Answer:
tyduyfjhg
Explanation:
A substance has a density of .80g/cm3 if you have 60cm3 what is the mass?
Answer:
168.56
Explanation:
Answer:
48 grams
Explanation:
If p and V are already given, calculate m by multiplying those two values.
m = pV
m = 4/5 * 60/1
m = 240/5
m = 48 grams
The mass of that substance is 48 grams.
what example best illustrates the difference between a community and a population.
Answer:
a community is a place with people and a population is like animals
A metal sphere of 0.5 kg is heated to 300 o C, than dropped into a beaker holding 4.08 kg mercury at 20 o C. The temperature of the mercury stabilizes at 99o C after a couple of minutes. What metal was the sphere made of
Answer:
The metal sphere was made of iron.
Explanation:
From the question,
Heat lost by the metal sphere = heat gained by the mercury.
Cm(t₁-t₃) = C'm'(t₃-t₂)................... Equation 1
Where C = specific heat capacity of the metal sphere, m = mass of the metal sphere, C' = specific heat capacity of the mercury, m' = mass of the mercury.
t₁ = initial temperature of the metal sphere, t₂ = initial temperature of the mercury, t₃ = Final temperature of the mixture.
Make C the subject of the equation
C = C'm'(t₃-t₂)/m(t₁-t₃)................. Equation 2
Given: m = 0.5 kg, m' = 4.08 kg, t₁ = 300 °C, t₂ = 20 °C, t₃ = 99 °C
Constant: C' = 140 J/kgK.
Substitute into equation 2
C = [140×4.08×(99-20)]/[0.5×(300-99)]
C = 45124.8/100.5
C = 449.0 J/kgK.
Hence from the specific heat capacity data sheet, the metal is suspected to be made of iron.
Using today's current price of gold - $1838.80 per troy ounce, how much are 5.17x1017 atoms of gold worth? (Hint: You will have to convert from grams to troy ounces as well.)
Answer:
0.010 $.
Explanation:
Hello!
In this case, since 1 troy ounce equals 31.1 grams, we can compute the price of gold per gram first:
[tex]1,838.80\frac{\$}{try\ ounce} * \frac{1try\ ounce}{31.1g} = 59.1\frac{\$}{g}[/tex]
Now, we need to compute the grams of copper in 5.17 x10¹⁷ atoms via the Avogadro's number:
[tex]m=5.17x10^{17}atomsAu*\frac{197.0gAu}{6.022x10^{23}atomsAu} \\\\m=1.69x10^{-4}g[/tex]
Thus, the price is:
[tex]\$ = 59.1\frac{\$}{g}*1.69x10^{-4}g \\\\\$ =0.010\$[/tex]
Best regards!
Why do earthquakes occur more often in some countries than in others?
Answer:
Some places have more earthquakes than others because they sit on the edges of tectonic plates.
Suppose of potassium bromide is dissolved in of a aqueous solution of silver nitrate. Calculate the final molarity of potassium cation in the solution. You can assume the volume of the solution doesn't change when the potassium bromide is dissolved in it. Round your answer to significant digits.
Answer:
[tex]M_{K^+}=0.0461M[/tex]
Explanation:
Hello!
In this case, as the amounts are not given, we can assume the following problem that is similar to this one:
"Suppose 0.549g of potassium bromide is dissolved in 100.mL of a 19.0mM aqueous solution of silver nitrate. Calculate the final molarity of bromide anion in the solution. You can assume the volume of the solution doesn't change when the potassium bromide is dissolved in it. Round your answer to 3 significant digits."
In such a way, we consider that the molarity of any substance is computed by dividing the moles of solute and the volume of the solution; it means we need to compute the moles of potassium bromide in 0.549 g considering its molar mass is 119.002 g/mol:
[tex]n_{KBr}=0.549gKBr*\frac{1molKBr}{119.002gKBr} =0.00461molKBr[/tex]
It also means that the moles of potassium cations are also 0.00461 mol as 1 KBr molecule has 1 potassium calcium. Moreover, given the volume of the silver nitrate solution, 100 mL, in L it would be 0.100 L, so the molarity of potassium ions turns out:
[tex]M_{K^+}=\frac{0.00461molKBr}{0.100L}\\\\ M_{K^+}=0.0461M[/tex]
Best regards!
