At the base of the incline, Sam is moving at a speed of 15.73 m/s. who weighs 75 kg puts on his skis and begins to descend a 50 m-high, 20 frictionless slope.
Sam's bottom-of-the-screen speed is determined using the Work-Energy Theorem as follows: An object moves parallel to the plane on a slope with no friction. Both the normal force and the gravitational perpendicular component cancel each other out because they are acting in the same speed. Therefore, an object on a frictionless slope is solely accelerated by the gravitational parallel component. On a surface on an inclined plane with no friction, any item accelerates.
delta W is equal to the delta kinetic energy for frictionless slope
(36750 - 27472) = 1/2*75*(v2 -0).
9278=37.5(v^2)
v^2 = 9278/37.5(v2)
v^2 = 247.4v = 15.73 m/s
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two lamps have different resistances. (a) if the lamps are connected in parallel, which one is brighter, the lamp with greater resistance or the lamp with less resistance? (b) if the lamps are connected in series, which one is brighter? note that the brighter lamp dissipates more power.
The correct option is (D). The (a) lamp with less resistance and (b) lamp with greater resistance.
(A) The total resistance reduces in comparison to the resistance of each individual lamp when the lamps are connected in parallel. Compared to the bulb with greater resistance, the lamp with less resistance will draw more current and become brighter.
(b) Compared to the resistance of each individual lamp, the total resistance rises when the lamps are connected in series. In comparison to the bulb with less resistance, the lamp with greater resistance will draw more current and become brighter.
Hence, the correct option is (D). The (a) lamp with less resistance and (b) lamp with greater resistance.
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#Complete question is:
Two lamps have different resistances. (a) If the lamps are connected in parallel, which one is brighter, the lamp with greater resistance or the lamp with less resistance? (b) If the lamps are connected in series, which one is brighter? Note that the brighter lamp dissipates more power.
A. (a) lamp with greater resistance; (b) lamp with less resistance
B. (a) lamp with greater resistance; (b) lamp with greater resistance
C. (a) lamp with less resistance; (b) lamp with less resistance
D. a. lamp with less resistance; b. lamp with greater resistance
What must be the units for the gravitational constant g in order for gravitational force to have units of newtons?.
To convert gravitational force into newtons sm3/(kgs2), we need to know the units again for gravitational constant g.
what is The short answer to gravity ?The force that attracts two masses to one another in physics is known as gravity. If you can believe it, every every particle of matter in the cosmos pulls on every other particle. When referring to the attraction between anything with energy or mass, the terms attraction and gravity are sometimes used synonymously.
What is so unique about gravitational force?Because it continually attempts to bring masses together and drive them apart, the gravitational force is referred to as attractive. Given that the strength of the gravitational attraction is clearly inversely correlated with the masses of the two interdependent parts, it stands to reason that larger, more galaxies will attract one another would fiercely.
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an object is 50 cm from a concave mirror with radius of curvature of magnitude 60 cm. what is the transverse magnification produced by the mirror?
An object is 50 cm from a concave mirror with radius of curvature of magnitude 60 cm. The transverse magnification produced by the mirror is 75 cm.
To find the transverse magnification, the given data is,
object distance=p=50cm
Radius of curvature=R=60cm
What is the magnification?Magnification refers to the image's size in relation to the item that produced it.
The ratio of image length to object length, measured in planes perpendicular to the optical axis, is referred to as linear magnification.
For imaging, optical microscopes combine ocular and objective lenses. The sum of the magnifying powers of the individual lenses produces the observation magnifying power.
then f=R/2
f=60/2
f=30cm
Using mirror formula,
1/f=1/p+1/q
1/30=1/50+1/q
1/30–1/50=1/q
(5–3)/150=1/q
2/150=1/q
2q=150
q=75
The transverse magnification produced by the mirror is 75 cm.
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a particular light photon carries an energy of 3.4x10^-19 j. what are the frequency, wavelength, and color of this light
51.3 x 10^14 is the frequency and the wavelength is 0.58 x 10^-7 m .
