An airplane is flying with velocity of 70km\hr in north east direction .The wind is blowing 30km\hr from north to south.What is the resultant displacement of the aeroplane in 4 h
Answer:
The resultant displacement of the airplane in 4 hours is 212.8 km.
Explanation:
The components of the airplane's velocity and wind's velocity are:
Airplane:
[tex] v_{a_{x}} = v_{a}cos(45) = 70 km/h*cos(45) = 49.50 km/h [/tex]
[tex] v_{a_{y}} = v_{a}sin(45) = 70 km/hsin(45) = 49.50 km/h [/tex]
Wind:
[tex] v_{w_{x}} = 0 [/tex]
[tex] v_{w_{y}} = v_{w} = -30 km/h [/tex]
Now, to know the new velocity of the airplane we to find the result vector:
[tex] v_{x} = v_{a_{x}} + v_{w_{x}} = 49.50 km/h + 0 = 49.50 km/h [/tex]
[tex]v_{y} = v_{a_{y}} + v_{w_{y}} = 49.50 km/h - 30 km/h = 19.50 km/h[/tex]
Now, the magnitude of the new speed of the airplane is:
[tex] v_{a} = \sqrt{v_{x}^{2} + v_{y}^{2}} = \sqrt{(49.50 km/h)^{2} + (19.50 km/h)^{2}} = 53.20 km/h [/tex]
Finally, after 4 hours the resultant displacement of the airplane is:
[tex] x = v*t = 53.20 km/h*4 h = 212.8 km [/tex]
Therefore, the resultant displacement of the airplane in 4 hours is 212.8 km.
I hope it helps you!
A car of mass 1470 kg is on an icy driveway
inclined at an angle of 40◦. The acceleration of gravity is 9.8 m.
If the incline is frictionless, what is the acceleration of the car Answer in units of m/s
Answer:
a = 7.5 m / s²
Explanation:
For this exercise let's use Newton's second law, let's create a coordinate system with the x axis parallel to the plane and the y axis perpendicular to the plane
Y axis
N - W cos θ = 0
N = mg cos θ
X axis
W sin θ = m a
mg sin θ = m a
a = g sin θ
let's calculate
a = 9.8 cos 40
a = 7.5 m / s²
what are the Standard System of unit
Answer:
SI
Explanation:
F = M x G
Find the force of gravity acting upon a 1500Kg Hippopatamus.
Answer:........... .. .....
Please help me out if you want brainliest !!!!! ASAP easy
Answer:
Road A = 8 meters Wet
Road B = 2 meters Muddy
Road C = 12 meters Dry
Explanation:
Question 13 (1 point)
The genetic material of an offspring of sexually reproducing organisms is best described as-
a
Ob
identical to that of the other offspring
a copy of the genetic material of the father.
a copy of The genetic material of the mother
genes from both parents, in unique combinations
ос
Od
The genetic material of an offspring of sexually reproducing organisms is best described as genes from both parents in unique combinations.
SEXUAL REPRODUCTION:
Sexual reproduction is a type of reproduction that involves two organisms (a male and a female). The male organism produces a gamete called SPERM while the female organism produces a gamete called EGG. The gametes are produced via a process called MEIOSIS. Meiosis is a process of cell division whereby genetically different daughter cells are produced. The genetic variation is attributed to a process called crossing over, which is the exchange of genetic material between non-sister chromatids of homologous chromosomes. At the end of the fertilization process between male sperm and female egg, the genetic material of the offspring will contain genes from both parents in unique combinations.Learn more at: https://brainly.com/question/11622266?referrer=searchResults
What is the voltage drop across the 10.0 Ω resistor?
Answer:
its 120 C
Explanation:
its 120 C
The voltage drop across the 10.0 Ω resistor is c)120V
What is voltage drop in a circuit ?Voltage drop is the decrease of electrical potential along the path of a current flowing in an electrical circuit.
since , all three resistors 10Ω , 20 Ω and 30Ω are in series combination
this implies that voltage drop across each resistor will be same as the total voltage drop in the circuit because in parallel combination voltage remain same in the circuit buy current get divided in each branch
hence , the voltage drop across the 10.0 Ω resistor = 120 V
correct answer c) 120 V
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Two forces of magnitude 40N and 70N acts on an object calculate and write the resultant force acting on the object and the resultant a
direction of force when both the force act in opposite direction
A) 70N in the direction of lesser force
B) 110N,opposite direction
C) 30N,in the direction of the greater force
D) 30N in the direction of lesser force
Explanation:
Required Answer70N-40N=30N
30N in lesser forceCan someone please help me with this, this question goes with my second most recent question.
The ship will speed up while the engine is firing.
Whatever speed it has when the engine cuts off, it will continue at that speed (and in a straight line) from then on, because there's no force acting on it, so it can't have any acceleration.
That's the 3rd choice.
