Answer:
Given :-mass = 65 kg
Height = 80 m
Acceleration = 9.8 m/s²
To Find :-Potential energy
Solution :-We know that
PE = mass × acceleration × height
PE = 65 × 80 × 9.8
PE = 50,960 Joules
[tex] \\ [/tex]
Find the moment of 300N force about B
Answer:
300
Explanation Hope I'm not wrong.
The manufacturer of a 9V dry-cell flashlight battery says that the battery will deliver 20 mA for 80 continuous hours. During that time the voltage will drop from 9 V to 6 V. Assume the drop in voltage is linear with time. How much energy does the battery deliver in this 80 h interval
Answer:
17280 J or 17.28 kJ
Explanation:
Given that the voltage drop,
U = U2 - U1
U = 9 - 6
U = 3V
Also, we're told that the current, I is equal to 20 mA with the discharge time, t being 80 hrs.
Converting the time from h oi urs to seconds, we have
t = 80 * 3600
t = 288000
Now, to find the energy needed, we're going to use the formula
w = pt, where p = U * I
p = 3 * 20*10^-3
p = 60*10^-3
w = 60*10^-3 * 288000
w = 17280 J or 17.28 kJ
Therefore, the total energy the battery delivers in the 80 hrs is 17.28 kJ
Consider the following three concentric systems two thick shells and a solid sphere all conductors The radii in the increasing order are a b c d and e The small sphere is given an excess charge of 3 C and the smaller shell is given an excess charge of 7 C The larger shell is electrically neutral The system quickly comes to electrostatic equilibrium state a Note that there are 5 conducting surfaces What are the electric charges values and signs on the each of them Are these charges distributed uniformly
Answer:
Explanation:
From the given question, the small sphere was provided with an excess charge of +3 C, while the smaller shell was given an excess of -7 C, it should be -7 C and not 7 C.
So, in light of that, to determine the electric charges values & signs on each of them, we have:
on a = +3 C
on b = -7 C
on c = -7 C
on d = +3 C
on e = -7 C
Gauss's law: Group of answer choices can always be used to calculate the electric field. relates the electric field throughout space to the charges distributed through that space. only applies to point charges. relates the electric field at points on a closed surface to the net charge enclosed by that surface. relates the surface charge density to the electric field.
Answer:
relates the electric field at points on a closed surface to the net charge enclosed by that surface.
Explanation:
Gauss Law states that overall electric flux of a closed surface is equivalent right to charge enclosed which is divided by the permittivity. In other words Gauss Law stress that
net electric flux that pass through an hypothetical closed surface is equivalent to overall electric charge present within that closed surface.
The Gauss law can be expressed mathematically as
ϕ = (Q/ϵ0)
Q = total charge within the surface,
ε0 = the electric constant
What is the subject Physic about
Explanation:
Physics is the branch of science concerned with the study of the properties and interactions of space, time, matter and energy.
Answer:
if you are very excited to know why ball doesn't go up
(a) What is the electric field 4.00 m from the center of the terminal of a Van de Graaff with a 3.00 mC charge, noting that the field is equivalent to that of a point charge at the center of the terminal?
______ N/C
(b) At this distance, what force does the field exert on a 2.00C charge on the Van de Graaff's belt?
_____ N
Answer:
a) E = 1.69 10⁶6 N / C, b) F = 3.38 10⁶ N
Explanation:
a) In this exercise using Gauss's law we can consider the charge of the generator sphere as if it were at its center, therefore the electric field is
E = k [tex]\frac{q}{r^2}[/tex]
let's calculate
E = 9 10⁹ 3.00 10⁻³ / 4²2
E = 1.6875 10⁶ N / C
E = 1.69 10⁶6 N / C
b) let's calculate the electric force
F = q E
F = 2.00 1.69 10⁶
F = 3.38 10⁶ N
5. Atoms may emit light energy when
O A electrons move to a lower energy level
OB protons move to a lower energy level
C electrons move to a higher energy level
OD protons move to a higher energy level
How far can you get away from your little
brother with the squirt gun filled with
paint if you can travel at 3 m/s and you
have 15s before he sees you?
Know
Find
Equation
Solve
spray him in the eyes and you have until he washes it put
State the four factors the magnetic force moving in magnetic field depends on
Explanation:
It depends upon the magnitude of the charge, the velocity of the particle and its strength .
