Square OABC is drawn on a centimetre grid. O is (0,0) A is (3,0) B is (3,3) C is (0,3) Write down how many invariant points there are on the perimeter of the square when OABC is translated by the vector [1 3]

Square OABC Is Drawn On A Centimetre Grid. O Is (0,0) A Is (3,0) B Is (3,3) C Is (0,3) Write Down How

Answers

Answer 1

Answer:

No invariant point

Step-by-step explanation:

Hello!

When we translate a form, in this case a polygon We must observe the direction of the vector. Since our vector is:

[tex]\vec{v}=\left ( \begin{matrix}1\\ 3\end{matrix} \right )[/tex]

1) Let's apply  that translation to this polygon, a square. Check it below:

2) The invariant points are the points that didn't change after the transformation, simply put the points that haven't changed.

Examining the graph, we can see that no, there is not an  invariant point, after the translation. There is no common point that belongs to OABC and O'A'B'C' simultaneously. All points moved.

Square OABC Is Drawn On A Centimetre Grid. O Is (0,0) A Is (3,0) B Is (3,3) C Is (0,3) Write Down How

Related Questions

What is jc ? (Picture included)

Answers

Answer:

jc is 40 i think

Step-by-step explanation:

Answer:

40(Maybe)

Step-by-step explanation:

I'm not 100% sure that 40 is correct but I'm pretty sure it is.

Please Help. Which system of linear equations is represented in the graph?

Answers

Answer:  

y = x - 3

y = -5x +2

Step-by-step explanation:  for The "missing" coefficient of x (m in the y=mx+b format) is an implied +1. So the slope is "up-one & over one." y-intercept is -3

y = -5x +2   The slope is -5 so "down 5 & over 1" on the graph, The y-intercept is +2

simply expression 1+5v+v​

Answers

Answer:

1 + 6v

Step-by-step explanation:

1+5v+v​

Combine like terms

1 + 6v

Answer:

6v + 1

Step-by-step explanation:

1 + 5v + v

Apply rule : a = 1a

1 + 5v + 1v

Combine like terms.

5v + 1v + 1

(5 + 1)v + 1

(6)v + 1

6v + 1

Calculate
(14x5x4) / (28 x 2)

Answers

Answer:

5

Step-by-step explanation:

(14 × 5 × 4) ÷ (28 × 2)

Solve brackets.

280 ÷ 56

Divide.

= 5

I need help urgent plz someone help me solved this problem! Can someone plz help I’m giving you 10 points! I need help plz help me! Will mark you as brainiest!

Answers

Answer: a) 8.779 years

               b) 8.664 years

Step-by-step explanation:

a)

[tex]A=P\bigg(1+\dfrac{r}{n}\bigg)^{nt}[/tex]

A: accumulated amount (balance)P: principal amount (original/initial investment)r: interest rate (convert to a decimal)n: number of times compounded per yeart: number of years

Given: A = 1800, P = 900, r = 8% = 0.08, n = 3, t = unknown

[tex]1800=900\bigg(1+\dfrac{0.08}{3}\bigg)^{3t}\\\\\\2=\bigg(1+\dfrac{0.08}{3}\bigg)^{3t}\\\\\\ln\ 2=ln \bigg(1+\dfrac{0.08}{3}\bigg)^{3t}\\\\\\ln\ 2=3t\ ln\bigg(1+\dfrac{0.08}{3}\bigg)\\\\\\\dfrac{ln\ 2}{3\ ln\bigg(1+\dfrac{0.08}{3}\bigg)}=t\\\\\\\large\boxed{8.779=t}[/tex]

b)  

[tex]A=Pe^{rt}[/tex]

[tex]1800=900e^{0.08t}\\\\\\2=e^{0.08t}\\\\\\ln\ 2=0.08t\\\\\\\dfrac{ln\ 2}{0.08}=t\\\\\\\large\boxed{8.664=t}[/tex]

Julie has three boxes of pens. The diagram shows expressions for the number of pens in each box. Look at these equations.
Equals B +12
B equals C +4
Write an equation to show the relationship between a + c

Answers

Answer:

a=c+16

here,

a=b+12

b=a-12----> equation (i)

b= c+4

putting the value of b from the equation (I)

a-12=c+4

a=c+4+12

a=c+16

hope this helps...