What are frequency and wavelength?The distance between two wave crests, which also applies to troughs, is known as the wavelength. The frequency is measured in microseconds (Hz), which is the quantity of vibrations that cross a specific area in a second (Hertz).
Briefing :
Well use the Planck’s equation to find the frequency of the laser;
E = hν where;
E = energy
h = Planck's constant = 6.626 x 10-34 J·s
ν = frequency
3.4x10^-19 j = 6.626 x 10-34v
v = 3.4x10^-19 j −19/6.626 x 10-34
v = 51.3 x 10^14
To find wavelength;
v =c / λ where;
c = speed of light = 3 x 10^8 m/sec
51.3 x 10^14 = 3 x 10^8 / λ
λ = 3 x 10^8/51.3 x 10^14
=0.58 x 10^-7 m
Based on the wavelength of the laser which is 0.58 x 10^-7 m, the color of the laser is RED.
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for supersonic flow in a round duct, if the diameter increases what happens to static pressure? group of answer choices
Answer: it explodes
Explanation:
You are the same age as someone in your group, is this absolute age or relative age?
The age comparison given between my age and the age of an individual n my group is a relative age.
What are relative age and absolute age?The relative age of an individual is the age of that individual when compared to the age of other people.
The Absolute age of an individual is the exact age of an individual given in years.
Considering the statement above:
You are the same age as someone in your group
The age given here is a comparison of the ages of two individuals without giving the exact age in years. Hence, the age given is a relative age.
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if it is known that the toggle clamp is a machine, what assumptions can be made about it? check all that apply. (you must provide an answer before moving to the next part.)
A toggle clamp is a device that you employ, often but not exclusively as part of a production process, to firmly place components or parts in place.
Explain about toggle clamp.
A toggle clamp's main characteristics are its rapid action and ability to be easily turned on and off by an operator. Toggle clamps also lock in place firmly. Because of this, toggle clamps are frequently employed in production lines where components need to be held firmly and quickly removed during routine manufacturing procedures.
Toggle clamps with standard or light action are often constructed from components of pressed steel that have been zinc-plated.
Depending on the setting in which you work, Stainless Steel is another alternative for Toggle Clamp production. Stainless steel toggle clamps are frequently used in regulated areas where hygiene is crucial, such as the food industry and the pharmaceutical business.
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a 2 ω resistor is connected to a battery with an emf of 6.30 v. what is the total power dissipated by the resistor?
The total power dissipated by the resistor is 6.30 V x 3.15 A = 19.845 W.
What is power?
The quantity of energy transferred as well as converted per unit of time is known as power in physics. The watt, or one joule per second, is the unit of power inside the International System of Units. Power is sometimes referred to as activity in older works. A scalar quantity is power.
Power has been related to other factors; for instance, the power required to move a ground vehicle is equal to the product of the vehicle's velocity, traction force on its wheels, and aerodynamic drag. A motor's output power is calculated by multiplying its torque output by the angular velocity of its driveshaft.
The total power dissipated by the resistor is equal to the voltage of the battery multiplied by the current through the resistor.
Since the voltage of the battery is 6.30 volts, and the resistance of the resistor is 2ω, then the current through the resistor is equal to 6.30 V/2ω = 3.15 A.
Therefore, the total power dissipated by the resistor is 6.30 V x 3.15 A = 19.845 W.
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Ben is measuring the effect that the potential energy of an object has on the height of an object's bounce
Which variable represents the height of an object's bounce?
Independent variable
Confounding variable
Response variable
Explanatory variable
The variable which represents the height of an object's bounce is Option A. Response variable
What is a response variable ?In a study or experiment, the query is focused on the response variable. A variable that explains changes in another variable is an explanatory variable. Anything could have an impact on the response variable.
The variable whose fluctuation depends on other variables is known as a response variable (or dependent variable).
