Researchers study the relationship between interpersonal violence and health in college age women. The selected an alpha of 0.05. The researchers wanted to see if there was a significant difference in the type of primary residence (home vs. student housing) for abused versus non abused college aged women. They report a p value of 0.35. You know this means:
Select There is an inadequate sample size. as your answer
There is an inadequate sample size.
Select A type II error has occurred. as your answer
A type II error has occurred.
Select There is a statistically significant difference in the type of primary residence for abused vs. non-abused college aged women. as your answer
There is a statistically significant difference in the type of primary residence for abused vs. non-abused college aged women.
Select There is not a statistically significant difference in the type of primary residence for abused vs. non-abused college aged women. as your answer
There is not a statistically significant difference in the type of primary residence for abused vs. non-abused college aged women.

Answers

Answer 1

Answer:

Explained below.

Step-by-step explanation:

A statistical hypothesis test is being performed to determine whether there was a significant difference in the type of primary residence (home vs. student housing) for abused versus non abused college aged women.

The hypothesis can be defined as:

H₀: There is no difference in the type of primary residence or abused versus non abused college aged women.

Hₐ: There is a significant difference in the type of primary residence or abused versus non abused college aged women.

The significance level of the test is:

α = 0.05

The computed p-value is:

p-value = 0.35

p-value = 0.35 > α = 0.05

The null hypothesis will not be rejected.

The p-value is inversely related to the sample size of the test.

That is, larger the sample size smaller is the p-value and smaller the sample size larger is the p-value.

A p-value of 0.35 is very large and unusual. This can happen because of the inadequate sample size selected.

As the p-value indicates an unusual result, it can be said that an error has been made while concluding that the null hypothesis is true, when in fact it is not.

This type of error is known as the type II error.

The correct decision should be:

There is a statistically significant difference in the type of primary residence for abused vs. non-abused college aged women.


Related Questions



How can this fact family model help us compare the
numbers shown? You can use the number line to help
you complete each statement.
The sum of 3 and 7 is
10 is
bigger than 3
bigger than 7
10 is
7

Answers

Answer:

The sum of 3 and 7 is - 1010 is - bigger than 77 - bigger than 3

Step-by-step explanation:

Hope it helps.

Answer:

The sum of 3 and 7 is ( 10 ).10 is ( 7 ) bigger than 3.

10 is ( 3 ) bigger than 7.

Lee watches TV for 2 hours per day. During that time, the TV consumes 150 watts per hour. Electricity costs (12 cents)/(1 kilowatt-hour). How much does Lee's TV cost to operate for a month of 30 days?

Answers

Answer:

$1.08

Step-by-step explanation:

30 days × (2 hrs/day) × (150 W) × (1 kW / 1000 W) × (0.12 $/kWh) = $1.08

simplify - long division symbol -48

Answers

Answer: [tex]4\sqrt{3}[/tex]

Step-by-step explanation:

Wow, this confused me for a while.  What you think is a long division symbol is actually a radical, in this case a square root.  Thus, it is actually asking for the square root of 48, which can be simplified into [tex]4\sqrt{3}[/tex]

Hope it helps, and if you want me to explain radicals a bit, just ask <3

Invoice Date Terms Date Goods Received June 28 4/8 ROM July 27

Answers

Answer:

The answer is "August 4".

Step-by-step explanation:

In the given discount term after receipt of the dates is [tex]\bold{\frac{4}{8}}\\\\[/tex] ROM, which can be defined as follows:

[tex]\Rightarrow 27 \ July + 8 \\\\\Rightarrow 4 \ August[/tex]

That's why the final answer is 'August  4'.

The population of Adamsville grew from 6000 to 13000 in 7 years. Assuming uninhibited exponential growth, what is the expected population in an additional 3 years?

Answers

Answer:

18107.32

Step-by-step explanation:

Set up the exponential function in the form:

       [tex]P = P_0(R)^t[/tex]

so P is the new population, [tex]P_0[/tex] is the original population, R is the rate of increase in population, and t is the time in years.

You have to use the information given to find the rate that the population is increasing and then use that rate to find the new population after more time passes.

