Refer to the table summarizing service times​ (seconds) of dinners at a fast food restaurant. How many individuals are included in the​ summary? Is it possible to identify the exact values of all of the original service​ times?
Time (sec) Frequency
60 to 119 7
120 to 179 24
180 to 239 14
240 to 299 1
300 to 359 4

Answer:

x = 4 , ∠ AXC = 150°

Step-by-step explanation:

∠ 1 and ∠ 2 form the angle AXC , that is

∠ AXC = ∠ 1 + ∠ 2 , then

6(6x + 1) = 102 + 10x + 8

36x + 6 = 10x + 110 ( subtract 10x from both sides )

26x + 6 = 110 ( subtract 6 from both sides )

26x = 104 ( divide both sides by 26 )

x = 4

Then by substituting x = 4

∠ AXC = 6(6x + 1) = 36x + 6 = 36(4) + 6 = 144 + 6 = 150°

Answer:

  both are rectangles

Step-by-step explanation:

You want to know what two quadrilaterals each having four right angles have in common.

A quadrilateral with four right angles is called a "rectangle." Each of the figures is a rectangle.

__

Additional comment

There are more general classifications that also apply. The figures are made from line segments connected end-to-end that enclose a space, so they are simple polygons. The adjacent right angles mean the figures have opposite sides parallel, so are parallelograms.

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The calculated value of the rate of the graph is 0.8

from the question, we have the following parameters that can be used in our computation:

The graph

Where, we have

(0, -16) and (20, 0)

The rate of the graph is calculated as

Rate = Change in y/x

using the above as a guide, we have the following:

Rate = (0 + 16)/(20 - 0)

Evaluate

Rate = 0.8

Hence, the rate is 0.8

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The equations of the other line are:

BC: y = 2x

AD: y = 2x + 2

CD = -¹/₂x + 5.5

The formula for the equation of a line between two coordinates is expressed as:

(y - y₁)/(x - x₁) = (y₂ - y₁)/(x₂ - x₁)

Thus, for the lines we have:

BC has B(-2, 4) and C(-1, 6)

Thus:

BC: (y - 4)/(x - 2) = (6 - 4)/(-1 + 2)

BC: (y - 4)/(x - 2) =2

BC: y - 4 = 2x - 4

BC: y = 2x

AD has  A(2,2) and D(3, 4)

Thus:

AD: (y - 2)/(x - 2) = (4 - 2)/(3 - 2)

AD: y - 2 = 2x - 4

AD: y = 2x + 2

CD has C(-1, 6) and D(3, 4)

CD: (y - 6)/(x + 1) = (4 - 6)/4

CD: y - 6 = -¹/₂(x + 1)

CD = -¹/₂x + 5.5

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The length of AB = CD and CD = AB based on the proof that :

Looking at the segments CD and AB, both segments are of equal length, hence they would be equal

Similarly , both segments are parallel and have the same end points. Hence, they are equal.

Therefore, AB = CD

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The recursive function that represents the number of books Ashley has at any time is Number of books(n) = Number of books(n-1) - n, starting at 100.

The recursive function that represents the number of books Ashley has at any time can be defined as follows:

Number of books(n) = Number of books(n-1) - n

Starting point: Number of books(0) = 100

Explanation:

In the recursive function, "n" represents the number of weeks that have passed. Each week, Ashley gives away "n" books. Therefore, the number of books she has at any time is equal to the number of books she had in the previous week (Number of books(n-1)) minus the number of books given away in the current week (n).

The starting point is given as Number of books(0) = 100, which means initially Ashley has 100 books before any weeks have passed.

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In the class , each child needs to pay (n * p) / y shillings to cover the cost of the lost books.

In the given scenario, there is a class of "y" children, and "n" mathematics books were lost, each costing "p" shillings. The teacher decides to distribute the cost of the lost books equally among all the children.

To find out how much money each child needs to pay, we need to divide the total cost of the lost books by the number of children in the class.

The total cost of the lost books can be calculated by multiplying the number of lost books ("n") by the cost of each book ("p").

Total cost = n * p

To distribute the cost equally among all the children, we divide the total cost by the number of children ("y"):

Cost per child = Total cost / Number of children

Substituting the values, we get:

Cost per child = (n * p) / y

Therefore, each child in the class needs to pay (n * p) / y shillings to cover the cost of the lost books.