Calculate the molar mass of hafnium (II) iodide, HfI2. This is 1 Hf and 2 Iodine. No hydrogen.
Question text What is the mole fraction of benzene in a benzene-toluene solution whose vapor pressure is 51 torr at 20°C?
Answer:
Mole fraction for benzene is 0.683
Explanation:
We need to determine the colligative property about vapour pressure which formula is:
ΔP = P° . Xm
where P° is vapour pressure of pure solvent.
ΔP = Vapor pressure of pure solvent - Vapor pressure of solution
In this case, our solvent is benzene and the solute is toluene. For this colligative property vapour pressure of solution is lower than pure solvent.
P° of benzene at 20°C is 74.7 Torr
Xm is the value for the mole fraction of solute.
Let's replace data: 74.7 Torr - 51 Torr = 74.7 Torr . Xm
Xm = 0.317 → That's the mole fraction for toluene.
Then, mole fraction for benzene will be: 1 - 0.317 → 0.683
2.524 g (5.1 × 106 g) ÷ (6.85 × 103 g) =
Answer:
1.93391595 grams I hope this helps
Explanation:
The heat gained by the ice melted the ice and raised the temperature of the melted ice from its initial temperature to the final temperature of the water.
a. True
b. False
Answer:
True
Explanation:
When ice is heated, the ice gains heat.
This heat gained by the ice is both used to break the intermolecular forces in ice to form water, as well as to raise the temperature of the water to it's final temperature.
What is the mass of 1.2x10^25 atoms of Helium
Answer:
dunno
Explanation:
sorry
Students build a model of a lithium atom with different colored marbles. Lithium Model Information Number of Marbles Blue (protons) 3 Green (neutrons) 4 Red (electrons) 3 Based on the chart, which marbles should the students place in the nucleus of their lithium atom model?(8th grade science)
Answer:
Blue and Green marbles
Explanation:
We have been given that:
Number of Marbles:
Blue(Protons) = 3
Green(Neutrons) = 4
Red (Electrons) = 3
The marble that should be placed in the nucleus of a lithium atom = ?
Solution:
The nucleus of an atom is made up of protons and neutrons.
Protons are the positively charged particles in an atom.
Neutrons do not carry any charges.
So;
The marble in the nucleus are the Blue and Green marbles.
Answer: blue and green
An ion can be created when a .................... is lost or gained by an element.
Answer:
electron and ignore this woejdnks
Neutralisation reactions
A)endothermic
B)exothermic
Answer:
Neutralisation reactions are generally B) Exothermic.here is paragraph 2 and i need help pls..lmk if u need more info
Answer:
i would say the first one!
What is the formula for zinc fluoride?
What amount of hydrogen peroxide should result ( theoretical yield) when 1.50g of barium peroxide is treated with 25.0 mL of hydrochloric acid solution containing 0.0272 g of HCl per mL
Answer:
[tex]m_{H_2O_2}=0.317gH_2O_2[/tex]
Explanation:
Hello!
