Simplify the expression below

12 / 3/5
(12 divided by 3/5)

Step-by-step explanation:

Answer: -40

Step-by-step explanation:

Answer:I think it’s 33.33%? Not 100% sure but I hope it helps!

Step-by-step explanation:

Answer:

23/6

Step-by-step explanation:

3/56

Answer:

1,728 yd²

Step-by-step explanation:

Area = b × h

36 yd will be the replacement for b

48 yd will be the replacement for h

Now we multiply 36 by 48

36 × 48 = 1,728 yd²

Answer:

1728

Step-by-step explanation:

Answer:

Hello

Step-by-step explanation:

Answer:

1 - 155 +27n

2- 2x+15=33

Step-by-step explanation:

hope this helps

Answer:

-x

Step-by-step explanation:

Answer:

9 hours with no stops

Step-by-step explanation:

540 mile drive  

60 MPH

distance divided by rate is 540 divided by 60 = 9

Answer:

351 Students

Step-by-step explanation:

First Find 57% of 817

817 x .57 = 465.69

Then subract that from how many students attend the school now(817)

817- 465.69= 351. 31

Answer = 351 Students

I can't see the picture, can you please explain the problem in the comment bar below this so can edit my answer to help?

Answer:

Rip i saw you said times up :/

Step-by-step explanation:

Answer:

D

Step-by-step explanation:

there are data values from 17-26

so D

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Answer:

B

Step-by-step explanation:

Answer:

35 squared plus x squared equals 78 Squared

which makes your answer

69.7

Step-by-step explanation:

Answer:

35 square + x square 78 square

= 69.7

Step-by-step explanation:

Answer:

[tex]f(x) = 3^x[/tex] --- Function A

[tex]f(x) = x^2 - 5[/tex] --- Function B

[tex]f(x) = 18x -6[/tex] --- Function C

Step-by-step explanation:

Solving (a): Equation of Function A

An exponential equation is represented as:

[tex]y = ab^x[/tex]

From the graph of function A,

[tex]x = 0\ when\ y = 1[/tex]

[tex]x = 1\ when\ y = 3[/tex]

For: [tex]x = 0\ when\ y = 1[/tex]

[tex]y = ab^x[/tex] becomes

[tex]1 = ab^0[/tex]

[tex]1 = a[/tex]

[tex]a =1[/tex]

For: [tex]x = 1\ when\ y = 3[/tex]

[tex]y = ab^x[/tex] becomes

[tex]3 = a*b^1[/tex]

[tex]3 = a*b[/tex]

Substitute 1 for a

[tex]3 = 1*b[/tex]

[tex]3 = b[/tex]

[tex]b = 3[/tex]

[tex]y = ab^x[/tex] becomes

[tex]y = 1*3^x[/tex]

[tex]y = 3^x[/tex]

Replace y with f(x)

[tex]f(x) = 3^x[/tex]

Solving (b): Equation of Function B

A quadratic equation is represented as:

[tex]y = ax^2 + bx + c[/tex]

From the table of function B,

[tex]x = 3\ when\ y =4[/tex]

[tex]x = 5\ when\ y =20[/tex]

[tex]x = 6\ when\ y =31[/tex]

For: [tex]x = 3\ when\ y =4[/tex]

[tex]y = ax^2 + bx + c[/tex] becomes

[tex]4 = a*3^2 + b*3 + c[/tex]

[tex]4 = a*9 + 3b + c[/tex]

[tex]4 = 9a + 3b + c[/tex]

For [tex]x = 5\ when\ y =20[/tex]

[tex]y = ax^2 + bx + c[/tex] becomes

[tex]20 = a*5^2 + b*5 + c[/tex]

[tex]20 = a*25 + b*5 + c[/tex]

[tex]20 = 25a + 5b + c[/tex]

For [tex]x = 6\ when\ y =31[/tex]

[tex]y = ax^2 + bx + c[/tex] becomes

[tex]31 = a*6^2 + b*6 + c[/tex]

[tex]31 = a*36 + b*6 + c[/tex]

[tex]31 = 36a + 6b + c[/tex]

So, we solve for a, b and c in:

[tex]4 = 9a + 3b + c[/tex]

[tex]20 = 25a + 5b + c[/tex]

[tex]31 = 36a + 6b + c[/tex]

Make c the subject in [tex]4 = 9a + 3b + c[/tex]

[tex]c = 4 - 9a - 3b[/tex]

Substitute [tex]c = 4 - 9a - 3b[/tex] in [tex]20 = 25a + 5b + c[/tex] and [tex]31 = 36a + 6b + c[/tex]

[tex]20 = 25a + 5b + c[/tex] becomes

[tex]20 = 25a + 5b + 4-9a-3b[/tex]

Collect Like Terms

[tex]-4+20 = 25a -9a+ 5b -3b[/tex]

[tex]16 = 16a+ 2b[/tex]

Divide through by 2

[tex]8 = 8a + b[/tex]

[tex]c = 4 - 9a - 3b[/tex]

