Answer:
PV= $40,279.36
Step-by-step explanation:
Giving the following information:
Number of periods= 8*12= 96 months
Interest rate= 0.039/12= 0.00325
Future value (PV)= $55,000
To calculate the initial investment, we need to use the following formula:
PV= FV/(1+i)^n
PV= 55,000 / (1.00325^96)
PV= $40,279.36
Not quite sure about the answer but it seems simple. Please answer!
Answer:
Its A
Step-by-step explanation:
A scientist needs 80 liters of a 30% solution of alcohol. She has a 20% solution and a 60% solution available. How many liters of the 20% solution and how many liters of the 60% solution should she mix to make the 30% solution?
Answer:
60 liters of 20% solution & 20 liters of 60% solution
Step-by-step explanation:
80*0.3=.2x+0.6(80-x)
24=0.2x+48-0.6x
-24=0.2x-0.6x
-24=0.4x
24=0.4x
60=x
Hope this helps!! This is step by step btw!
You finance a $500 car repair completely on credit, you will just pay the minimum payment each month for the next three months. The APR is 18.99% and the minimum payment each month is 4% of the balance. Determine the finance charge, carry-over balance, and minimum payment required for each of the next two months, and the starting balance for month 2 in the table below.
Answer:
Determination of the Finance Charge, Carry-over balance, Minimum Payment for each of the next two months:
Finance Charge:
First month = $7.91
Second month = $7.72
Carry-over balance:
First month = $487.59
Second month = $475.50
Minimum Payment:
First month = $20.32
Second month = $19.81
Starting balance (Carry-over balance + Finance charge):
First month = $507.91
Second month = $495.31
Step-by-step explanation:
a) Data and Calculations:
Credit Finance = $500
APR = 18.99%
Minimum monthly payment = 4% of the balance
Monthly rate of interest = 0.1899/12 = 0.015825
Finance Charge:
First month = $7.91 ($500 * 0.015825)
Second month = $7.72 ($487.59 * 0.015825)
Carry-over balance:
First month = $487.59($507.91 - $20.32)
Second month = $475.50 ($495.31 - $19.81)
Minimum Payment:
First month = $20.32 ($507.91 * 4%)
Second month = $19.81 ($495.31 * 4%)
Starting balance (Carry-over balance + Finance charge):
First month = $507.91 ($500 + $7.91)
Second month = $495.31 ($487.59 + $7.72)
Rainfall was 6 inches in September and 4.9 inches in October. What was the difference in rainfall?
Answer:
1.1
Step-by-step explanation:
6-4.9=1.1
Hope I helped!
Please mark Brainliest!!!
Answer:
1.1
Step-by-step explanation:
it's easy you just subtract.
Solve the inequality 8y - 3(y - 2)< 2y + 4(2y + 4) write solution in interval notation
Answer: y>-2
Step-by-step explanation:
8y-3(y-2) < 2y+4(2y+4)
8y-3y+6 < 2y+8y+16
6-16<2y+8y-8y+3y
-10<5y
y>-2
Answer:
(−∞,−2)
Step-by-step explanation:
Start by simplifying each side as much as possible by distributing and combining like terms to get
8y−3(y−2)8y−3y+65y+6>2y+4(2y+4)>2y+8y+16>10y+16
Subtract 10y from both sides to collect the variables on the left, then subtract 6 from both sides to collect all the constants on the right.
5y+65y+6−10y−5y+6−5y+6−6−5y>10y+16>10y+16−10y>16>16−6>10
Divide each side by −5 to solve for y. Since −5<0, the inequality changes direction.
−5y−5y−5y>10<10−5<−2
In interval notation, we write this as (−∞,−2).
If 1 inch represents 10 miles on a map then how many inches will represent 120 miles ?
Answer:
12 inches
Step-by-step explanation:
We can write this as a proportion:
inches/miles = inches/miles
1/10 = x/120
Solving for x, we get 12 inches.
Katie played 5 consecutive games of soccer without being taken off the field. Then, after a single game on the sidelines, she played another 7 consecutive games. What is the percent of increase in the number of consecutive games she played?
Mrs.Rodriquez is purchasing trophies for each child that plays little league she wants to spend no more than $7.00 per thropy
Answer:
7 trophies for $49.00
5 trophies for $30.00
-----------------------------------
Explination:
It says that she wants to pay no more than 7 dollars for each trophy she buys, which means 7 and less. So we have to multiply 7 x the number of trophies, And if it gives you the excact number or less its correct.