[tex]13000 = 6000(R)^7\\\\\\frac{13000}{6000} = R^7\\\\\sqrt[7]{\frac{13000}{6000} } = R\\\\\\ R = 1.116786872[/tex]

Now that you found the rate, you can use the function to find the population after another 3 years.

[tex]P = 13000(1.116786872)^3\\P = 18107.32317\\[/tex]

So the population is 18107, rounded to the nearest whole number.

El costo de pintar un muro se calcula con un tercio del doble del área por el triple del numero de trabajadores. Si se planea pintar un muro de 1200m² y se contrataran a 3 trabajadores. ¿Cuanto se pagara?

Answers

Answer:

Se pagará $7200.

Step-by-step explanation:

La ecuación del costo puede descomponerse en dos factores que luego se multiplican:

1) Siendo A el area del del muro, la parte del costo que depende del área se calcula como un tercio (1/3) del doble (2) del área A. Este factor se puede escribir como:

[tex]C_1=(1/3)\cdot 2 \cdot A=(2/3)\cdot A[/tex]

2) Siendo T el número de trabajadores, el siguiente factor es el triple del numero de trabajadores T. Esto es:

[tex]C_2=3T[/tex]

Multiplicando ambos factores, tenemos la ecuacion del costo en función de A y T:

[tex]C=C_1\cdot C_2=(2/3)A\cdot 3T=2 AT[/tex]

Si se planea pintar un muro de 1200m² y se contrataran a 3 trabajadores, el costo será:

[tex]C=2AT=2(1200)(3)=7200[/tex]

Currently, I am $9$ times as old as my son. Next year, I will be $7$ times as old as my son. How old is my son now?

Answers

Answer:

He is 3 years old.

Step-by-step explanation:

3 times 9 is 27. She is 9 times older than her 3 year old son.

Next year he will be 4 and she will be 28. 4 times 7 is 28. She will be 7 times older than her son.

Answer:

The son is 3 years now.

Step-by-step explanation:

Let x and y represent his age and his son's age respectively.

Given;

I am $9$ times as old as my son

9y = x ........1

Next year, I will be $7$ times as old as my son.

7(y+1) = x + 1 ....2

Substituting equation 1 to 2;

7(y+1) = 9y + 1

7y + 7 = 9y + 1

Collecting the like terms

9y - 7y = 7 -1

2y = 6

y = 6/2 = 3

Since x = 9y

x = 9(3)

x = 27

The son is 3 years and he is 27 years now.

[tex]5(2x-7)+42-3x=2[/tex]

Answers

Answer:

[tex]\displaystyle x=- \frac{5}{7}[/tex]

Step-by-step explanation:

[tex]5(2x-7)+42-3x=2[/tex]

Expand brackets.

[tex]10x-35+42-3x=2[/tex]

Combine like terms.

[tex]10x-3x+42-35=2[/tex]

[tex]7x+7=2[/tex]

Subtract 7 on both sides.

[tex]7x+7-7=2-7[/tex]

[tex]7x=-5[/tex]

Divide both sides by 7.

[tex]\frac{7x}{7} =\frac{-5}{7}[/tex]

[tex]x=- \frac{5}{7}[/tex]

Answer:

[tex] \boxed{\sf x = - \frac{5}{7}} [/tex]

Step-by-step explanation:

[tex] \sf Solve \: for \: x: \\ \sf \implies 5(2x-7)+42-3x=2 \\ \\ \sf 5(2x - 7) = 10x - 35 : \\ \sf \implies \boxed{ \sf 10x - 35} - 3x + 42 = 2 \\ \\ \sf Grouping \: like \: terms, \: 10x - 35 - 3x + 42 = \\ \sf (10x - 3x) + ( - 35 + 42) : \\ \sf \implies \boxed{ \sf (10x - 3x) + ( - 35 + 42)} = 2 \\ \\ \sf 10x - 3x = 7x : \\ \sf \implies \boxed{ \sf 7x} + ( - 35 + 42) = 2 \\ \\ \sf 42 - 35 = 7 : \\ \sf \implies 7x + \boxed{ \sf 7} = 2 \\ \\ \sf Subtract \: 7 \: from \: both \: sides: \\ \sf \implies 7x + (7 - \boxed{ \sf 7}) = 2 - \boxed{ \sf 7} \\ \\ \sf 7 - 7 = 0 : \\ \sf \implies 7x = 2 - 7 \\ \\ \sf 2 - 7 = - 5 : \\ \sf \implies 7x = \boxed{ \sf - 5} \\ \\ \sf Divide \: both \: sides \: of \: 7x = - 5 \: by \: 7: \\ \sf \implies \frac{7x}{7} = \frac{ - 5}{7} \\ \\ \sf \frac{7}{7} = 1 : \\ \\ \sf \implies x = - \frac{5}{7} [/tex]

