Answer:
140
hope this helps
have a good day :)
Explanation:
A ray of light travels through air (n = 1.00) and
approaching the boundary with water (n =
1.33). The angle of incidence is 45.0°.
Determine the angle of refraction.
Answer:
32.1176°
Explanation:
In the picture above, I hope that it's a correct answer.
From the Snell's law, the angle of refraction will be 32.117°.
What is Snell's law?The Snell's law states that the ratio of sine of angle of incidence and angle of refraction is equal to the ratio of refractive index of second medium to the first medium.
sin i/sin r = n(water) / n(air)
r =sin⁻¹ (sin 45 x 1/ 1.33)
r =32.117°
The angle of refraction is 32.117°.
Learn more about Snell's law.
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8. Jay drives his truck to football practice. He gives Jen a ride. The truck stalls in the parking
lot. He gets out and pushes it, but it won't budge. He tells Jen to get out and help him
push. They manage to push the truck into a parking space. (Thank goodness he is a
tackle!) Which law applies?
Answer:
Action Reaction
Explanation:
Linear vectore F
En una feria, se gana una jirafa de peluche lanzando una moneda a un platito, el cual está sobre una repisa más arriba del punto en que la moneda sale de la mano y a una distancia horizontal de 2.1 m desde ese punto (figura 3.41). Si lanza la moneda con velocidad de 6.4 m>s, a un ángulo de 60° sobre la horizontal, la moneda caerá en el platito. Ignore la resistencia del aire. A) ¿A qué altura está la repisa sobre el punto donde se lanza la moneda? B) ¿Qué componente vertical tiene la velocidad de la moneda justo antes de caer en el platito?
Answer:
A) La altura de la repisa sobre el punto donde se lanza la moneda es de aproximadamente 0,42 m
B) La velocidad de la moneda justo antes de que golpee el platillo es de aproximadamente 0,895 m/s hacia abajo
Explanation:
A) Los parámetros dados son;
La distancia horizontal del plato desde donde se lanza la moneda = 2,1 m
La velocidad con la que se lanza la moneda, u = 6,4 m / s
El ángulo al que se lanza la moneda, θ = 60 °
La componente horizontal de la velocidad, vₓ = 6.4 m / s × cos (60°) = 3.2 m/s
El tiempo que tarda la moneda en recorrer una distancia horizontal de 2,1 m, 't' se calcula de la siguiente manera;
t = 2,1 m/(3,2 m/s) = 0,65625 segundos
Por tanto, la altura de la moneda a 0,65625 segundos se da de la siguiente manera;
y = u × sin (θ) × t - (1/2) × g × t²
En t = 0,65625 segundos, obtenemos;
y = 6,4 × sin (60°) × 0,65625 - (1/2) × 9,81 × (0,65625) = 0,41840044589
La altura de la repisa sobre el punto donde se lanza la moneda, y ≈ 0.42 m
B) La velocidad vertical de la moneda justo antes de que golpee el platillo, [tex]v_y[/tex], se da como sigue;
[tex]v_y[/tex] = u × sin(θ) - g·t
∴ [tex]v_y[/tex] = 6.4 × sin(60°) - 9.81 × 0.65625 ≈ -0.895
La velocidad de la moneda justo antes de golpear el platillo, [tex]v_y[/tex] ≈ 0.895 m/s (hacia abajo)
( Science) Do you think seismographs predict earthquakes or measure earthquakes? Explain your answer.
Answer:
No. Neither the USGS nor any other scientists have ever predicted a major earthquake. We do not know how, and we do not expect to know how any time in the foreseeable future. USGS scientists can only calculate the probability that a significant earthquake will occur in a specific area within a certain number of years.
Answer:
No. Neither the USGS nor any other scientists have ever predicted a major earthquake. We do not know how, and we do not expect to know how any time in the foreseeable future. USGS scientists can only calculate the probability that a significant earthquake will occur in a specific area within a certain number of years.
Explanation:
What are the four major tasks of the digestive system?
Ingestion, Digestion, Absorption, Elimination.
Ingestion, Procrastination, Absorption, Face the Nation.
