Answer:
High current flow
Explanation:
Generally , the measuring instruments used by technician also have some resistance, though its value is very low . So when high current is present in the circuit , that current also passes through the instrument which creates a good potential drop across the instrument . So the external voltage used in the circuit measures less voltage .
It has been suggested, and not facetiously, that life might have originated on Mars and been carried to Earth when a meteor hit Mars and blasted pieces of rock (perhaps containing primitive life) free of the surface. Astronomers know that many Martian rocks have come to Earth this way. One objection to this idea is that microbes would have to undergo an enormous, lethal acceleration during the impact. Let us investigate how large such an acceleration might be. To escape Mars, rock fragments would have to reach its escape velocity of 5.0 km/s, and this would most likely happen over a distance of about 4.0m during the impact.
1) What would be the acceleration, in m/s, of such a rock fragment?
2) What would be the acceleration, in g's, of such a rock fragment?
3) How long would this acceleration last?
4) In tests, scientists have found that over 40% of Bacillius subtilis bacteria survived after an acceleration of 450000g. In light of your answer to part A, can we rule out the hypothesis that life might have been blasted from Mars to Earth?
Answer and Explanation:
Given that
v_f = 5 km/s = 5,000 m/s
d = 4 m
v_i = 0 m/s
The computation is shown below:
1. The acceleration in m/s is
Here we use the motio third equation which is
[tex]v_f^2 = v_i^2 + 2ad[/tex]
5000^2 = 0^2 + 2 (a) (4)
So
[tex]a = 3.125 \times 10^{6} m/s^2[/tex]
2. Now acceleration in g is
[tex]= \frac{3.125 \times 10^{6} m/s^2}{9.81}[/tex]
[tex]= 3.18 \times 10^{5}g[/tex]
3. The long of acceleration last is
[tex]t = \frac{v-u}{a}[/tex]
[tex]= \frac{5000 - 0}{3.125 \times 10^{6}}[/tex]
[tex]= 1.6 \times 10^{-3}s[/tex]
4.As we can see that
[tex]3.18 \times 10^{5}[/tex] is smaller than the [tex]4.5 \times 10^{5}g[/tex]
So, it should not be ruled out
A material that does not conduct electricity is called a... what?
A material that does not conduct electricity is known as an insulator
A material which conducts electricity is called conductor whereas, the materials that does not conduct electricity is called insulators.
What are insulators?There are three types of materials based on the conductivity of them namely conductors, semiconductors and insulators. Conductors are those which conduct thermally and electrically. Materials such as metals are good conductors.
Semiconductors are materials which does not conduct at room temperature but partially conducts at higher temperatures or through doping with other materials. For example silicon, germanium etc.
Materials that does not conduct electricity at all conduct electricity is called insulators. Electrons are unable delocalize through these materials and cannot be made conductive at normal conditions. eg: wood, plastic etc.
To find more on insulators, refer here:
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Mt Everest is at the height of 8850 m; its base is at an elevation of 5400m. The temperature here drops at the rate of 1 degree per 100m. If temperature at the base is -5, what will be the temperature at the top?
Answer:
The temperature at the top is -39.5 degree
Explanation:
The height of Mt Everest = 8850 m
The base is at the elevation of = 5400 m
The drop in temperature = 1 degree per 100 m
At the base, the temperature = -5
Since every 100 meter rise in height results in the one degree drop of temperature. Therefore, first find the difference between the base and height. Multiply with negative one.
Difference in heights = 8850 – 5400 = 3450
The temperature at the top = (3450 / 100) + 5 = -39.5 degree
Since there is fall in temperature so we use negative sign.
Show all work and answer all 4 parts. Projectile motion. 20 points. Thank you.
Answer:
i took g = 9.8m/s
A. 1.16secs
B. 2.32secs
C. 6.57m
D. 57.91m
Explanation:
A. How long does the Missile take to reach ot peak?
Time taken (t) =( U²Sin (angle) )/g
u = initial velocity = 25m/s
angle given = 30°
g = acceleration due to gravity = 9.8m/s²
t = U² x Sin (angle) / g
t = 25² x Sin(30)/9.8
t = 1.61secs
B. How long is the missile in the air in total?
T = 2t
T = 2 x 1.61 = 2.32 secs
C. what maximum Height does the missile reach?
Maximum height = U²Sin²(angle) / 2gM.H =25² x Sin(30)² / 2 x 9.8M.H=6.57mMaximum height= 6.57mD. How far does the missile travel Horizontally?
Range = U²2Sin(angle)/gRange = 25² x 2 x Sin(30) / 9.8Range = 57.91mStudy the image of earths layer which statement correctly compares the thicknesses of earths layers
This question is incomplete because the options are missing; here is the complete question:
Study the image of the Earth's layer which statement correctly compares the thicknesses of earths layers
A. Earth’s mantle is thinner than its oceanic crust.
B. Earth’s outer core is thicker than its mantle.
C. Earth’s continental crust is thicker than its lithosphere.
D. Earth’s lithosphere is thinner than its asthenosphere.
The answer to this question is D. Earth’s lithosphere is thinner than its asthenosphere.