Good luck on your assignment...

The value of a + c is 16.

What is Algebra?

A branch of mathematics known as algebra deals with symbols and the mathematical operations performed on them.

Variables are the name given to these symbols because they lack set values.

In order to determine the values, these symbols are also subjected to various addition, subtraction, multiplication, and division arithmetic operations.

Given:

a=b+12

So, b=a-12 ---- equation (i)

and, b= c+4

Substitute the value of b from the equation (I)

a-12=c+4

a=c+4+12

a=c+16

Hence, the value of a+ c is 16.

Learn more about Algebra here:

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What are the vertex and X intercepts of the graph of the function below Y =(x+4)(x-2)

Answers

Answer:

Vertex:  ( -1 , − 9 )

X intercepts (0,-4)(0,2)

Step-by-step explanation:

Answer:

( -1, -9)

And

x-intercepts: (-4, 0), (2,0)

Step-by-step explanation:

Sacrificed my grade

PLEASE HELP!!! You want to distribute 7 candies to 4 kids. If every kid must receive at least one candy, in how many ways can you do this?

Answers

Answer:

1140 ways.

Step-by-step explanation:

The applicable formula is: (n +r - 1)C(r-1), where n is the number of identical items (the candies), and r is the possible number of recipients (the kids).

The 17 identical candies, can be distributed among the 4 children in :  

=(17 + 4 - 1)C(4–1) = 20C3 ways.

= 20!/((20–3)!*3!) ways.

= 20*19*18*17!/(17!*(3*2*1)) = 20*19*18/6 ways

= 20*19*3 ways.  

=1140 ways.

Joan is selling handmade bead necklaces
at a local art fair. She paid $180 to
reserve her booth. The cost of supplies
for each necklace averages $2. So, her
cost, y, for x necklaces is represented by
y = $180 + 2x. If she sells her necklaces
for $12, her revenue, y, is represented
by y = 12x.
The solution of this system is the break-
even point, the point beyond which she
starts making a profit.
HELP PLS QUICK

Answers

Answer:. x = 18

Step-by-step explanation:

Solve by substitution. Given: y= 12x. Rewrite the original equation y= 180 + 2x to 12x = 180 +2x. Subtract 2x from both sides. 10x = 180. Then divide both sides by 10.

x=18

So once she has sold 18 necklaces, she has covered her costs (180 + 36) and she begins to make a profit.

Find the rate of change of the height from age 8 to 16 and from age 60 to 80. Express both answers in units of cm per year, to two significant figures. Separate your answers with a comma.

Answers

Complete Question

The complete question is shown on the first and second uploaded image

Answer:

a

 [tex]z = 6.25 \ cm/yr[/tex]

b

   [tex]k = -0.25 \ cm /yr[/tex]

Step-by-step explanation:

From the first image  the rate of  rate of change of the height from age 8 to 16  

  is  mathematically evaluated from the graph as  

             [tex]z = \frac{175 - 125}{16-8}[/tex]

            [tex]z = 6.25 \ cm/yr[/tex]

From the first image  the rate of  rate of change of the height from age 60 to 80.

  is  mathematically evaluated from the graph as

             [tex]k = \frac{175 - 170}{60-80}[/tex]

            [tex]k = -0.25 \ cm /yr[/tex]

Diane's bank is offering 5% interest, compounded monthly. If Diane invests $10,500 and wants $20,000 when she withdrawals, how long should she keep her money in for? Round to the nearest tenth of a year.

Answers

Answer:

The time period is 13 years.

Step-by-step explanation:

Interest rate (r )= 5% or 5%/12 = 0.42% per months

The investment amount (Present value) = $10500

Final expected amount (future value) = $20000

Since we have given the initial amount and final amount. Therefore we have to calculate the time period for which the initial amount is kept in the bank.

Use the below formula to find the time period.

Future value = present value (1 + r )^n

20000 = 10500(1+0.0042)^n

1.9047619 = (1+0.0042)^n

1.9047619 = 1.0042^n

n = 153.74 months.

Time in years = 153.74 / 12 = 12.8 years or 13 years (round off)

Which of the following systems of inequalities would produce the region indicated on the graph below?