It's important to note that this calculation assumes that the total cost is evenly distributed among all the children, regardless of whether they were responsible for losing the books or not.

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The approximate mean of the number of cars sold by the salesman in the past 10 weeks is 4.1.

To find the approximate mean, first, we add all the numbers in the data set, and then we divide that sum by the total number of values in the data set.

The formula for finding the approximate mean is as follows: Approximate mean = sum of the values in the data set / total number of values in the data set.

The following data set is given: Number of cars sold by a salesman in the past 10 weeks: 3, 5, 2, 4, 7, 5, 6, 3, 2, 4.

To find the approximate mean, we first need to add all the values: 3 + 5 + 2 + 4 + 7 + 5 + 6 + 3 + 2 + 4 = 41 The sum of all the values is 41.

Next, we need to divide this sum by the total number of values in the data set. In this case, the total number of values is 10. Therefore, the approximate mean for the given data set is: Approximate mean = 41 / 10 = 4.1

Therefore, the approximate mean of the number of cars sold by the salesman in the past 10 weeks is 4.1.

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The solution to the piecewise-defined function is shown in the attached graph.

The function g(x) is defined as follows:

g(x) = -4     if x ≠ 0

g(x) = 5       if x = 0

On the graph, when x is any value other than 0, the function takes the value of -4. This means that there will be a horizontal line at y = -4 for all x ≠ 0. The point (0, 5) will be represented by a solid dot since it's the only point where g(x) equals 5.

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The absolute maximum and minimum values obtained from the graph of the functions are;

Absolute maximum of g; [1, 4]

Absolute minimum of g; [4, -3]

Absolute maximum h; [4, 3]

Absolute minimum of h; (-4, -5)

The absolute maximum and minimum of a function are the coordinates of the highest and lowest points on the graph of the function, within the specified domain.

The points on the graph of the functions indicates that the maximum and minimum values of the functions are;

Graph of g; Absolute maximum of g = (1, 4)

Absolute minimum of g ; [4, -3]

Graph of h

Absolute maximum of h; [4, 3]

Absolute minimum of h; (-4, -5)

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(a) The magnitude of the rod's angular acceleration is (3g/2L) rad/s^2.

(b) The tangential acceleration of the rod's center of mass is (3g/4) m/s^2.

(c) The tangential acceleration of the rod's free end is (3g/2) m/s^2.

(a) To find the magnitude of the rod's angular acceleration, we can use the formula for rotational motion. The torque acting on the rod is due to the gravitational force acting at its center of mass.

The torque is given by τ = Iα, where τ is the torque, I is the moment of inertia, and α is the angular acceleration.

For a thin rod rotating about one end, the moment of inertia is (1/3)ML^2, where M is the mass of the rod and L is its length.

The torque is equal to the product of the gravitational force and the perpendicular distance from the pivot to the center of mass, which is (1/2)L.

So we have τ = (1/2)MgL, where g is the acceleration due to gravity. Substituting these values into the torque equation, we get (1/2)MgL = (1/3)ML^2 α.

Simplifying the equation, we find α = (3g/2L).

Therefore, the magnitude of the rod's angular acceleration is (3g/2L) rad/s^2.

(b) The tangential acceleration of the rod's center of mass can be found using the formula a = αr, where a is the tangential acceleration, α is the angular acceleration, and r is the distance from the center of mass to the pivot point.

In this case, the distance r is (1/2)L, so substituting the values, we get a = (3g/2L)(1/2)L = (3g/4) m/s^2.

Therefore, the tangential acceleration of the rod's center of mass is (3g/4) m/s^2.

(c) The tangential acceleration of the rod's free end is equal to the sum of the tangential acceleration of the center of mass and the product of the angular acceleration and the distance from the center of mass to the free end.

Since the distance from the center of mass to the free end is (1/2)L, the tangential acceleration of the free end is

a + α(1/2)L = (3g/4) + (3g/2L)(1/2)L = (3g/4) + (3g/4) = (3g/2) m/s^2.

Therefore, the tangential acceleration of the rod's free end is (3g/2) m/s^2.