The independent variable, often known as the explanatory variable, and the response variable are frequently connected. In an experiment, the response variable is the thing that changes, frequently as a result of variations in the explanatory factors.
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at sea level, at a latitude where , a pendulum that takes 2.00 s for a complete swing back and forth has a length of 0.993 m. what is the value of g in m/s 2 at a location where the length of such a pendulum is 0.960 m for period 2.00 s?
The value of acceleration due to gravity in at a location where the length of such a pendulum is 0.960 m for period 2.00 s is 9.48 m/s².
What is the period of oscillation of pendulum?
The period of oscillation of a pendulum is the time taken for the pendulum to complete one cycle.
Mathematically, the period of oscillation is given as;
T = 2π √ (L / g)
where;
T is the period of the oscillationL is the length of the pendulumg is acceleration due to gravityAt a constant period, the final equation becomes;
L₁ / g₁ = L₂ / g₂
g₂ = (g₁L₂) / (L₁)
g₂ = (g₁ x 0.96 ) / (0.993)
g₂ = 0.967 g₁
g₂ = 0.967 x 9.8 m/s²
g₂ = 9.48 m/s²
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A 4. 0-kilogram object is accelerated at 3. 0 meters per second^2 north by an unbalanced force. The same unbalanced force acting on a 2. 0-kilogram object will accelerate this object toward the north at.
According to the given statement 6.0 m/s² accelerate this object toward the north at.
What is a acceleration explain?Velocity: the rate at which direction and velocity of a moving item vary over time. When something moves faster or slower, it is considered to be accelerating. Motion on a circle increases even while the speed remains constant because the vector will always be changing.
Briefing:The force is directly related to the rate of change in momentum, according to Newton's second law of motion.
F is the energy, m is the mass, and an is the acceleration, so F = ma.
F = 4 × 3
= 12 Newtons
The same force acts on a 2.0 kg object
F = ma
a = F/ m
= 12 /2
= 6.0 m/s²
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How does plasma, the fourth state of matter, differ from gas?
Answer: Plasma is made up of groups of positively and negatively charged particles but particles of a gas are mostly uncharged.
Explanation:
Because unlike ordinary gases, plasmas are made up of atoms in which some or all of the electrons have been stripped away and positively charged nuclei, called ions, roam freely.
Which of the following graphs shows the correct relationship betwveen the pressure and volume of an ideal gas at a given temperature? Note the origin corresponds to P= 0 and V= 0.
The volume and temperature graph is straight line passing through origin .
The origin corresponds to V = 0 and T = 0, the volume of gas is directly proportional to absolute temperature at constant pressure. so the volume and temperature graph is straight line passing through origin.
The cube (x3) of a unit of length represents a unit of volume in its most basic form. The cubic metre is the comparable unit of volume, for instance, if the metre (m) is chosen as the length unit (m3). [12] So, L3 is the unit dimension for volume, a SI-derived unit. [13] Metric prefixes that are strictly powers of ten are used with the metric units of volume. When prefixes are applied to volume units, which are stated as units of length cubed, the cube operators are applied to the unit of length containing the prefix. Converting from cubic centimeter to cubic meter is demonstrated by the following formula: 2.3 cm3 = 2.3 (cm)3 = 2.3 (0.01 m)3 = 0.0000023 m3 (five zeros).
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A meterstick of negligible mass is placed on a fulcrum at the 0. 4 m mark, with a 1 kg mass hung at the zero mark and a 0. 5 kg mass hung at the 1. 0 m mark. The meterstick is held horizontal and released. Immediately after release, the magnitude of the net torque on the meterstick about the fulcrum is most nearly.
After release, the magnitude of the net torque on the meterstick about the fulcrum is nearly 1 N middot m.
What is fulcrum?The term fulcrum refers to the point or support on which a lever rotates, or to the center of a key activity.
Given, distance between fulcrum and mark , d = 0.4 m
mass hung with fulcrum , m = 1 kg.