HELP ASAP PLS ILL GIVE YOU BRAINLIEST
Select the correct answer.
Which civilization was the first to record a solar eclipse?
A.
Greek
B.
Chinese
C.
Aztec
D.
Polynesian
Answer:
chinese
Explanation:
Answer:
B chinese
hope this helps you
What is the difference between inertia and momentum?
Add a suffix to each of the following words to make new words?
Where's the following words?
A 1.3-kg book rests on a table. A downward force of 15 N is exerted on the top of the book by a hand pushing down on the
book
What is the net force on the book?
Answer:
The net force will be:
[tex] F_{net} = 142.53\: N[/tex]
Explanation:
The net force is given by:
[tex] F_{net} = W_{b}+F[/tex]
[tex] F_{net} = m_{b}g+15[/tex]
[tex] F_{net} = 142.53\: N[/tex]
I hope it helps you!
If the force of static friction on a crate is 67 N and the weight of the create is 289 N, what is the coefficient of static friction?
a
19363
b
0.23
c
4.31
d
222
Answer:
B) μ = 0.23
Explanation:
The coefficient of friction is equal to μ = F / N where μ (mu) is the coefficient of friction, F is the friction force, and N is the normal force (the force of an object being applied onto the earth by gravity).
F, the friction force, is given as 67 N
Since the weight of the crate is 289 N, that means the normal force is 289 N.
This means that the coefficient of friction is μ = F / N = 67 N / 289 N = 0.23183391 = 0.23
Therefore, B is the correct answer
A 0.15kg baseball is pushed with a 100N force. What will its acceleration be?
all of the following elements will form ions by losing electrons except
aluminum
iron
sodium
oxygen
Which is the best description of biodiversity?
1. All animals in an ecosystem
2. The variety of the type of life within the biosphere
3. The study of life
3. The variety of plants on Earth
Answer:2
Explanation:
For Water, determine the missing property and determine the state. 1) P = 300 kPA, v = 0.5 m3/kg. Find T 2) P = 28 MPa, T = 200oC. Find v 3) P = 1 MPa, T = 405 oC. Find v 4) T = 100oC, x = 60%. Find v
Answer:
1) LIQUID, 2) LIQUID, 3) GASEOU, 4) GASEOUS, v = 0.76 m³ / kg
Explanation:
In this exercise it is asked to determine the state of the water, that is, if it is solid, liquid or gas. For this we must use a phase diagram of water which is a graph of Pressure versus Temperature. Let's describe the water diagram
* Below 0ºC and normal pressure the water is in a solid state
* Below this temperature and at low pressure it becomes a gaseous state
* Above 0.01ºC and normal pressure is in liquid state
* Above 0.01ºC and low pressure is in a gaseous state
there are two important points
* The triple point at t + 0.01ºC and P = 0.006 atm where the three states coexist
* The critical point T = 374ºC and P = 218 atm where water decomposes into hydrogen and oxygen
Specific volume is related to density
v = 1 / ρ
ρ = 1 / v
the density of water is approximately 1000 kg / m³ in the liquid state at t = 4ºC and decreases with increasing pressure 960 kg / m³ at T = 100ºC (but without changing to the gaseous state
With the above considerations we can answer the questions
1) P = 300 kPa = 3 105 Pa
v = 0.5 m³ / kg
atmospheric pressure is Patm = 1.01 105 Pa
P = 3 105 Pa (1 atm / 1.01 105 Pa) = 3 atm
From the phase diagram described, the water can be in two liquid or gaseous states, depending on the temperature, as indicated by the speed of the same state, the water must be LIQUID
the parameter v that you indicate is the
with the other parameter we can calculate the density
rho = 1 / 0.5
rho = 2.0 kg / m³
in a thermodynamic system the three basic properties are: pressure, volume and temperature,
we can calculate the body temperature
The body must be at a temperature between 0 <T <100ºC
2) P = 28 Mpa = 28 106 Pa
P = 28 106 Mpa (1 atm / 1.01 105 Pa) = 280 atm
T = 200ºC
When examining the diagram it can be seen that the water is in the range of the LIQUID state
3) P = 1MPa
P = 1 106 Pa (1atm / 1.01 105Pa) = 10 atm
T = 405ºC
In this case, the only accessible state is the GASEOUS
4) T = 100ºC
x = 60%
Examining the phase diagram at this temperature depending on the pressure the possible states are Vapor and liquid, for pressures below 1 atm the state is GASEOUS
for the gaseous state we can use the ideal gas equation
PV = nR T
let us perform the calculation for a mole of gas n = 1, the ideal gas constant is R = 8,206 10-2 atm / mol K
V = nRT / p
V = 1 8,206 10-2 100/1
V = 8,206 m³
v = V / m
The mass of the water is 18 Kg / mol, which indicates that 60% is in the gaseous state, so the mass in this state is
m = 0.60 18
m = 10.8 kg
v = 8.206 / 10.8
v = 0.76 m³ / kg
A polycondensation reaction takes place between 1.2 moles of a dicarboxylic acid, 0.4 moles of glycerol (a triol) and 0.6 moles of ethylene glycol (a diol). A.Calculate the critical extents of reaction for gelation using (i) the statistical theory of Flory and (ii) the Carothers theory.B.Comment on the observation that the measured value of the critical extent of reaction is 0.866.
