Solve four ninths minus four tenths equals blank.

Help Me ASAP

Answer:

3.93700787 Inch

Step-by-step explanation:

:)

Answer:

3.93701

Step-by-step explanation:

In order to convert cm into inches you divide the cm by 2.54.

Hi! I believe your answer is 0.42, (simplified form of 0.42424242424) which is 14/33 (or [tex]\frac{14}{33}[/tex] ) as a decimal. I hope this helps you! Good luck and have a great day. ❤️✨

Answer:

I am not really good at this but...if I had to choose the ones that make sense

A and B

Step-by-step explanation:

Your are incresing the amount is going up, so if you go backwards you woild have to the negatuves.

Then again I woild not trust my math for the second answer cause I am no good at math.

Answer:

y(1,6) x(-4,6) z(1,1)

Step-by-step explanation:

Answer:

X(-8,6)Y(-3,6)Z(-3,1)

Step-by-step explanation:

just moving the coordinate over to the left 4 times

Answer:

20 gallons

Step-by-step explanation:

First start off by dividing 48 by 12 to see how many times 12 goes into 48.

48 / 12 = 4

now that you know that 12 goes into 48 4 times, multiply 4 by 5 to see how many gallons the leaky faucet will fill in 48 hours.

4 x 5 = 20

therefore the answer is 20 gallons

I hope this helps ^^

hi there! here's my answer for you...

Answer:

slope:

m = -3/4

y-intercept:

y = −3x/4 + 9/4

hope this helped. have a good one!

Answer:

3

Step-by-step explanation:

Answer:

80$

Step-by-step explanation:

Answer:

2/3

Step-by-step explanation:

1/2 dresses = 36x1/2 = 18

18 dresses in 3/4 hr. ==> 1/4hr ==> 18/3 = 6

1hr ==> 6x4 = 24

fraction = 24/36 = 2/3

Answer:

Andre says: "I think the number of paper clips in the box is less than 1000.

The equality that shows Andre's statement, or information:

p p p (for the number of clips)

So,

p>1000

1000>p

Hope that helps...

Answer:

Its A

Step-by-step explanation:

Answer:

[tex]the \: solution \: set \:is \to \{{-6, 6} \}[/tex]

A polar graph that is a limacon has a formula similar to [tex]r=a+bcos\theta[/tex]

Option B is correct.

A  limacon has a formula similar to [tex]r=a+bcos\theta[/tex]

Case 1 .  If  a < b  or  [tex]\frac{b}{a}>1[/tex]

Then the curve is limacon with an inner loop.

Case 2.  If  a>b   or   [tex]\frac{b}{a}<1[/tex]

Then the limacon does not have an inner loop.

Here, given that,  [tex]r=3+4cos\theta[/tex]

It is observed that,  a < b  or [tex]\frac{b}{a}>1[/tex]

Therefore, the curve is limacon with an inner loop.

Hence, option B is correct.

Learn more:

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Answer:

It will take 35.46 quarters for the account to grow to $3000.

Step-by-step explanation:

Since the annual rate is compounded quarterly, this can be calculated using the formula for calculating the future value as follows:

FV = PV * (1 + r)^n ............................ (1)

Where;

FV = future value or the amount the deposit expected to grow to = $3,000

PV = Present value or the amount place in the savings = $2,000

r = Quarterly rate = Annual rate / 4 = 4.6% / 4 = 0.046 / 4 = 0.0115

n = number of quarters it will take for the loan to grow to $3000 = ?

Substituting the values into equation (1) and solve for n, we have:

$3,000 = $2,000 * (1 + 0.0115)^n

$3,000 / $2,000 = (1.0115)^n

1.50 = (1.0115)^n

Loglinearise both sides, we have:

log(1.50) = n log(1.0115)

0.176091259055681 = n * 0.00496588710682352

n = 0.176091259055681 / 0.00496588710682352

n = 35.4601816891322

Rounding to the nearest hundredth, which also implies to rounding to 2 decimal places, we have:

n = 35.46

Since the the annual rate is compounded quarterly, it will therefore take 35.46 quarters for the account to grow to $3000.