A cat gave birth to 3333 kittens who each had a different mass between 147147147147 and 159 g159\,\text{g}159g159, start text, g, end text. Then, the cat gave birth to a 4th4^{\text{th}}4th4, start superscript, start text, t, h, end text, end superscript kitten with a mass of 57 g57\,\text{g}57g57, start text, g, end text. [Show data] How will the birth of the 4th4^{\text{th}}4th4, start superscript, start text, t, h, end text, end superscript kitten affect the mean and median? Choose 1 answer: Choose 1 answer: (Choice A) A Both the mean and median will decrease, but the median will decrease by more than the mean. (Choice B) B Both the mean and median will decrease, but the mean will decrease by more than the median. (Choice C) C Both the mean and median will increase, but the median will increase by more than the mean. (Choice D) D Both the mean and median will increase, but the mean will increase by more than the median.

Answers

Answer:

The correct option is (B).

Step-by-step explanation:

The median (m) is a measure of central tendency. To obtain the median, we assemble the data in arising order. If the data is odd, the median is the mid-value. If the data is even, the median is the arithmetic-mean of the two mid-values.

The mean of a data set is:

[tex]\bar X=\frac{1}{n}\sum\limits^{n}_{x=0}{X}[/tex]

For the three kittens it is provided that the weights are in the range 147 g to 159 g.

So, the mean and median weight for the 3 kittens lies in the middle of this range.

Now a fourth kitten is born, with weight 57 g.

Now the range of the weight of 4 kittens is, 57 g to 159 g.

The mean is going to decrease as one more value is added to the data and the value is the least.

The median will also decrease because now the median will be mean of the 2nd and 3rd values.

But the mean would decrease more than the median because a smaller value is added to the data.

Thus, the correct option is (B).


The table shows the temperature of an amount of water set on a stove to boil, recorded every half minute.

Answers

Answer:show the table so I can help

Step-by-step explanation:

The largest fish ever caught in Lake A weighed 650 pounds. This is 208.2 pounds less than seven times the weight of the largest fish ever caught in Lake B. Find the weight of the largest fish caught in Lake B nts​

Answers

Answer:

122.6 pounds

Step-by-step explanation:

Let's call the weight of the largest fish from lake A 'x', and the weight of the largest fish from lake B 'y'.

If x is 208.2 pounds less than seven times y, we have that:

[tex]x = 7y - 208.2[/tex]

We know that x is equal 650 pounds, so we can find y:

[tex]650 = 7y - 208.2[/tex]

[tex]7y = 650 + 208.2[/tex]

[tex]7y = 858.2[/tex]

[tex]y = 122.6\ pounds[/tex]

So the weight of the largest fish caught in Lake B is 122.6 pounds

If f(x)=8x and g(x)=2x+1, what is (f×g)(x)

Answers

Answer:

(f * g)(x) has a final product of 16x² + 8x.

Step-by-step explanation:

When you see (f * g)(x), this means that we are going to be multiply f(x) and g(x) together.

f(x)=8x

g(x)=2x+1

Now, we multiply these terms together.

(8x)(2x + 1)

Use the foil method to multiply.

16x² + 8x

So, the product of these terms is 16x² + 8x.

What’s the answer to this question?

Answers

Answer: B

Step-by-step explanation:

(f+g)(x) means f(x)+g(x). It is saying to add f(x) and g(x). Since we were given f(x) and g(x), we can directly add them together.

(f+g)(x)=4x+2+x²-6                        [combine like terms]

(f+g)(x)=x²+4x-4

Now that we have found (f+g)(x)=x²+4x-4, the answer is B.