Value of another mass , m = 0.5 kg.
distance kept , d' = 1.0 m.
torque= F d- F1 (d1- d)
Torque = m g - m g(d1 - d)
= 1 * 9.8 * 4 - 0.5 * 9.8(1 - 0.4)
Torque = 1N
Thus, the magnitude of the torque on the meterstick about the fulcrum is nearly 1 N middot m.
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A block with a mass M compresses a spring a distance A and is then released. The block travels along a horizontal surface and encounters a rough region with friction. The block comes to a stop after traveling a distance L along the rough region. How far along the rough region would the block travel if it had a mass of 2M? 4L L/2 OL OL L/4 O 2LPrevious question
The rough region would the block travel if it had a mass of 2M is L/2. Option B.
Solution:
[tex]\frac{1}{2}[/tex] KA² = MGL 2
Similarly, for the second case, we can write (let the distance traveled is x)
[tex]\frac{1}{2}[/tex]kA²= 2u Mgx
Dividing the above equations we can write,
[tex]2x = L \Rightarrow x = \frac{L}{2}[/tex]
A property of a body that is a measure of inertia is usually viewed as a measure of the amount of matter contained in the body that causes it to have weight in a gravitational field. Mass is a dimensionless quantity that describes the amount of matter in a particle or object.
The mass of an object is a measure of its inertial properties or the amount of matter it contains. The weight of an object is a measure of the force exerted on it by gravity, or the force required to support it. Mass can best be understood as the amount of matter present in an object or body. Everything around us has mass.
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a uniform thin rod of length 0.832 m0.832 m is hung from a horizontal nail passing through a small hole in the rod located 0.084 m0.084 m from the rod's end. when the rod is set swinging about the nail at small amplitude, what is the period Tt of oscillation?
The time period of oscillation is 1.670s
What is time period?
A period of time committed for a specific activity that regularly takes up a portion of a calendar year.
Time period of rod is calculated by
T = 2π [tex]\sqrt{\frac{I}{MgD} }[/tex]
Here,
D = x = [tex]\frac{L}{2} -0.084[/tex]
= 0.332m
The moment of inertia = [tex]I[/tex] = [tex]I_cm + MD^2 \\[/tex]
[tex]= \frac{1}{12} MD^2 + Mx^2[/tex]
Time period = 2π [tex]\sqrt{\frac{I}{MgD} }[/tex]
= 2π [tex]\sqrt{\frac{I}{MgD} }[/tex]
where [tex]I =[/tex] [tex]\frac{1}{12} MD^2 + Mx^2[/tex]
= 2π [tex]\sqrt{\frac{ \frac{1}{12} 0.832^2 + 0.084^2}{9.8 * 0.084}[/tex]
= 2π [tex]\sqrt{ \frac{0.0576 + 0.00059}{0.8232}[/tex]
= 2π * 0.265
= 1.670s
The time period of oscillation is 1.670s
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A glider on an air track is connected by springs to either end of the track. Both springs have the same spring constant, k, and the glider has mass M
a) Determine the frequency of the oscillation, assuming no damping, if k = 125 N/m and M = 210 g .
b) It is observed that after 55 oscillations, the amplitude of the oscillation has dropped to one-half of its initial value. Estimate the value of γγ, using x(t)=A* e^γt * cosω′t
c) How long does it take the amplitude to decrease to one-quarter of its initial value?
After 102.7 oscillations, the amplitude decreases to one-fourth of the initial value.
What do amplitude and frequency mean?Amplitude is the separation between the wave's resting position and its maximum displacement. Frequency is the number of waves that cross a particular point in a second. Period is the length of time it takes for a wave cycle to complete.
λ = 1/51⋅0.20slog(1/2)
λ = −0.68⁻¹s
Using the previous finding, we can calculate the amplitude as a function of time to determine how long it will take before it reaches one-fourth of its initial value.