Congestion, Progestion, Ingestion, Elimination
Answer:
Option A
The four major tasks of the digestive system are - Ingestion, Digestion, Absorption, Elimination
Explanation:
A digestive system has primarily four main functions
a) Motility - In this the food is ingested through opening in the form of mouth and then it starts moving from the mouth via esophagus to the stomach
b) Digestion - In the stomach, the food gets digestion and then it is passed on to the intestine
c) Absorption - In the small intestine essential nutrients and water is absorbed
b) Secretion - The waste remaining after intestine digestion is passed on to the rectum for secretion
Hence, option A is correct
pls help ASAP i have already failed this test once i cant fail it again
Answer:
Petrochemicals are a set of chemical compounds that fuel a wide array of products across the globe. They are made of hydrocarbons that are separated and extracted from petroleum (crude oil) and natural gas and are at the core of multiple industries, including: Cosmetics. Electronics. Packaging.
Answer:
B. I think Gasoline, natural gas, and diesel fuel
I'm truly sorry if it's wrong :(
Explanation:
A rollercoaster cart that has a mass of 4500 kg has 67.5 kJ (kilojoules), or 67,500 J (joules), of gravitational potential
energy. What is its height above the ground?
PT.2
The same 4500 kg rollercoaster cart is moving with 63.0 kJ (kilojoules), or 63,000 J (joules), of kinetic energy at the
bottom of its biggest hill. What is its velocity?
Answer: The height of rollercoaster cart above the ground is 1.53 m.
The velocity of rollercoaster cart is 5.29 m/s.
Explanation:
Potential energy is the energy occupied by a substance due to its position. Formula for potential energy is as follows.
P.E = mgh
where,
m = mass of substance
g = gravitational constant = [tex]9.8 m/s^{2}[/tex]
h = height
Substitute the values into above formula as follows.
[tex]P.E = m \times g \times h\\67500 J = 4500 kg \times 9.8 m/s^{2} \times h\\h = \frac{67500 J}{4500 kg \times 9.8 m/s^{2}}\\= 1.53 m[/tex]
Hence, the height of rollercoaster cart above the ground is 1.53 m.
Kinetic energy is the energy occupied by the motion of a substance. Formula for kinetic energy is as follows.
[tex]K.E = \frac{1}{2}m \times v^{2}[/tex]
where,
m = mass of substance
v = velocity of substance
Substitute the values into above formula as follows.
[tex]K.E = \frac{1}{2}m \times v^{2}\\63000 J = \frac{1}{2} \times 4500 kg \times v^{2}\\v^{2} = \frac{63000 J \times 2}{4500 kg}\\v = 5.29 m/s[/tex]
Hence, the velocity of rollercoaster cart is 5.29 m/s.
True or False. The Magnitude of the induced voltage in a coil of wire depends on how quickly the magnetic flux through the coil of wire changes.
Answer:
Yes, its true
Explanation:
hdheheishdhieijzuwhs
Answer: yes its true
Explanation:
nmo
What is a pulley and the how does it make lifting heavy loads easier?
identify 2 properties of sound waves
can someone help?? 4/5
Answer: I may not have the awser but
Explanation: Try calculating 8.932 times
10^22 kg
Answer:
F = 2.68 x 10²³ N
Explanation:
The force between lo and Jupiter is given by Newton's Gravitational Formula:
[tex]F = \frac{Gm_1m_2}{r^2} \\[/tex]
where,
F = Force = ?
G = Universal Gravitational Constant = 6.67 x 10⁻¹¹ Nm²/kg²
m₁ = mass of lo = 8.932 x 10²² kg
m₂ = mass of Jupiter = 1.9 x 10²⁷ kg
r = distance between lo and Jupiter = 4.22 x 10⁸ m
Therefore,
[tex]F = \frac{(6.67\ x\ 10^{-11}Nm^2/kg^2)(8.932\ x\ 10^{22}\ kg)(1.9\ x\ 10^{27}\ kg)}{(4.22\ x\ 10^8\ m)^2}[/tex]
F = 2.68 x 10²³ N
1. A massive object can distort the light of more distant objects behind it through the phenomenon that we call ________. 2. ________ are defined as subatomic particles that have more mass than neutrinos but do not interact with light. 3. The _____________ of spiral galaxies provide strong evidence for the existence of dark matter. 4. Models show that the _________ of the universe is better-explained when we include the effects of dark matter along with the effects of luminous matter.