If a rock is dropped from the top of a tower at the front of it and takes 3.6 seconds to hit the ground. Calculate the final velocity of the penny in m/s. What is the height of the tower?
Answer:
35.28m/s; 63.50m
Explanation:
Given the following data;
Time, t = 3.6 secs
Since it's a free fall, acceleration due to gravity = 9.8m/s²
Initial velocity, u = 0
To find the final velocity, we would use the first equation of motion;
[tex] V = u + at[/tex]
Substituting into the equation, we have;
[tex] V = 0 + 9.8 * 3.6[/tex]
V = 35.28m/s
Therefore, the final velocity of the penny is 35.28m/s.
To find the height, we would use the second equation of motion;
[tex] S = ut + \frac {1}{2}at^{2}[/tex]
Substituting the values into the equation;
[tex] S = 0(3.6) + \frac {1}{2}*9.8*(3.6)^{2}[/tex]
[tex] S = 0 + 4.9*12.86[/tex]
[tex] S = 0.5 *36[/tex]
S = 63.50m
Therefore, the height of the tower is 63.50m.
help!
Jerome solves a problem using the law of conservation of momentum. What should
Jerome always keep constant for each object after the objects collide and bounce apart?
velocity
mass
momentum
direction
Answer:
What shouldJerome always keep constant for each object after the objects collide and bounce apart? That would be Mass.
Answer:
B: Mass
Explanation:
please help me very urgent :((
What is the net force (including direction and magnitude) acting on the object on the above left?
What is the net force (including direction and magnitude) acting on the object on the above right?
Answer:
-150 N
Explanation:
(Newton's second law) F=ma
Sum of forces in Y direction= (+200 N)+(-200 N)= 0...
forces cancel, object does not accelerate up/down
Sum of forces in X direction= (+65 N)+(-65 N)+(-150 N)
= -150 N
notice that the +/- 65 components cancel, leaving a net force of 150 N in the LEFTwards direction (which is typically defined as negative)
Overall, the net force is -150 N
How much force must a 40,000 W engine exert to get a car up to 75 m/s?
Edit: Answer - 533N
Answer:
Force = 533.33N
Explanation:
Given the following data;
Power = 40000watt
Velocity = 75m/s
To find the force;
[tex] Power = force * velocity [/tex]
Making force the subject of formula, we have;
[tex] Force = \frac {Power}{velocity}[/tex]
[tex] Force = \frac {40000}{75} [/tex]
Force = 533.33N
What is the net force (including direction and magnitude) acting on the object on the above left?
Answer:
Explanation:
the net force on the right left is 25 N and is directed upward
the net force on the left one is zero because 200N force act upward and 200N force act downward so both cancel each other and net force is zero
i hope this will help you
The net force on the right left is 25 N and is directed upward.
The net force on the left one is zero because 200 N force act upward and 200 N force act downward so both cancel each other and net force is zero.
What is force?A force is an effect that can alter an object's motion according to physics. An object with mass can change its velocity, or accelerate, as a result of a force. An obvious way to describe force is as a push or a pull. A force is a vector quantity since it has both magnitude and direction.
By looking at both figure we get idea of net force after calculation,
The net force on the right left is 25 N and is directed upward.
The net force on the left one is zero because 200 N force act upward and 200 N force act downward so both cancel each other and net force is zero.
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Christina drives her moped 7 kilometers North. She stops for lunch and then drives 5 kilometers East.
What distance did she cover? Please include the number and unit.
What was the magnitude of her displacement? Please include the number and unit.
What was the direction of her displacement? Please abbrieviate (N, S, E, W, etc.)
Explanation:
Given that,
Christina drives her moped 7 kilometers North. She stops for lunch and then drives 5 kilometers East. At first she traveled North and then East. They are perpendicular to each other.
Total path traveled = distance covered by an object
D = 7 km + 5 km = 12 km
Shortest path covered = Displacement
[tex]d=\sqrt{7^2+5^2} \\\\d=8.6\ km[/tex]
For direction :
[tex]\tan\theta=\dfrac{d_y}{d_x}\\\\\tan\theta=\dfrac{7}{5}\\\\\theta=\tan^{-1}(\dfrac{7}{5})\\\\\theta=54.46^{\circ}[/tex]
She is moving in the direction of 54.46 degrees.
A truck accelerates from 25 km/hr to 45 km/hr in 40 seconds. Calculate the average acceleration of the vehicle in m/s?.
Answer:
0.138889 m/s2
Explanation:
The average acceleration of the vehicle would be 0.139 meters/second².
What is acceleration?The rate of change of the velocity with respect to time is known as the acceleration of the object.
As given in the problem a truck accelerates from 25 kilometers/hour to 45 kilometers/hour in 40 seconds.