Answers

Answer:

  A.  y > x+1; y≤10; x≥0

Step-by-step explanation:

Other things being equal, which they are, you're looking for an inequality that has "y >". You know this because shading is above (>) the dashed line (not ≥). Only choice A matches.

__

If the boundary line were solid, you would be looking for "y ≥", since y=(boundary line) is included in the solution set in that case.

A random sample of n = 8 E-glass fiber test specimens of a certain type yielded a sample mean interfacial shear yield stress of 32.9 and a sample standard deviation of 4.9. Assuming that interfacial shear yield stress is normally distributed, compute a 95% CI for true average stress. (Give answer accurate to 2 decimal places.)

Answers

Answer:

[tex]32.9-2.365\frac{4.9}{\sqrt{8}}=28.80[/tex]    

[tex]32.9+2.365\frac{4.9}{\sqrt{8}}=37.00[/tex]    

Step-by-step explanation:

Information given

[tex]\bar X=32.9[/tex] represent the sample mean for the sample  

[tex]\mu[/tex] population mean (variable of interest)

s=4.9 represent the sample standard deviation

n=8 represent the sample size  

Confidence interval

The confidence interval for the mean is given by the following formula:

[tex]\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}[/tex]   (1)

the degrees of freedom are given by:

[tex]df=n-1=8-1=7[/tex]

Since the Confidence is 0.95 or 95%, the value of [tex]\alpha=0.05[/tex] and [tex]\alpha/2 =0.025[/tex], and the critical value for this cae would be [tex]t_{\alpha/2}=2.365[/tex]

Now we have everything in order to replace into formula (1):

[tex]32.9-2.365\frac{4.9}{\sqrt{8}}=28.80[/tex]    

[tex]32.9+2.365\frac{4.9}{\sqrt{8}}=37.00[/tex]    

Please help I don’t understand And I need an explanation

Answers

Hey there! :)

Answer:

56 m².

Step-by-step explanation:

To find the area, simply split the figure into a triangle and rectangle. Solve for the areas separately:

Solve for the rectangle: (A = l × w)

A = 8 × 5

A = 40 m²

Solve for the triangle: (A = 1/2 (bh))

A = 1/2(4 · 8)

A = 1/2(32)

A = 16 m².

Add up the two areas:

40 + 16 = 56 m².

Answer:

Area of triangle+ the area of rectangle

Step-by-step explanation:

Since, area of triangle is 1/2×base×height in right angled triangle, 1/2×4×8: 1/2×32= 16m²

Area of rectangle is length × breadth= 5×8: 40 m²

Area of the shape is 40m²+16m²= 56m²

Tammy and Lawrence like to bike competitively. Tammy biked seven less than three times the number of miles that Lawrence biked. If c represents the number of miles Lawrence biked, write an expression for the number of miles Tammy biked.

Answers

Answer:

3c - 7

Step-by-step explanation:

c - the number of miles Lawrence biked

Tammy biked seven less than three times the number of miles that Lawrence biked.

So, 3 x c (the # of miles Lawrence biked) - 7 (she biked seven less)

The answer is 3c - 7.

A student is given that point P(a, b) lies on the terminal ray of angle Theta, which is between StartFraction 3 pi Over 2 EndFraction radians and 2Pi radians. The student uses the steps below to find cos Theta. Which of the following explains whether the student is correct? The student made an error in step 3 because a is positive in Quadrant IV; therefore, cosine theta = StartFraction a Over StartRoot a squared + b squared EndRoot EndFraction = StartFraction a StartRoot a squared + b squared EndRoot Over a squared + b squared EndFraction. The student made an error in step 3 because cosine theta = StartFraction negative b Over StartRoot a squared + b squared EndRoot EndFraction = Negative StartFraction b StartRoot a squared + b squared EndRoot Over a squared + b squared EndFraction. The student made an error in step 2 because r is negative in Quadrant IV; therefore, r = Negative StartRoot a squared + b squared EndRoot. The student made an error in step 2 because using the Pythagorean theorem gives r = plus-or-minus StartRoot (a squared) minus (b squared) EndRoot = StartRoot a squared minus b squared EndRoot.

Answers

Answer:

A.