Suppose that $2000 is placed in a savings account at an annual rate of 4.6%, compounded quarterly. Assuming that no withdrawals are made, it will take him 8.86 years for the account to grow to $3000

From the information given:

By using the compound interest formula:

[tex]\mathbf{A = P( 1+\dfrac{r}{n})^{nt}}[/tex]

replacing the values from above, we have:

[tex]\mathbf{3000= 2000( 1+\dfrac{0.046}{4})^{4t}}[/tex]

[tex]\mathbf{\dfrac{3000}{2000}= ( 1+\dfrac{0.046}{4})^{4t}}[/tex]

[tex]\mathbf{\dfrac{3000}{2000}= ( 1+0.0115)^{4t}}[/tex]

[tex]\mathbf{\dfrac{3000}{2000}= ( 1.0115)^{4t}}[/tex]

[tex]\mathbf{log(\dfrac{3000}{2000})= 4t \times log ( 1.0115)}[/tex]

[tex]\mathbf{0.17609= 4t \times0.004966}[/tex]

[tex]\mathbf{t = \dfrac{0.17609}{4 \times 0.004966 }}[/tex]

t = 8.86 years to the nearest hundredth.

Learn more about compound interest here:

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Answer:

12 inches

Step-by-step explanation:

We can write this as a proportion:

inches/miles = inches/miles

1/10 = x/120

Solving for x, we get 12 inches.

Answer:

3 x y − 7 y 2 − 6 x + 20 y + 5

Step-by-step explanation:

Answer:

substitution

Step-by-step explanation:

Answer: y>-2

Step-by-step explanation:

8y-3(y-2) < 2y+4(2y+4)

8y-3y+6 < 2y+8y+16

6-16<2y+8y-8y+3y

-10<5y

y>-2

Answer:

(−∞,−2)

Step-by-step explanation:

Start by simplifying each side as much as possible by distributing and combining like terms to get

8y−3(y−2)8y−3y+65y+6>2y+4(2y+4)>2y+8y+16>10y+16

Subtract 10y from both sides to collect the variables on the left, then subtract 6 from both sides to collect all the constants on the right.

5y+65y+6−10y−5y+6−5y+6−6−5y>10y+16>10y+16−10y>16>16−6>10

Divide each side by −5 to solve for y. Since −5<0, the inequality changes direction.

−5y−5y−5y>10<10−5<−2

In interval notation, we write this as (−∞,−2).

Answer:

1. (0,5), (0,9), (10,4), (10,0), (5,0)

2. [tex]Q_{max}=912[/tex]

[tex]Q_{min}=300[/tex]

Step-by-step explanation:

1.

In order to determine the coordinates of the vertices of the feasible region, we must first graph each of the inequalities. The feasible region is the region where all the inequalities cross each other. In this case it's the region shaded on the attached picture.

The first point is the intercept between the equations x=0 and x+y=5 so in order to find this first coordinate we need to substitute x=0 and solve for y.

0+y=5

y=5

(0,5)

The next point is the intercept between the equations x=0 and x+2y=18, so again, we substitute x for zero and solve for y:

0+2y=18

[tex]y=\frac{18}{2}[/tex]

y=9

(0,9)

The next coordinate is the intercept between the lines x=10 and x+2y=18, so we substitute x for 10 and solve for y:

10+2y=18

2y=18-10

2y=8

[tex]y=\frac{8}{2}[/tex]

y=4, so the oint is

(10,4)

The next point is the intercept between the lines x=10 and y=0, so the point is:

(10,0)

The final point is the intercept between the equations: y=0 and x+y=5. We substitute y for zero and solve for x:

x+0=5

x=5

so the point is:

(5,0).

2. In order to determine the maximum and minimum value of the function Q=60x+78y on the feasible region, we must evaluate it for each of the points found on part 1.

