Soap bubbles can display impressive colors, which are the result of the enhanced reflection of light of particular wavelengths from the bubbles' walls. For a soap solution with an index of refraction of 1.29, find the minimum wall thickness that will enhance the reflection of light of wavelength 709 nm in air.

Answers

Answer 1

Answer:

The value is  [tex]t = 1.374 *10^{-7} \ m[/tex]

Explanation:

From the question we are told that

   The refractive index is  [tex]\mu = 1.29[/tex]

    The wavelength is [tex]\lambda = 709 \ nm = 709 *10^{-9} \ m[/tex]

Generally the condition for constructive interference is  

          [tex]2 * \mu * t = (n - \frac{1}{2} )\lambda[/tex]

At minimum thickness(t)  the order of the fringe(n) will be equal to   1

So

         [tex]2 * 1.29 * t = (1 - \frac{1}{2} )* 709 *10^{-9}[/tex]

=>       [tex]t = 1.374 *10^{-7} \ m[/tex]


Related Questions

Velocity ratio of single movable pulley is 2 when Velocity ratio of single fixed pulley is 1. why​

Answers

Answer:

Velocity ratio of single pulley = 2

Explanation:

Given:

Tension T

Distance = T + T = 2T

Find:

Velocity ratio of single pulley

Computation:

Velocity ratio of single pulley = Total distance / Distance effort

Velocity ratio of single pulley = 2T / T

Velocity ratio of single pulley = 2

g A 240-kg merry-go-round in the shape of a uniform, solid, horizontal disk of radius 1.50 m is set in motion by wrapping a rope about the rim of the disk and pulling on the rope. What constant force would have to be exerted on the rope to bring the merry-go-round from rest to an angular speed of 0.600 rev/s in 2.00 s

Answers

Answer:

339.3 N

Explanation:

First, we start by converting the units.

1 rev/s = 2π rad/s, so

0.6 rev/s = 2π * 0.6 rad/s

0.6 rev/s = 1.2π rad/s

0.6 rev/s = 3.77 rad/s

Now we apply the equation of motion,

W(f) = w(o) + αt

3.77 = 0 + α * 2

3.77 = 2α

α = 3.77/2

α = 1.885 rad/s²

Torque = I * α

Torque = F * r

This means that

I * α = F * r, where I = 1/2mr²

Substituting for I, we have

1/2mr²α = F * r, making F the subject of formula, we have

F = 1/2mrα, then we substitute for the values

F = 1/2 * 240 * 1.5 * 1.885

F = 678.6 / 2

F = 339.3 N

what is the best inference for the speed of the car after 3 seconds

Answers

Answer:

B. 17m/s

Explanation:

This question contains a graph that illustrates the relationship between the speed of a car over time. The graph shows that one can make an inference of the amount of time it takes for the car to cover a particular speed and vice versa.

In this case, after 3 seconds, the speed of the car will be 17 m/s. This inference was got by tracing the position of 3s in the x-axis to the value on the y-axis. Doing this, the best inference for the speed of the car after 3 seconds is 17m/s.

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