Solve the following equation for 0 ≤ ѳ< 2π. Show your work.

sec^2ѳ-6=-4

Answer:

*WILLIAM AFTON*

Real Answer:

38 dollars and 11 cents.

Answer:

2feet at the least man

Answer:

4ft

Step-by-step explanation:

i did 12ft - 8ft which would of gotten the length of the bottom length.

Answer:

what?

Step-by-step explanation:

[tex]\huge\text{Hey there!}[/tex]

[tex]\large\textsf{5 - 3(7x + 8)}\\\\\large\text{DISTRIBUTE -3 WITHIN the PARENTHESES}\\\large\textsf{5 - 3(7x) + (-3)(8)}\\\large\textsf{-3(7x) = -21x}\\\large\textsf{-3(8) = -24}\\\large\textsf{= \underline{5 - 21x - 24}}\\\\\large\text{COMBINE the LIKE TERMS}\\\large\textsf{(-21x) + (5 - 24)}\\\large\textsf{-21 does NOT have any LIKE TERMS so we could leave it the same}\\\large\textsf{5 - 24 is the only LIKE TERM pair}\\\large\textsf{5 - 24 = -19}\\\large\textsf{-21x = -21x}[/tex]

[tex]\boxed{\boxed{\large\text{Answer: \huge\textsf{\bf -21x - 19}}}}\huge\checkmark[/tex]

[tex]\bf{Good\ luck\ on\ your\ assignment\ and\ enjoy\ your\ day!}[/tex]

~[tex]\frak{Amphitrite1040:)}[/tex]

Answer:

The decimal value of the volume already given= 1885.2 unit³

For radius 11 unit height 12 unit

Volume= 484π unit³

Volume= 1520.73 unit ³

For radius 4 unit height 6 unit

Volume= 32π unit³

Volume= 100.544 unit³

For radius 20 unit height 15 unit

Volume= 2000π unit³

Volume= 6284 unit³

Step-by-step explanation:

The decimal value of the volume already given= 600π

The decimal value of the volume already given= 600*3.142

The decimal value of the volume already given= 1885.2 unit³

For radius 11 unit height 12 unit

Volume= πr²h/3

Volume= 11²*12/3 *π

Volume= 484π unit³

Volume= 1520.73 unit ³

For radius 4 unit height 6 unit

Volume = πr²h/3

Volume= 4²*6/3(π)

Volume= 32π unit³

Volume= 100.544 unit³

For radius 20 unit height 15 unit

Volume= πr²h/3

Volume= 20²*15/3(π)

Volume= 2000π unit³

Volume= 6284 unit³

Hope this helps, best of look to all who needed help!!

Answer:

9

Step-by-step explanation:

it is 9 thats why

Answer:

ok sooo is there something you need to be figured out orr are you just saying

Step-by-step explanation:

Answer:

6:72

9:108

Step-by-step explanation:

For every 24 screws that Gary has he can build 2 chairs.

24=2

24+24+24=72

Gary needs 72 screws for 6 chairs.

24+24+24+18+18=108

Gary needs 108 screws for 9 chairs.

6:72

9:108

Answer:

Step-by-step explanation:

To find the angle measure of an angle inside an arc then you multiply 1/2 by the sum of the 2 intercepted arcs.

x=1/2(42+56)

x=1/2(98)

x=49

Answer:

sooo sory because I did not know answer

Answer:

Option a  doesn't equal 100.

option b equals 100

c doesnt equal 100

d doesnt equal 100

the answer is b

ANSWER:

The surface area of the star is 3.2700 x [tex]10^{8}[/tex] square kilometres.

EXPLANATIONS:

Diameter of the star = 1.8083 x [tex]10^{4}[/tex] Km.

Surface area of the star = 4[tex]n^{2}[/tex]

Where n is the radius of the star.

So that;

n = [tex]\frac{ 1.8083 * 10^{4} }{2}[/tex]

   = 0.90415 x [tex]10^{4}[/tex]

n =  0.90415 x [tex]10^{4}[/tex] Km

Thus,

Surface area = 4 x [tex](0.90415*10^{4} )^{2}[/tex]

                     = 326994889

Surface area = 3.2700 x [tex]10^{8}[/tex] [tex]km^{2}[/tex]

Therefore, the surface area of the star is 3.2700 x [tex]10^{8}[/tex] square kilometres.

Answer:

[tex]\boxed {\boxed {\sf a= 3, b=7, c=2}}[/tex]

[tex]\boxed {\boxed {\sf Y-intercept = c }}[/tex]

[tex]\boxed {\boxed {\sf Minimum}}[/tex]

Step-by-step explanation:

a. a, b, c

Quadratic equations in standard form are written as:

[tex]f(x)= ax^2+bx+c[/tex]

The exponents are listed from greatest to least. The quadratic is already in this form, so match up the variables and values in the equation.