The student made an error in step 3 because a is positive in Quadrant IV; therefore,

[tex]cos\theta = \frac{a\sqrt{a^2 + b^2}}{a^2 + b^2}[/tex]

Step-by-step explanation:

Given

[tex]P\ (a,b)[/tex]

[tex]r = \± \sqrt{(a)^2 + (b)^2}[/tex]

[tex]cos\theta = \frac{-a}{\sqrt{a^2 + b^2}} = -\frac{\sqrt{a^2 + b^2}}{a^2 + b^2}[/tex]

Required

Where and which error did the student make

Given that the angle is in the 4th quadrant;

The value of r is positive, a is positive but b is negative;

Hence;

[tex]r = \sqrt{(a)^2 + (b)^2}[/tex]

Since a belongs to the x axis and b belongs to the y axis;

[tex]cos\theta[/tex] is calculated as thus

[tex]cos\theta = \frac{a}{r}[/tex]

Substitute [tex]r = \sqrt{(a)^2 + (b)^2}[/tex]

[tex]cos\theta = \frac{a}{\sqrt{(a)^2 + (b)^2}}[/tex]

[tex]cos\theta = \frac{a}{\sqrt{a^2 + b^2}}[/tex]

Rationalize the denominator

[tex]cos\theta = \frac{a}{\sqrt{a^2 + b^2}} * \frac{\sqrt{a^2 + b^2}}{\sqrt{a^2 + b^2}}[/tex]

[tex]cos\theta = \frac{a\sqrt{a^2 + b^2}}{a^2 + b^2}[/tex]

So, from the list of given options;

The student's mistake is that a is positive in quadrant iv and his error is in step 3

Answer:

a on e2020 :)

Step-by-step explanation:

I NEED HELP PLEASE, THANKS! :)

Answers

Answer:

Option B

Step-by-step explanation:

Again, another great question! Here we are given the following system of equations, bound by quadrant 1 -

[tex]\begin{bmatrix}2x+7y\le \:70\\ 8x+4y\le \:136\end{bmatrix}[/tex]

Convert this to slope - intercept form -

[tex]\begin{bmatrix}y\le \frac{70-2x}{7}\\ y\le \:2\left(-x+17\right)\end{bmatrix}[/tex]

Now the graphed solution of this intersects at a shaded region with which there are 3 important point that lie on the border. They are the following -

( 0, 10 ),

( 15, 9 ),

( 17, 0 )

When these point are plugged into the main function f ( x, y ) = 2x + 6y, the point ( 15, 9 ) results in the greatest solution of 84. Thus, it is our maximum point -

Option B

Which statements about the dilation are true? Check all that apply. Triangle X prime Y prime Z prime. Point X prime is 2 units from the center of dilation C and point Z prime is 3 units from the center of dilation. Triangle X Y Z. Point X is 5 units from point C and point Z is 7.5 units from point C.

Answers

Answer:

A,B,E

Step-by-step explanation:

Just took the quiz

Answer:

A,B,E

Step-by-step explanation:

Give me brainliest.

Solve the system of linear equations.

Answers

Answer:

dependent systemx = 2 -ay = 1 +az = a

Step-by-step explanation:

Let's solve this by eliminating z, then we'll go from there.

Add 6 times the second equation to the first.

  (3x -3y +6z) +6(x +2y -z) = (3) +6(4)

  9x +9y = 27 . . . simplify

  x + y = 3 . . . . . . divide by 9 [eq4]

Add 13 times the second equation to the third.

  (5x -8y +13z) +13(x +2y -z) = (2) +13(4)

  18x +18y = 54

  x + y = 3 . . . . . . divide by 18 [eq5]

Equations [eq4] and [eq5] are identical. This tells us the system is dependent, and has an infinite number of solutions. We can find them in terms of z:

  y = 3 -x . . . . solve eq5 for y

  x +2(3 -x) -z = 4 . . . . substitute into the second equation

  -x +6 -z = 4

  x = 2 - z . . . . . . add x-4

  y = 3 -(2 -z)

  y = z +1

So far, we have written the solutions in terms of z. If we use the parameter "a", we can write the solutions as ...

  x = 2 -a

  y = 1 +a

  z = a

_____

Check

First equation:

  3(2-a) -3(a+1) +6a = 3

  6 -3a -3a -3 +6a = 3 . . . true

Second equation:

  (2-a) +2(a+1) -a = 4

  2 -a +2a +2 -a = 4 . . . true

Third equation:

  5(2-a) -8(a+1) +13a = 2

  10 -5a -8a -8 +13a = 2 . . . true

Our solution checks algebraically.

