Someone help me I’ll give brainliest

Answer:

Please find the answer in the explanation

Explanation:

Take the regular compass and hold it so the case is vertical. Now use it to investigate the direction of the coil’s magnetic field at locations other than the central axis.

What happens as you move away from the center axis toward the coil? The direction of the magnetic compass needle will move in an opposite direction since the direction of the induced voltage is reversed.

What happens above the coil?

the needle on the magnetic compass will be deflected. Since compasses work by pointing along magnetic field lines

Outside the coil? The magnetic compass needle will experience no deflection. Since there is no induced voltage or current.

Below the coil?

The needle will move in an opposite direction.

Answer:

light reflects when it hits the surface

Explanation:

Youngs double slit is a evidence for wave nature,

The properties refraction are attributed as properties of waves. The phenomena of interference and diffraction also fall in this category.

So,

     the answer must be B

Answer: Light does not need a medium to travel.

Explanation: I took the test and got it right :]

Answer:

The magnitude of the net force acting on an object is equal to the mass. and the direction is in 20N

Explanation:

Answer:

Maybe

Explanation:

I say maybe because it will help them still but not quite

The complete question is;

A person with body resistance between his hands of 10 kΩ accidentally grasps the terminals of a 16-kV power supply. What is the power dissipated in his body?

A) If the internal resistance of the power supply is 1600 Ω , what is the current through the person's body?

B) What is the power dissipated in his body?

C) If the power supply is to be made safe by increasing its internal resistance, what should the internal resistance be for the maximum current in the above situation to be I_max = 1.00mA or less?

Answer:

A) I = 1.379 A

B) P = 19016.41 W

C) r = 15990000 Ω

Explanation:

A) We are given;

Internal resistance of the power supply; r = 1600 Ω

Body resistance between hands; R = 10kΩ = 10000 Ω

Power supply voltage; E =16 kV = 16000 V

Formula for the current through the person's body with internal resistance is given by;

I = E/(R + r)

Thus;

I = 16000/(10000 + 1600)

I = 1.379 A

B) Formula for power dissipated is;

P = I²R

P = 1.379² × 10000

P = 19016.41 W

C) Now, we are told that the maximum current should be I_max = 1.00mA or less. So, I_max = 0.001 A

Thus, from I = E/(R + r) and making r the subject, we have;

r = (E/I) - R

r = (16000/0.001) - 10000

r = 15990000 Ω

Answer:

6.7 m/s

Explanation:

Given:

Δx = 5 m

v₀ = 5 m/s

a = 2 m/s²

Find: v

v² = v₀² + 2aΔx

v² = (5 m/s)² + 2 (2 m/s²) (5 m)

v = 6.7 m/s

Answer:

B 5.0 A .

Explanation:

Hello.

In this case, since we know the charge (1200 C), time (4 min =240 s) and resistance (10Ω) which is actually not needed here, we compute the current as follows:

[tex]I=\frac{Q}{t}[/tex]

Then, for the given data, we obtain:

[tex]I=\frac{1200C}{4min}*\frac{1min}{60s}\\\\I=5A[/tex]

Therefore, answer is B 5.0 A .

Best regards!

Answer:

[tex]a=2.4\ m/s^2[/tex]

Explanation:

Given that,

The initial speed of a car, u = 0

Time, t = 18 s

Distance, d = 390 m

We need to find the acceleration of the car. Let it is a. Using the second equation of motion to find it.

[tex]d=ut+\dfrac{1}{2}at^2[/tex]

or

[tex]d=\dfrac{1}{2}at^2\\\\a=\dfrac{2d}{t^2}\\\\a=\dfrac{2\times 390}{(18)^2}\\\\a=2.4\ m/s^2[/tex]

So, the acceleration of the car is [tex]2.4\ m/s^2[/tex].

