Answer:
Sebastian should have used –9 and 7.
Step-by-step explanation:
Sebastian went up 7 floors not down so it should be 7 and then he went down 9 floors so it should be 7-9
Answer:
A) Sebastian should have used –9 and 7.
The Downtown Parking Authority of Tampa, Florida, reported the following information for a sample of 228 customers on the number of hours cars are parked and the amount they are charged.
Number of Hours Frequency Amount Charged
1 21 $4
2 36 6
3 53 9
4 40 13
5 22 14
6 11 16
7 9 18
8 36 22
228
A. Convert the information on the number of hours parked to a probability distribution. Is this a discrete or a continuous probability distribution?
B. Find the mean and the standard deviation of the number of hours parked. How would you answer the question: How long is a typical customer parked?
C. Find the mean and the standard deviation of the amount charged.
Answer: A. This is a discrete probability distribution.
hours probability
1 0.09
2 0.16
3 0.23
4 0.17
5 0.09
6 0.05
7 0.04
8 0.16
B. E(X) = 4.12; σ = 2.21
C. μ = 12.75; s = 6.11
Step-by-step explanation: Probability Distribution is an equation or table linking each outcome of an experiment with its probability of ocurrence. For this case, since the experiment is performed a high number of times and in a long run, the relative frequency of the event is its probability. Therefore:
A. To convert to a probability distribution, find the probability through the frequency by doing:
Hour 1
P(X) = [tex]\frac{21}{228}[/tex] = 0.09
Hour 2
P(X) = [tex]\frac{36}{228}[/tex] = 0.16
Hour 3
P(X) = [tex]\frac{53}{228}[/tex] = 0.23
Hour 4
P(X) = [tex]\frac{40}{228}[/tex] = 0.17
Hour 5
P(X) = [tex]\frac{22}{228}[/tex] = 0.09
Hour 6
P(X) = [tex]\frac{11}{228}[/tex] = 0.05
Hour 7
P(X) = [tex]\frac{9}{228}[/tex] = 0.04
Hour 8
P(X) = [tex]\frac{36}{228}[/tex] = 0.16
The table will be:
hours probability
1 0.09
2 0.16
3 0.23
4 0.17
5 0.09
6 0.05
7 0.04
8 0.16
This is a discrete distribution because it lists all the possible values that the discrete variable can be and its associated probabilities.
B. Mean for a probability distribution is calculated as:
E(X) = ∑[[tex]x_{i}[/tex].P([tex]x_{i}[/tex])]
E(X) = 1*0.09 + 2*0.16+3*0.23+4*0.17+5*0.09+6*0.05+7*0.04+8*0.16
E(X) = 4.12
Standard Deviation is:
σ = √∑{[x - E(x)]² . P(x)}
σ = [tex]\sqrt{(1-4.12)^{2}*0.09 + (2-4.12)^{2}*0.16 + ... + (7-4.12)^{2}*0.04 + (8-4.12)^{2}*0.16}[/tex]
σ = [tex]\sqrt{4.87}[/tex]
σ = 2.21
The average number of hours parked is approximately 4h with a standard deviation of approximately 2 hours, which means that a typical costumer parks between 2 to 6 hours.
C. Mean for a sample is given by: μ = ∑[tex]\frac{x_{i}}{n}[/tex] , which is this case is:
μ = [tex]\frac{4+6+9+13+14+16+18+22}{8}[/tex]
μ = 12.75
Standard Deviation of a sample: s = √[tex]\frac{1}{n-1}[/tex]∑([tex]x_{i}[/tex] - μ)²
s = [tex]\sqrt{ \frac{(4-12.75)^{2} + (6-12.74)^{2} + ... + (18-12.75)^{2} + (22-12.75)^{2} }{8-1}}[/tex]
s = 6.11
The average amount charged is 12.75±6.11.
Solve for b. -11b+7 = 40 Two step equations
Step-by-step explanation:
-11b + 7 = 40
-11b = 40 - 7
-11b = 33
b = 33/-11
b = - 3
When $\frac{1}{1111}$ is expressed as a decimal, what is the sum of the first 40 digits after the decimal point?
