Answer:
i don't get it
Explanation:
4 people are playing a tug of war. Two are pulling on the right side. Two are pulling on the left side. On the right side, one is pulling with a force of 60 N and the other with a force of 70 N. On the left side, one is pulling with a force of 30 N. How much force should the second person on the left apply to keep the rope in equilibrium? HINT: The rope will be in equilibrium if the net force is 0.
Answer:
100
Explanation:
since the two at the left side is pulling with a force of 70 and 60 which equals to 130 for the rope to be in equilibrium, those at the left must also pull with same force. Which makes it 130-30=100N
1. What does the Work-Energy Theorem state?
Work is equal to the change in kinetic energy
Work is equal to the change in momentum
Work is equal to the change in impulse
Work is equal to the change in position
The Work-Energy Theorem states that Work is equal to the change in kinetic energy, which is the first option . This theorem is an essential principle in physics and mechanics, so first option is correct.
Work (W) is a measure of the energy transferred to or from an object by a force acting on it. It is defined as the product of the force applied to the object and the displacement of the object in the direction of the force. When a force does positive work on an object, it transfers energy to the object, increasing its kinetic energy. Conversely, when a force does negative work on an object (opposite to its direction of motion), it takes energy away from the object, decreasing its kinetic energy. So, first option is correct.
Learn more about the work-energy theorem here.
https://brainly.com/question/30560150
#SPJ6
Please help me with this 29 points
Answer:
)Give the definition of poverty line as defined by the World Bank.
what are three physical properties of gases
Answer: Gases have three characteristic properties: (1) they are easy to compress, (2) they expand to fill their containers, and (3) they occupy far more space than the liquids or solids from which they form. An internal combustion engine provides a good example of the ease with which gases can be compressed.
Explanation:
Why are dominant alleles always shown as capital letters?
Answer:
When writing a genotype, the dominant allele is usually represented by a capital letter, while the recessive allele has a lowercase letter.
Explanation:
Please mark me brainlest.
Answer:
Because in a punnett square, dominant alleles need to be differentiated from the recessive alleles, to do this, we write the dominant alleles as capital letters.
Explanation:
what is the name for a force of gravity acting on an object
Answer:
Weight
Explanation:
We call it "Ralph" or "the object's weight".
At the bottom of the air track, the glider hits and stretches a rubber band, that causes the glider to change direction. When the rubber band is maximally stretched, the glider's kinetic energy is zero, because it is momentarily at rest. Since the glider is at the bottom of the air track, its (gravitational) potential energy is also zero. So the sum of the kinetic energy and gravitational potential energies is zero, yet energy is conserved. Where did the energy go?
Answer:
That energy is the elastic potential energy of the rubber band. At the bottom position, all the energy is being stored in the stretched rubber band, in the form of elastic potential energy.
Explanation:
When the glider reaches the bottom, its kinetic energy and potential energy become zero due to zero velocity and zero height, respectively. So, the sum of these energies will become zero. This will violate the law of conservation f energy. Hence, there must be a third type of energy that accounts for the conservation of the energy of the system at other configurations.
That energy is the elastic potential energy of the rubber band. At the bottom position, all the energy is being stored in the stretched rubber band, in the form of elastic potential energy.
Consider a large truck carrying a heavy load, such as steel beams. A significant hazard for the driver is that the load may slide forward, crushing the cab, if the truck stops suddenly in an accident or even in braking. Assume, for example, that a 10 000-kg load sits on the flatbed of a 20 000-kg truck moving at 12.0 m/s. Assume that the load is not tied down to the truck, but has a coefficient of friction of 0.500 with the flatbed of the truck.
A) Calculate the minimum stopping distance for which the load will not slide forward relative to the truck.
B) Is any piece of data unnecessary for the solution?
a) mass of the load.
b) mass of the truck.
c) velocity.
d) coefficient of static friction.
e) all are necessary.