1/4=Aeλt
Solving for the time,
t = 1/λlog(1/4)
t = 20.4s
Comparing this result with the period,
t = 102.7T.
The amplitude is the largest displacement or distance that a point on a vibrating body or wave can move away from its equilibrium location. It is equal to dividing by two the length of the vibration path. The distance between a wave's resting position and its greatest displacement is known as amplitude. The frequency is the number of waves that pass through a specific location in a second. Period: the time required to complete a wave cycle to complete.
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how do we know that spheroidal stars (stars in the bulge and halo) are older, on average, than disk stars?
There are no blue spheroidal stars.
What is meant by disk stars ?Population I stars are disc stars. They are therefore relatively young stars with circular orbits in the galactic plane. They are typically rich in metal. As a result of the disk's abundance of gas and dust, vigorous star formation occurs there. The spiral arms of the galaxy are where stars develop.
There is always some matter around the star when it originates, and this material collects into a disc around the rotating star's equator. This substance can also condense into solid or gaseous structures in the form of a disc.
The researchers discovered that the thick disc of the galaxy's stars were, in fact, billions of years older than the stars observed elsewhere.
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A skateboarder traveling at 13.6 meters per second rolls rona stop at the top of a ramp in 2.5 seconds. What is the skateboarder’s acceleration
Answer:
Below
Explanation:
Acceleration = Δ v / Δ t = -13.6 m/s / 2.5 s = - 5.4 m/s^2
( the negative sign shows this to be a deceleration)
consider that 224.0 j of work is done on a system and 313.9 j of heat is extracted from the system. in the sense of the first law of thermodynamics, what is the value (including algebraic sign) of w, the work done by the system?
The work done by the system including the algebraic sign is -89.9 J.
Work done on the system = W = 224.0 J
Heat extracted from the system = Q = - 313.9 J
Using the first law of thermodynamics,
The work done by the system is = U =
= U = Q + W
= U = -313.9 + 224.0
= U = -89.9 J
The First Law of Thermodynamics states that heat is a form of energy, and thermodynamic processes are therefore subject to the principle of conservation of energy. This means that heat energy cannot be created or destroyed.
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Which describes one way that aristarchus's explanation of the movement of objects in the sky was different from other scientists' earlier explanations.
Aristarchus argued that Earth rotates on its axis.
Who was Aristarchus of Samos?
Ancient Greek astronomer and mathematician Aristarchus of Samos proposed the first known heliocentric model, according to which the Sun is at the center of the known universe and the Earth revolves once a day around the Sun.
Aristarchus believed the stars to be very distant suns, and as a result, he believed there was no detectable parallax—the movement of the stars with respect to one another as the Earth revolves around the Sun. Aristarchus determined that planets circled around the Sun after discovering that the Sun was much larger than the Earth and the other planets.
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calculate the displacement current id between the square plates, 7.0 cm on a side, of a capacitor if the electric field is changing at a rate of 3.0×106 v/m⋅s .
The separation between the plates is [tex]8.51*10^{-8}[/tex].
Information: The distance between the square plates is 8.6 cm, and the rate at which the electric field changes is 1.3 x 106 V/m.s.
using formula: d=eA(E/t), d=8.85*10¬¹²*(0.086)²*1.30*10⁶
d=8.51*10⁻⁸m.
What do you mean by Current?A flow of electrical charge carriers, often electrons or atoms deficient in electrons, is referred to as current. The capital letter I is a typical sign for current. The ampere, represented by the letter A, is the common unit.
Does "current" refer to the present time?It is current if it is true at the moment, right now, and in the present. The term current's origins all relate to its "present" sense. Things that are current are now occurring; they are a part of the present. Since past events are history and no longer news, news reporting focuses on "present affairs."
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A star was observed to have a planet orbiting it at a distance of 1.12×108 km. The orbital period of the planet is 329 days. Calculate the mass of the star.
The mass of the star would be 9.97 x 10³⁵ Kg.