Answer:
90
Step-by-step explanation:
1/1111= 0. (0009) cycles of 0009 after decimal point (one 9 per 4 digits)
Number of digits 9:
40/4= 1010*9= 90Answer:
90
Step-by-step explanation:
Owen gets paid $280 per week plus 5% commission on all sales for selling electronic equipment. If he sells d dollar worth of electronic equipment in one week, which algebraic expression represents the amount of money he will earn in weeks?a. (2800 + 5)w b. 280 +0.05dw c. (280+ 0.050d)w d. 280w +0.050d
Answer:
c. (280+ 0.050d)w
Step-by-step explanation:
Owen gets paid $280 per week
=$280 per week
Plus 5% commission on all sales of electronic equipment
=0.05
If he sells the dollar(d) worth of electronic equipment in one week
=(0.05d)w
Total earnings
=280w+0.05(d)w
Factorise
=(280+0.05d)w
Owen=(280+0.05d)w
c. (280+ 0.050d)w
*0.050=0.05
Danessa needs to compare the area of one large circle with a diameter of 8 to the total area of 2 smaller circles with a diameter one-half that of the large circle. Which statements about the areas are true? Select three options.
The area of the large circle is 16 pi.
The area of one small circle is 4 pi.
The area of one small circle will be one-half of the area of the large circle.
The total area of the two small circles will equal that of the large circle.
The total area of the two small circles will be one-half of the area of the large circle.
Answer:
=>The area of the larger circle is 16π
=>The area of 1 small circle is 4π
=>The total area of the two small circles will be one-half of the area of the large circle
Step-by-step explanation:
To find out which statements are true about the areas of the given circle, let's find out dimensions and areas of the 3 circles:
==>Large circle (A):
diameter = 8
radius (r) = ½ × 8 = 4
Area = πr² = π4² = 16π
Area of Circle A = 16π
==>Small circles (B and C):
Diameter of 1 small circle = ½ of diameter of big circle A
Therefore, d of small circles = ½×8 = 4
Radius of small circles = ½d = ½×4 = 2
Area of the 2 small circles = 2(πr²)
= 2(π2²)
= 2(π4)
Area of 2 small circles = 8π
Area of 1 small circle = 4π
From our calculation the statements that would be true are:
=>The area of the larger circle is 16π
=>The area of 1 small circle is 4π
=>The total area of the two small circles will be one-half of the area of the large circle (8π/16π = ½). I.e. area of 1 big circle is twice that of the total area of the 2 small circles (2 × 8π).
Answer:
A, B, and E
Step-by-step explanation:
I'm doing the exam review hope this helps!
A tire manufacturer is measuring the margin of error in the thickness of their tires to make sure it is within safety limits. Overall, the tires' thickness is normally distributed with a mean of 0.45 inches and a standard deviation of 0.05 inches. What thickness separates the lowest 5% of the means from the highest 95% in a sample size of 65 tires
Answer:
Z = -1.65
[tex]\bar x \approx 0.44 \ inches[/tex]
Step-by-step explanation:
The main objective is to compute the data for the Z value and determine the [tex]\bar x[/tex] of the sample distribution
Given that;
the tires' thickness is normally distributed with a mean μ = 0.45 in
standard deviation σ = 0.05 in
sample size = 65 tires
Also; we are being told that the thickness separates the lowest 5% of the means from the highest 95%
∴
P(Z < Z) =0.05
From the Z- table
P(Z < -1.645) = 0.05
Z = -1.65
Similarly;
Let consider [tex]\bar x[/tex] to be the sample mean;
Then:
mean [tex](\mu_{\bar x}) = \mu = 0.45[/tex]
standard deviation[tex](\sigma_{\bar x} ) = \dfrac{\sigma}{\sqrt{n}}[/tex]
[tex]=\dfrac{0.05}{\sqrt{65}}[/tex]
= 0.00620174
By applying the Z-score formula:
x = μ + ( Z × σ )
[tex]\bar x = \mu _{\bar x} +(Z * \sigma _{\bar x})[/tex]
[tex]\bar x = 0.45 + (-1.65 *0.00620174)[/tex]
[tex]\bar x= 0.439767129[/tex]
[tex]\bar x \approx 0.44 \ inches[/tex]
Microsoft excel was used on a set of data involving the number of defective items found in a random sample of 46 cases of light bulbs produced during a morning shift at a plant. A manager wants to know if the mean number of defective bulbs per case is greater than 20 during the morning shift. She will make her decision using a test with a level of significance of 0.10. The following information was extracted from the microsoft excel output for the sample of 46 cases:
n=46, Arithmetic mean=28.00, Std Dev =25.92, standard error=3.82, Null hypothesis: H0 : u<=20, alpha =0.10, df=45, t-test statistic=2.09, one tail test upper critical value =1.3006, p-value=0.021
i) what parameter is the manager interested in?