Answer:
A) i) using statistical theory of floxy
(Pa)c = 0.816
(Pb)c = 0.816
ii) using Carothers theory
( Pc ) = 0.917
B) To Obtain the measured value of critical extent of reaction ( 0.866) 1 mol of Glycerol will react with 1 mol of dicarboxylic acid, but the same can not be applied to our obtained value because our stoichiometry is different
Explanation:
Given data :
Polycondensation reaction takes place between : 1.2 moles of dicarboxylic acid , 0.4 moles of glycerol and 0.6 moles of ethylene glycol
A) Calculate the critical extents of reaction for gelation
i) using statistical theory of floxy
(Pa)c = 0.816
(Pb)c = 0.816
ii) using Carothers theory
( Pc ) = 0.917
attached below is the detailed solution
B) To Obtain the measured value of critical extent of reaction ( 0.866) 1 mol of Glycerol will react with 1 mol of dicarboxylic acid, but the same can not be applied to our obtained value because our stoichiometry is different
Help me please I wrote some but I am still stuck
Answer:
write something like after the spacecraft launched all of the potential energy transformed into kinetic energy causing the spacecraft to go at an abnormal spped.
Explanation:
How long must a 0.54-mm-diameter aluminum wire be to have a 0.42 A current when connected to the terminals of a 1.5 V flashlight battery
Answer:
L = 30.85 m
Explanation:
First, we calculate the resistance of the wire by using Ohm's Law:
V = IR
where,
V = Potential Difference = 1.5 V
I = Current = 0.42 A
R = Resistance of Wire = ?
Therefore,
[tex]R = \frac{1.5\ V}{0.42\ A}\\\\R = 3.57\ Ohms[/tex]
Now, the cross-sectional area of wire will be:
[tex]Area = A = \frac{\pi d^{2}}{4}\\\\A = \frac{\pi (0.00054\ m)^{2}}{4}\\\\A = 2.29\ x\ 10^{-7}\ m^{2}[/tex]
Now, the resistance of the wire is given as:
[tex]R = \frac{\rho L}{A}\\\\L = \frac{RA}{\rho}[/tex]
where,
L = Length of Wire = ?
ρ = resistivity of aluminum = 2.65×10⁻⁸ Ohm.m
Therefore,
[tex]L = \frac{(3.57\ Ohms)(2.29\ x\ 10^{-7}\ m^{2})}{2.65\ x\ 10^{-8}\ Ohm.m}[/tex]
L = 30.85 m
Which one of the following is an example of an acid-base reaction?
Answer:
B
Explanation:
Acid reacts with base to give salt and water.
HCL - Acid
Mg(OH)2 - Base
H2O - Water
MgCl2 - Salt
Answer: B because A p e x
Explanation:
A monk is sitting atop a mountain in complete rest in meditation. What is the Kinetic
Energy of the monk? (assume mass of 65 kg and the mountain's height was 1000 m)
4,225,000
No Kinetic Energy - because there is no movement
637,000
65.000
Answer:
No kinetic energy-because there is no movement
Explanation:
It states that the monk is at complete rest so there is no movement.
A high frequency sound will have a ?
Answer:
The frequency of a sound wave is what your ear understands as pitch. A higher frequency sound has a higher pitch and the lower the period
Answer:
High-frequency sound waves produce high-pitched sounds, and low-frequency sound waves produce low-pitched sounds.
