state the law of nature​

Answer:

I think its the electromagnetic spectrum

Answer:

1. This is a speed graph.

2. The slope represents how much the item/ thing is moving at how much distance it moved and the minutes it takes it too move how much distance, but the slope is representing the decrease and increase of it.

3. Increasing, kind of rapidly going up since the slope is rising not falling.

Answer:

  [tex]E_{y} (x,t)[/tex]= 10 cos (1.15 10⁻¹¹ x - 3.427 10¹⁵ t)

Explanation:

The general equation of a traveling wave on the x-axis is

        [tex]E_{y}(x,t)[/tex] = E₀ cos (kx -wt)

the amplitude of the wave is E₀ = 10 V / m

the wave number is

         k = 2π /λ

indicate the value of   λ = 550 nm = 550 10⁻⁹ m

we substitute

         k = 2π / 550 10⁻⁹

         k = 1.15 10⁻¹¹ m⁻¹

angular velocity is related to frequency

          w = 2πf

the speed of light is related to the wavelength and frequency

           c = λ f

           f = c /λ

we substitute

           w = [tex]2\pi \frac{c}\lambda }[/tex]

           w = 2π  3 10⁸/550 10⁻⁹

           w = 3.427 10¹⁵ rad / s

we substitute in the electric field equation

           [tex]E_{y} (x,t)[/tex]= 10 cos (1.15 10⁻¹¹ x - 3.427 10¹⁵ t)

Let's test the value of this wave for t = 0 at the point x = 0, the wave is worth

           Ey (0,0) = 10

which corresponds to its maximum positive value, therefore this is the expression of the traveling wave

Answer:

mucilage can detect objects the size of millimeters, whereas humans can only detect objects larger than centimeters

Explanation:

The human ear can detect sound in the range of 20 to 20000hz, we are asked to find the mid-range wavelength of the ear at f = 10000 Hz

let's use the relationship between wave speed, wavelength and frequency

           v = λ f

           λ= v / f

           λ = 343/10000

           λ = 3.43 10⁻² m

the sound range of a bat is between 25 10³ Hz and 100 10³ Hz, they also ask for the wavelength in the middle range

          f = (100 10³ + 25 10³) / 2

          f = 62.5 10³ Hz

          λ = 343 / 62.5 10³

          λ = 5.5 10⁻³ m

Therefore the size of the object that a bat can detect is much smaller than the size that a human can detect, therefore the bat is capable of detecting insects, but humans.

The mucilage can detect objects the size of millimeters, whereas humans can only detect objects larger than centimeters

Answer:

Another term used to describe a wave is frequency. Since waves are moving, we define frequency as the number of waves that pass a given point in a specified unit of time. The unit commonly used is Hertz which is the number of wave cycles pass a point in one second. So one cycle per second equals one Hertz

Answer:

Explanation:

Force between charge is given by the following expression

F = k Q₁ Q₂ / R² , k = 9 x 10⁹ , Q₁ and Q₂ are charges , R is distance between charges .

Putting the given values ,

.85  = 9 x 10⁹ x 7.1 x 10⁻⁶ x Q₂ / 5.4²

Q₂ = .85 x  5.4² / (9 x 10⁹ x 7.1 x 10⁻⁶ )

= .38788  x 10⁻³ C .

= 387.88 x 10⁻⁶ C .

Answer: 1.5 N/C

Explanation:

The equation is derived from Coulomb's Law, but is not exactly Coulomb's Law:

F = qE

q is the test charge

E is the electrical field produced by the source charge

F is the force in Newtons

In this problem, we were given the value of the test charge q, and the force acting on it due to the electric field from the source charge.

E = F/q

E = 6.5N/4.3C

E = 1.5 N/C

Answer:

Explanation:

Given parameters:

Voltage  = 12V

Quantity of charge  = 4C

Unknown:

Potential energy  = ?

Solution:

Within this circuit, the value of the potential energy can be found using the expression below:

   Potential energy  = [tex]\frac{1}{2}[/tex] c v²  

c is the quantity of charge

v is the voltage

 Potential energy   =  [tex]\frac{1}{2}[/tex] x 4 x 12²  = 288J

Answer:

B. 2.5

not 2.5m because IMA is unitless.

The identical mechanical advantage of the inclined plane is 2.5.