In this case, for the chemical reaction between hydrochloric acid and barium peroxide is:
[tex]BaO_2(s)+2HCl(aq)\rightarrow H_2O_2(aq)+BaCl_2(aq)[/tex]
Thus, since the barium peroxide (169.33 g/mol) and hydrochloric acid (36.45 g/mol) are reacting in a 1:2 mole ratio, we need to identify the limiting reactant first by computing the yielded moles of hydrogen peroxide by each reactant:
[tex]n_{H_2O_2}^{by\ BaO_2}=1.50gBaO_2*\frac{1molBaO_2}{169.33gBaO_2}*\frac{1molH_2O_2}{1molBaO_2}=0.00886molH_2O_2\\\\ n_{H_2O_2}^{by\ HCl}=0.0272\frac{gHCl}{mL}*25.0mL *\frac{1molHCl}{36.46gHCl}*\frac{1molH_2O_2}{2molHCl}=0.00933molH_2O_2[/tex]
That's why the HCl is the limiting reactant, so the resulting mass of hydrogen peroxide, theoretical yield, is:
[tex]m_{H_2O_2}=0.00933molH_2O_2*\frac{34.02gH_2O_2}{1molH_2O_2}\\\\m_{H_2O_2}=0.317gH_2O_2[/tex]
Best regards!
What are the ingredients in a margaritaWhat are the ingredients in a margarita drink
Answer:
cointreau, tequila,lime juice
2. Why can animal waste be toxic?
O A. The ammonia in manure smells like rotten gas.
O B. The methane in manure is converted to particulate matter
OC. The hydrogen sulfide in manure can cause respiratory failure
O D. Carbon dioxide accumulates on top of liquid manure and is highly flammable
Calculate the [OH-] of a 0.20 M aqueous 20
solution of NaF. Ka of HF is 7.1 x 104
The [OH-] of NaF solution : 1.7 x 10⁻⁶
Further explanationGiven
0.2 M NaF
Ka of HF is 7.1 x 10⁻⁴
Required
[OH⁻]
Solution
Hydrolysis of NaF salt which is formed from weak acid HF and strong base NaOH
F⁻(aq) + H₂O(l) ⇄ HF(aq) + OH⁻(aq)
General formula :
[tex]\tt [OH^-]=\sqrt{\dfrac{Kw}{Ka}\times M }[/tex]
Input the value :
[OH⁻]=√(10⁻¹⁴/7.1 x 10⁻⁴) x 0.2
[OH⁻]= 1.678 x 10⁻⁶ ≈ 1.7 x 10⁻⁶
P4010
+ 4P + 5 O2
How many moles of phosphorus would be
produced if 8.19 mol of P4010 reacted? Enter
your answer with 2 decimal places.
Answer:
32.76mole of P
Explanation:
The reaction expression is given as;
P₄O₁₀ → 4P + 5O₂
Given parameters:
Number of moles of P₄O₁₀ = 8.19mol
Unknown:
Number of moles of P produced = ?
Solution:
From the balanced reaction expression;
1 mole of P₄O₁₀ will produce 4 mole of P
8.19mole of P₄O₁₀ will therefore produce 4 x 8.19 = 32.76mole of P
?
Which of the following can you conclude about a particle labeled
Check all that apply.
D A. It has one nucleon.
B. It has one proton.
I C. It has no neutrons.
D. It has one neutron.
E. It is a beta particle.
F. It has one electron.
G. It is an alpha particle.
Answer:it has one proton,
and one electron
Explanation:
It has one neutron and It has one nucleon
If you combust 7.500g of methanol with an excess of oxygen, a) how many grams and molecules of water will be produced, and b) how many grams and molecules of carbon dioxide will be produced
Explanation:
The equation for this reaction is given by;
2CH3OH(l) + 3O2(g) → 2CO2(g) + 4H2O(g)
From the reaction;
2 mol of methanol produces 2 mol of CO2 and 4 mol of water
In terms of mass;
Mass = Molar mass * Number of mol
Methanol;
Mass = 32 g/mol * 2 mol = 64 g
CO2;
Mass = 44 g/mol * 2 mol = 88g
H2O;
Mass = 18 g/mol * 4 mol = 72 g
This means;
64g of methanol produces 88g of CO2 and 72g of water
a) how many grams and molecules of water will be produced
64g of Methanol = 72g of Water
7.5g would produce xg of Water
X = (7.5 * 72) / 64 = 8.4375 g of water
Number of moles = Mass / Molar mass = 8.4375 / 18 = 0.46875 mol
Molecules = moles * Avogadro number = 0.46875 * 6.022 * 10^23 = 2.82 * 10^23 molecules
b) how many grams and molecules of carbon dioxide will be produced
64g of Methanol = 88g of CO2
7.5g would produce xg of CO2
X = (7.5 * 88) / 64 = 10.3125 g of CO2
Number of moles = Mass / Molar mass = 10.3125 / 44 = 0.2344 mol
Molecules = moles * Avogadro number = 0.2344 * 6.022 * 10^23 = 1.411 * 10^23 molecules
An oxygen atom has a mass of 2.66 x 10 g and a glass of water has a mass of 0.050 kg. Use this information to answer the questions below. Be sure your answers have the correct number of significant digits. What is the mass of 1 mole of oxygen atoms? 0x10 Х 5 ? How many moles of oxygen atoms have a mass equal to the mass of a glass of water?
