seth put $500 in his savings account, which earns a earns a simple interest rate of 4%

A. use the simple interest equation ( I=Prt ) to find out how much interest seth earns after 6 years.
B. now find out how much interest seth wold earn if he were to earn 7% compound interest for 6 years

Someone help me out :)

Answers

Answer 1

Answer:  sorry i dont know this

Step-by-step explanation:


Related Questions

PLEASE HELP DUE IN 5 MINUTES!! NO LINKS! HELP PLEASE!!

Answers

Answer:

Step-by-step explanation:

its about 263.08!

Answer: about 263.08 sq meters (choice C)

====================================================

Explanation:

We'll use this formula

S = (x/360)*A

where,

S = area of pie slice, aka sectorx = central angle in degreesA = area of full circle

We'll plug in S = 85.5 and x = 117 to find solve for A.

S = (x/360)*A

85.5 = (117/360)*A

85.5*(360/117) = A

A = 85.5*(360/117)

A = 263.076923076923 which is approximate

A = 263.08 square meters (choice C)

------------

Side note: As the formula suggests, the x/360 portion is the fractional portion of the full area A. For example, if x = 180 degrees, then x/360 = 180/360 = 1/2, meaning we'll take half of the full circle area to get S.

sushmila is buying Mehdi supplies

Answers

Answer:

3(p - 5) + 2s should be the correct answer!

Step-by-step explanation:

3 henna powder, and you get $5 off each henna powder so equation is 3(p - 5)

2 bottle so, 2s

add them up and get the answer

Anyways, hope this helped!

Ken recorded the weights (in pounds) of 78 boxes. He created a box plot of his data. What is the interquartile range of Ken’s data?

A) 8

B) 10

C) 17

D) 48

Answers

The answer is d 48 I just took the test

The interquartile range(IQR) of the recorded weight of ken is calculated as 17 pounds.

What is the interquartile range of a data?

The interquartile range(IQR) = third quartile(Q3) - first quartile(Q1)

The third quartile of in the box plot given is : 56 pounds

The third quartile of the data as represented in the box plot given :

39 pounds

The interquartile range(IQR) of ken's data = 56 - 39

= 17 pounds

Hence, The interquartile range(IQR) of the recorded weight of ken is calculated as 17 pounds.

Find more information about the interquartile range here

https://brainly.com/question/4102829

#SPJ2

the radius of a circle is 14.2 m. Find the circumference to the nearest tenth.​

Answers

Answer:

C=89.2

Step-by-step explanation:

The formula of the circumference of a circle is C=2piR (or C=piD). Now, when calculating, plug in the numbers, giving you C=2pi14.2. Multiply everything, you get a super long irrational number; just round. You will get 89.2.


Imani is a scientist working with a cylindrical beaker. The base of the right cylinder has a diameter of 19 cm. She fills the
beaker with 2256.254 Cms of an acid. Approximately how high did the acid fill up the beaker?

Answers

Answer:

7.96 cm

Step-by-step explanation:

radius of bottom: 19/2 = 9.5

area of bottom = pi * r^2 = 283.53

height * base area = volume

What is the value of X?

Answers

Answer:

16

Step-by-step explanation:

AB = BC    

32[tex]\sqrt{2}[/tex] = [tex]\sqrt{2 *AB^{2} } \\ => AB = 32 = BC\\x= BC/2 => x = 32/ 2 = 16[/tex]

The following pie chart represent the number of valid votes by four students the total no of voters is 720. A) who has won and by how many votes B) who got the minimum c) how man votes are obtained
Plz hurry plz I need urgently

Answers

Answer:

I only know this much.....

A) Deepthi has won the election.

B) Rashmi got minimum number of votes.

NEED HELP HERE PLEASE!! π∆π

Give the value of the six trigonometric ratios in the figure.​

Answers

Answer:

Step-by-step explanation:

take theta as reference angle

using sin rule

sin theta=opposite/hypotenuse

sin theta=3/5

sin theta=0.60

theta=sin 37 degree

therefore the value of theta is 37 degree.

Find the HCF of 12 and 16 ​

Answers

Answer:

4  Hope that helped

The answer is four please tell me if this helped

What is the arc length of PQ?

Answers

Answer:

43.9823

Step-by-step explanation:

[tex]Arc length = 2\pi r(\frac{0}{360} )\\ = 2\pi 12(\frac{210}{360} )[/tex]

74,308 Problem: Round the number above to the nearest ten.

Answers

Answer:

74,310

Hope this helped! ^^

Answer:

[tex] = 74,310[/tex]

step by step explanation:

Find the value of x and y.

Answers

Answer:

x=34[tex]\sqrt{2}[/tex]

y=34[tex]\sqrt{3}[/tex]

Step-by-step explanation:

Solve the triangle for all missing sides and angles

Answers

Answer:

a=9

c= 17.5

angles: a =31, b =59, c =90

Step-by-step explanation:

a:

tan (31) = a/15 *cross multiply*

a = 15 (tan (31))

a = 9

c:

*use pythagorean theorum*

9^2 + 15^2 = c^2

81 + 225 = c^2

306 = c^2

17.5 = c

Answer:

B = 59

a = 9.01

c = 17.49

Step-by-step explanation:

Angle B

180 - 90 - 31 = 59

c

The sine of an angle is equal to the ratio of the opposite side to the hypotenuse.

sin(B)=opp/hyp

sin(B)=15/c

sin(59)=15/c

c=15/sin(59)

c=17.49

Find the last side of the triangle using the Pythagorean theorem.

[tex]a^{2} +b^{2} =c^{2} \\a^{2} +15^{2} =17.49^{2} \\\\a^{2} =17.49^{2} -15^{2}\\a=9.01[/tex]

Help plz math question. EXPLAIN HOW YOU GOT THE ANSWER. 30 PTS btw thx if u help

Answers

Answer:

256

Step-by-step explanation:

4^4^4 = 4^(4^4) = 4^256

so written in base 4, there will be 256 zeroes after a 1.

This translates to approximately 154 digits in decimal.

Just like 2^2^2 =  2^4

there will be four zeroes after a 1.

2^2^2=2^(2^2) = 2^4 = 16 = 10000 (16 in base 2).

A Dilation has a center (0,0). Find the image of this point for the given scale factor: P (2-4); D 0.5 (P)

Answers

Answer:

(1, -2)

Step-by-step explanation:

The dilation that has a center of (0, 0) means that you would multiply each number in your coordinate point by your given scale factor.

For your given point (2, -4) with a scale factor of 0.5:

2 times 0.5 = 1

-4 times 0.5 = -2

Therefore your new point will be (1, -2).

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