What is the m ZACB?
10°
50°
90°
180°

Answers

Answer:

50 deg

Step-by-step explanation:

In an right triangle, the acute angles are complementary. That means their measures have a sum of 90 deg.

m<C + m<B = 90

7x - 20 + 4x = 90

11x = 110

x = 10

m<ACB= 7x - 20

m<ACB = 7(10) - 20

m<ACB = 70 - 20

m<ACB = 50

Answer: m<ACB = 50 deg

Sample data for the arrival delay times (in minutes) of airlines flights is given below. Determine whether they appear to be from a population with a normal distribution. Assume that this requirement is loose in the sense that the population distribution need not be exactly normal, but it must be a distribution that is roughly bell-shaped Click the icon to view the data set. Is the requirement of a normal distribution satisfied? A. No, because the histogram of the data is not bell shaped, there is more than one outlier, and line points in the normal quantile plot do not lie reasonably close to a straight line.B. Yes, because the histogram of the data is bell shaped, there are less than two outliers, and the line points in the normal quantile plot lie reasonably close to a straight line.C. Yes, because the histogram of the data is not bell shaped, there is more than one outlier, and line points in the normal quantile plot do not lie reasonably close to a straight line.D. No, because the histogram of the data is bell shaped, there are less than two outliers, and the the points in the normal quantile plot do not lie reasonably close to a straight

Answers

Answer:

(Option A) . No, because the histogram of the data is not bell shaped, there is more than one outlier, and line points in the normal quantile plot do not lie reasonably close to a straight line.

Step-by-step explanation:

After plotting the histogram, you will see that the data does not represent the normal distribution because the histogram is not bell shaped and there are two outliers.

PLEASE HELP!!! A LOT OF POINTS AND BRAINLIEST TO CORRECT ANSWERS!!!
1. Find the area of the region enclosed by the graph of [tex]$x^2 + y^2 = 2x - 6y + 6$[/tex].

2. The line [tex]x=4[/tex] is an axis of symmetry of the graph of [tex]$y = ax^2 + bx + c.$[/tex] Find [tex]$\frac{b}{a}$.[/tex].

3. The graph of [tex]$y = ax^2 + bx + c$[/tex] is shown below. Find [tex]$a \cdot b \cdot c$[/tex]. (The distance between the grid lines is one unit, picture of graph attached.)

4. Geometrically speaking, a parabola is defined as the set of points that are the same distance from a given point and a given line. The point is called the focus of the parabola and the line is called the directrix of the parabola. Suppose [tex]$\mathcal{P}$[/tex] is a parabola with focus [tex]$(4,3)$[/tex] and directrix [tex]$y=1$[/tex]. The point [tex]$(8,6)$[/tex] is on [tex]$\mathcal{P}$[/tex] because [tex]$(8,6)$[/tex] is 5 units away from both the focus and the directrix. If we write the equation whose graph is [tex]$\mathcal{P}$[/tex] in the form [tex]$y=ax^2 + bx + c$[/tex], then what is [tex]$a+b+c$[/tex]?

5. (This is a Writing Problem - please please please explain and answer the question thoroughly!) A quadratic of the form [tex]$-2x^2 + bx + c$[/tex] has roots of [tex]$x = 3 + \sqrt{5}$[/tex] and [tex]$x = 3 - \sqrt{5}.$[/tex] The graph of [tex]$y = -2x^2 + bx + c$[/tex] is a parabola. Find the vertex of this parabola.

If you do manage to answer every single one of these correctly, THANK YOU SO MUCH and please know you are very much appreciated! :)

Answers

Answer:

1. [tex]Area=16\,\pi=50.265[/tex]

2.- [tex]\frac{b}{a} =-8[/tex]

3.  [tex]y=\frac{1}{2} x^2+3x+\frac{5}{2}[/tex]

4.  [tex]a+b+c=\frac{17}{4}[/tex]

5.   the vertex is located at: (3, 10)

Step-by-step explanation:

1. If we rewrite the formula of the conic given by completing squares, we can find what conic we are dealing with:

[tex](x^2-2x)+(y^2+6y)=6\\\,\,\,\,\,\,+1\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,+9\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,+10\\(x-1)^2+(y+3)^2=16\\(x-1)^2+(y+3)^2=4^2[/tex]

which corresponds to a circle of radius 4, and we know what the formula is for a circle of radius R, then:

[tex]Area=\pi\,R^2=\pi\,4^2=16\,\pi=50.265[/tex]

2.