So we multiply
7 x 7 = 49 (The excact number, correct)
9 x 7 = 63 (The price they are selling it at is higher, incorrect)
12 x 7 = 84 (The price they are selling it at is higher, incorrect)
5 x 7 = 35 (Paying less, Correct)
3 x 7 (The price they are selling it at is higher, incorrect)
---------------------------------------------------------------------------------------
Its really easy if you put your mind into it! Goodluck <3
The price of a technology stock was $9.66 yesterday. Today, the price fell to $9.55. Find the percentage decrease.
Find the amount that results from investing $5000 at 3% compounded continuously for 5 years. Round your
answer to two decimal places.
Answer:
The amount that results from investing $5000 at 3% compounded continuously for 5 years is $5800
Step-by-step explanation:
We are given:
Principal Amount (P) = $5000
Years (t) = 5
Rate (r) = 3% or 0.03
We need to find New Amount (A)
The formula used is: [tex]A=P(1+\frac{r}{n})^{nt}[/tex]
Since amount is compounded continuously so n=1
Putting values and finding A
[tex]A=P(1+\frac{r}{n})^{nt}\\A=5000(1+\frac{0.03}{1})^{1*5}\\A=5000(1+0.03)^5\\A=5000(1.03)^5\\A=5000(1.16)\\A=5800[/tex]
So, New Amount (A) = $5800
The amount that results from investing $5000 at 3% compounded continuously for 5 years is $5800
Consider the system of equations below. What could be the first step in solving by elimination?
The first step would be to multiply the bottom equation by -1 to eliminate x, then you would combine like terms, like 5y + 2y, and 16 + 10.
Answer:
Subtracting the 2 equations
Step-by-step explanation:
3x + 5y = 16
3x + 2y = 10
Subtract it;
3y = 6
Divide both sides b 3;
y = 2
Substitute y;
3x + 5y = 16
3x + 5(2) = 16
3x + 10 = 16
Subtract 10 from both sides;
3x = 6
Divide both sides by 3;
x = 2
(x, y) = (2, 2)
A jogger is running home. His distance from home, as a function of time, is modeled by y=-7x +8.
Which statement best describes the function?
A. The function is nonlinear.
B. Not enough information is given.
C. The function is linear at some points and nonlinear at other points.
D. The function is linear.
Answer: the function is a liner
Step-by-step explanation: trust
simplify (3x+2) (y-2) - (7y+3) (y-3)
Answer:
3 x y − 7 y 2 − 6 x + 20 y + 5
Step-by-step explanation:
Suppose that $2000 is placed in a savings account at an annual rate of 4.6%, compounded quarterly. Assuming that no withdrawals are made, how long will it take for the account to grow to $3000? Do not round any intermediate computations, and round your answer to the nearest hundredth.
If necessary, refer to the list of financial formulas.
Answer:
It will take 35.46 quarters for the account to grow to $3000.
Step-by-step explanation:
Since the annual rate is compounded quarterly, this can be calculated using the formula for calculating the future value as follows:
FV = PV * (1 + r)^n ............................ (1)
Where;
FV = future value or the amount the deposit expected to grow to = $3,000
PV = Present value or the amount place in the savings = $2,000
r = Quarterly rate = Annual rate / 4 = 4.6% / 4 = 0.046 / 4 = 0.0115
n = number of quarters it will take for the loan to grow to $3000 = ?
Substituting the values into equation (1) and solve for n, we have:
$3,000 = $2,000 * (1 + 0.0115)^n
$3,000 / $2,000 = (1.0115)^n
1.50 = (1.0115)^n
Loglinearise both sides, we have:
log(1.50) = n log(1.0115)
0.176091259055681 = n * 0.00496588710682352
n = 0.176091259055681 / 0.00496588710682352
n = 35.4601816891322
Rounding to the nearest hundredth, which also implies to rounding to 2 decimal places, we have:
n = 35.46
Since the the annual rate is compounded quarterly, it will therefore take 35.46 quarters for the account to grow to $3000.
Suppose that $2000 is placed in a savings account at an annual rate of 4.6%, compounded quarterly. Assuming that no withdrawals are made, it will take him 8.86 years for the account to grow to $3000
From the information given:
The principal amount placed in the savings account (P) = 2000The annual interest rate = 4.6%number of times interest is compounded n = 4By using the compound interest formula:
[tex]\mathbf{A = P( 1+\dfrac{r}{n})^{nt}}[/tex]
replacing the values from above, we have:
[tex]\mathbf{3000= 2000( 1+\dfrac{0.046}{4})^{4t}}[/tex]
[tex]\mathbf{\dfrac{3000}{2000}= ( 1+\dfrac{0.046}{4})^{4t}}[/tex]
[tex]\mathbf{\dfrac{3000}{2000}= ( 1+0.0115)^{4t}}[/tex]
[tex]\mathbf{\dfrac{3000}{2000}= ( 1.0115)^{4t}}[/tex]
[tex]\mathbf{log(\dfrac{3000}{2000})= 4t \times log ( 1.0115)}[/tex]
[tex]\mathbf{0.17609= 4t \times0.004966}[/tex]
[tex]\mathbf{t = \dfrac{0.17609}{4 \times 0.004966 }}[/tex]
t = 8.86 years to the nearest hundredth.