ii) state the alternative hypothesis for this study.
iii) what critical value should the manager use to determine the rejection region.
iv) explain if the, null hypothesis should be rejected and why or why not?
v) explain our risk of committing of a type1 error.
vi) explain if the data evidence proves beyond a doubt that the mean number of defective bulbs per case is greater than 20 during the morning shift
vii) what can the manager conclude about the mean number of defective bulbs per case during the morning shift using a level of significance of 0.10?
viii) what would the p-value be if these data were used to perform a two tail test?
Answer:
Step-by-step explanation:
i. The parameter the manager is interested in is number of defective bulbs in a case.
ii. Null hypothesis: u <= 20
Alternative hypothesis: u > 20
iii. The critical value the manager should use to determine the rejection region is 1.645.
iv. Using the p value which is 0.021 at 0.10 significance level we will reject the null as the p value is less than 0.1. Thus, we will conclude that there is enough statistical evidence to prove that the mean number of defective bulbs per case is greater than 20.
v. Our risk of committing type one error is alpha which is the level of significance set for the hypothesis test. An alpha level of 0.1 shows that we are willing to accept a 10% chance that we are wrong when you reject the null hypothesis.
vi. With a low p value, the data has enough evidence to prove that the mean number of defective bulbs per case is greater than 20 during the morning shift
vii. The manager will conclude that there is sufficient statistical evidence to prove that mean number of defective bulbs per case is greater than 20 during the morning shift.
viii. the p value if this is a two tail test would be 0.03662
In Denver, Colorado, they experience a lot of snow in the winter. During the last
snow storm, it snowed for 3 straight days and the snow consistently accumulated at
a rate of inch per hour. How much snow did Denver get over three days?
Your answer
Answer:
Denver got 72 inches of snow over three days.
Step-by-step explanation:
Since it has snowed consistently for 3 days, accumulating an inch of snow per hour, over that number of days at least 72 inches of snow would have accumulated.
This is so because, since each day has 24 hours, in the event of a 3-day snowfall, it would have lasted 72 hours. Thus, while every hour a new inch of snow would accumulate, at the end of the storm the city of Denver would have accumulated 72 inches of snow (1 x 24 x 3 = 72).
I rlly rlly rlly need help! Complete the following proof. Given: Points R, S, T, Q on circle O Prove: m\overarc RS + m\overarc ST + m\overarc TQ + m\overarc RQ
Answer:
[tex]m(\widehat {RS})+m(\widehat{ST})+m(\widehat{TQ}) + m(major\ arc RQ) = 360\ degree[/tex]
Step-by-step explanation:
As we can see in the figure that
The R, S, T ,and Q are the points on the circle O.
Also
The measurement of the circular arc is equivalent to the measurement of the angle at the center of the arc
So by this
[tex]m(\widehat{RS})=m(\angle ROS)[/tex]
[tex]m(\widehat{ST})=m(\angle SOT)[/tex]
[tex]m(\widehat{TQ})=m(\angle TOQ)[/tex]
m(major arc RQ) = m(∠QOR)
So,
[tex]m(\widehat {RS})+m(\widehat{ST})+m(\widehat{TQ}) + m(major\ arc RQ) = m(\angle ROS)+m(\angle SOT)+m(\angle TOQ)+m(\angle QOR)[/tex]
And as we know that
All angles sum = 360°
Therefore
[tex]m(\widehat {RS})+m(\widehat{ST})+m(\widehat{TQ}) + m(major\ arc RQ) = 360\ degree[/tex]
It take Donna 15 minutes to complete 3 levels of Candy Crush. At this rate, how many levels will she complete in 3 hours?