Answer:
A. 16.0 grams
B. 3.1 mol of oxygen
Explanation:
A.
The oxygen atom has mass = 2.66x10^-23g
A mole of oxygen atoms can be calculated as:
[2.66x10^-23/1 oxygen atom] x [6.023x10²³ oxygen atoms/1 mol]
= 16.0 grams of oxygen
So a mole of oxygen has 16.0 grams of O2
B.
For 0.050 kg of water, we have 16.0 grams
(0.050x10³g/kg )x (1mol/16)
= 3.1 mol of oxygen
So 3.1 mol of oxygen has mass which is equal to the mass of water.
An unknown acid was titrated two times with 0.10 M NaOH. The first titration was done using an indicator to determine the equivalence point volume. A second titration was carried out where the pH was determined throughout the entire titration. The data is given below.
Titration 1: mL unknown acid = 25.0, mL of NaOH needed to reach equivalence point = 30.00
Titration 2: mL unknown acid = 25.0
mL 0.1M pH
NaOH Added
0.0 3.72
5.0 5.82
10.0 6.22
15.0 6.52
20.0 6.82
25.0 7.22
30.0 9.63
35.0 11.92
a. What is the concentration of the unknown acid?
b. What is the Ka of the unknown acid?
c. Which of the indicators given below would be a good choice to use in the titration of this acid with the NaOH?
Answer:
hello your question is incomplete attached below is the complete question
a) 0.12 M
b) Ka = 3.0 * 10^-7
c) Alizarin Yellow R
Explanation:
A) Determine the concentration of the unknown acid
The PH of the unknown acid before addition of NaOH is ; 3.72 ( weak acid )
First determine the moles of of NaOH
= molarity * volume
= 0.10 M * 30.0 ML = 0.0030 mol
at equivalence point
moles of NaOH = moles of unknown acid = 0.0030 mol
volume of unknown acid = 25.0 mL
Next calculate the concentration of the Acid ( HA )
= moles / volume
= 0.0030 mol / 25.0 mL
= 0.12 M
b) Determine the Ka of the unknown acid
attached below is the detailed solution
Ka = 3.0 * 10^-7
c) The indicator that would be a good choice to use in the titration of this acid with NaOH is ; Alizarin Yellow R . this is because the titration is between a strong base and a weak acid.
Write the balanced COMPLETE ionic equation for the reaction when aluminum nitrate and sodium hydroxide are mixed in aqueous solution. If no reaction occurs, simply write only NR.
Answer:See explanation
Explanation:
MOLECULAR REACTION EQUATION;
Al(NO3)3(aq) + 3NaOH(aq) --->Al(OH)3(s) +3NaNO3(aq)
complete ionic equation:
Al^3+(aq) + 3NO3^-(aq) + 3Na^+(aq) + 3OH^-(aq) ---->Al(OH)3(s) + 3Na^+(aq) + 3NO3^-(aq)
Net ionic reaction equation;
Al^3+(aq) + 3OH^-(aq) ------> Al(OH)3(s)
The density of water at 60.0 °C is 0.9832 g/mL. If the specific gravity of acetic acid is 1.023 at 60.0 °C, what is the density of acetic acid at 60.0 °C?