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Answer:

y=15

Step-by-step explanation:

y varies directly as x so:

y=k(x)

y = kx

if y is 6 and x is 2;

input the values

y=kx

6=k(2)

[tex] \frac{6}{2} = \frac{2k}{2} [/tex]

k = 3

then find y if x=5

use the previous formula

y=kx so:

y=3(5)

therefore y=15

Answer:

2.2

Step-by-step explanation:

(1.85 x 2) - 1.50

...............

Answer:

We need more information to accurately predict the population in 2016. The following information is needed:

The initial population (population in a given baseline year)

The known population decrease rate as a percentage or absolute number per year

For example, if:

The initial population (in 2010) was 10,000

The population is decreasing at a constant rate of 100 people per year

Then we can calculate the population in 2016 as follows:

2010 population: 10,000

2011 population: 10,000 - 100 = 9,900

2012 population: 9,900 - 100 = 9,800

2013 population: 9,800 - 100 = 9,700

2014 population: 9,700 - 100 = 9,600

2015 population: 9,600 - 100 = 9,500

2016 population: 9,500 - 100 = 9,400

Therefore, based on this information, the predicted population in 2016 would be 9,400.

In summary, to accurately predict population changes over time, we need to know the initial population and population decrease rate. With that information, we can calculate the population for each subsequent year by subtracting the decrease amount from the population in the previous year.

Hope this helps! Let me know if you have any other questions.

Step-by-step explanation:

The coefficient of x is -1, indicating that there is one fewer x term compared to the original expression. The constant term is -4, which is the result of subtracting 5 from -9.

To find the difference when subtracting 8x - 5 from 7x - 9, we can use the distributive property to distribute the negative sign to each term in 8x - 5:

(7x - 9) - (8x - 5) = 7x - 9 - 8x + 5

Next, we can combine like terms by adding or subtracting the coefficients of the same variables:

7x - 9 - 8x + 5 = (7x - 8x) + (-9 + 5) = -x - 4

Therefore, the expression that represents the difference when 8x - 5 is subtracted from 7x - 9 is -x - 4.

In this expression, the coefficient of x is -1, indicating that there is one fewer x term compared to the original expression. The constant term is -4, which is the result of subtracting 5 from -9.

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The statement that describes the transformations applied in the figure above include the following: C. 7 units left and a reflection about the x-axis.

In Mathematics and Geometry, a reflection over or across the x-axis is represented by this transformation rule (x, y) → (x, -y).

Based on the graph, the coordinates of point A are located at (-6, 1) in quadrant II.

By applying a translation to the A horizontally right by 7 units, the new coordinate A1 of quadrilateral ABCD include the following:

(x, y)                               →                  (x + 7, y)

A (-6, 1)                        →                  (-6 + 7, 1) = A1 (1, 1)

By applying a reflection over the x-axis to the coordinates of point A1, we have the following coordinates of the image A';

(x, y)                              →      (x, -y)

Point A1 (1, 1)             →      A' (1, -(1)) = G' (1, -1)

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Answer:

Step-by-step explanation:

To sketch the surface represented by the equation 9x² - y² + 3z² = 0 and find the equations for the cross sections, we can start by isolating each variable and considering different values for the fixed variables.

(1) - Cross section at z = 0:

Substituting z = 0 into the equation, we get 9x² - y² = 0 . Rearranging this equation, we have:

9x² = y²

Taking the square root of both sides, we get:

y = ±3x

So the equation for the cross section at z = 0 is y = ±3x and our trace is a line in the xy-plane.

(2) - Cross section at y = -9:

Substituting y = -9 into the equation, we get 9x² - (-9)² + 3z² = 0. Simplifying this equation, we have:

9x² - 81 + 3z² = 0

Rearranging, we obtain:

9x² + 3z² = 81

Dividing by 3, we get:

3x² + z² = 27

So the equation for the cross section at y = -9 is 3x² + z² = 27 and our trace is an ellipse in the xz-plane.

(3) - Cross section at y = 9:

Substituting y = 9 into the equation, we get 9x² - (9)² + 3z² = 0. Simplifying this equation, we have:

9x² - 81 + 3z² = 0

Rearranging, we obtain:

9x² + 3z² = 81

Dividing by 3, we get:

3x² + z² = 27

So the equation for the cross section at y = -9 is 3x² + z² = 27 and our trace is an ellipse in the xz-plane.