Answer: she will have 36 levels completed
The function h(t) = –16t2 + 28t + 500 represents the height of a rock t seconds after it is propelled by a slingshot.
What does h(3.2) represent?
the height of the rock 3.2 seconds before it reaches the ground
the time it takes the rock to reach the ground, or 3.2 seconds
the time it takes the rock to reach a height of 3.2 meters
the height of the rock 3.2 seconds after it is propelled
Answer:
h(3.2) represents the height of the rock 3.2 seconds after it is propelled. Remember, h(t) represents the height of a rock t seconds after it is propelled.
Answer:
D
Step-by-step explanation:
the height of the rock 3.2 seconds before it reaches the ground
the time it takes the rock to reach the ground, or 3.2 seconds
the time it takes the rock to reach a height of 3.2 meters
the height of the rock 3.2 seconds after it is propelled
4. Rational, irrational (4 points) (1) (2 points) Prove or disprove that if x y is an irrational number, then x or y is also an irrational number. (2) (2 points) Prove that if x 2 is irrational, then x is irrational. (Hint: try a proof by contrapositive)
Answer:
See explanation below
Step-by-step explanation:
1) Prove or disprove that if [tex] x^y[/tex] is an irrational number, then x or y is also an irrational number.
Let's take the following instances:
i) When x= 2 and y=[tex] \sqrt{2} [/tex] we have: [tex] 2^\sqrt^{^2^} [/tex]
ii) When [tex] x=2\sqrt{2} [/tex] and y=3, we have: [tex] (x=2\sqrt{2})^3 [/tex]
iii) When [tex] x=2\sqrt{2} [/tex] and [tex] y = \sqrt{2}[/tex], we have: [tex] (2\sqrt{2})^\sqrt^{^2^}[/tex]
It is proven because, in scenario
i) x is rational and y is irrational
ii) x is irrational and y is rational
iii) x and y are irrational
2) Prove tha x² is irrational, then x is irrational.
Use contradiction here.
Thus, x² is irrational and x is rational.
[tex] x =\frac{b}{a} [/tex] when x is rational, a & b are integers.
Therefore, [tex] x^2 =\frac{b^2}{a^2} [/tex]. This x² is rational.
This contradicts the statement that x² is irrational.
Therefore, if x² is irrational, x is also irrational.
The First National Bank of Wilson has 600 checking account customers. Recent sample of 50 of these customers show 29 have a visa card with the bank. Construct the 90% confidence interval for the proportion of checking account customers who have a visa card with the bank. (Use a Z distribution table0
Answer:
[tex]0.58 - 1.64\sqrt{\frac{0.58(1-0.58)}{50}}=0.466[/tex]
[tex]0.58 + 1.64\sqrt{\frac{0.58(1-0.58)}{50}}=0.694[/tex]
The 90% confidence interval would be given by (0.466;0.694)
Step-by-step explanation:
The estimated proportion of interest would be:
[tex] \hat p=\frac{29}{50}= 0.58[/tex]
In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 90% of confidence, our significance level would be given by [tex]\alpha=1-0.90=0.1[/tex] and [tex]\alpha/2 =0.05[/tex]. And the critical value would be given by:
[tex]z_{\alpha/2}=-1.64, z_{1-\alpha/2}=1.64[/tex]
The confidence interval for the mean is given by the following formula:
[tex]\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}[/tex]
If we replace the values obtained we got:
[tex]0.58 - 1.64\sqrt{\frac{0.58(1-0.58)}{50}}=0.466[/tex]
[tex]0.58 + 1.64\sqrt{\frac{0.58(1-0.58)}{50}}=0.694[/tex]
The 90% confidence interval would be given by (0.466;0.694)
please solve this for me T_T
If
[tex]x - \sqrt{a} [/tex]
is a factor of
[tex]2 {x}^{4} - 2 {a}^{2} {x}^{2} - 3 {x} + 2 {a}^{3} - 2 {a}^{2} + 3[/tex]
then find the value of
[tex]a[/tex]
Answer:
[tex]\boxed{\sf \ a = 1 \ }[/tex]
Step-by-step explanation:
let s assume that a >=0 so that we can take the square root
if [tex]x-\sqrt{a}[/tex] is a factor of this expression it means that [tex]\sqrt{a}[/tex] is a root of it
it comes
[tex]2*(\sqrt{a})^4-2*a^2*(\sqrt{a})^2-3*\sqrt{a}+2*(\sqrt{a})^3-2(\sqrt{a})^2+3=0[/tex]
So
[tex]2*a^2-2*a^3-3*\sqrt{a}+2*a*\sqrt{a}-2*a+3=0[/tex]
we can notice that 1 is a trivial solution as
2-2-3+2-2+3=0
so the answer is 1
let s double check
if a =1
the expression is
[tex]2x^4-2x^2-3x+2-2+3=2x^4-2x^2-3x+3[/tex]
and we can write
[tex]2x^4-2x^2-3x+3=(x-1)(2x^3+2x^2-3)[/tex]
so 1 is the correct answer
finding angle measures between intersecting lines.