Answer:
1.0058 g/mL
Explanation:
Note: Specific gravity of a substance is same as the relative density.
R.D = Density of the substance/ Density of water.
R.D = D/D'................... Equation 1
Make D the subject of the equation
D = R.D×D'................. Equation 2
Where R.D = Specific gravity of acetic acid, D = density of acetic acid, D' = density of water.
At 60°C,
R.D = 1.023, D' = 0.9832 g/mL
Substitute into equation 2
D = (1.023×0.9832)
D = 1.0058 g/mL
Hence the density of acetic at 60°C is 1.0058 g/mL
PLEASE HELP!!!!!
4. Assume that the water stream is replaced by a stream of CCl4. Predict what would happen in each case:
a. charged comb
b. PVC pipe
C. charged balloon
5. Explain your predictions.
Water is a polar substance, while CCL4 is non polar, which implies that Charged comb and charged balloon will not react with CCL4 as they react with water which is polar substance.
Reactivity of carbon tetrachloride CCL4
Carbon tetrachloride CCL4 has practically no flammability at lower temperatures.
CCl4 is nonpolar because all the four bonds are symmetrical, and they are they extended in all the directions.
Water is a polar substance, while CCL4 is non polar, which implies that Charged comb and charged balloon will not react with CCL4 as they react with water which is polar substance.
However, when CCL4 is passed into PVC it will be swollen due to the presence of chlorinated hydrocarbon.
Learn more about Carbon tetrachloride here: https://brainly.com/question/10963193
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What volume of gold would be equal in mass to a piece of copper with a volume of 121 mL? The density of gold is 19.3 g/mL; the density of copper is 8.96 g/mL.
Answer:
We are tasked to solve for the volume of Gold given that the mass of Gold is equivalent to that of a copper.
Explanation:
Details:
Density of Copper= 8.96 g/ml
Volume of Copper=141 ml
mass of Gold = mass of Copper
Density of Gold=19.3 g/ml
In order to solve for the mass of copper, we need to use the density formula
Density= mass/volume
Since we are to solve for the mass of copper
mass of copper= Density of Copper * Volume of Copper
mass of copper= 8.96 g/ml* 141 ml= 1263.36 g
Thus,
mass of gold=mass of copper=1263.36 g
Hence,
Using still the density formula to solve for the volume of gold,
Volume of gold=mass of gold/ Density of gold
Volume of gold=1263.36 g/ 19.3 g/ml = 65.46 mL
Therefore, the volume of the gold must be 65.46 mL in order to have the same mass of a copper
Calculate the number of moles of magnesium, chlorine, and oxygen atoms in 5.40 moles moles of magnesium perchlorate, Mg(ClO4)2Mg(ClO4)2. Express the number of moles of MgM, Cl Cl, and OO atoms numerically, separated by commas.
Answer:Moles of Mg, Cl, 0 = 5.40, 10.80, 43.2
Explanation:
1 mole of Mg(ClO4)2 contains 1 mole of Magnesium, Mg atoms
2 Moles of Chlorine, Cl atoms
8 Molresof Oxygen atoms
Such that to find the number of moles of each element, We have that
------1 mole Magnesum atoms/ 1 mol of Mg(ClO4)2 x 5.40 moles of magnesium perchlorate, Mg(ClO4)2 = 1 x 5.40 =5.40 moles
------2 moles ofChlorine atoms/ 1 mol of Mg(ClO4)2 x 5.40 moles of magnesium perchlorate, Mg(ClO4)2 = 2 x 5.40 = 10.80 moles
------8 moles Oxygen atoms/ 1 mol of Mg(ClO4)2 x 5.40 moles of magnesium perchlorate, Mg(ClO4)2 = 8 x 5.40 = 43.2 moles