(4) - Cross section at x = 0:

Substituting x = 0 into the equation, we get - y² + 3z² = 0. Rearranging this equation, we have:

y² = 3z²

Taking the square root of both sides, we get:

y = ±√3z

So the equation for the cross section at x = 0 is y = ±√3z and our trace is a parabola in the yz-plane.

Fraction 7/3 is convertible to a decimal. It is a proper fraction. Because here the numerator is lesser than the denominator. Any fraction can be represented as a decimal number.

To transform the fraction into a decimal, it has to go through a process of division. It will be like this, 7÷3.

During the process of the division after the use of the decimal point, the same number will keep repeating. The number that keeps repeating is known as the recurring number.

If 7 is divided by 3, the result is 2.333333. Here the digit 3 is recurring. So the representation of 7/3 as a decimal is 2.333333.

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Answer:

Step-by-step explanation:

For the left graph g:

The absolute max is 4   because the highest it goes is to 4 but there is no min because the arrows at bottom means it keeps going

For right graph h:

The absolute max is 3  because that's the highest point

The absolute min is -5 because that's the lowest but there are no arrows so the curve ends on both ends.

1) The probability that 5 will be working is: 0.187

2) The probability that at least one machine would be working is: 0.006

3) The probability that all would be working is : 1

We are given the parameters as:

Total number of machines = 200

Probability that a Machine is working = 12% = 0.12

1) Now, you want to pick 40 machines and want to find the probability that 5 will be working.

This probability is given by the expression:

P(5 working) = C(40,5) * 0.12⁵·0.88³⁵ ≈ 0.187

where C(n, k) = n!/(k!(n-k)!)

2) The probability that at least one machine would be working is:

0.88⁴⁰ ≈ 0.006

3) The probability that all would be working is the complement of the probability that all have failed. Thus:

P(all working) = 1 - 0.12⁴⁰ ≈ 1

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The value of a and b in the given complex expression is  1/10 and -1/10 respectively.

This is a problem related to the complex numbers. The complex numbers has a general form of (a+bi) where 'i' is the imaginary number or √-1. The part without an 'i' is called Real Part and the part with an 'i' is called Imaginary Part.

(2i/2+i) - 3i/(3+i) = a + bi

{ 2i(3+i) - 3i(2+i) }/ (2 + i)(3 + i) = a+bi

6i + 2i² - 6i - 3i² / (2 + i)(3 + i) = a+bi

(-2 + 3) / (6 + 5i - 1) = s+bi

1 / (5 + 5i) = a+bi

Now we multiply top and bottom by 5 - 5i :

5 - 5i / (5 + 5i)(5 - 5i) = a+bi

5 - 5i / 25 -25i² = a+bi

5 - 5i / 50 = a+bi

1/10 - 1/10i = a+bi

On comparing the real and imaginary part on the both sides:

a= 1/10 , b= -1/10.

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The polynomial with real coefficients from the zeros is P(x) = 2x³ - 18x² + 2x + 58

From the question, we have the following parameters that can be used in our computation:

zeros =  5+2i, 5-2i, -1

One such polynomial P(x) can be defined as

P(x) = x³ - 9x² + x + 29.

When this polynomial is multiplied by a costant, the roots and zeros remain the same

Let the constant be 2

So, we have

New P(x) = 2(x³ - 9x² + x + 29)

Evaluate

New P(x) = 2x³ - 18x² + 2x + 58

Hence, the function is P(x) = 2x³ - 18x² + 2x + 58

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Answer:

33.33%

Step-by-step explanation:

We Take

(35 ÷ 105) x 100 ≈ 33.33%

So, 35 is 33.33% of 105

The coefficient of [tex]x^2y^3[/tex] in the expression [tex](2x+y)^5[/tex] is 10

To find the coefficient of the term containing [tex]x^2y^3\\[/tex] in the expansion of [tex](2x+y)^5[/tex], we can use the binomial theorem. The binomial theorem states that the expansion of [tex](a + b)^n[/tex] can be written as the sum of the binomial coefficients multiplied by the respective powers of a and b, where n is a positive integer.