Complete Question

The diagram for this question is shown on the first uploaded image

Answer:

The tension in the rope on the left of the mountain climber is [tex] T_a = 1106 \ N [/tex]

Explanation:

From the question we are told that

The weight of the mountain climber is m = 555 N

Generally from the diagram , the total amount of force acting on the rope along the vertical axis at equilibrium is mathematically represented as  

       [tex]T_a*  cos 65 -555 + T_b * cos(85) =  0[/tex]

Here  [tex]T_a, T_b[/tex] are the tension of the rope on the left and on the right hand side

 So

    [tex]0.423T_a   + 0.0871T_b  =  555[/tex]

=>   [tex] 0.0871T_b  =  555 - 0.423T_a[/tex]

=>   [tex] T_b  =  \frac{555 - 0.423T_a}{0.0871}[/tex]

Generally from the diagram , the total amount of force acting on the rope along the horizontal  axis at equilibrium is mathematically represented as

      [tex]T_a*  sin 65 - T_b * sin(85) =  0[/tex]

=>     [tex] 0.9063T_a - 0.9962T_b =  0[/tex]

=>     [tex] 0.9063T_a =   0.9962T_b [/tex]

=>     [tex] 0.9063T_a =   0.9962[\frac{555 - 0.423T_a}{0.0871}] [/tex]

=>     [tex] 0.9063T_a =   [\frac{552.891 - 0.421T_a}{0.0871}] [/tex]

=>    [tex] 0.0789T_a =   [552.891 - 0.421T_a[/tex]

=>    [tex] 0.4999T_a =   552.891 [/tex]

=>      [tex] T_a = 1106 \ N [/tex]

Answer:

Explanation:

graphing is helpful

helps visualize the line

of your equation

Answer:

Explanation:

To find the force given the mass , velocity and time can be found by using the formula

[tex]f = \frac{m \times v}{t} \\ [/tex]

where

m is the mass

v is the velocity

t is the time

From the question

m = 1500 kg

v = 30 m/s

t = 3 s

We have

[tex]f = \frac{1500 \times 30}{3} = \frac{45000}{3} \\ [/tex]

We have the final answer as

Hope this helps you

Answer:

His weight would be zero on the scale i.e he is weightless at that instance.

Explanation:

weight = mg

where m is the mass of the object, and g is the acceleration of gravity.

⇒ 810 = mg

During free fall, the weight of an object can be determined by:

W = mg - ma (provided that acceleration of gravity is greater than acceleration of the object)

where a is the acceleration of the object.

But since James fall at the acceleration of gravity, then:

g = a

mg = ma = 810 N

So that;

W = 810 - 810

    = 0 N

Therefore though the weight of James is 810 N, but the scale reads 0 N. this condition is referred to as weightlessness.

v² - u² = 2 a ∆x

where u = initial velocity (27 m/s), v = final velocity (0), a = acceleration (-8 m/s², taken to be negative because we take direction of movement to be positive), and ∆x = stopping distance.

So

0² - (27 m/s)² = 2 (-8 m/s²) ∆x

∆x = (27 m/s)² / (16 m/s²)

∆x ≈ 45.6 m

The stopping distance of car achieved during the braking is of 45.56 m.

Given data:

The initial speed of car is, u = 27 m/s.

The final speed of car is, v = 0 m/s. (Because car comes to stop finally)

The magnitude of deacceleration is, [tex]a = 8\;\rm m/s^{2}[/tex].

In order to find the stopping distance of the car, we need to use the third kinematic equation of motion. Third kinematic equation of motion is the relation between the initial speed, final speed, acceleration and distance covered.

Therefore,

[tex]v^{2}=u^{2}+2(-a)s[/tex]

Here, s is the stopping distance.

Solving as,

[tex]0^{2}=27^{2}+2(-8)s\\\\s = 45.56 \;\rm m[/tex]

Thus, we can conclude that the stopping distance of car achieved during the braking is of 45.56 m.

Learn more about the kinematic equation of motion here:

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Answer:

Tolerance: [tex]\pm 10\%[/tex]

Explanation:

Resistor Color Codes

Resistor Color Coding uses colored bands to quickly identify the resistive value or resistors and its percentage of tolerance.

Since the question does not provide a specific color table, we'll use the table attached below.

The colors of the resistor shown in the question are:

First band: orange

Second band: blue

Third band: brown

Fourth band: silver

The colors relate to the following numbers respectively:

3, 6, 10Ω, [tex]\pm 1\%[/tex]

The first two colors form the number 36

The third color is the multiplier: 36*10Ω = 360Ω

And the fourth color is the tolerance or the possible variation of the resistance [tex]\pm 1\%[/tex]

Resistance: 360Ω

Tolerance: [tex]\pm 10\%[/tex]

Answer:

A Cell

Explanation:

Answer:

[tex](1630.13\pm 300.10)\ kg/m^3[/tex]

Explanation:

Given that,

The radius of a sphere is (6.45 ± 0.30) cm

Mass of the sphere is (1.79 ± 0.08) kg

Density = mass/volume

For sphere,

[tex]d=\dfrac{m}{V}\\\\d=\dfrac{m}{\dfrac{4}{3}\pi r^3}\\\\d=\dfrac{1.79\ kg}{\dfrac{4}{3}\pi (6.4\times 10^{-2}\ m)^3}\\\\d=1630.13\ kg/m^3[/tex]

We can find the uncertainty in volume as follows :

[tex]\dfrac{\delta V}{V}=3\dfrac{\delta r}{r}\\\\=3\times \dfrac{0.3\times 10^{-2}}{6.45\times 10^{-2}}\\\\=0.1395[/tex]

Uncertainty in mass,

[tex]\dfrac{\delta m}{m}=\dfrac{0.08}{1.79}\\\\=0.0446[/tex]

Now, the uncertainty in density of sphere is given by :

[tex]\dfrac{\delta d}{d}=\dfrac{\delta m}{m}+\dfrac{\delta V}V}\\\\=0.0446+0.1395\\\\\dfrac{\delta d}{d}=0.1841\\\\\delta d=0.1841\times d\\\\\delta d=0.1841\times 1630.13\\\\\delta d = 300.10\ kg/m^3[/tex]

Hence, the density pf the sphere is [tex](1630.13\pm 300.10)\ kg/m^3[/tex]

Answer:

1. Huge wildfires

2. Deforestation

3. Reduced amount of aforestation, etc

Complete Question

The complete question is shown on the first and second uploaded image

Answer:

The expression is  [tex]W_c =  P_o V_o ln (R_v)[/tex]  

Explanation:

Generally smallest workdone done by  a gas is mathematically represented as

          [tex]dW  =  PdV[/tex]

Generally for an isothermal process

    [tex]PV  =  nRT = constant [/tex]

=>   [tex]P = \frac{nRT}{V}[/tex]

Generally the total workdone is mathematically represented as

   [tex]W_c =  \int\limits^{v_f}_{V_o} {\frac{nRT}{V} } \, dV[/tex]

=> [tex]W_c = nRT  \int\limits^{V_f}_{V_o} {\frac{1}{V} } \, dV[/tex]

=>  [tex]nRT [lnV]   | \left \ {V_f}} \atop {V_o}} \right.[/tex]

=>  [tex]W_c = nRT [ln(V_f) - ln(V_o)][/tex]

=>  [tex]W_c = nRT ln \frac{V_f}{V_o}[/tex]

From the question [tex]\frac{V_f}{V_o }  =  R_v[/tex]

=> [tex]W_c =  P Vln (R_v)[/tex]

at initial  state

[tex]W_c =  P_o V_o ln (R_v)[/tex]  

Answer:

The acceleration of the car is 10.16m/s²

Explanation:

Given parameters:

  Initial velocity = 8.77m/s

   Final velocity = 47.8m/s

   Time duration  = 3.84s

Unknown:

Acceleration of the car = ?

Solution:

To find the acceleration, we must bear in mind that this physical quantity is the change in velocity with time;

     Acceleration  = [tex]\frac{V - U}{T}[/tex]

V is the final velocity

U is the initial velocity

T is the time taken

  Input the parameters and solve for acceleration;

      Acceleration  = [tex]\frac{47.8 - 8.77}{3.84}[/tex]   = 10.16m/s²

The acceleration of the car is 10.16m/s²

Answer:

1.66m

Explanation:

Using the conservation law

PE = KE

mgh = 1/2mv²

gh = V²/2

g is the acceleration due to gravity = 9.81m/s²

h is the height of the hill

V is the velocity = 5.71m/s

Substitute

9.81h = 5.71²/2

Cross multiply

2×9.81h = 5.71²

19.62h = 32.6041

h = 32.6041/19.62

h = 1.66m

Hence the height of the hill is 1.66m

Answer:

The average force exerted on the superball by the sidewalk is 0.00122 N.

Explanation:

Given;

mass of the super ball, m = 50 g = 0.05 kg

initial velocity of the super bowl, u = -27 m/s (assuming downward motion to be negative)

final velocity of the super bowl, u = 17 m/s (assuming upward motion to be positive)

time of motion, t = 1800 s

The average force exerted on the superball by the sidewalk is given by;

[tex]F = ma\\\\F = \frac{m(v-u)}{t} \\\\F = \frac{0.05(17-(-27))}{1800}\\\\ F = \frac{0.05(44)}{1800}\\\\F = 0.00122 \ N[/tex]

Therefore, the average force exerted on the superball by the sidewalk is 0.00122 N.