(0,5)

Q=60(0)+78(5)

Q=390

(0,9)

Q=60(0)+78(9)

Q=702

(10,4)

Q=60(10)+78(4)

Q=912

(10,0)

Q=60(10)+78(0)

Q=600

(5,0)

Q=60(5)+78(0)

Q=300

So now we compare the answers and pick the minimum and maximum results.

We get that:

[tex]Q_{max}=912[/tex]

when x=10 and y=4

and

[tex]Q_{min}=300[/tex]

When x=5 and y=0

The feasible region is the possible set of a constraint

(a) The coordinates of the vertices at the feasible region

The constraints are given as:

[tex]\mathbf{x \ge 0}[/tex]

[tex]\mathbf{y \ge 0}[/tex]

[tex]\mathbf{x \le 0}[/tex]

[tex]\mathbf{x + y\ge 5}[/tex]

[tex]\mathbf{x + 2y\ge 18}[/tex]

See attachment for the graph of the constraints

From the graph, the vertices are:

[tex]\mathbf{(x,y) \to (0,5), (0,9), (5,0)}[/tex]

(b) The minimum and the maximum values of objective function Q

The objective function is:

[tex]\mathbf{Q=60x +78y}[/tex]

Substitute [tex]\mathbf{(x,y) \to (0,5), (0,9), (5,0)}[/tex] in Q

[tex]\mathbf{Q=60(0) +78(5) = 390}[/tex]

[tex]\mathbf{Q=60(0) +78(9) = 702}[/tex]

[tex]\mathbf{Q=60(5) +78(0) = 300}[/tex]

Hence, the maximum and the minimum values are 702 and 300, respectively.

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Answer: 84

Step-by-step explanation: Multiply 75 by 3. That is 225, and is the value the three numbers must add up to. 73+68=141. 225-141 is 84.

Answer:

Step-by-step explanation:

S=

S = 55√3

Answer:

s=✓3(1+2+3+...10)

s=✓3[10/2×(10+1)]

here, applying sum of 1st n natural number is n/2×(n+1)

so, s=✓3×5×11

hence, s=55✓3.

Answer:

Determination of the Finance Charge, Carry-over balance, Minimum Payment for each of the next two months:

Finance Charge:

First month = $7.91

Second month = $7.72

Carry-over balance:

First month = $487.59

Second month = $475.50

Minimum Payment:

First month = $20.32

Second month = $19.81

Starting balance (Carry-over balance + Finance charge):

First month = $507.91

Second month = $495.31

Step-by-step explanation:

a) Data and Calculations:

Credit Finance = $500

APR = 18.99%

Minimum monthly payment = 4% of the balance

Monthly rate of interest = 0.1899/12 = 0.015825

Finance Charge:

First month = $7.91 ($500 * 0.015825)

Second month = $7.72 ($487.59 * 0.015825)

Carry-over balance:

First month = $487.59($507.91 - $20.32)

Second month = $475.50 ($495.31 - $19.81)

Minimum Payment:

First month = $20.32 ($507.91 * 4%)

Second month = $19.81 ($495.31 * 4%)

Starting balance (Carry-over balance + Finance charge):

First month = $507.91 ($500 + $7.91)

Second month = $495.31 ($487.59 + $7.72)

Answer:

Graph A

Step-by-step explanation:

3x+y=5

y=-3x+5

4x-y=2

-y=-4x+2

4=2x-2

9514 1404 393

Answer:

  $7,358

Step-by-step explanation:

Assuming the interest is compounded annually, the amortization formula is useful here.

  A = Pr/(1 -(1+r)^-t)

A is the annual scholarship, P is the principal invested at rate r for t years.

  A = $100,000(0.04)/(1 -1.04^-20) = $7,358.18

The university could give $7,358 in scholarships each year.

Answer: the function is a liner

Step-by-step explanation: trust

Answer:

you forgot the picture

Step-by-step explanation:

Please put a picture