Answer:
A)
the minimum stopping distance for which the load will not slide forward relative to the truck is 14 m
B)
data that were not necessary to the solution are;
a) mass of truck and b) mass of load
Explanation:
Given that;
mass of load [tex]m_{LS}[/tex] = 10000 kg
mass of flat bed [tex]m_{FB}[/tex] = 20000 kg
initial speed of truck [tex]v_{0}[/tex] = 12 m/s
coefficient of friction between the load sits and flat bed μs = 0.5
A) the minimum stopping distance for which the load will not slide forward relative to the truck.
Now, using the expression
Fs,max = μs [tex]F_{N}[/tex] -------------let this be equation 1
where [tex]F_{N}[/tex] = normal force = mg
so
Fs,max = μs mg
ma[tex]_{max}[/tex] = μs mg
divide through by mass
a[tex]_{max}[/tex] = μs g ---------- let this be equation 2
in equation 2, we substitute in our values
a[tex]_{max}[/tex] = 0.5 × 9.8 m/s²
a[tex]_{max}[/tex] = 4.9 m/s²
now, from the third equation of motion
v² = u² + 2as
[tex]v_{f}[/tex]² = [tex]v_{0}[/tex]² + 2aΔx
where [tex]v_{f}[/tex] is final velocity ( 0 m/s )
a is acceleration( - 4.9 m/s² )
so we substitute
(0)² = (12 m/s)² + 2(- 4.9 m/s² )Δx
0 = 144 m²/s² - 9.8 m/s²Δx
9.8 m/s²Δx = 144 m²/s²
Δx = 144 m²/s² / 9.8 m/s²
Δx = 14 m
Therefore, the minimum stopping distance for which the load will not slide forward relative to the truck is 14 m
B) data that were not necessary to the solution are;
a) mass of truck and b) mass of load
3)
An eagle carries a 330g snake to a height of 250 m.
What is the potential energy of the snake after the eagle carries it away?
-)))
A)
1,050,00)
B)
10,000
©
80.850)
D)
808.5)
Answer:
b
Explanation:
Answer:
The table shows the height y (in thousands of feet) of an unmanned aerial vehicle (UAV) x minutes after it begins its descent from cruising altitude. Minutes, x Height (thousands of feet), y 0,62 5,58 10,54 15,50
Physics gravity question, Please help
Answer: 2.7 x10^-4 N
Explanation: 6.674 ×10^-11 × 1000 x 1000 divided by 0.5 squared.
200 Coulombs of charge passes through a point in a circuit for 0.6 minutes. what is the magnitude of the current flowing
Answer:
5.56 A
Explanation:
From the question,
Q = it.............. Equation 1
Where Q = charges, i = current, t = time.
Make i the subject of the equation
i = Q/t.............. Equation 2
Given: Q = 200 coulombs, t = 0.6 minutes = (0.6×60) seconds
Substitite these values into equation 2
i = 200/(0.6×60)
i = 5.56 A
Hence the magnitude of the current flowing through the circuit is 5.56 A
What is the weight of a 25 kg object on Earth with an acceleration due to gravity of 9.8m/s/s?
2.45 n
24.5 n
245 n
2450 n
I want answer plzz??
Answer:
a=0.5g ms^-2
Explanation:
Let tension be T
acceleration be a
g be gravitational acceleration 9.81ms^-2
They share same T and a
by force diagram the net force on m:
T-2.1g=2.1a
net force on M:
6.3g-T=6.3a
solve:
(T-2.1g)/(6.3g-T)=2.1a/6.3a
3T+T=12.6g
T=3.15g newton
3.15g-2.1g=2.1a
a=0.5g ms^-2
What are characteristics of wide-angle lenses?
10POINTS!!
A satellite orbits Earth 350 km above Earth's surface. Calculate the free-fall acceleration at this altitude.
Answer:
8.82 m/s²
Explanation:
Formula for the free fall or gravitational acceleration is;
a = GM/r²
Where;
G is gravitational constant = 6.67 × 10^(-11) m³/kg.s²
M is mass of earth = 5.972 × 10^(24) kg
r is radius of earth = 6371 km
We are given that the satellite orbits Earth 350 km above Earth's surface.
Thus, new radius = 6371 + 350 = 6721 km = 6721000 m
Thus;
a = (6.67 × 10^(-11) × 5.972 × 10^(24))/(6721000²)
a = 8.82 m/s²
Each vertical line on the graph is 1 millisecond (0.001 s) of time. What is the period and
frequency of the sound waves?