Answer:
56
Step-by-step explanation:
to find x u add 60 and 64 which is 124
the total is 180 so u would subtract 180 by 124
hope this helps
What are the zeros of f(x) = x^2 + x - 20?
A. x= -4 and x = 5
B. x= -2 and x = 10
C. x= -5 and x = 4
O D. x= -10 and x = 2
Assume the random variable X has a binomial distribution with the given probability of obtaining a success. Find the following probability, given the number of trials and the probability of obtaining a success. Round your answer to four decimal places. P(X≤2), n=5, p=0.8
Answer:
0.0579
Step-by-step explanation:
P(X≤2) = P(X=0) + P(X=1) + P(X=2)
P(X≤2) = ₅C₀ (0.8)⁰ (0.2)⁵ + ₅C₁ (0.8)¹ (0.2)⁴ + ₅C₂ (0.8)² (0.2)³
P(X≤2) = 0.00032 + 0.0064 + 0.0512
P(X≤2) = 0.0579
Probability of obtaining a success is 0.0579 .
Here,
Binomial distribution formula:
P(x:n,p) = nCx px (1-p)n-x Or P(x:n,p) = nCx px (q)n-x
Substituting the values of n and p
n = 5
p = 0.8
So,
P(X≤2) = P(X=0) + P(X=1) + P(X=2)
P(X≤2) = ₅C₀ (0.8)⁰ (0.2)⁵ + ₅C₁ (0.8)¹ (0.2)⁴ + ₅C₂ (0.8)² (0.2)³
P(X≤2) = 0.00032 + 0.0064 + 0.0512
P(X≤2) = 0.0579
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Need help with this . The picture is enclosed
Answer: (fоg)(24)=5
Step-by-step explanation:
(fоg)(24) is f of g of 24. This means you plug in g(24) into f(x).
[tex]g(24)=\sqrt{24-8}[/tex]
[tex]g(24)=\sqrt{16}[/tex]
[tex]g(24)=4[/tex]
Now that we know g(24), we can plug it into f(x).
f(4)=2(4)-3
f(4)=8-3
f(4)=5
Plz help for 80 points question is attached
Answer:
2 and 256
Step-by-step explanation:
Check the attachment
Answer:
2 and255
Step-by-step explanation:
look atyourquestion
Benny is trying to learn how to ride a bike, but is terrified of falling. He did some research, and discovered that if he rides a bike with training wheels, the probability of falling is 0.1; if he learns to ride a bike by using a bike without training wheels, his probability of falling is 0.5, and if he uses a unicycle, his probability of falling is 0.8. Benny came home crying with a bruise on his knee, after falling. His mom is trying to guess how Benny was trying to learn to ride a bike.
a) Assuming that the probability that Benny was using each of these 3 methods is equal, what is the probability that Benny was learning to ride a bike using the training wheels?
b) Since Benny's mom knows Benny so well, she knows that the probability that he was using training wheels is 0.7, regular bike is 0.2, and unicycle is 0.1. What is the probability now that Benny fell while using the training wheels?
Answer:
a) 7.14% probability that Benny was learning to ride a bike using the training wheels
b) 28% probability that Benny was learning to ride a bike using the training wheels
Step-by-step explanation:
Bayes Theorem:
Two events, A and B.