The concept of work, which asserts that work produced through a basic machine (the lever) is equal to the work input, forms the basis for the mechanical advantage of the inclined plane. The length of the slope divided by the height of the inclined plane represents the inclined plane's mechanical advantage.

Given parameters:

Length of the inclined plane; d = 5 m.

Height of the inclined plane; h = 2 m.

So, identical mechanical advantage (IMA) of the inclined plane is = Length of the inclined plane ÷ Height of the inclined plane

= 5 m/2 m

= 2.5.

Hence, the  identical mechanical advantage (IMA) of an inclined plane that is 5m long and 2m high is 2.5.

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Answer:

Explanation:

We shall express each displacement vectorially , i for each unit displacement towards east , j for northward displacement and k for vertical displacement .

14 m due west = - 14 i

22.0 m upward in the elevator = 22 k

12 m north = 12 j

6.00 m east = 6 i

Total displacement = - 14 i + 22 k + 12 j + 6 i

D = - 8 i + 12 j + 22 k

magnitude = √ ( 8² + 12² + 22² )

= √ ( 64 + 144 + 484 )

= √ 692

= 26.3 m

Net displacement from starting point = 26.3 m .

Answer:

a)  v = 7.69 10³ m / s,  b)    T = 92.6 min

Explanation:

a) For this exercise we use the centripetal acceleration ratio, which in itself assumes a circular orbit, is equal to the acceleration of gravity

          a = v² / r

          v = [tex]\sqrt{a r}[/tex]

the distance to the ISS is

           r = R_earth + d

           r = 6400 10³ + 400 10³

           r = 6800 10³ m

we calculate

           v = [tex]\sqrt{8.69 \ 6800 \ 10^3}[/tex]Ra (8.69 6800 103)

           v = [tex]\sqrt{59.09 \ 10^6}[/tex]

           v = 7.687 10³ m / s

the result with the correct significant figures

            v = 7.69 10³ m / s

b) The speed of the ISS is constant, so we can use the uniform motion relationships

            v = d / t

if distance is the orbit distance

            d = 2π r

time is called period

            v = 2π r / T

            T = 2π r / v

let's calculate

            T = 2π 6800 10³ /7,687 10³

            T = 5.558 10³ s

let's reduce the period to minutes

            T = 5.558 10³ s (1 min / 60s)

            T = 9.26 10¹ min

            T = 92.6 min

Answer:

Coulomb's law of Electrostatic Force states that a charged particle attracts or repels other charged particles with a force which is directly proportional to the product of their charges and inversely proportional to the square of the distance between their centers.

Explanation:

Answer:

The mass of the feather would be 0.0075 kg.

Explanation:

If the feather were to be on earth, it would have experienced the gravitational pull of the earth downwards. So that from Newton's second law of motion,

F = mg

where f is the force on the object, m is the mass of the object and g is the acceleration due to gravity of the earth.

But, F = 0.075 N, g = 10 m/[tex]s^{2}[/tex].

So that,

0.075 = m x 10

m = [tex]\frac{0.075}{10}[/tex]

   = 0.0075 kg

The mass of the feather would be 0.0075 kg.

Answer:

I think the answer is c electrical, and light , sound hewt

Answer:

Explanation:

From the given information.

The charge density of the cylinder can be computed as:

[tex]\rho = \dfrac{Q_t}{V_t}[/tex]

where:

[tex]Q_t[/tex] = total charge on cylinder

[tex]\rho[/tex] = density of the cylinder

[tex]V_t =[/tex] net volume on cylinder

Considering the charge enclosed by the Gaussian surface; we have:

Q = ρV

Now, determining the volume of the cylinder at a distance r from the axis of the cylinder as follows:

[tex]\int Edsn = \dfrac{q}{\varepsilon_o}[/tex]

Here;

[tex]\hat E \ \ and \ \ \hat n[/tex] are in the same direction;

If we replace [tex]\int Edsn[/tex] with [tex]E ( 2 \pi rl)[/tex] and q with [tex]\rho \pi r^2 l[/tex]; Then:

[tex]E ( 2 \pi rl ) = \dfrac{\rho \pi r^2 l}{\varepsilon _o}[/tex]

By rearrangement;

[tex]E = \dfrac{\rho \pi r^2 l}{ ( 2 \pi rl ) \varepsilon _o}[/tex]

[tex]\mathbf{E = \dfrac{\rho r}{ 2 \varepsilon _o}}[/tex]

(b)

Using the same formula:

[tex]\int Edsn = \dfrac{q}{\varepsilon_o}[/tex]

where;

[tex]\hat E \ \ and \ \ \hat n[/tex] are in the same direction;

If we replace [tex]\int Edsn[/tex] with [tex]E ( 2 \pi rl)[/tex] and [tex]Q_t[/tex] with q;

Then:

[tex]E ( 2 \pi rl ) = \dfrac{Q_t}{\varepsilon _o}[/tex]

[tex]E = \dfrac{Q_t}{( 2 \pi R l ) \varepsilon _o}[/tex]

Replacing [tex]\lambda[/tex] for [tex]\dfrac{Q_t}{l}[/tex].

From above [tex]\lambda[/tex] = the charge per unit length

∴

[tex]\mathbf{E = \dfrac{\lambda}{ 2 \pi R \varepsilon _o}}[/tex]

Answer:

266 m

Explanation:

Answer:

go to settings and find what your looking for

Explanation:

Answer:

[tex] \frac{{v}^{2} g}{2 } [/tex]

Answer:

94,5 x 3,17 = 299,565 m/s

Explanation:

To find the speed of waves (V), you just need to multiply wavelength with frequency. That's all.

The speed of the given electromagnetic waves is equal to 3 × 10⁸ m/s.

The frequency can be described as the number of oscillations of a wave in 1 second. The S.I. units of the frequency can be represented as per second or hertz.

The wavelength can be described as the distance between the two points in phase on the wave w.r.t. each other. The separation between two crests or two troughs on a wave is known as wavelength.

The relation between the wavelength (λ) of the wave, frequency (ν), and speed of the wave (V) can be written as:

V = νλ

Given, the frequency of the wave, ν = 94.5 MHz = 94.5 ×10⁶ s⁻¹

The wavelength of the waves, λ  = 3.17 m

The speed of the waves can determine from the above-mentioned relationship:

V = λν = 3.17 × 94.5 ×10⁶ =  3 × 10⁸ m/s

Therefore, the speed of the wave is equal to 3 × 10⁸ m.

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Answer:

180 turns

Explanation:

Given data

Vi= 240 volts

Vo= 960volts

Ns= 720 turns

Required

The amount of Primary turns Np

The expression relating voltage and turns in a transformer is given as

Np/Ns= Vi/Vo

substitute

Np/720= 240/960

cross multiply

720*240= Np*960

172800= Np*960

Np= 172800/960

Np= 180

Hence the primary turns is 180 turns

Answer:

P = √1.66 * 10^-19 days^2miles^-3d^3

Explanation:

The mathematical statement of Kepler's third law is;

P^2 α d^3

Where;

P = Period of the body orbiting the sun

d = its average distance from the sun

Introducing a constant of proportionality K, known as Kepler's constant then;

P^2 = Kd^3

K = P^2/d^3

P=365 days

d = 93,000,000 miles

K = (365)^2/(93,000,000)^3

K=1.66 * 10^-19 days^2miles^-3

P = √1.66 * 10^-19 days^2miles^-3d^3

Option 3) a Soccer Ball

will travel the farthest distance.

Answer:

a bowling ball

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Answer:

The entire conductor is at the same potential.

The electric field inside is zero.

Explanation:

For a conductor in electrostatic equilibrium, the properties are:

A conductor is an object or kind of material that permits the movement of charge (electric current) in one or more directions. This term is used in both physics and electrical engineering. Metal-based materials are frequently used as electrical conductors.

It is not essential for one charged particle to move from the component creating the current (the current source) to those consuming it for current to flow within a closed electrical circuit (the loads).

Instead, all that is required of the charged particle is a small amount of nudging from its neighbor, who in turn will nudging its neighbor, and so on, until a particle gets nudged into the consumer, so supplying it with power.

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Answer:

6.00 x 10⁻⁸N

Explanation:

Given parameters:

Mass of each dump trucks  = 1500kg

Distance between them  = 50m

Unknown:

New gravitational force between them = ?