Choose the correct number to finish the sentence. For the function f(x)=√x+4, the average rate of change to the nearest hundredth over the interval 2 ≤ x ≤ 6 is? A. 0.2 B. 0.17 C. 0.16 D. 0.18

Answers

Answer:

See below under "explanation".

General Formulas and Concepts:

Algebra I

Functions

Function Notation

Average Rate of Change Formula:
[tex]\displaystyle \text{Average Rate of Change} = \frac{f(b) - f(a)}{b - a}[/tex]

b is upper interval bounda is lower interval bound

Step-by-step explanation:

*Note:

The function is unclear, so I will provide 2 possible answers.

Step 1: Define

Identify given.

[tex]\displaystyle \begin{aligned}1. \ f(x) & = \sqrt{x} + 4 \\2. \ f(x) & = \sqrt{x + 4} \\\end{aligned}[/tex]

[tex]\displaystyle \text{Interval: } 2 \leq x \leq 6[/tex]

Step 2: Find Average Rate of Change

For the 1st function:

[tex]\displaystyle\begin{aligned}\text{Average Rate of Change} & = \frac{\big( \sqrt{b} + 4 \big) - \big( \sqrt{a} + 4 \big)}{b - a} \\& = \frac{\big( \sqrt{6} + 4 \big) - \big( \sqrt{2} + 4 \big)}{6 - 2} \\& = \frac{\sqrt{6} - \sqrt{2}}{4} \\& = 0.258819 \\& \approx \boxed{0.26} \\\end{aligned}[/tex]

∴ the average rate of change, if using the 1st defined function, will be approximately 0.26.

For the 2nd function:

[tex]\displaystyle\begin{aligned}\text{Average Rate of Change} & = \frac{\sqrt{b + 4} - \sqrt{a + 4} }{b - a} \\& = \frac{\sqrt{6 + 4} - \sqrt{2 + 4}}{6 - 2} \\& = \frac{\sqrt{10} - \sqrt{6}}{4} \\& = 0.178197 \\& \approx \boxed{0.18} \\\end{aligned}[/tex]

∴ the average rate of change, if using the 2nd defined function, will be approximately 0.18.

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Topic: Algebra I

A random sample of 13 items is drawn from a population whose standard deviation is unknown. The sample mean is x¯ = 950 and the sample standard deviation is s = 10. Use Appendix D to find the values of Student’s t.
1. Construct an interval estimate of mu with 99% confidence. (Round your answers to 3 decimal places.)
The 99% confidence interval is from_____ to ______ .
2. Construct an interval estimate of mu with 99% confidence, assuming that s = 20. (Round your answers to 3 decimal places.)
The 99% confidence interval is from_____ to ______ .
3. Construct an interval estimate of mu with 99% confidence, assuming that s = 40. (Round your answers to 3 decimal places.)
The 99% confidence interval is from_____ to ______ .

Answers

Answer:

1. The 99% confidence interval is from 941.527 to 958.473

2. The 99% confidence interval is from 933.054 to 966.946

3. The 99% confidence interval is from 916.108 to 983.892

Step-by-step explanation:

The confidence interval is given by

[tex]\text {confidence interval} = \bar{x} \pm MoE\\\\[/tex]

Where [tex]\bar{x}[/tex] is the sample mean and Margin of error is given by

[tex]$ MoE = t_{\alpha/2}(\frac{s}{\sqrt{n} } ) $ \\\\[/tex]

Where n is the sample size,

s is the sample standard deviation,

[tex]t_{\alpha/2[/tex] is the t-score corresponding to some confidence level

The t-score corresponding to 99% confidence level is

Significance level = α = 1 - 0.99 = 0.01/2 = 0.005

Degree of freedom = n - 1 = 13 - 1 = 12

From the t-table at α = 0.005 and DoF = 12

t-score = 3.055

1. 99% Confidence Interval when s = 10

The margin of error is

[tex]MoE = t_{\alpha/2}(\frac{s}{\sqrt{n} } ) \\\\MoE = 3.055\cdot \frac{10}{\sqrt{13} } \\\\MoE = 3.055\cdot 2.7735\\\\MoE = 8.473\\\\[/tex]