Help me!!!!!
Answer:
1000 Hz
Explanation:
please mark me as brainliest
A truck of mass 1600 kg is traveling at 15 m/s. In order to avoid running over a squirrel in the middle of the road, the truck driver begins to brake. What must the braking force on the truck be if the truck comes to stop in 2 s? *
a)12000n
b) 8000n
c)7000n
d)6000n
14
How many
electrons
are in the
atom
pictured?
9 p*
10 nº
Answer:
9 electrons
Explanation:
The structure has 9 protons and hence the number of electrons equals the number of protons that's why it is said to be electrical neutral
Joe has a mass of 110 kg. If Joe has to climb a 10 m ladder to get to the top of a chimney, how much work did do?
Using the American Engineering system of units (AES), a) Calculate the weight of a 170.5 lbm person on the surface of the earth, where the local acceleration due to gravity is 32.174 ft/s2 . Report your answer in pound-force, lbf. b) What would be the weight of a 170.5 lbm astronaut on the moon, where the local acceleration due to gravity is 5.32 ft/s2 . Report your answer in pound-force, lbf.
Answer:
a) the weight of the person is 170.5 lbf
b) weight of the astronaut on the moon is 28.2 lbf
Explanation:
Given the data in the question;
a)
we know that;
weight on the surface of the earth = m[tex]g_{earth[/tex]
given that m = 170.5 lbm and g = 32.174 ft/s²
we substitute
weight on the surface of the earth = 170.5 lbm × 32.174 ft/s²
= 5485.667 lbm-ft/s²
1 lbf = 32.174 lbm-ft/s²
so
weight on the surface of the earth = (5485.667 / 32.174) lbf
weight on the surface of the earth = 170.5 lbf
Therefore, the weight of the person is 170.5 lbf
b)
given that;
weight on the surface of the earth = m[tex]g_{moon[/tex]
m = 170.5 lbm and g = 5.32 ft/s²
weight on the surface of the earth = 170.5 lbm × 5.32 ft/s²
= 907.06 lbm-ft/s²
1 lbf = 32.174 lbm.ft/s²
weight on the surface of the earth = ( 907.06 / 32.174 ) lbf
weight on the surface of the earth = 28.2 lbf
Therefore, weight of the astronaut on the moon is 28.2 lbf
An alumium rod when measured with a steel scale both being at 25 degree celcius appears to be 1 meter long. If the scale is correct at 0 degree celcius, what is the true length of the rod at 25 degree celcius? What wull be the length of rod at 0 degree celcius?
The spacecraft was moved closer to the launcher by the same amount Wednesday as it was on Tuesday, and yet its speed went up much more. Claim 3 suggests that the magnetic force was much stronger on Wednesday than on Tuesday.
Consider the two subclaims for Claim 3 and answer the question below.
Claim 3.A: The magnetic force was much stronger on Wednesday because the magnet was stronger.
Claim 3.B: The magnetic force was much stronger on Wednesday because the magnetic force is stronger closer to the magnets.
Which claim do you think is more convincing, and why?
Answer:
The magnetic force was much stronger on Wednesday because the magnetic force is stronger closer to the magnets.
Explanation:
The magnetic force was much stronger on Wednesday than on Tuesday because the magnetic force is stronger closer to the magnets. Therefore claim 3B is more convincing.
What is magnetic force?Magnetic force can be described as a consequence of electromagnetic force which is caused due to the motion of charges. A moving charge surrounds itself with a magnetic field and the force that arises due to interacting magnetic fields.
The magnetic force between two moving charges is the effect exerted upon either charge by a magnetic field generated by the other. The magnetic force depends on the charge, the motion of each of the objects, and the separation between them.
The magnitude of the force is determined by the cross product of velocity and the magnetic field is equal to q.[v × B]. The resultant force can be described as perpendicular to the direction of the velocity and the magnetic field.
Therefore, the magnetic force was much stronger closer to the magnets.