Learn more about compound interest here:
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ion f (x) = -2(x+8)+11
Standard form
A computer manufacturer built a new facility for assembling computers. There were construction and new equipment costs. The company paid for these costs and made combined profits of $40 million after 4 years, while profits increased $30 million per year. Select the correct graph of this function. (2 points)
A)There is a graph of a line that has a y intercept that is approximately $80 million and passes through the point of approximately x equals 2 years and y equals $140 million.
B)There is a graph of a line that has a y intercept that is approximately negative $80 million and an x intercept that is approximately 2.7 years.
C)There is a graph of a line that has a y intercept that is approximately negative $45 million and an x intercept that is approximately 2 years.
D)There is a graph of a line that has a y intercept that is approximately negative $45 million and an x intercept that is approximately 0.6 years.
Answer:
I am not really good at this but...if I had to choose the ones that make sense
A and B
Step-by-step explanation:
Your are incresing the amount is going up, so if you go backwards you woild have to the negatuves.
Then again I woild not trust my math for the second answer cause I am no good at math.
If I work four days from 6-4:30 and earn $600. How much of taxes is being taken off my check
Answer:
80$
Step-by-step explanation:
S= √3+2√3+3√3+...10√3
write S as a√3
Answer:
S = 55√3Step-by-step explanation:
S=
√3+2√3+3√3+...10√3 =√3( 1 + 2 + 3+...+ 10) =√3(1/2)(10)(10 + 1) =√3(55) =55√3S = 55√3
Answer:
s=✓3(1+2+3+...10)
s=✓3[10/2×(10+1)]
here, applying sum of 1st n natural number is n/2×(n+1)
so, s=✓3×5×11
hence, s=55✓3.
Does anyone know the solution to this question
Answer:
Graph A
Step-by-step explanation:
3x+y=5
y=-3x+5
4x-y=2
-y=-4x+2
4=2x-2
-4x+6y=-7
-13x-2y=-4
Elimination or substitution
Answer:
substitution
Step-by-step explanation:
Write the fractional equivalent (in reduced form) to each number
10
0.125 =
0.16
Consider the feasible region in the xy-plane defined by the following linear inequalities.
x≥0
y ≥0
x ≤ 10
x +y≥ 5
x + 2y ≤ 18
Part 2 Exercises:
1. Find the coordinates of the vertices of the feasible region. Clearly show how each vertex is determined and which lines form the vertex.
2. What is the maximum and the minimum value of the function Q = 60x+78y on the feasible region?
Answer:
1. (0,5), (0,9), (10,4), (10,0), (5,0)
2. [tex]Q_{max}=912[/tex]
[tex]Q_{min}=300[/tex]
Step-by-step explanation:
1.
In order to determine the coordinates of the vertices of the feasible region, we must first graph each of the inequalities. The feasible region is the region where all the inequalities cross each other. In this case it's the region shaded on the attached picture.
The first point is the intercept between the equations x=0 and x+y=5 so in order to find this first coordinate we need to substitute x=0 and solve for y.
0+y=5
y=5
(0,5)
The next point is the intercept between the equations x=0 and x+2y=18, so again, we substitute x for zero and solve for y:
0+2y=18
[tex]y=\frac{18}{2}[/tex]
y=9
(0,9)
The next coordinate is the intercept between the lines x=10 and x+2y=18, so we substitute x for 10 and solve for y:
10+2y=18
2y=18-10
2y=8
[tex]y=\frac{8}{2}[/tex]
y=4, so the oint is
(10,4)
The next point is the intercept between the lines x=10 and y=0, so the point is:
(10,0)
The final point is the intercept between the equations: y=0 and x+y=5. We substitute y for zero and solve for x:
x+0=5
x=5
so the point is:
(5,0).
2. In order to determine the maximum and minimum value of the function Q=60x+78y on the feasible region, we must evaluate it for each of the points found on part 1.
(0,5)
Q=60(0)+78(5)
Q=390
(0,9)
Q=60(0)+78(9)
Q=702
(10,4)
Q=60(10)+78(4)
Q=912
(10,0)
Q=60(10)+78(0)
Q=600
(5,0)
Q=60(5)+78(0)
Q=300
So now we compare the answers and pick the minimum and maximum results.