Answer:
1. Gravitational lensing.
2. Weakly interacting massive particles (WIMPs).
3. Rotation curves.
4. Large-scale structure.
Explanation:
In science, matter can be defined as anything that has mass and occupies space. Any physical object that is found on earth is typically composed of matter. Matter are known to be made up of atoms and as a result has the property of existing in states.
Generally, matter exists in three (3) distinct or classical phases and these are; solid, liquid and gas.
Light wave can be defined as an electromagnetic wave that do not require a medium of propagation for it to travel through a vacuum of space where no particles exist.
The following statements are matched to give the characteristics of matter with respect to light;
1. A massive object can distort the light of more distant objects behind it through the phenomenon that we call: gravitational lensing. The gravitational field distorts and magnifies light from a distant galaxy such as quasars.
2. Weakly interacting massive particles (WIMPs): are defined as subatomic particles that have more mass than neutrinos but do not interact with light.
3. The rotation curves of spiral galaxies provide strong evidence for the existence of dark matter.
4. Models show that the large-scale structure of the universe is better-explained when we include the effects of dark matter along with the effects of luminous matter.
Una rueda arranca desde el reposo y después de girar 30 revoluciones, alcanza una velocidad de 15 rad/s. Calcular:
a) Su aceleración.
b) El tiempo transcurrido.
Ayuda xfi c:
Dr. Kirwan is preparing a slide show that he will present to the executive board at tonight's committee meeting. He places a 3.50-cm slide behind a lens of 20.0 cm focal length in the slide projector. A) How far from the lens should the slide be placed in order to shine on a screen 6.00 m away? B) How wide must the screen be to accommodate the projected image?
Answer:
A) d_o = 20.7 cm
B) h_i = 1.014 m
Explanation:
A) To solve this, we will use the lens equation formula;
1/f = 1/d_o + 1/d_i
Where;
f is focal Length = 20 cm = 0.2
d_o is object distance
d_i is image distance = 6m
1/0.2 = 1/d_o + 1/6
1/d_o = 1/0.2 - 1/6
1/d_o = 4.8333
d_o = 1/4.8333
d_o = 0.207 m
d_o = 20.7 cm
B) to solve this, we will use the magnification equation;
M = h_i/h_o = d_i/d_o
Where;
h_o = 3.5 cm = 0.035 m
d_i = 6 m
d_o = 20.7 cm = 0.207 m
Thus;
h_i = (6/0.207) × 0.035
h_i = 1.014 m
What is a wave's speed if it has a wavelength of 3.2x10^-7 m and a period of 2.8x10^-12s
Answer: 1.1·10^5 m/s
Explanation: speed = wavelength · frequency v = λf and
frequency f = 1/T , in which T = period
Speed v= λ/T = 3.2·10^-7 m /2.8·10^-12 s = 114285,7 m/s
A , as recorded by a seismometer,will be a lot of vibration versus timeline
Answer:
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Explanation:
Generally, a seismograph consists of a mass attached to a fixed base. During an earthquake, the base moves and the mass does not. The motion of the base with respect to the mass is commonly transformed into an electrical voltage. The electrical voltage is recorded on paper, magnetic tape, or another recording medium.
The moist bread becomes mouldy after a few days when it is left in a container with a cover. Which of the following conditions favour the growth of the fungus?
Answer: Moisture and food (bread)
Explanation:
Mould grows best in humid, damp air/wet conditions.
Since the bread is moist it will provide humidity for the mould as well as food.
A container with a cover would not be a favoring condition as mould needs oxygen to grow and survive.
pls help with science!!!!!
Answer:
Your answer is C~
Explanation:
nt: what is the unit of measurement for work?)
A body builder lifts a 200kg barbell up 2m into the air. How
much work does the bodybuilder do?
Answer:
The unit of measurement of work is Nm which is also called as Joule and written J.
work done by the body builder against gravity = 3920J
Explanation:
work = force x displacement
force on barrel = 200 x gravity = 200 x 9.8 = 1960 N
displacement = 2m
work done against gravity = 1960 x 2 = 3920 J
Which of the following quantities is inversely proportional to the gravitational pull between two objects?