If x=4 is the axis of symmetry of the parabola

[tex]y=ax^2+bx+c[/tex]

then recall the formula to obtain the position of the x-value of the vertex:

[tex]x_{vertex}=-\frac{b}{2a} \\4=-\frac{b}{2a}\\4\,(-2)=\frac{b}{a} \\\frac{b}{a} =-8[/tex]

3.  

From the graph attached, we see that the vertex of the parabola is at the point: (-3, -2) on the plane, so we can write the general formula for a parabola in vertex form:

[tex]y-y_{vertex}=a\,(x-x_{vertex})^2\\y-(-2)=a\,(x-(-3))^2\\y+2=a(x+3)^2[/tex]

and now find the value of the parameter "a" by requesting the parabola to go through another obvious point, let's say the zero given by (-1, 0) at the crossing of the x-axis:

[tex]y+2=a\,(x+3)^2\\0+2=a(-1+3)^2\\2=a\,2^2\\a=\frac{1}{2}[/tex]

So the equation of the parabola becomes:

[tex]y+2=\frac{1}{2} (x+3)^2\\y+2=\frac{1}{2} (x^2+6x+9)\\y+2=\frac{1}{2} x^2+3x+\frac{9}{2} \\y=\frac{1}{2} x^2+3x+\frac{9}{2} -2\\y=\frac{1}{2} x^2+3x+\frac{5}{2}[/tex]

4.

From the location of the focus of the parabola as (4, 3) and the directrix as y=1,  we conclude that we have a parabola with dominant vertical axis of symmetry, displaced from the origin of coordinates, and responding to the following type of formula:

[tex](x-h)^2=4\,p\,(y-k)[/tex]

with focus at: [tex](h,k+p)[/tex]

directrix given by the horizontal line [tex]y=k-p[/tex]

and symmetry axis given by the vertical line [tex]x=h[/tex]

Since we are given that the focus is at (4, 3), we know that [tex]h=4[/tex], and that [tex]k+p=3[/tex]

Now given that the directrix is: y = 1, then:

[tex]y=k-p\\1=k-p[/tex]

Now combining both equations with these unknowns:

[tex]k+p=3\\k=3-p[/tex]

[tex]1=k-p\\k=1+p[/tex]

then :

[tex]1+p=3-p\\2p=3-1\\2p=2\\p=1[/tex]

and we now can solve for k:

[tex]k=1+p=1+1=2[/tex]

Then we have the three parameters needed to write the equation for this parabola:

[tex](x-h)^2=4\,p\,(y-k)\\(x-4)^2=4\,(1)\,(y-2)\\x^2-8x+16=4y-8\\4y=x^2-8x+16+8\\4y=x^2-8x+24\\y=\frac{1}{4} x^2-2x+6[/tex]

therefore: [tex]a=\frac{1}{4} , \,\,\,b=-2,\,\,and\,\,\,c=6[/tex]

Then [tex]a+b+c=\frac{17}{4}[/tex]

5.

The vertex of a parabola can easily found because they give you the roots of the quadratic function, which are located equidistant from the symmetry axis. So we know that is one root is at [tex]x=3+\sqrt{5}[/tex]and the other root is at [tex]x=3-\sqrt{5}[/tex]

then the x position of the vertex must be located at x = 3 (equidistant from and in the middle of both solutions. Then we can use the formula for the x of the vertex to find b:

[tex]x_{vertex}=-\frac{b}{2a}\\3=-\frac{b}{2\,(-2)}\\ b=12[/tex]

Now, all we need is to find c, which we can do by using the rest of the quadratic formula for the solutions [tex]x=3+\sqrt{5}[/tex]  and [tex]x=3-\sqrt{5}[/tex] :

[tex]x=-\frac{b}{2a} +/-\frac{\sqrt{b^2-4\,a\,c} }{2\,a}[/tex]

Therefore the amount [tex]\frac{\sqrt{b^2-4\,a\,c} }{2\,a}[/tex],  should give us [tex]\sqrt{5}[/tex]

which means that:

[tex]\sqrt{5}=\frac{\sqrt{b^2-4\,a\,c} }{2\,a} \\5=\frac{b^2-4ac}{4 a^2} \\5\,(4\,(-2)^2)=(12)^2-4\,(-2)\,c\\80=144+8\,c\\8\,c=80-144\\8\,c=-64\\c=-8[/tex]

Ten the quadratic expression is:

[tex]y=-2x^2+12\,x-8[/tex]

and the y value for the vertex is:

[tex]y=-2(3)^2+12\,(3)-8=-18+36-8=10[/tex]

so the vertex is located at: (3, 10)

A number is equal to twice a smaller number plus 3. The same number is equal to twice the sum of the smaller number and 1. How many solutions are possible for this situation? (a)Infinitely many solutions exist because the two situations describe the same line. (b)Exactly one solution exists because the situation describes two lines that have different slopes and different y-intercepts. (c)No solutions exist because the situation describes two lines that have the same slope and different y-intercepts. (d)Exactly one solution exists because the situation describes two lines with different slopes and the same y-intercept.

Answers

Answer:

The correct answer option is: No solutions exist because the situation describes two lines that have the same slope and different y-intercepts.

Monique only has $36 to buy pens and notebooks. Each pen costs $2. Each
notebook costs $3. Which of the following graphs represents the possible
combinations of pens and notebooks that she may purchase?

Answers

Answer:

B.

Step-by-step explanation:

Let's call x the number of pens and y the number of notebooks that Monique can buy.

If each pen costs $2 and each notebook costs $3, so she is going to spend 2*x on pens and she is going to spend 3*y on notebooks.

Additionally, she is going to spend a maximum of $36. so:

2x + 3y [tex]\leq[/tex] 36

It means that the line that  separated the region is:

2x + 3y = 36

This is the same that a line that passes for the points (0,12) and (18,0) or the line of the region B

Select the fraction that is equivalent to 2/6 ?

Answers

Answer:

The fraction that is equivalent to 2/6 is 1/3

10
55:46
Which graph represents a line with a slope of - and a y-intercept equal to that of the line y =
-2/3x-2

Answers

(-1/3,0)for the x intercept and (0,-2) for the y intercept

True or False?
2 is a solution to 8m - 6 < 10
True
False

Answers

Answer:

2 is not a solution

False

Step-by-step explanation:

8m - 6 < 10

Add 6 to each side

8m -6+6 < 10+6

8m < 16

Divide by 8

8m/8 <16/8

m < 2

m must be less than 2

2 is not a solution

Answer:

FALSE

Step-by-step explanation:

Trust Me

Find the values of x and y.[tex]x = 34\sqrt3 y = 17\\x = y = 34, y = 17\sqrt3\\x= y = 17, y = 34\sqrt3\\\\\\x= 17\sqrt3 y = 34[/tex]

Answers

Answer:

The value of "x" is 34 and the value of "y" is 17.

Step-by-step explanation:

"x" is shown as 34 and "y" is shown on the rectangular shape in the number form of 17. If your trying to find the area of the rectangle the area is 578.

I need help please!!!!

Answers

Answer:

1/3( x-5)= -2/3

Multiply both sides by 3

x = 3

Step-by-step explanation:

1/3( x-5)= -2/3

Multiply both sides by 3

3*1/3( x-5)= -2/3*3

x-5 = -2

Add 5 to each side

x-5+5 = -2+5

x = 3

Answer:

1/3( x-5)= -2/3

Multiply both sides by 3

x = 3

Step-by-step explanation:

1/3( x-5)= -2/3

Multiply both sides by 3

3*1/3( x-5)= -2/3*3

x-5 = -2

Add 5 to each side

x-5+5 = -2+5

x = 3

Hope this helps!

Alex is on a boat going to an island twelve miles away for a picnic. The way there, with the current, it takes her 3 hours while the way back, against the current, it takes her 4 hours. What is the speed of her boat and what is the speed of the current?

Answers

Answer:

the boat is going at 3.5 mph and the current is going at .5 mph

Step-by-step explanation:

which inequality represents the statement? the number of new cars(C) a ship carries cant exceed 975.
A. c<975
B. c>975
C. c<(—under<)975
D. c>(—under>)975

Answers

"can't exceed 975" means this is the largest value possible for C. So we could have C = 975 or smaller. We write this as [tex]C \le 975[/tex] which is read as "C is less than or equal to 975".