Let us first convert the velocities from kilometers/hour to meters/seconds
25 kilometers/hour ⇒ 25×1000/3600
= 6.94 meters/seconds
45 kilometers/seconds = 45×1000/3600
= 12.5 meters/seconds
acceleration = change in the velocity/time
=(12.5 -6.94)/40
=0.139 meters/second²
Thus, the acceleration of the truck would be 0.139 meters/second²
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Find the horizontal and vertical components of 75.0 N at 65 degrees
Horizontal component = 75 · cosine(65°) = 31.7 N
Vertical component = 75 · sine(65°) = 68.0 N
Identify the 3 types of energy transfer shown in the diagram.
Answer:
1.Conduction.
2.Convection.
3.Radiation.
Explanation:
I'm sure it's correct
A car is driving down the road at 35 m/s when the driver slams on the brakes. The car stops in a distance of 75 meters. The braking force necessary to do this is 9,800 Newtons. How much work do the brakes perform stopping the car?
Answer:
If the car is initially travelling at u m/s, then the stopping distance d m travelled by ... the speed of the car at the instant the brakes are applied. ... Common usage will force us to depart from this later in the notes. ... The history of these equations is not absolutely clear, but we do have some ... Newton (1642–1727) and Leibniz.
Explanation:
hope this helped
the velocity of a car changes from 5 m/s to 20 m/s in 30 sec the acceleration?
Answer:
0.5m/s2
..............
A car traveling at 25 m/s speeds up to 30 m/s over a period of 5 seconds. The average acceleration of the car is?
Answer:
a= 1 m/s^2
Explanation:
Average acceleration can be found by dividing the change in velocity by the time.
a= ΔV/t
The change in velocity is the difference of the final velocity and initial velocity.
ΔV= final velocity - initial velocity
The final velocity is 30 m/s and the initial velocity is 25 m/s
ΔV= 30 m/s- 25 m/s
ΔV= 5 m/s
The time is 5 seconds.
Now we know the two values.
ΔV= 5 m/s
t= 5 s
Substitute the values into the formula.
a= 5 m/s / 5 s
Divide.
a= 1 m/s/s
a= 1 m/s^2
The average acceleration of the car is 1 meter per second squared.
A motorbike is traveling to the left with a speed of 27.0 m s 27.0 s m 27, point, 0, start fraction, start text, m, end text, divided by, start text, s, end text, end fraction when the rider slams on the brakes. The bike skids 41.5 m 41.5m41, point, 5, start text, m, end text with constant acceleration before it comes to a stop. What was the acceleration of the motorbike as it came to a stop?
Answer:
Explanation:
Initial velocity , u = 27 m/s
displacement before stop, s = 41.5 m .
final velocity, v = 0
acceleration a = ?
v² = u² + 2 a s
0 = 27² + 2 x a x 41.5
a = - 27² / 2 x 41.5
= - 8.78 m /s
How did einstines and Newton’s theory’s differ in terms of explaining the cause of gravity
Answer: in the Newton concluded that objects fall because they are pulled by Earth's gravity. Einstein's interpretation was that these objects do not fall.
Explanation: These objects and Earth just freely move in a curved spacetime and this curvature is induced by mass and energy of these objects. - I HOPE THAT HELPED!!
state three ways of conserving energy
energy drinks
sitting
watching TV
Answer:
use natural lights
turn off electrical appliances..if not in use
check your wires every next Month
When we describe both the speed and direction of motion, we are
descriting its acceleration.
True
False
Answer:
True
Explanation:
Acceleration measures how much the ___________ of an object changes over time.
a) velocity
b) location
Answer: velocity
Explanation: v/t
In a drag race, a car takes off from rest and covers 375 meters in 5 seconds. What is the
final velocity?
Explanation:
s = ut + 1/2 a t^2
375 = 0 * 5 + 1/2 * a * (5)^2
375 = 1/2 * a * 25
a = 375*2/25
a = 15* 2
a = 30m/sec^2
v = u + at
v = 0 + 30 * 5
v = 150 m/sec
hope it helps you
Can you please help I’m sorry I promise this is the last time
Answer:
?
Explanation:
Definition of uniform speed
Answer:
Uniform Speed: A body is said to be moving with uniform speed, if it covers equal distances in equal intervals of time. Variable Speed: A body is said to be moving with variable speed if it covers unequal distances in equal intervals of time.
Explanation:
I got it from google
Answer:
Speed is a measure of how fast an object is moving at a given instant of time. It is a scalar quantity. Its unit is m/s. For a body covering equal distances in equal time intervals, the speed is called uniform speed.
Explanation:
A motorcyclist sees a branch in the road and hits the brakes, slowing down at -6.42 m/s. if it takes him 2.85 seconds to stop, what was his starting velocity?
Use the definition of average acceleration:
a = ∆v / t
If v is the starting speed, then ∆v = 0 - v, so solve for v :
-6.42 m/s² = (0 - v) / (2.85 s)
v = (6.42 m/s²) (2.85 s)
v ≈ 18.3 m/s