Solution:

From Newton's law of universal gravitation,

        F = [tex]\frac{G m1 m2}{r^{2} }[/tex]  

F is the gravitational force

G is the universal gravitation constant

m is the mass

r is the distance

           F  = [tex]\frac{6.67 x 10^{-11} x 1500 x 1500}{50^{2} }[/tex]    = 6.00 x 10⁻⁸N

Answer:

Δx = 23.0 m

Explanation:

       [tex]x_{2} = v_{2} * t = 1.17m/s * 14.5 s = 17.0 m (1)[/tex]

       [tex]x_{1} = v_{1} * t = 2.75 m/s * 14.5 s = 40.0 m (2)[/tex]

Option B

kskmsnsnsmjsjsn

Answer:

C. The potential energy of the particles increases as the intermolecular forces are overcome

Explanation:

Answer:

We can easily find out the beginning point of the line by using dot representation. When it comes to position vector, it expresses the exact position of certain object from the starting point of the coordinate system. The vector is a straight line that has a certain end which is fixed to its body.

Position vectors are used to determine the starting position of a line with reference to the origin or starting point of  the coordinate system

Position vectors start at the origin and terminate at any arbitrary point.

In terms of position of a line, position vectors depict the exact position of a line from the starting point of the coordinate system.

In terms of direction of the line, the direction of the position vector points from the starting point of  the coordinate system towards the given point.

Thus, we can conclude that position vectors are used to determine the starting position of a line with reference to the origin or starting point of  the coordinate system.

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Answer:

Workdone = 0.67 Joules

Explanation:

Given the following data;

Workdone = 6J

Extension = 43 - 28 = 15cm to meters = 15/100 = 0.15m

The workdone to stretch a string is given by the formula;

Workdone = ½ke²

Where;

k is the constant of elasticity.

e is the extension of the string.

We would solve for string constant, k;

6 = ½*k*0.15²

6 = ½*k*0.0225

Cross-multiplying, we have;

12 = 0.0225k

k = 12/0.0225

k = 533.33N/m

a. To find the workdone when e = 33, 38.

Extension = 38 - 33 = 5 to meters = 5/100 = 0.05m

Workdone = ½*533.33*0.05²

Workdone = 266.67 * 0.0025

Workdone = 0.67 Joules

Therefore, the amount of work (in J) needed to stretch the spring from 33 cm to 38 cm is 0.67.

Answer:

F_total = -65.5 N

Explanation:

Coulomb's law is

           F = [tex]k \frac{q_1 q_2}{r^2}[/tex]k q1q2 / r2

In this exercise the force on the charge q3 is asked, for this we use that the force is a vector

          F_total = F₁₃ + F₂₃

let's look for every force

          F₁₃ = [tex]k \frac{q_1 q_3}{r_{13}^2}[/tex]

it is indicated that charge 1 is equal to q₁ = -11.5 nC = -11.5 10⁻⁹ C, located at x₁ = -1.675 mm = -1.675 10⁻³ m and charge q₃ = 48.0 nC = 48.0 10⁻⁹ C located at x₃ this position is not written in the exercise, suppose the position x₃ = -0.5 mm = 0.5 10⁻³ m

the distance is

          r₁₃ = [tex]\sqrt{(x_3 - x_1 )^2}[/tex]

          r₁₃ = [tex]\sqrt{(0.5-1.675)^2} \ 10^{-3}[/tex]

          r₁₃ = 1.175 10⁻³ m

we calculate

          F₁₃ = [tex]\frac{9 \ 10^{9} 11.5\ 10^{-9} 48.0\ 10^{-9} }{(1.175 10^{-3})^2 }[/tex]

          F₁₃ = 3.598 N

as the charge q₁ is negative and the charge q₃ is positive the force is attractive directed to the right

we look for F₂₃, where q₂ = 40 nC = 40.0 10⁻⁹ C located at x₂ = 0

             F₂₃ = [tex]k \frac{q_2q_3}{r_{23}^2}[/tex]

            r₂₃ = [tex]\sqrt{(x_3-x_2)^2}[/tex]

            r₂₃ = [tex]\sqrt{(0.5 -0)} \ 10^{-3}[/tex]RA (-0.5 0) 2 103

            r₂₃ = 0.5 10⁻³ m

             F₂₃ = [tex]\frac{9 \ 10^{9}\ 40\ 10^{-9} \ 48.0\ 10^{-9} x}{(0.5 \ 10^{-3})^2 }[/tex]

             F₂₃ = 6.912 10¹ N

             F₂₃ = 69.12 N

as the two charges are of the same sign, the force is repulsive, therefore it is directed to the left

the total force is

            F = total = 3.598 - 69.12

            F_total = -65.5 N

the negative sign indicates that the force is to the left