(A) The sum of their masses
(B)The sum of their volumes
(C) The square of the distance that separates them
(D) The distance from their center to their surface
Answer:
C
Explanation:
Since gravitational force is inversely proportional to the square of the separation distance between the two interacting objects, more separation distance will result in weaker gravitational forces
I hope this helps a little bit
The correct Option is :
=》(C) The square of the distance that separates them
[tex]f \: \: \dfrac{1}{ \alpha } \: \: r {}^{2} [/tex]where,
f = gravitational force
r = distance between the objects
Jack and Jill are pushing a 3 kg object on a rough surface; the object accelerates at a rate of 5 m/s2. Calculate the force applied by the Jack knowing that Jill is pushing 4 N and the rough surface applies 2 N force on the box as friction force.
Answer:
13 N
Explanation:
From the question,
(F₁+F₂)-F' = ma................ Equation 1
Where F₁= Jack's force, F₂ = Jill's force, F' = Friction force, m = mass of the object, a = acceleration of the object.
Given: F₂ = 4 N, F' = 2 N, m = 3 kg, a = 5 m/s²
Substitute these values into equation 1 and solve for F₁
(F₁+4)-2 = 3×5
(F₁+4)-2 = 15
F₁+4 = 15+2
F₁+4 = 17
F₁ = 17-4
F₁ = 13 N
Hence the force applied by Jack is 13 N
what is shot-curciting
Answer:
A path that allows most of the current in an electric circuit to flow around or away from the principal elements or devices in the circuit.
The lens of a telescope has a diameter of 25 cm. You are using it to look at two stars that are 2 × 1017 m away from you and 6 × 109 m from each other. You are measuring light with a wavelength of 700 nm. As the light goes through the lens, it diffracts. a. Is it possible, using this telescope, to see the two stars as separate stars? b. What is the minimum possible lens diameter you would need in order to resolve these two stars?
Answer:
a)It is NOT possible using this telescope, to see the two stars as separate stars
b)[tex]d_{min} =28.466m[/tex]
Explanation:
From the question we are told that:
Diameter of lens,[tex]d = 25 cm \approx 0.25 m[/tex]
Distance from both star [tex]D_f= 2*10^{17} m[/tex]
Distance between both stars [tex]D_b= 6*10^9 m[/tex]
Wavelength of light [tex]\lambda =700 nm \approx 700*10^-9 m[/tex]
Generally the equation for angle subtended by the two stars at the lens is mathematically given by
[tex]\theta=\frac{D_f}{D_b}[/tex]
[tex]\theta=\frac{6*10^9}{2*10^{17}}[/tex]
[tex]\theta=3.0*10^{-8} rad[/tex]
Generally the equation for minimum angular separation of two object is mathematically given by
[tex]\theta_{min} = 1.22*\lambda/d[/tex]
[tex]\theta_{min}= \frac{1.22*700*10^-9}{0.25}[/tex]
[tex]\theta_{min}= 3.416*10^-^6 rad[/tex]
Therefore
[tex]\theta < \theta_{min}[/tex]
[tex]3.0*10^{-8} rad< 3.416*10^-^6 rad[/tex]
It is NOT possible using this telescope, to see the two stars as separate stars
b)
Generally the equation for minimum diameter of the lens is mathematically given by
[tex]d_{min} =\frac{ 1.22*\lambda}{\theta}[/tex]
[tex]d_{min} =\frac{ 1.22*700*10^{-9}}{3*10^{-8}}[/tex]
[tex]d_{min} =28.466m[/tex]
Smaller the surface area greater the gravitational force and vice–versa yes or no? justify the statement.