What is Star? What is centripetal force?Stars are huge celestial bodies made mostly of hydrogen and helium that produce light and heat from the churning nuclear forges inside their cores. We can write the relation absolute magnitude [M] and apparent magnitude [m] as follows : M = m + 5(log₁₀p + 1). The centripetal force is the force needed to make a body move in circular motion. It is given by : F{C} = mv²/rWe have a star was observed to have a planet orbiting it at a distance of 1.12 × 10⁸ km. The orbital period of the planet is 329 days.
Let the mass of star be [M] and that of planet be [m]. Since, the planet revolves around the star, we can write -
F{Centripetal} = F{Gravitation}
mv²/r = GMm/r²
v² = GM/r
(rω)² = GM/r
r²ω² = GM/r
ω² = GM/r³
(2π/T)² = GM/r³
M = (2π/T)² (r³)/G
M = 46.8 x (r³)/G
M = {46.8 x (1.12)³ x (10⁸)³}/{(6.6) x 10 ⁻¹¹}
M = (65.7/6.6) x (10²⁴/ 10 ⁻¹¹)
M = 9.97 x 10³⁵ Kg
Therefore, the mass of the star would be 9.97 x 10³⁵ Kg.
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what is the multiple of the eenjrgy needed to escape from earth gives the energy needed to escape from the moonon andn jpitier
The ratio of energy needed to escape from the surface of the moon to the energy needed to escape from the earth is 0.045
The ratio of energy needed to escape from the surface of Jupiter to energy needed to escape from the earth is 28.5
Calculation:-
Mass of earth = 5.95 *10²⁴ kg
Mass of moon = 7.36*10²² kg
Mass of Jupiter = 1.89 * 10²⁷kg
The radius of the earth = 6.37 * 10⁶ m
The radius of the moon = 1.74 *10⁶ m
The radius of Jupiter = 6.99 *10⁷
The amount of energy needed to escape from the surface is the same as its gravitational potential energy at the original position.
The formula is as follows:
K = GMm/R
where, M, and m are masses, R is the radius, G is the gravitational constant and K is energy.
DetermiNE the ratio of energy needed to escape from the surface of the moon to energy needed to escape from the earth.
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the coefficient of kinetic frition between an object and the surface upon which it is sliding is 0.10. the mass of the object is 8.0 kg. what is the force of friction
The force of friction is 0.8 N.
Friction is the force that prevents motion when the surface of one object comes into contact with the surface of another.
It also has the same SI unit as other forces have as Newton (N).Frictional force can be calculated by the formula F = μ * Fnμ is the coefficient of friction between the surfaces which are in the contact.
Fn is the normal force acting on the object due to its mass.
Mass of the object = m = 8.0 kg
coefficient of kinetic friction between an object and the surface upon which it is sliding = 0.10
Frictional force = F = 8.0 * 0.10
F = 0.8 N
The force of friction is 0.8 N.
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A rock with density 2300 kg/m3 is suspended from the lower end of a light string. When the rock is in air, the tension in the string is 38.0 N. What is the tension in the string when the rock is totally immersed in a liquid with density 750 kg/m3?
The tension in the string when the rock is totally immersed in a liquid with density 750 kg/m3 is 25.6 N
How to solve for the tensionThe upward buoyant force of a given object can be said to be the same as the weight that it has.
The formula that would be used to get the tension is given as
[tex]mg [1 - \frac{P_{u} }{P_{object} } ][/tex]
Where we have Pu = 750 this is the liquid density
mg = 38.0 N. This is the tension in the string
P object is the rock density = 2300
[tex]38[1-\frac{750}{2300} ][/tex]
38 * 1 - 0.3260
38 * 0.674
= 25 . 6N
The tension is 25.6N
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in state-of-the-art vacuum systems, pressures as low as 1.00 10-9 pa are being attained. calculate the number of molecules in a 1.30-m3 vessel at this pressure and a temperature of 31.0°c.