We get that:
[tex]Q_{max}=912[/tex]
when x=10 and y=4
and
[tex]Q_{min}=300[/tex]
When x=5 and y=0
The feasible region is the possible set of a constraint
The vertices are: [tex]\mathbf{(x,y) \to (0,5), (0,9), (5,0)}[/tex]The maximum and the minimum values are 702 and 300, respectively.(a) The coordinates of the vertices at the feasible region
The constraints are given as:
[tex]\mathbf{x \ge 0}[/tex]
[tex]\mathbf{y \ge 0}[/tex]
[tex]\mathbf{x \le 0}[/tex]
[tex]\mathbf{x + y\ge 5}[/tex]
[tex]\mathbf{x + 2y\ge 18}[/tex]
See attachment for the graph of the constraints
From the graph, the vertices are:
[tex]\mathbf{(x,y) \to (0,5), (0,9), (5,0)}[/tex]
(b) The minimum and the maximum values of objective function Q
The objective function is:
[tex]\mathbf{Q=60x +78y}[/tex]
Substitute [tex]\mathbf{(x,y) \to (0,5), (0,9), (5,0)}[/tex] in Q
[tex]\mathbf{Q=60(0) +78(5) = 390}[/tex]
[tex]\mathbf{Q=60(0) +78(9) = 702}[/tex]
[tex]\mathbf{Q=60(5) +78(0) = 300}[/tex]
Hence, the maximum and the minimum values are 702 and 300, respectively.
Read more about feasible regions at:
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Juan got grades of 68 and 73 on his first two math tests. What grade must he get on the third test if all were weighted equally and he wants to raise his grade to a 75 average?
Answer: 84
Step-by-step explanation: Multiply 75 by 3. That is 225, and is the value the three numbers must add up to. 73+68=141. 225-141 is 84.
Andre looks at a box of paper clips. He says: "I think the number of paper clips in the box is less than 1,000."
Lin also looks at the box. She says: "I think the number of paper clips in the box is more than 500."
Choose an inequality to show Andre's statement, using LaTeX: p
p
p
for the number of paper clips.
Group of answer choices
p > 1000
1000 > p
Answer:
Andre says: "I think the number of paper clips in the box is less than 1000.
The equality that shows Andre's statement, or information:
p p p (for the number of clips)
So,
p>1000
1000>p
Hope that helps...
What is the answer to
5 + 3 x 3x -2 X=2
Answer:
x = 1/6
Step-by-step explanation:
Liam had a container of oatmeal that contained 5 and one-half cups of oatmeal. Liam ate StartFraction 4 over 9 EndFraction cup of oatmeal every morning before school for a week. Which is the best estimate of the number of cups of oatmeal that Liam had left in the container at the end of the five-day week?
2 and one-half
3
3 and one-half
5
Answer:
3
Step-by-step explanation:
What is the decimal expansion for 14 over 33?
Hi! I believe your answer is 0.42, (simplified form of 0.42424242424) which is 14/33 (or [tex]\frac{14}{33}[/tex] ) as a decimal. I hope this helps you! Good luck and have a great day. ❤️✨
A XYZ is translated left 4 units to form the image A X'Y'Z'.
What are the coordinates of the vertices of A X'Y'Z' ?
Enter your answer by filling in the boxes.
Plz Help
Answer:
y(1,6) x(-4,6) z(1,1)
Step-by-step explanation:
Answer:
X(-8,6)Y(-3,6)Z(-3,1)
Step-by-step explanation:
just moving the coordinate over to the left 4 times
A train travels at 45 mph for 3 h and then increases its speed to 55 mph for 2 more hours. How far does the train travel in the 5-hour period
Answer:
245milesStep-by-step explanation:
Step one:
given that the first 3 hours the train travels at a speed of 45 mph.
i.e Time = 3 hours
speed =45 mph
distance=?
we know that speed = distance/time
distance= speed*time
distance= 45*3
distance=135miles
Step two:
For the nex two hours it travels at 55 mph
i.e time= 2hours
speed= 55mph
distance=?
distance= speed*time
distance= 2*55
distance= 110mile
Step three:
Hence for a total of 5 hours drive, the total distance covered is
135+110= 245miles
Consider the limaçon with equation r = 3 + 4cos(θ). How does the quotient of a and b relate to the existence of an inner loop?
A polar graph that is a limacon has a formula similar to [tex]r=a+bcos\theta[/tex]
Option B is correct.
A limacon has a formula similar to [tex]r=a+bcos\theta[/tex]
Case 1 . If a < b or [tex]\frac{b}{a}>1[/tex]
Then the curve is limacon with an inner loop.
Case 2. If a>b or [tex]\frac{b}{a}<1[/tex]
Then the limacon does not have an inner loop.
Here, given that, [tex]r=3+4cos\theta[/tex]
It is observed that, a < b or [tex]\frac{b}{a}>1[/tex]
Therefore, the curve is limacon with an inner loop.
Hence, option B is correct.
Learn more:
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