Answer: Choice C. [tex]C \le 975[/tex]

Answer:

5

Step-by-step explanation:

The top speed you will ever need
to go in a parking lot is
O A. 20 mph
OB. 10 mph
OC. 1 mph
D. 15 mph

Answers

Answer:

10 mph

Step-by-step explanation:

The top speed you will ever need to go in a parking lot is 10 mph.

15 mph is the fastest you should ever drive in a parking lot. The right answer is D.

What is National Motorists Association?

The National Motorists Association was established in 1982 and is a divisive nonprofit advocacy group representing drivers in North America.

The Association promotes engineering standards that have been demonstrated to be effective, justly drafted and applied traffic legislation, and full due process for drivers.

Given to give information about the top speed you will ever need

to go into a parking lot is,

A group of drivers came together to form the National Motorists Association, Inc., a non-profit organization, to defend drivers' rights in the legal system, on the highways, and inside our cars.

Usually, there are marked speed limits in parking lots. Obey speed limits when you see them to avoid tickets and to keep everyone safe.

The National Motorists Association advises driving no faster than 15 miles per hour at all times when there are no written speed limits.

Therefore, the correct option is D.

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Find the value of x and simplify completely.

Answers

Answer:

x=910

Given: A right triangle in which an altitude is drawn from the right angle vertex to the hypotenuse.

To find: 'x' the larger leg of triangle

Solution,

Using let rule for similarity in right triangle:

[tex] \frac{leg}{part} = \frac{hypotenuse}{leg} \\ or \: \frac{x}{27} = \frac{3 + 27}{x} \\ or \: x \times x = 27(3 + 27) \\ or \: x \times x = 81 + 729 \\ or \: {x}^{2} = 810 \\ or \: {x}^{2} = 81 \times 10 \\ or \: {x} = \sqrt{81 \times 10} \\ or \: x = \sqrt{81} \times \sqrt{10} \\ or \: x = \sqrt{ {(9)}^{2} } \times \sqrt{10} \\ \: x = 9 \sqrt{10} [/tex]

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(x + 1) (x+8) multiply binomials and put in standard form.

Answers

Answer:

x² + 9x + 8

Step-by-step explanation:

Step 1: FOIL

x² + 8x + x + 8

Step 2: Combine like terms

x² + 9x + 8

Answer:

x^2 + 9x + 8

Step-by-step explanation:

(x + 1)(x + 8)

x(x + 1) +8(x + 1)

x^2 + x + 8x +8

x^2 + 9x + 8

A coin will be flipped repeatedly until the sequence TTH (tail/tail/head) comes up. Successive flips are independent, and the coin has probability p of coming up heads. Let N,TTH be the number of coin flips until TTH first appears. What value of p minimizes Ex[N,TTH]

Answers

Answer:

[tex]P = \frac{1}{3}[/tex]

Step-by-step explanation:

The calculation of the value of p minimizes is shown below:-

We will assume the probability of coming heads be p

p(H) = p

p(T) = 1 - P

Now, H and T are only outcomes of flipping a coin

So,

P(TTH) = (1 - P) = (1 - P) (1 - P) P

= (1 + P^2 - 2 P) P

= P^3 - 2P^2 + P

In order to less N,TTH

we need to increase P(TTH)

The equation will be

[tex]\frac{d P(TTH)}{dP} = 0[/tex]

3P^2 - 4P + 1 = 0

(3P - 1) (P - 1) = 0

P = 1 and 1 ÷ 3

For P(TTH) to be maximum

[tex]\frac{d^2 P(TTH)}{dP} < 0 for\ P\ critical\\\\\frac{d (3P^2 - 4P - 1)}{dP}[/tex]

= 6P - 4

and

(6P - 4) is negative which is for

[tex]P = \frac{1}{3}[/tex]

Eight times the difference of y and nine

Answers

Answer:

(y-9)8

Step-by-step explanation:

you first solve 8-9, and then multiply is by 8.

Eight times the difference of y and nine will be 8(y - 9).

It should be noted that eight times the difference of y and nine simply means that one has to subtract 9 from y and then multiply the difference by 8.

Therefore, eight times the difference of y and nine will be 8(y - 9).

In conclusion, the correct option is 8(y - 9).

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