A spring with a spring constant of 80 N/m is at rest and is attached to a block. If the block (attached to the end of the spring) is moved from 0.6 m to 0.4 m and then let go, what will be the spring force exerted on the block? Rightward is positive.
Answer:
–I6 N
Explanation:
From the question given above, the following data were obtained:
Spring constant (K) = 80 N/m
Initial position = 0.6 m
Final position = 0.4 m
Force (F) =?
Next, we shall determine the compression of the spring. This can be obtained as follow:
Initial position = 0.6 m
Final position = 0.4 m
Compression (x) =?
Compression = Final position – Initial position
Compression (x) = 0.4 – 0.6
Compression (x) = – 0.2 m
Finally, we shall determine the force. This can be obtained as follow:
Spring constant (K) = 80 N/m
Compression (x) = – 0.2 m
Force (F) =?
F = Kx
F = 80 × –0.2
F = –I6 N
.) What will be the unit of time in that system in
which unit of length is m, unit of mass is kg and
unit of force is kg wt?
(a) [1/V(9.8) second (b) (9.8)2 second
(c) V(9.8) second
(d) 9.8 second
Answer:
yes it is a great question. Thank you .
Is inertia a force (will give brainleist for first answer)
Answer:
Yes.
Explanation:
Answer:
I do believe it is. (more characters for character limit)
Consider a length of pipe bent into a U-shape. The inside diameter of the pipe is 0.5 m. Air enters one leg of the pipe at a mean velocity of 100 m/s and exits the other leg at the same magnitude of velocity, but moving in the opposite direction. The pressure of the flow at the inlet and exit is the ambient pressure of the surroundings. Calculate the magnitude and direction of the force exerted on the pipe by the airflow. The air density is 1.23 kg/m3 .
Answer:
The magnitude of the force exerted on the pipe by the air is 4830 N and it acts horizontally
Explanation:
Given the data in the question;
from the Newton's second law of motion;
F = ma
where m is the mass, a is acceleration and F is the force exerted on the pipe due to the airflow in it
now in terns of mass flow;
F = [tex]m^{"}[/tex]V
where [tex]m^{"}[/tex] is the mass flow rate, V is the velocity(
so
[tex]m^{"}[/tex] = pAV
[tex]m^{"}[/tex] = p × ([tex]\frac{\pi }{4}[/tex] d² ) × V
where d is the diameter of the pipe( 0.5 m)
p is the density( 1.23 kg/m³ )
velocity v is 100 m/s
so we substitute
[tex]m^{"}[/tex] = 1.23 × ([tex]\frac{\pi }{4}[/tex] (0.5)² ) × 100
[tex]m^{"}[/tex] = 30.75 × [tex]\frac{\pi }{4}[/tex]
[tex]m^{"}[/tex] = 24.15 kg/s
Now lets write the equation for the force exerted on the pipe by the airflow
F = [tex]m^{"}[/tex]( V₁ - V₂)
where V₁ is velocity at inlet ( 100 m/s )
V₂ is velocity at exit ( - 100 m/s )
so we substitute
F = 24.15 ( 100 - (-100))
F = 24.15 × 200
F = 4830 N
The pipe is symmetric about horizontal axis so the force should also b acting only in the horizontal direction since any force component in the vertical direction is nullified due to this symmetry
Therefore, The magnitude of the force exerted on the pipe by the air is 4830 N and it acts horizontally
can someone please answer this for me ❤️
Answer:
I don't understand the question
Explanation:
sorry I cant help because I am just a first former
g Consider a (12.5 A) cm long metal bar moving horizontally across a vertical magnetic field at a speed of (2.40 B) m/s. The magnetic field strength is 2.45 T. If the ends of the bar are connected to a (1.20 C) ohm resistor, find the power dissipated in the resistor while the bar is moving. Calculate the answer in watts (W) and rounded to three significant figures.
Answer:
Explanation:
emf due to movement of a rod of length L in a perpendicular to magnetic field B with velocity v is given as
emf = BLv
Putting in the given values ,
E = 2.45 x 12.5 x 10⁻² x 2.4
= .735 V
This emf produces current in resistance . Power consumed by resistance
V² / R where R is resistance , V is emf induced .
Power = .735² / 1.2
= .45 W .