C.1cm

Explanation:

precision is how close two or more measurements are to each other

4?

Explanation:

sorry im not sure but

You can always take a metre ruler as a starting point. Your metre ruler has the same precision as your 15.0cm or 30.0cm ruler, so bring a ruler during exams as they'll come in handy ;)

The order goes like this:

rulers: 0.1cm or 1mm

measuring tape: 0.01cm or 0.1mm

vernier calipers: 0.001cm or 0.01mm

micrometer screw gauge: 0.0001cm or 0.001mm

((if i'm not wrong))

Answer:

a

The pressure will increase

b

[tex]T_2 =  576^oC[/tex]

Explanation:

From the ideal gas law we have that

     [tex]PV  =  nRT[/tex]

We see that the temperature varies directly with the pressure so if there is an increase in temperature that pressure will increase

   The initial  temperature is [tex]T_i  =  10^oC = 10 + 273 =  283 \  K [/tex]

The objective of this solution is to obtain the temperature of the gas where the pressure is tripled

Now from the above equation given that nR and V  are constant  we have that

    [tex]\frac{P}{T}  =  constant[/tex]

=>  [tex]\frac{P_1}{T_1}  =\frac{P_2}{T_2}[/tex]

Let assume the initial  pressure is [tex]P_1 =  1 Pa[/tex]

So tripling it will result  to the pressure being [tex]P_2 =  3 Pa[/tex]

So

     [tex]\frac{1}{283}  =\frac{3}{T_2}[/tex]  

=>   [tex]T_2  =  3 *  283[/tex]

=>    [tex]T_2  =  3 *  283[/tex]

=>    [tex]T_2  = 849 \ K [/tex]

Converting back to [tex]^oC[/tex]

   [tex]T_2  =  849 -  273[/tex]

=>  [tex]T_2 =  576^oC[/tex]

The particles of a more dense substance are closer together than the particles of a less dense substance. Thus, the given statement is true.

Density of the particles is the substance's mass per unit of volume. The symbol which is most often used for the density is ρ (rho), although the Latin letter D can also be used to denote density.

Density is the mass of a unit volume of a material substance or particle. The formula for density is d = M/V (mass per unit volume), where d is density, M is the mass of particle, and V is the volume. Density is commonly expressed in the units of grams per cubic centimeters.

The S.I. unit of density is made up of the mass of the particle which is kg and that of volume is meter cube. Hence, the S.I. unit of density is kg/m³.

Learn more about Density here:

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Answer:

Explanation:

Given the density of silicon as 2.33g/cm³

We are to convert this to kg/cm³

We will be using the following conversion factors

1000g = 1kg

2.33g = x

Cross multiply

1000x = 2.33

x = 2.33/1000

x = 0.00233kg

Also we need to convert 1cm³ to 1m³

1cm = 0.01m

1cm³ = 0.01×0.01×0.01

1cm³ = 0.000001m³

Substituting into the density value of silicon

2.33g/cm³ = 0.00233kg/0.000001m³

= 2330kg/m³

Answer:

We are given:

initial velocity (u) = 20m/s

acceleration (a) = 4 m/s²

time (t) = 8 seconds

displacement (s) = s m

Solving for Displacement:

From the seconds equation of motion:

s = ut + 1/2 * at²

replacing the variables

s = 20(8) + 1/2 * (4)*(8)*(8)

s = 160 + 128

s = 288 m

The cyclist accelerates at 1.2 m / s² after 2 seconds he reaches a speed of 2.4 m / s, then the momentum at this point would be 211.2 kg-m/s, therefore the correct answer is option D.

It can be defined as the product of the mass and the speed of the particle, it represents the combined effect of mass and the speed of any particle, and the momentum of any particle is expressed in Kg m/s unit.

As given in the problem a cyclist and his bicycle has a combined mass of 88 kg and a combined weight of 862.4 N. The cyclist accelerates at 1.2 m/s2. After 2 seconds he reaches a speed of 2.4 m/s.

The momentum of the cyclist = 88 × 2.4

                                                 = 211.0 kgm/s

Thus, the momentum of the cyclist would be  211.0 kgm/s.

To learn more about momentum from here, refer to the link given below;

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Answer:

9 ft*lb

Explanation:

super simple but you just have to understand that the integral is going with the curve

work = integral a to b of f(x)dx = integral 0 to 9 of 10/(1+x)^2dx = 9ft*lb