[tex]31 = 36a + 6b + c[/tex] becomes

[tex]31 = 36a + 6b + 4 - 9a - 3b[/tex]

Collect Like Terms

[tex]-4+31 = 36a - 9a+ 6b - 3b[/tex]

[tex]27 = 27a+ 3b[/tex]

Divide through by 3

[tex]9 = 9a + b[/tex]

Solve for a and b in: [tex]8 = 8a + b[/tex] and [tex]9 = 9a + b[/tex]

Subtract both equations:

[tex]8 - 9 = 8a - 9a + b - b[/tex]

[tex]8 - 9 = 8a - 9a[/tex]

[tex]-1 = -a[/tex]

Divide both sides by -1

[tex]1 = a[/tex]

[tex]a = 1[/tex]

Substitute 1 for a in [tex]9 = 9a + b[/tex]

[tex]9 = 9*1 + b[/tex]

[tex]9 = 9 +b[/tex]

Subtract 9 from both sides

[tex]9-9=9-9+b[/tex]

[tex]0=b[/tex]

[tex]b = 0[/tex]

Substitute [tex]b = 0[/tex] and [tex]a = 1[/tex] in [tex]c = 4 - 9a - 3b[/tex]

[tex]c = 4 - 9*1-3*0[/tex]

[tex]c = 4 - 9-0[/tex]

[tex]c = -5[/tex]

So, the equation is:

[tex]y = ax^2 + bx + c[/tex]

[tex]y=1*x^2 +0*x-5[/tex]

[tex]y=x^2 -5[/tex]

Replace y with f(x)

[tex]f(x) = x^2 - 5[/tex]

Solving (c): Equation of Function C

This is calculated using:

[tex]f(x) =a + (x -1)d[/tex]

Where

[tex]a = 12[/tex] -- the first term

d = the difference between successive terms

[tex]d = 30 -12 = 48-30 = 66 -48[/tex]

[tex]d =18[/tex]

So, we have:

[tex]f(x) =a + (x -1)d[/tex]

[tex]f(x) = 12 + (x - 1)*18[/tex]

Open bracket

[tex]f(x) = 12 + 18x - 18[/tex]

Collect Like Terms

[tex]f(x) = 18x - 18+12[/tex]

[tex]f(x) = 18x -6[/tex]

Answer:

17.08

Step-by-step explanation:

From the values in the statistical data we have;

The possible given data in question, are as follows;

[tex]\begin{array}{cccc}1\frac{3}{4} &2\frac{1}{2} &2&2\frac{3}{4} \\\\1&1\frac{3}{4} &1\frac{1}{4} &3\\\\3\frac{1}{4} &3\frac{3}{4} &2&2\end{array}\right][/tex]

From the data, we have;

The most amount of time spent = [tex]3\frac{3}{4}[/tex]

The least amount of time spent = 1

Therefore;

The most amount of time is [tex]3\frac{3}{4} \times 1[/tex] = [tex]3\frac{3}{4}[/tex] times the least amount of time

Second part;

The number of students that spent less than [tex]2\frac{1}{2}[/tex] = 7

The number of students that spent [tex]2\frac{1}{2}[/tex] or more = 5

The number of students in the survey = 12

Therefore, more than half the students spent less than [tex]\mathbf{2\frac{1}{2}}[/tex] hours on homework

Learn more about analysis of statistical data here:

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Answer:

x+40 or 40+x

Step-by-step explanation:

It doesn't tell you the amount of money she's saved before so you make it a variable. I used x.

After mowing she got $40 and decided to add that to her savings.

You already know her savings before, x, and now you have $40.

So you end up writing the expression x+40 or 40+x.

Answer:

I'm sorry but I was doing it in my notebook and no and it came out a proper answer and well I'm not going to answer something that this bad I don't like to look bad the truth I thought was going to be easier but I couldn't do it I hope that another volunteer arrives and helps you and give you a better answer I will tell you what was my answer I think is not going to be bad 45.90

Step-by-step explanation:

Answer:

This is a triangular prism

Step-by-step explanation:

Based on the model, we find the dimensions of the cube. The length of the model building is 2/3 centimeter. The width of the model building is 1/3 centimeter. The height of the model building is 1/2 centimeter. The volume of the model building is 1/9 cubic centimeter.

A cube is 3- dimensional shape with 6 equal sides, 6 faces, and 6 vertices in geometry. Each face of a cube is a square. In 3 – dimension, the cube’s sides are; the length, width, and height. Sides of a cube are all equal i.e. Length = Width = Height = a.

The length = breadth = height (of one cube) = 1/6 cm

The length of the model consist of 4 cubes.

Length of model building = 4 * 1/6 cm = 2/3 cm

The width of the model consist of 2 cubes.

Width of model building = 2 * 1/6 cm = 1/3 cm

The height of the model consist of 3 cubes.

Height of model building = 3 * 1/6 cm = 1/2 cm

Volume of the model (cuboid) =

= Length * breadth * height

= [tex]\frac{2}{3} * \frac{1}{3}*\frac{1}{2} = \frac{1}{9}[/tex]

Learn more about dimensions of a cube here

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