Number of molecules in the vessel are n = 3.15 x [tex]10^{11}[/tex] molecules
What pressure ?A physical formula that states that the ratio of an ideal gas's measurable qualities is P (pressure) V (volume) = n (number of moles) R (the gas constant) T. (temperature in Kelvin). It is developed from a synthesis of the Boyle, Charles, and Avogadro gas laws. referred to as the universal gas law.
According to the given information
P = 1.00 x 10-9 Pa
V = 1.30 [tex]m^{3}[/tex]
Temperature T = 26° C = 299.15 K
Known
Gas constant R = 8.314 J/ moles K
Avogadro's constant N = 6.022 x [tex]10^{23}[/tex]
Solution :
PV = n RT
1.00 x [tex]10^{-9}[/tex] x 1.30 = n x 8.314 x 299.15
n = 5.23 x [tex]10^{-13}[/tex] moles
n = 5.23 x [tex]10^{-13}[/tex] x 6.022 x [tex]10^{23}[/tex]
n = 3.15 x [tex]10^{11}[/tex] molecules
Number of molecules in the vessel are n = 3.15 x [tex]10^{11}[/tex] molecules
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a 1,000-mw (el) power plant working at 35% thermal efficiency 100% of the time (base load) uses coal with formula ch and a heating value of 30 mj/kg. how much co2 does this plant emit (metric tons/y)?
A 1,000-mw (el) energy plant running at 35% thermal performance 100% of the time (base load). The quantity of CO₂ emitted through the plant is 7773579.832 metric tones consistent with year.
What is thermal efficiency?
The thermal efficiency of a heat engine is the percentage of heat energy that is transformed into work. Thermal efficiency is defined as. The efficiency of even the best heat engines is low; usually below 50% and often far below. So the energy lost to the environment by heat engines is a major waste of energy resources.
The amount of CO₂ emitted by the plant is 7773579.832 metric tonnes per year.
Power of the plant = Capacity of the plant = 1000 MW
Working efficiency = 35%
Time = 100%
Heating value of coal = 30 mj/Kg
One year KWh of the plant =
= 1000 X 1000 X 365 X 24
= 31536 X 10¹² metric tonnes per year
Amount of coal =
= (31536 X 10¹² ) / (30 X 10⁶ X 0.35)
= 3003428571 Kg
Thus, the amount of CO₂ emitted by the plant =
= (3003428571 X 44) / 17
= 7773579832 Kg/ year
= 7773579.832 metric tonnes per year
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describe the relationship between the force and length and how the curves differ between a weak spring and a strong spring
The relationship between the force and length is given by F = -kx.
What is hooke's law?
The force a spring applies to items fastened to its ends is proportional to the distance the spring travels from its equilibrium length and is always pointed in the direction of equilibrium.
The equilibrium point of the spring's free end is at x = 0, and if the x-axis of a coordinate system is selected to be parallel to the spring, then
F = -kx.
The term "spring constant" refers to the proportional constant k.
So,
K will be large if the spring is stiff or powerful, and it will be little if the spring is weak.
According to hooke's law
ΔF / Δx = k
Slope of the graph gives "spring constant"
So,
If we consider strong spring, then curve will have high slope.
and if we consider weak spring, then the curve will have low slope.
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how far from the lens must the film in a camera be, if the lens has a 35.0-mm focal length and is being used to photograph a flower 75.0 cm away? explicitly show how you follow the steps in the lenses.
The lens should be kept at a distance of 3.67 cm from the film in the camera to be photographed and convex lens should be used.
Focal length = f = 35.0 mm = 3.5 cm
Distance at which flower is kept = p = 75 cm
The type of lens that should be used = convex
Distance at which camera should be kept = q =
= Using the lens formula
= 1/p + 1/q = 1/f
= 1/75 + 1/q = 1/3.5
= 1/q = 1/3.5 - 1/75
= q = 3.67 cm
So, the film should be kept 3.67 cm behind the convex lens.
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