Covalent compounds are those that involve the sharing of electrons between two elements. Electrons are shared between hydrogen and carbon in this case. Because hydrogen and carbon are nonmetals, they will form a covalent bond. The property of the covalent bond's name is given by,
(1). We must first write the names of the more electronegative element and then the less electronegative element.
(II). When the number of atoms in an element exceeds one, we add to prefixes, which are as follows:
For a single atom = mono
For two atoms = di
For three atoms = tri
4 atoms = tatra
5 atoms = penta
6 atoms = hexa
7 atoms = septa
For example, 8 atom octa.
As a result, the compound's name will be tricarbon octahydride.
As a result, tricarbon octahydride is the correct name for the compound C3H8.
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na and k both use to passively diffuse across the plasma membrane. leak channels voltage-gated channels facilitated diffusion exocytosis carrier-mediated transport
Na and K both use to passively diffuse across the plasma membrane to leak channels.
The membrane that isolates a cell's interior from its external environment is termed the plasma membrane, sometimes known as the cell membrane, and it can be found in every type of cell. On the exterior of both bacterial and plant cells, the plasma membrane is connected by a cell wall. The cell is shielded from its surroundings by the plasma membrane, which also controls cellular movement and sends messages. According to the fluid mosaic model, the plasma membrane is made up of a patchwork of phospholipids.
Ion channels that are not gated are those that are constantly open. Because they simply permit ions to pass through the channel without any impedance, these channels are sometimes known as leak channels. Due to the high permeability of the neuron cell membrane to potassium ions, the neuron experiences significant potassium leakage through potassium leak channels.
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to calculate the energy needed to boil water that initially starts in the liquid state below the boiling point, what quantities are needed?
The quantities needed to boil water that initially starts in the liquid state below the boiling point are the mass of the water, the initial temperature of the water, and the specific heat capacity of water.
The energy needed to boil water is specific heat capacity. Specific heat capacity is the amount of heat energy required to rise 1 degree of one kilogram of substance. The formula
Q = m × c × ΔT
ΔT = T - T₀
where
m = the mass of the substance (kg)c = specific heat capacity of the substance (Joule/kg K)ΔT = temperature rise (K)T₀ = the initial temperature (K)T = the final temperature (K)Q = the amount of heat absorbed or released (Joule)The boiling point of water is 100 °C, so we needed to know the mass of water, the initial temperature of the water, and the specific heat capacity of water to calculate the amount of heat energy needed to boil water.
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Dodd's experiment and subsequent experiments by others using fruit flies supported earlier conclusions that.
Fruit flies were studied by Diane Dodd for their responses to geographic isolation and selection.
What was the Dodd's experiment on fruit flies?To mimic geographic isolation, she separated a single colony of fruit flies into several populations that lived in various cages. Maltose-based foods were consumed by half of the populations, while starch-based foods were consumed by the other populations. The flies were examined to determine which flies they chose to mate with after many generations (almost 40 generations).
Conclusions-
Due to geographic isolation & selection for various food sources in the two settings, Dodd discovered that some reproductive isolation had taken place.Starch flies liked other "starch flies, whereas maltose insects chose other "maltose flies."Know more about Diane Dodd's experiment:
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what is the purpose of the test standards prepared in this experiment? the test standards are good practice for making solutions that contain different excess reactants. each test standard shows what an excess of each reagent looks like, so they are the standards against which to compare the different samples. each test standards shows how the limiting reactant is left over after the reaction, so they are the standards against which to compare other samples. each test standards shows how the excess reactant is completely consumed in the reaction, so they are the standards against which to compare other samples.
Standard experiments are good practice for making solutions that contain different excess reactants.
Standards and Specifications are a necessary tool to perform a chemical testing on a uniform and consistent basis. Standards and Specifications represent written directions of the criteria needed for a specific product, process, test, or procedure.
A test is any form of test that requires all test takers to answer the same questions, or a selection of questions from common bank of questions, in the same way, and that is scored in a “standard” or consistent manner, which makes the comparison of the relative performance of individual students or groups of students possible, such tests are known as standardized test.
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If the electron were replaced with a proton moving with the same velocity, how would the resulting acceleration of the particle change?.
The resulting acceleration of proton, compared to the electron's acceleration is in the opposite direction and at a similar rate.
How to describe resulting acceleration of the particle change?Being a vector quantity, acceleration includes components in both the x- and y-axes. By computing the vector's magnitude and direction, we can determine the object's final acceleration.
Because the mass of the proton is greater than the mass of the electron, the acceleration of the proton will be in the opposite direction and at a similar rate. However, the proton's acceleration is smaller in comparison to the electron's acceleration.
In conclusion, when compared to the electron's acceleration, the proton's subsequent acceleration would be smaller in amplitude and in the opposite direction.
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oxalic acid is a diprotic acid. if a solid material contains 53.66 percent of oxalic acid (h2c2o4), by mass, then a 0.6543-g sample of that solid will require ________ ml of 0.3483 m naoh for neutralization.
A 0.6543-g sample of that solid will require 22.39 mL ml of 0.3483 m NaOH for neutralization.
It is given that the Mass of the sample is 0.6543 g andthe Mass percent of oxalic acid is 53.66 %. This means that 53.66 grams of oxalic acid are present in 100 grams of the sample.Then Mass of oxalic acid in the given as follows
Mass of oxalic acid = 53.66/100x(0.6543) = 0.351g
To calculate the number of moles, the equation following equation is used:
No of moles = Given mass/Molar mass.
Here,Given the mass of oxalic acid is 0.351 g and the Molar mass of oxalic acid is 90 g/mol
Putting values in the above equation, we get the number of moles as follows:
No of Moles = 0.351/90
No moles = 0.0039mol
The chemical reaction between oxalic acid and NaOH is as follows:
C₂H₂O₄ + 2NaOH ------> Na₂C₂O₄ + 2H₂O
According to the Stoichiometry of the reaction:
1 mole of oxalic acid reacts with 2 moles of NaOH in the reaction
Then, 0.0039 moles of oxalic acid will react with 2/1 x(0.0039) = 0.0078mol of NaOH
To calculate the volume of the solution, we use the equation used to calculate the molarity of the solution by rearranging it:
Molarity = Number of moles/ Volume of solution
The volume of solution = number of moles/Molarity
We have, Moles of NaOH as 0.0078 moles and Molarity of the solution is 0.3483 M
Putting values in the above-rearranged equation, we get:
The volume of the solution = 0.0078/0.3483x(10000)
The volume of solution = 22.39ml
Hence, the volume of NaOH required is 22.39 mL
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