Summarize the differences between applied science and basic science.

Answers

Answer 1

Answer:

basic would be more of how it works such as cells where applied is to fix like medical

Explanation:

from internet

Basic science, such as understanding how cells work, is research aimed at understanding fundamental problems. Applied science, such as the medical field, is the application of basic scientific knowledge to solve practical problems. Applied science uses and applies information obtained through basic science.

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Related Questions

**Can someone please help me solve these problems step by step, thank you!


1. If a 12-inch diameter driving Gear A has 100 tooth which turns CCW with a torque of 200 ft-lb and 100 rpm is meshed with Gear B, 25 tooth, turn along with Gear C, 50 tooth as they are a compound gear and Gear D, 150 tooth meshed with C.

-->sketch and annotate the gear train.

-->what direction does gear ratio B, C, and D turn?

-->what is the gear ratio for B, C, and D?

-->what is the angular velocity for gears B, C, and D?

-->what is the torque for gears B, C, and D?

-->what is the diameter of gears B, C, and D?


2. In a pulley system, pulley A is moving 1000 rpm and has a diameter of 18inches. There are two pulleys with different sizes, B moving ot 1575 rpm and C moving at 1850 rpm attached on a single axle.

-->sketch and annote the pulley system.

-->what is the diameter of pulley B and pulley C?

Answers

Answer:

The answer is "[tex]\bold{11.428 \ in \ \ and \ \ 9.729 \ in}[/tex]".

Explanation:

The second question solution can be defined as follows:

[tex]N_A= 1000 \ rpm\\\\N_B=1575 \ rpm\\\\N_C=1850 \ rpm\\\\D_A= 18 \ in \\\\[/tex]

In point 1:

Calculating the value of the linear velocity is the same:

[tex]\to V_A=V_B\\\\\to \pi D_A N_A=\pi D_BN_B\\\\\to D_B= \frac{D_A \times N_A}{N_B}[/tex]

          [tex]=\frac{18 \times 1000}{1575}\\\\=11.428 \ in \ \ \text{Diameter of pulley B}[/tex]    

In point 2:

[tex]\to V_A=V_C\\\\\to \pi D_A N_A=\pi D_C N_C\\\\\to D_C=\frac{D_A \times N_A}{N_C}\\\\[/tex]

          [tex]=\frac{1000 \times 18}{1850}\\\\=9.729 \ in \ \ \text{Diameter of pulley B}[/tex]

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