[tex]f(x)= 3x^2+7x+2[/tex]

[tex]a=3 \\b=7 \\c=2[/tex]

b. Y-intercept

The y-intercept for a quadratic is c.

You can also substitute 0 in for x, because the y-intercept occurs when the quadratic crosses the y-axis (at x=0).

[tex]f(0)= 3(0)^2+7(0)+2[/tex]

[tex]f(0)=3(0)+7(0)+2\\f(0)= 0+0+2\\f(0)=2[/tex]

We know that c=2, so the y-intercept is c.

c. Maximum/minimum

The entire quadratic is positive, so the quadratic opens up and has a minimum.

Equation 1: 6y = 12x + 36

Equation 2: 15y = 45x + 60

Solve equation 1 for y by dividing both sides by 6 to get: y = 2x + 6

Replace y in equation 2:

15(2x + 6) = 45x + 60

Simplify:

30x + 90 = 45x + 60

Subtract 45x from both sides:

-15x + 80 = 60

Subtract 90 from both sides

-15x = -30

Divide both sides by -15:

X = 2

Now replace x in the first equation and solve for y:

6y = 12(2) + 36

6y = 24 + 36

6y = 60

Divide both sides by 6

Y = 10

The solution is x = 2, y = 10

The answer is there is only one solution.

Answer:

7\11

Step-by-step explanation:

you just multiply to get an integer then convert that

Answer:

2:11

Step-by-step explanation:

divide both sides by 9

Answer:

how are we supposed to get a number line if you didn't provide it i would answer it/

Step-by-step explanation:

Answer:

x=0 or x=28

im not sure

Answer: 120

Step-by-step explanation:

100-20 is 80. 80 percent are not red. Find 80 percent of 150. That is 120?

Answer:

D) [tex]b>3\frac{2}{15}[/tex]

Step-by-step explanation:

Answer:

The number that cannot be the largest possible 6-digit number is;

(D) AAABCB

Step-by-step explanation:

From the question, we have;

A, B, and C = Distinct digits, therefore, A ≠ B ≠ C

The number of digits in the number to be formed = 6 digits

The number of 'A' in the number to be formed = 3

The number of 'B' in the number to be formed = 2

The number of 'C' in the number to be formed = 1

We have;

When A > B > C

The largest possible number = AAABBC

When C > A > B

The largest possible number = CAAABB

When B > A > C

The largest possible number = BBAAAC

When A > C > B

The largest possible number = AAACBB

Therefore, given that when A > B > C, the largest possible number = AAABBC, we have;

AAABBC > AAABCB, because B > C, therefore, within the tens and unit of the two 6 digit numbers, we have, BC > CB

∴ AAABBC > AAABCB and AAABCB, cannot be the largest possible 6-digit number

Answer:

1/2

Step-by-step explanation:

x change: 2 --> -4 = -6

y change: 3 --> 0 = -3

y/x = -3/-6 = -1/-2 = 1/2

Answer:

1/2

Step-by-step explanation:

(y2-y1)/(x2-x1) is the formula for slope

(0-3)/(-4-2) = 1/2

Answer:

5

Step-by-step explanation:

Answer:

22

Step-by-step explanation:

Answer:

45°

Step-by-step explanation:

I assume you meant 45°, not 45%.

90-45=45

If it is actually 45%, then the answer would be:

90x.55=49.5°

Answer:

24

Step-by-step explanation:

First, find the total volume of the shape by multiplying all side lengths:

1 * 2 * (3/2) = 3 cubic cm

A cube with side length of 1/2 has a volume of (1/2)(1/2)(1/2) = 1/8 cubic cm

If the total volume is 3 cubic cm, how many 1/8 cm cubes would fit?

3 / (1/8) = 24 cubes

Answer:

156 seats were sold at the store and 244 at the gallery

Step-by-step explanation:

Let the amount of stalls be x

Let the price per ticket for gallery be y

If 400 seats were sold in total, then;

x+y = 400 ... 1

If concert tickets are sold for $ 8 for the stalls and $ 6 for the gallery with a total of $2888, then;

8x + 6y = 2888 ....2

Solve both equation simultaneously

x+y = 400 ... 1 * 8

8x + 6y = 2888 ....2 .*1

__________

8x+8y = 3200 .