So the required 99% confidence interval is

[tex]\text {confidence interval} = \bar{x} \pm MoE\\\\\text {confidence interval} = 950 \pm 8.473\\\\\text {confidence interval} = 950 - 8.473, \: 950 + 8.473\\\\\text {confidence interval} = (941.527, \: 958.473)\\\\[/tex]

The 99% confidence interval is from 941.527 to 958.473

2. 99% Confidence Interval when s = 20

The margin of error is

[tex]MoE = t_{\alpha/2}(\frac{s}{\sqrt{n} } ) \\\\MoE = 3.055\cdot \frac{20}{\sqrt{13} } \\\\MoE = 3.055\cdot 5.547\\\\MoE = 16.946\\\\[/tex]

So the required 99% confidence interval is

[tex]\text {confidence interval} = \bar{x} \pm MoE\\\\\text {confidence interval} = 950 \pm 16.946\\\\\text {confidence interval} = 950 - 16.946, \: 950 + 16.946\\\\\text {confidence interval} = (933.054, \: 966.946)\\\\[/tex]

The 99% confidence interval is from 933.054 to 966.946

3. 99% Confidence Interval when s = 40

The margin of error is

[tex]MoE = t_{\alpha/2}(\frac{s}{\sqrt{n} } ) \\\\MoE = 3.055\cdot \frac{40}{\sqrt{13} } \\\\MoE = 3.055\cdot 11.094\\\\MoE = 33.892\\\\[/tex]

So the required 99% confidence interval is

[tex]\text {confidence interval} = \bar{x} \pm MoE\\\\\text {confidence interval} = 950 \pm 33.892\\\\\text {confidence interval} = 950 - 33.892, \: 950 + 33.892\\\\\text {confidence interval} = (916.108, \: 983.892)\\\\[/tex]

The 99% confidence interval is from 916.108 to 983.892

As the sample standard deviation increases, the range of confidence interval also increases.

X = ??????geometryyyy

Answers

Answer:

3.75

Step-by-step explanation:

Using Secant-Secant theorem we can find the value of x.

The product of one segment and its external segment is equal to the product of the other segment and its external segment.

5 × 3 = x × 4

15 = 4x

15/4 = x

3.75 = x

Q‒1. [5×4 marks] a) How many three-digit numbers can be formed from the digits 0, 1, 2, 3, 4, 5, and 6? (150) b) How many three-digit numbers can be formed from the digits 0, 1, 2, 3, 4, 5, and 6 if each digit can be used only once? c) How many odd numbers can be formed from the digits 0, 1, 2, 3, 4, 5, and 6 if each digit can be used only once? d) How many three-digit numbers greater than 330 can be formed from the digits 0, 1, 2, 3, 4, 5, and 6? e) How many three-digit numbers greater than 330 can be formed from the digits 0, 1, 2, 3, 4, 5, and 6 if each digit can be used only once?

Answers

Answer:

a) 294

b) 180

c) 75

d) 174

e) 105

Step-by-step explanation:

I assume that for each problem, the first digit can't be 0.

a) There are 6 digits that can be first, 7 digits that can be second, and 7 digits that can be third.

6×7×7 = 294

b) This time, no digit can be used twice, so there are 6 digits that can be first, 6 digits that can be second, and 5 digits that can be third.

6×6×5 = 180

c) Again, each digit can only be used once, but this time, the last digit must be odd.

If only the last digit is odd, there are 3×3×3 = 27 possible numbers.

If the first and last digits are odd, there are 3×4×2 = 24 possible numbers.

If the second and last digits are odd, there are 3×3×2 = 18 possible numbers.

If all three digits are odd, there are 3×2×1 = 6 possible numbers.

The total is 27 + 24 + 18 + 6 = 75.

d) If the first digit is 3, and the second digit is 3, there are 1×1×6 = 6 possible numbers.

If the first digit is 3, and the second digit is greater than 3, there are 1×3×7 = 21 possible numbers.

If the first digit is greater than 3, there are 3×7×7 = 147 numbers.

