Mathematics College

In Δ Q R S s = 7.9 cm ∠ Q = 125 ∘ and ∠ R = 23 ∘ '. Find the length of q, to the nearest 10th of a centimeter.

Answer- 12.2

Answers

Answer 1

Answer:

See the attachment ⬆️⬆️

In Q R S S = 7.9 Cm Q = 125 And R = 23 '. Find The Length Of Q, To The Nearest 10th Of A Centimeter.

Related Questions

a serving of crackers has 1.5 grams of fat. How many grams of fat are in 3.75 servings

Answers

Answer:

5.625

Step-by-step explanation:

You just have to multiply 1.5 by 3.75 which is 5.625.

So there are 5.625 grams of fat in 3.75 servings.

5.625 grams of fat are in 3.75 servings.

You just have to multiply 1.5 by 3.75 which is 5.625.

So there are 5.625 grams of fat in 3.75 servings.

What is a Unitary method?

The unitary method is a technique for solving a problem by first finding the value of a single unit, and then finding the necessary value by multiplying the single unit value.

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Mars is on average 2.25 x 108 miles away from Earth. The moon is on average 2.388 x 105 miles away from Earth. Approximately how many times
farther is Mars from Earth than the moon is ?

A.0.94 times
B.9.4 times
C.94 times
D.940 times

Answers

Answer:

I believe the answer is D

Step-by-step explanation:

Mars is approximately 940 times farther away from Earth than the Moon.

What is the division operation?

In mathematics, divides left-hand operands into right-hand operands in the division operation.

Mars is on average 2.25 x 10⁸ miles away from Earth.

The moon is on average 2.388 x 10⁵ miles away from Earth.

To calculate the answer, we need to divide the distance from Mars to Earth by the distance from the Moon to Earth. This gives us:

2.25 x 10⁸ miles / 2.388 x 10⁵ miles = 942.42

Rounded to the nearest whole number, this means that Mars is approximately 940 times farther away from Earth than the Moon is.

Therefore, the answer is D) 940 times.

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Integrate Sin(3x)Cos(3x) dx

Answers

Answer:

[tex]I = \frac{1}{6}\cdot \sin^{2} 3x + C[/tex]

Where [tex]C[/tex] is the integration constant.

Step-by-step explanation:

We use integration by substitution to obtain the integral, where:

[tex]u = \sin 3x[/tex], [tex]du = 3\cdot \cos 3x\,dx[/tex]

[tex]I = \int {\sin 3x\cdot \cos 3x} \, dx[/tex]

[tex]I = \frac{1}{3} \int {u} \, du[/tex]

[tex]I = \frac{1}{6}\cdot u^{2} + C[/tex]

[tex]I = \frac{1}{6}\cdot \sin^{2} 3x + C[/tex]

Where [tex]C[/tex] is the integration constant.

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