In this case, we have [tex](2x + y)^5[/tex]. The term [tex]x^2y^3[/tex] can be obtained by selecting two x's from [tex](2x)^2[/tex] and three y's from [tex]y^3[/tex]. The coefficient of [tex]x^2y^3[/tex] will be the product of the corresponding binomial coefficients.

The binomial coefficients for this term can be calculated as follows:

Coefficient = C(5, 2) * C(3, 3)

C(n, k) represents the binomial coefficient, which is calculated as n! / (k! * (n - k)!), where "!" denotes the factorial operation.

Plugging in the values, we have:

Coefficient = C(5, 2) * C(3, 3)

[tex]= (5! / (2! * (5 - 2)!)) * (3! / (3! * (3 - 3)!))\\= (5! / (2! * 3!)) * (3! / (3! * 0!))\\= (5 * 4 * 3! / (2 * 1 * 3!)) * 1\\= (5 * 4) / (2 * 1)\\= 10.[/tex]

Therefore, the coefficient of [tex]x^2y^3[/tex] in the expression [tex](2x+y)^5[/tex] is 10.

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The mean score of Dora's bowling for this week would be = 161.

To calculate the mean score for the week the following would be carried out as follows;

The formula that is used to calculate mean = summation of the score/ number of scores recorded.

That is;

The weeks scores = 152+170+161

= 483/3

= 161

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The range of the inverse of the function is [2, ∝)

From the question, we have the following parameters that can be used in our computation:

f(x) = √x - 2

Set the radicand greater tahn or equal to 0

So, we have

x - 2 ≥ 0

When evaluated, we have

x ≥ 2

This means that

[2, ∝)

Hence, the range of the inverse of the function is [2, ∝)

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The expression that is equivalent to x√6 is option C, 62/37/3.The correct choice is C. 62/37/3.

To find an expression that is equivalent to √(6x²), we need to simplify the square root.

Using the properties of square roots, we know that the square root of a product is equal to the product of the square roots. Therefore, we can simplify the expression as follows:

√(6x²) = √6 * √(x²)

The square root of x² is simply x, and the square root of 6 cannot be simplified further. Therefore, the expression can be simplified as:

√(6x²) = x√6

Among the given options, the expression that is equivalent to x√6 is option C, 62/37/3.

Therefore, the correct choice is C. 62/37/3.

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Jabez is correct without calculating the product of 54 x 0.06 correctly because his estimation aligns with the mathematical principle that multiplying a number by a decimal less than 1 will result in a smaller product.

To determine who is correct without calculating the product of 54 x 0.06, we can use estimation.
Jabez estimated that the answer will be less than 54 but greater than 5.4. Let's analyze his estimation. When multiplying a number by a decimal less than 1, the product will always be smaller than the original number. In this case, 54 is the original number. Since 0.06 is less than 1, the product of 54 x 0.06 will definitely be smaller than 54.
On the other hand, Christina thinks the answer will be less than 5.4. Let's analyze her estimation. The original number, 54, is already greater than 5.4. When multiplying it by a decimal less than 1, the product will be even smaller. Therefore, Jabez's estimation is incorrect.
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The end of 6 months, Ram should pay Rs. 276250 compounded half-yearly.

Ram borrowed Rs. 250000 from Sit at an interest rate of 21% per annum. To calculate the compound interest, we need to know the compounding period. In this case, the interest is compounded half-yearly, which means it is calculated twice a year.

To find out how much Ram should pay at the end of 6 months, we can use the compound interest formula:

A = P(1 + r/n)^(nt)

Where:
A = the amount to be paid at the end of the time period
P = the principal amount (the initial amount borrowed) = Rs. 250000
r = the interest rate per period (in decimal form) = 21% = 0.21
n = the number of compounding periods per year = 2 (since it's compounded half-yearly)
t = the number of years = 6 months = 6/12 = 0.5 years

Plugging in these values into the formula, we get:

A = 250000(1 + 0.21/2)^(2*0.5)

Simplifying the equation:

A = 250000(1 + 0.105)^(1)

A = 250000(1.105)

A = Rs. 276250

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