The total is 6 + 21 + 147 = 174.

e) If the first digit is 3, and the second digit is greater than 3, then there are 1×3×5 = 15 possible numbers.

If the second digit is greater than 3, there are 3×6×5 = 90 possible numbers.

The total is 15 + 90 = 105.

In this activity, you will use equations to represent this proportional relationship: Olivia is making bead bracelets for her friends. She can make 3 bracelets in 15 minutes.

Part A
Find the constant of proportionality in terms of minutes per bracelet.

Part B
What does the proportionality constant represent in this situation?

Part C
Write an equation to represent the proportional relationship. Use the constant of proportionality you found in part A. Be sure to assign a variable for each quantity.

Part D
Now find the constant of proportionality in terms of number of bracelets per minute.

Part E
What does the proportionality constant represent in this situation?

Part F
Write an equation to represent the proportional relationship. Use the constant of proportionality you found in part D. Be sure to assign a variable for each quantity.

Part G
How are the constants of proportionality you found in parts A and D related?

Part H
Are the two equations you developed in parts C and F equivalent? Explain.
​​

Answers

Answer:

Step-by-step explanation:

A) The constant of proportionality in terms of minutes per bracelet is

15/3 = 5 minutes per bracelet

B) The constant of proportionality represents man hour rate

C) let k = constant of proportionality, t = time in minutes and b = number of bracelets produced. Therefore,

t = kb

D) the constant of proportionality in terms of number of bracelets per minute is

3/15 = 1/5

E) The constant of proportionality represents production rate

F) let k = constant of proportionality, t = time in minutes and b = number of bracelets produced. Therefore,

b = kt

G) The constants of proportionality are reciprocals

H) Two equations are equivalent if they have the same solution. They are not equivalent. By inputting the different values of k, the solutions will always be the same. Therefore, they are equivalent.

Answer:the sample answers, change them up so you dont get in trouble

A To find the constant of proportionality in minutes per bracelet, divide the total time by the number of bracelets:

constant of proportionality=15 MINUTES/3 BRACELETS=5  minutes per bracelet.

B The proportionality constant of 5 minutes per bracelet means it takes Olivia 5 minutes to make 1 bracelet.

C Here’s one way to set up the equation:

time = constant of proportionality × number of bracelets

Let m be time in minutes and let b be the number of bracelets. Substitute the variables (m and b) and the value of the proportionality constant (5 minutes per bracelet) into the equation: m = 5b.

thats all ik srry

Step-by-step explanation:

What is the volume of the cylinder below? A cylinder with a height of 12 millimeters and diameter of 18 millimeters. 108 pi mm3 216 pi mm3 648 pi mm3 972 pi mm3

Answers

Answer:

V =972 pi mm ^3

Step-by-step explanation:

The diameter is 18 so the radius is 1/2 of the diameter

18/2 = 9

r=9

The volume of a cylinder is

V = pi r^2 h

V = pi (9)^2 12

V =972 pi mm ^3

Answer:

972pi mm^3

Step-by-step explanation:

What is the volume of the cylinder below? A cylinder with a height of 12 millimeters and diameter of 18 millimeters. 108 pi mm3 216 pi mm3 648 pi mm3 972 pi mm3

V = (pi)r^2h

r = d/2 = 18 mm/2 = 9 mm

V = (pi)(9 mm)^2(12 mm)

V = 972pi mm^3

What is the equation of the line, in general form, that passes through the point (1, 1) and has a y-intercept of 2. A. x - y - 2 = 0 B. x - y + 2 = 0 C. x + y - 2 = 0

Answers

Answer:

The answer is option C

Step-by-step explanation:

Equation of a line is y = mx + c

where

m is the slope

c is the y intercept

To find the equation of the line first find the slope

The line has a y intercept of 2 which is

(0 , 2)

Slope of the line using points

( 1 ,1) and (0,2) is

[tex]m = \frac{2 - 1}{0 - 1} = \frac{1}{ - 1} = - 1[/tex]

So the equation of the line using point (1,1) is

y - 1 = - 1(x - 1)

y - 1 = - x + 1

x + y - 1 - 1 = 0

We have the final answer as

x + y - 2 = 0

Hope this helps you


SOS Help me please
Q‒2. [5×4 marks] Suppose that you pick a bit string from the set of all bit strings of length ten. Find the probability that
a) the bit string has exactly two 1s;
b) the bit string begins and ends with 0;
c) the bit string has the sum of its digits equal to seven;
d) the bit string has more 0s than 1s;
e) the bit string has exactly two 1s, given that the string begins with a 1.