Learn more about magnetic force, here:
https://brainly.com/question/3160109
#SPJ2
A centrifuge is a device used to separate materials by their masses. A sample in a centrifuge is rotated at high speeds along a circular path a distance of 10.0 cm from the center of the centrifuge. A centrifuge constantly accelerates a 1.00-gram sample from rest to a speed of 1,000 revolutions per minute in 1.00 seconds. Eventually, the sample reaches a speed 10.5 m/s. What is the magnitude and direction of the centripetal force acting on the sample
Answer:
F = 1.047 10⁻² N
Explanation:
Let's use kinematics to find the angular acceleration
w = w₀ + α t
as for rest w₀ = 0
w = α t
α = w / t
let's reduce the magnitudes to the SI system
w = 1000 rev / min (2π rad/ 1 rev) (1 min/ 60s) = 104.72 rad / s
m = 1.00 g (1 kg / 1000 g) = 1,000 10⁻³ kg
r = 10.0 cm (1 m / 100 cm) = 0.100 m
let's calculate
α = 104.72 / 1
α = 104.72 rad / s²
angular and linear variables are related
a = α r
a = 104.72 0.100
a = 10.47 m / s²
finally we substitute in Newton's second law
F = 1 10⁻³ 10.47
F = 1.047 10⁻² N
Which of the following types of models could be used to represent a cell?
a.
idea model
b.
physical model
c.
computer model
d.
all of the above
Answer:
d. all of the above
Missy Diwater, the former platform diver for the Ringling Brother's Circus had a kinetic energy of 15,000 J just prior to hitting the bucket of water. If Missy's mass is 50 kg, then what is her speed?
Answer:
24.5 m/s
Explanation:
KE=1/2mv^2
15000=1/2(50)v^2
30000=(50)v^2
600=v^2
sqrt600=v
v=24.5 m/s!!
A flat loop of wire consisting of a single turn of cross-sectional area 8.80 cm2 is perpendicular to a magnetic field that increases uniformly in magnitude from 0.500 T to 1.80 T in 1.10 s. What is the resulting induced current if the loop has a resistance of 2.20
Answer:
The magnitude of the induced current is 4.73 x 10⁻³ A.
Explanation:
Given;
number of turns, N = 1
cross sectional area of the loop, A = 8.8 cm² = 8.8 x 10⁻⁴ m²
change in magnetic field strength, ΔB = 1.8 T - 0.5 T = 1.3 T
change in time, Δt = 1.10 s
resistance of the loop, R = 2.2 ohm
The magnitude of the induced emf is calculated as;
[tex]emf = \frac{NA \Delta B}{\Delta t} \\\\emf = \frac{1 \times 8.8\times 10^{-4} \times 1.3}{1.10} \\\\emf = 1.04 \times 10^{-3} \ V[/tex]
The induced current in the loop is calculated as;
[tex]I = \frac{emf}{R} \\\\I = \frac{1.04 \times 10^{-3}}{2.2} \\\\I= 4.73 \times 10^{-4} \ A[/tex]
Therefore, the magnitude of the induced current is 4.73 x 10⁻³ A
a guitar string transmits waves at 509 m/s. to create a 491 Hz note, to what length should the guitar player shorten the string?
Answer:
Wavelength = 1.04 meters
Explanation:
Given the following data;
Speed = 509m/s
Frequency = 491Hz
To find the wavelength;
Wavelength = speed/frequency
Wavelength = 509/491
Wavelength = 1.04 meters
Therefore, the guitar player should shorten the length of the string to 1.04 meters.
Answer: 0.52
Explanation:
What is the unique geological feature found on Mercury surface?
Answer:
The surface of Mercury has landforms that indicate its crust may have contracted. They are long, sinuous cliffs called lobate scarps. These scarps appear to be the surface expression of thrust faults, where the crust is broken along an inclined plane and pushed upward.
Explanation:
I hope this helps a little bit.
Yanni just turned one. He loves to play with his cars and trucks. He can also name the animals he sees in books.
In which stage of development is Yanni?
childhood
infancy
adolescence
adulthood
How much power does motor provides an elevator in a building when the total mass when loaded is 500 kg to a height of 3m in 25 seconds?