8x + 6y = 2888

Subtract

__________

8y - 6y = 3200 - 2888

2y = 312

y = 312/2

y = 156

Since x = 400 - x

y = 400 - 156

y = 244

hence 156 seats were sold at the store and 244 at the gallery

Answer:

total cost = sell price + (sell price * 0.07)

Part A

Given:

Volume of square pyramid = 73.5 cubic inches

height of square pyramid = 4.5 inches

To find:

1)Side length of square pyramid.

2)if side length of square pyramid is rational or irrational

Steps:

1) Side length = [tex]\sqrt{\frac{3v}{h} }[/tex]

Side length = [tex]\sqrt{\frac{3*73.5}{4.5} }[/tex]

Side length = [tex]\sqrt{\frac{3*73.5*10}{4.5*10} }[/tex]         (multiplying both sides to make it a whole number)

Side length = [tex]\sqrt{\frac{3*735}{45} }[/tex]

Side length = [tex]\sqrt{\frac{735}{15} }[/tex]                  (3 gets canceled out)

Side length = [tex]\sqrt{49}[/tex]

Side length = 7 inches

Therefore, the side length of the square pyramid is 7 inches long

2) 7 is a rational number, so the side length of the square pyramid is a rational number.

It is a rational number because,

it can be written in the form p/q,  where

1) q [tex]\neq[/tex]0

2) p and q are co-prime

3) p and q are integers

Part B

Given:

Volume of Khafre's pyramid = 9/10 of Khufu's pyramid's volume

Volume of Kristina's first pyramid = 73.5 cubic inches

To find:

Volume of Kristina's second pyramid

Steps:

Volume of Kristina's second pyramid = 9/10 the volume of Kristina first pyramid

Volume of second pyramid = [tex]\frac{9}{10}*73.5[/tex]

Volume of second pyramid = 9 [tex]*[/tex] 7.35

Volume of second pyramid = 66.15 cubic inches

The volume of the second pyramid should be 66.15 cubic inches

Part C

Given:

Height of pyramid = 4.41 inches

Volume of pyramid = 66.15 cubic inches

To find:

1) Side length of pyramid

2) if the side length is rational or irrational

Steps:

1) Side length = [tex]\sqrt{\frac{3v}{h} }[/tex]

Side length = [tex]\sqrt{\frac{3*66.15}{4.41} }[/tex]

Side length = [tex]\sqrt{\frac{3*66.15*100}{4.41*100} }[/tex]         (multiplying both sides to make it a whole number)

Side length = [tex]\sqrt{\frac{3*6615}{441} }[/tex]

Side length = [tex]\sqrt{\frac{6615}{147} }[/tex]                   (3 gets canceled)

Side length = [tex]\sqrt{45}[/tex]

Side length of pyramid is [tex]\sqrt{45}[/tex] inches

2) [tex]\sqrt{45}[/tex] cant be written in the form of a fraction, so it is an irrational number

(if u want i can explain this more)

Part D

Given

Height of model pyramid = 4.5 inches

Height of Khufu's pyramid = 755.75 feet (had to search the internet for the answer, so I am not sure if it is correct)

Side length of model pyramid = 7 inches

Side length of Khufu's pyramid = 481.4 feet (had to search the internet for the answer)

To find:

1)If the model is to scale with Khufu's pyramid

2) If the model is close to scale with Khufu's pyramid

Steps:

1) First lets find the ratio of the height to the side length of the model

Ratio = 4.5 in : 7 in

         = 45 : 70

         = 9 : 14

         = 0.6428

Now lets find the ratio of the height to the side length of Khufu's pyramid

Ratio = 481.4 feet : 755.75 feet

         = 5776.8 in : 9069 in

         =  0.6369

Therefore the model is not to scale with Khufu's pyramid

2) Yes the scale is close

Part E

Given:

Height of model pyramid = 4.41 inches

Height of Khafre's pyramid = 448 feet

Side length of model pyramid = [tex]\sqrt{45}[/tex] inches

Side length of Khafre's pyramid = 706 feet

To find:

1) If the model is to scale with Khafre's pyramid

2) If the model is close to scale with Khafre's pyramid

Steps:

1) First lets find the ratio of the height to the side length of the model pyramid,

Ratio = 4.41 in : [tex]\sqrt{45}[/tex] in

= 4.41 : 6.7082

= 0.6574

Now lets find the ratio of the height to the side length of Khafre's pyramid

Ratio = 448 ft : 706 ft

= 5376 in : 8472 in

= 0.6345

Therefore the model is not to scale with Khafre's pyramid

2) No, the model is not close to scale,  (it depends by what is meant by close, for me its 0.01)

Happy to help, and I hope you learnt something from this answer that will help you in the future

If you didn't understand any topic pls ask