Answers

Answer:

a. 45/1024

b. 1/4

c. 15/128

d. 193/512

e. 9/256

Step-by-step explanation:

Here, each position can be either a 0 or a 1.

So, total number of strings possible = 2^10 = 1024

a) For strings that have exactly two 1's, it means there must also be exactly eight 0's.

Thus, total number of such strings possible

10!/2!8!=45

Thus, probability

45/1024

b) Here, we have fixed the 1st and the last positions, and eight positions are available.

Each of these 8 positions can take either a 0 or a 1.

Thus, total number of such strings possible

=2^8=256

Thus, probability

256/1024 = 1/4

c) For sum of bits to be equal to seven, we must have exactly seven 1's in the string. Also, it means there must also be exactly three 0's

Thus, total number of such strings possible

10!/7!3!=120

Thus, probability

120/1024 = 15/128

d) Following are the possibilities :

There are six 0's, four 1's :

So, number of strings

10!/6!4!=210

There are seven 0's, three 1's :

So, number of strings

10!/7!3!=120

There are eight 0's, two 1's :

So, number of strings

10!/8!2!=45

There are nine 0's, one 1's :

So, number of strings

10!/9!1!=10

There are ten 0's, zero 1's :

So, number of strings

10!/10!0!=1

Thus, total number of string possible

= 210 + 120 + 45 + 10 + 1

= 386

Thus, probability

386/1024 = 193/512

e) Here, we have fixed the starting position, so 9 positions remain.

In these 9 positions, there must be exactly two 1's, which means there must also be exactly seven 0's.

Thus, total number of such strings possible

9!/2!7!=36

Thus, probability

36/1024 = 9/256

There are 4 Board of Directors positions open. 2 will be for men, 2 will be for women.
Out of 20 candidates, 11 are men, 9 are women. How many total outcomes are
possible?

Answers

Answer:

4290

Step-by-step explanation:

Lets find the total number of men and women .

9 women are out and 2 became the member of the Board=> total 11 women

11 men are out and 2 became the member of the Board=> total 13 men

11 women-candidates for 2 positions can make C11 2  outcomes =11!/(11-2)!/2

13 men-candidates for 2 positions can make C13 2 outcomes= 13!/(13-2)!/2

The total number of outcomes is C11 2 *C13 2 = 13!*11!/9!/11!/2/2=

10*11*12*13/2/2=11*13*5*6=4290 outcomes

Mahesh has Rs 150 and he buys a pen costing Rs 75 now he has to buy a copies costing Rs 10 each what is the maximum number of copies did he buy?​

Answers

Answer:

7

Step-by-step explanation:

Rs 150- Rs 75=Rs 75 remaining

Rs 75/10= 7 as whole

Step-by-step explanation:

given,

total amnt =rs.150

cost of pen= rs.75

now,

left money =150_75

=rs.75

now,cost of 1 copy=10

then , no. of copies=75/10

=7.5

so he can buy 7 copies.

Fathi has \$1.10$1.10dollar sign, 1, point, 10 in his printing account. Each sheet of paper he uses reduces his printing account balance by \$0.25$0.25dollar sign, 0, point, 25. Fathi wants to print out a PDF document that is 474747 pages long. To save paper, he decides to print on both sides of each sheet and to print two pages on each side of the sheet. After Fathi prints, what will be the balance in his printing account?

Answers

Answer:

$-4.90.

Step-by-step explanation:

Fathi has $1.10. Each sheet costs him $0.25. He wants to print 47 pages.

If he prints double sided, then he will use 47 / 2 = 23.5 sheets of paper. But he can't print a half-sheet, so he will use 24 sheets of paper.

Each sheet costs $0.25. 0.25 * 24 = 6. The printing will cost him $6.

Since he only has $1.10, his remaining balance will be 1.1 - 6 = -4.9. The balance on his printing account will be $-4.90.

Hope this helps!

Answer:

-1.90

Step-by-step explanation:

Khan Academy

I got it right for sure

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