[tex]P(B|A) = \frac{P(B)*P(A|B)}{P(A)}[/tex]
In which P(B|A) is the probability of B happening when A has happened and P(A|B) is the probability of A happening when B has happened.
Benny came home crying with a bruise on his knee, after falling. His mom is trying to guess how Benny was trying to learn to ride a bike.
a) Assuming that the probability that Benny was using each of these 3 methods is equal, what is the probability that Benny was learning to ride a bike using the training wheels?
So
Event A: Benny fell
Event B: Benny was using training wheels.
The probability that Benny was using each of these 3 methods is equal
This means that [tex]P(B) = \frac{1}{3}[/tex]
He did some research, and discovered that if he rides a bike with training wheels, the probability of falling is 0.1;
This means that [tex]P(A|B) = 0.1[/tex]
Probability of falling:
1/3 of the time, he uses training wheels. With training wheels, the probability of falling is 0.1.
1/3 of the time, he uses the bike without training wheels. Without training wheels, the probability of falling is 0.5
1/3 of the time, he uses the unicycle, for which he has an 0.8 probability of falling. Then
[tex]P(A) = \frac{0.1 + 0.5 + 0.8}{3} = 0.4667[/tex]
So
[tex]P(B|A) = \frac{\frac{1}{3}*0.1}{0.4667} = 0.0714[/tex]
7.14% probability that Benny was learning to ride a bike using the training wheels
b) Since Benny's mom knows Benny so well, she knows that the probability that he was using training wheels is 0.7, regular bike is 0.2, and unicycle is 0.1. What is the probability now that Benny fell while using the training wheels?
Similar as above, just some probabilities change.
Event A: Benny fell
Event B: Benny was using training wheels.
The probability that he was using training wheels is 0.7
This means that [tex]P(B) = 0.7[/tex]
He did some research, and discovered that if he rides a bike with training wheels, the probability of falling is 0.1;
This means that [tex]P(A|B) = 0.1[/tex]
Probability of falling:
0.7 of the time, he uses training wheels. With training wheels, the probability of falling is 0.1.
0.2 of the time, he uses the bike without training wheels. Without training wheels, the probability of falling is 0.5
0.1 of the time, he uses the unicycle, for which he has an 0.8 probability of falling. Then
[tex]P(A) = 0.7*0.1 + 0.2*0.5 + 0.1*0.8 = 0.25[/tex]
So
[tex]P(B|A) = \frac{0.7*0.1}{0.25} = 0.28[/tex]
28% probability that Benny was learning to ride a bike using the training wheels
george cut a cake into 8 equal pieces. what is the unit fraction for the cake
Answer: 1/8
Step-by-step explanation:
Unit Fractions: A unit fraction is a rational number written as a fraction where the numerator is one and the denominator is a positive integer. A unit fraction is therefore the reciprocal of a positive integer, 1/n.
Example of Unit Fractions: 1/1, 1/2, 1/3, 1/4 ,1/5, etc.
Hope this helps! Please mark as brainliest!
The unit fraction of the cake is 1/8
What is a unit fraction?A unit fraction is a rational number written as a fraction where the numerator is one and the denominator is a positive integer.
A unit fraction is therefore the reciprocal of a positive integer, 1/n.
Examples are 1/1, 1/2, 1/3, 1/4, 1/5, etc.
Given that, George cut a cake into 8 equal pieces, we need to find the unit fraction for the cake
Since, George cut the cake in 8 equal pieces so, 1 part will be shown by 1/8 of the cake, that mean 1/8 is one unit of the cake, we can say that 1/8 is the unit of the whole cake.
Hence, the unit fraction of the cake is 1/8
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a circle with radius of 1 cm sits inside a 11 cm x 12 cm rectangle.
Answer:
125.72
Step-by-step explanation:
radius equals pi(r)2
rectangle equals b times h
radius is 6.28
rectangle is 132
you now subtract them
132 minus 6.28 which is 125.72
hope this helps
Answer:
No the other answer is wrong, I just did it, this is the right answer for sure, I will give it right after you subscibe to Iconic Cooking, here is the answer...