Answer:
It is true that Smaller the surface area greater the gravitational force and vice versa
Explanation:
The gravitational force depends on the distance between the two objects
F=GMm/r2
where G = gravitational constant
M = mass of one object
m = mass of second object
r is the distance between the two objects
Gravitational force is inversely proportional to the square of the distance between two objects. Hence, it can be said the Gravitational force is inversely proportional to the area and hence as the area increases gravitational force will decrease or vice versa
Se tiene un objeto que oscila con MAS. Si la amplitud del movimiento es de 15 cm y el periodo es de 2 seg, encontrar las magnitudes de la velocidad y la aceleración cuando: a) x= 0 cm b) x=7,5 cm Por favor, ayúdenme es para hoy :c
Answer:
a) v = 0, a = - 15 pi²
b) v = - 40.8 cm / s, a = -74.2 cm / s
Explanation:
the simple harmonic motion is described by the expression
x = A cos (wt + Ф)
in that case they indicate the amplitude of the movement
A = 15 cm
angular velocity and period are related
w = 2π / T
w = 2π/ 2
w = π rad / s
speed is defined by
v = dx / dt
v = -A w sin (wt + Ф)
acceleration is defined by
a = dv / dt
a = - A w² cos (wt + Ф)
In order to evaluate this expression we must know the value of the phase constant (Ф) that meets the initial conditions, the most common thing is that the system is released, v = 0 for y = 0 s, let's use the speed equation
v = -A w sin (0+ Ф)
for this expression to be zero, the sine must be zero, so
Ф= 0
now let's write the equations for our case
v = - 15 π sin (π t)
a = - 15 π² cos (π t)
a) for x = 0
v = 0
a = - 15 pi²
b) for x = 7.5 cm
Let's find out how long it takes to get to this position
x = 15 cos (π t)
7.5 / 15 = cos π t
pi t = cos⁻¹ 0.5
t = 1.047/π
don't forget that the angles are in radians
t = 0.333 s
now let's look for speed and acceleration
v = - 15 π sin (π 0.333)
v = - 40.8 cm / s
a = - 15 π² cos (π 0.333)
a = -74.2 cm / s
A 1220-w hair dryer is used by several members of the family for a total of 30 min per day during a 30 day month. How much elecrical energy is consumed by the hair dryer during the month give your answer in kilowatt hours
Answer:
Energy = 18.3 Kilowatt-hour
Explanation:
Given the following data;
Power = 1220 Watts
Time = 30 * 30 = 900 minutes to hours = 900/60 = 15 hours
To find the energy consumption;
Power can be defined as the energy required to do work per unit time.
Mathematically, it is given by the formula;
[tex] Power = \frac {Energy}{time} [/tex]
Making energy the subject of formula, we have;
Energy = power * time
Energy = 1220 * 15
Energy = 18300 Joules
To convert energy to Kilowatt-hour;
Energy = 18300/1000
Energy = 18.3 Kilowatt-hour
What is the acceleration of a 250 kg object pushed with a force of 7500 newtons?
Answer:
a = 30 m/s²
Explanation:
Given: 250 kg, 7500N
To find: Acceleration (a)
Solution: To find the acceleration (A), divide the force by the weight
A = F ÷ m
= 7500 ÷ 250
= 30 m/s²
Newtons are derived units, equal to 1 kg-m/s². In other words, a single Newton is equal to the force needed to accelerate one kilogram one meter per second squared.
a body falls freely from rest.calculate it's acceleration
Answer:
10 m/s²
Explanation:
Since the body is falling freely from the rest, it will be having an acceleration equal to the acceleration due to gravity.
∴ Acceleration = g = 9.8 m/s². ≈ 10 m/s².
Answer:
10 m/s^2 I hope it helps u a lot
4) Based on your results, what can you infer about the distribution of
touch receptors on the skin?
Answer:
what are the results? Also
Explanation:
The distribution of touch receptors in human skin is not consistent over the body. In humans, touch receptors are less dense in skin covered with any type of hair, such as the arms, legs, torso, and face. If two points are felt as two separate points, each is in the receptive field of two separate sensory receptors.
A van accelerates from 4m/s to 20m/s in 8s. How far does it travel in this time?
Answer:
96 m
Explanation:
Given,
Initial velocity ( u ) = 4 m/s
Final velocity ( v ) = 20 m/s
Time ( t ) = 8 s
Let Acceleration be " a ".
Formula : -
a = ( v - u ) / t
a = ( 20 - 4 ) / 8
= 16 / 8
a = 2 m/s²
Let displacement be " s ".
Formula : -
s = ut + at² / 2
s = ( 4 ) ( 8 ) + ( 2 ) ( 8² ) / 2
= 32 + ( 2 ) ( 64 ) / 2
= 32 + ( 2 ) ( 32 )
= 32 + 64
s = 96 m
Therefore, it travels 96 m in time 8 s.