Step-by-step explanation:
128.86
Determine whether the following statement is true or false.
To construct a confidence interval about the mean, the population from which the sample is drawn must be approximately normal.
a. True
b. False
Answer:
Step-by-step explanation:
In constructing a confidence interval about the mean, the central limit theorem is usually applied. This makes it possible to use the normal distribution. As the number of samples is increasing, the distribution tends to be normal. This would require using the z distribution. In the case where the sample size is small, we assume a normal distribution and use the t distribution. Therefore, the given statement is true.
Please answer this correctly
Answer:
66.7%
Step-by-step explanation:
The numbers less than 7 on the list are 3, 4, 5, and 6.
4 numbers are less than 7 out of total 6 numbers.
4/6 = 2/3 = 0.667 = 66.7%
Which is equivalent to 3/8*1/4x
Answer:
9 1/2
Step-by-step explanation:
Answer:
[tex]\frac{3x}{32}[/tex]
Step-by-step explanation:
[tex]\frac{3}{8}\times \frac{1}{4}x[/tex]
[tex]\frac{3\times \:1\times \:x}{8\times \:4}[/tex]
[tex]=\frac{3x}{32}[/tex]
Find the most suitable system of coordinates to describe cylindrical shell of height 10 determined by the region between two cylinders with the same center, parallel rulings, and radii of 2 and 6 respectively.
Answer:
The answer is explained below
Step-by-step explanation:
We have a system that would be a cylindrical shell with a certain length. I will attach an allusive image, they ask us to determine which would be the most suitable system of coordinates:
Most suitable surface is cylindrical annular for this annular 30 disk most suitable coordinate system would be Cylindrical Coordinate System as one at coordinate "z" remains constant and that would be advantageous
What is g(x)?
5-
X
10
-10
Answer: g(x)= -x^2
Step-by-step explanation:
BRO THIS IS THE MOST BASIC ALGEBRA 1 !?!?!?!?!?!?!?!
PLEASE HELP!!!!!!!!!!!!!!!!!!!!!!!!!
Answer: x < -4 and -4 > x
x < -4 would be one of the two options.
This means that any number less than -4 is a solution.
This is shown by drawing an open dot on -4 and then
drawing an arrow to the left shows all answer less tan 4.
-4 > x would be our second option.
We can change it to say x < -4.
All I did was changed the order of numbers and switched the sign.
So x < -4 is the same as the first option.
|2x − 1| = |4x + 9| please solve these i want hurryly
Answer:
[tex]\boxed{\sf \ the \ solutions \ are \ -5 \ and \ -4/3 \ }[/tex]
Step-by-step explanation:
Hello,
we need to find x so that
|2x-1|=|4x+9|
and we know that |x|=x if x >= 0 -x otherwise
2x-1=0 <=> 2x=1 <=> x = 1/2
4x+9=0 <=> 4x=-9 <=> x = -9/4
So we need to work in three different intervals
case 1: x <= -9/4 ( <= 1/2)
so |2x-1| = -(2x-1) = -2x+1
and |4x+9| = -4x-9
so we need to solve -2x+1=-4x-9<=> 2x=-9-1=-10 <=> x = -5
case 2: -9/4 <= x <= 1/2
so |2x-1| = -(2x-1) = -2x+1
and |4x+9| = 4x+9
so we need to solve -2x+1=4x+9<=> 6x=1-9=-8 <=> x = -8/6 = -4/3
case 3: -9/4 <= 1/2 <= x
so |2x-1| = 2x-1
and |4x+9| = 4x+9
so we need to solve 2x-1=4x+9<=> 2x=-1-9=-10 <=> x = -10/2 = -5
Finally, the solutions are -5 and -4/3
to verify, you can see below the graph of the two functions
which of the following is equivalent to this?
a: b over a divided by d over c
b: a over b divided by d over c
c: b over a divided by d over c
d: b over a divided by c over d
please help me!
Answer:
b: a over b divided by do over c
Step-by-step explanation:
You can solve this by plugging in numbers for each variable.
For example: a=1, b=4, c=1, d=2
1/4 ÷ 1/2 = 0.125
If you plug in the numbers for all the equations listed, only 1/4 ÷ 2/1 = 0.125.