Explanation:
The image shows the different layers that are part of Earth, as well as the thickness of each layer, in kilometers. In this, the thickest layer is the Mantle that is almost 2900 kilometers; this is followed in thickness by the outer and the inner core.
Additionally, other layers such as the continental/oceanic crust, the asthenosphere, and the lithosphere that are near the surface are thinner. About this, it can be concluded the lithosphere is thinner than the asthenosphere because the lithosphere has a thickness of 100 km, while the asthenosphere thickness is 660km. This makes option D the correct.
Which option describes the most cost-effective way for a skateboard company to purchase plywood?
- a pallet of 100 sheets for $1,000
- a pallet of 200 sheets for $1,800
- a pallet of 500 sheets for $3,500
- a pallet of 1,000 sheets for $8,000
Answer:
a pallet of 500 sheets for $3,500
Explanation:
just did the test
A car is parked at rest on a horizontal road. The upward force of the road on the car (the normal force) is the same size as the downward pull of gravity A car is parked at rest on a horizontal road. The upward force of the road on the car (the normal force) is the same size as the downward pull of gravity Because of Newton's first law. Because they are an action/reaction pair. Both of the above. None of the above. Some other reason.
Answer:
Option A - Because of Newton's first law of motion
Explanation:
This is as a result of Newton's first law of motion.
Newton's first law of motion which is also referred to as the law of inertia states that; an object at rest will remain at rest and an object in motion will remain in motion with the same speed and in the same direction unless it's acted upon by an unbalanced force.
In this question, the car is at rest and it doesn't move because the upward force of the car is balanced by the downward pull of gravity. It can only move when an external force is applied to it. This fulfills Newton's first law of motion.
6. While standing on an ice surface (assume no friction), a 60 kg skater pushes against
a wall with an average force of 240 N east for 0.360 s. Calculate the velocity
(magnitude and direction) of this student at 0.360 s.
Answer: 1.44m/s West
Explanation:
Given the following :
Mass of skater = 60kg
Average force = 240N east
Time of = 0.360 seconds
The Velocity after 0.360seconds
Recall the relation:.
Force(f) * time(t) = mass (m) * (final Velocity(V) - initial velocity(u))
Where ; final Velocity(v) - initial velocity(u) = Magnitude of velocity(V)
Ft = mV
240 × 0.360 = 60 × V
60 × V = 86.4
V = 86.4 / 60
V = 1.44m/s
According to Newton's third law, to every action, there is an equal and opposite reaction.
The action force acts in the eastern direction hitting the wall with a force of 240N, therefore direction after hitting the wall will be in the opposite (western direction) direction, which is the direction of the reaction force
Therefore, velocity is 1.44ms West
Two teams are playing tug-of-war. Team A, on the left, is pulling on the rope with an effort of 5000 N. If the rope is moving at a constant velocity, how hard and in which direction is team B pulling?
A. 2500 N to the left
B. 5000 N to the right
C. 2500 N to the right
D. 5000 N to the left
Explanation:
If Team A is on the left, B is on the right
if the force is constant, it means that the effort applied is equal.
So Team B is pulling 5000N to the right.
Distinguish between homogeneous and heterogeneous mixture with 2 example each. Do not use the examples give above
if a current of 0.01 A is flowing through a circuit with two resistors in a series what is the voltage?
Answer:
V = 0.01(R₁ + R₂)
Explanation:
From Ohm's law, the voltage V across a resistor with resistance R and a current I passing through it is given by
V = IR
If we have two resistances, R₁ and R₂ in series, the total resistance R is the sum of their resistances.
So, R = R₁ + R₂
Now, if the current in the circuit is 0.01 A, the voltage V is
V = IR
V = 0.01R
Substituting R = R₁ + R₂ into the equation for V, we have
V = 0.01(R₁ + R₂)
So, the voltage in two series resistors with current 0.01 A is
V = 0.01(R₁ + R₂)
The density of an object is .835 g/cm3. If its volume is 34 cm3, what is the mass of the object? (Density: D = )
.02 g
.41 g
28.39 g
40.72 g
Answer:
28.39 g
Explanation:
D= m ÷ v
So, M= D × V
0.835 × 34= 28.39
Answer:
C. 28.39 g
Explanation:
took the test<3
Title: Ohm’s Law using PhET Simulation The fundamental relationship among the three important electrical quantities current, voltage, and resistance was discovered by Georg Simon Ohm. The relationship and the unit of electrical resistance were both named for him to commemorate this contribution to physics. One statement of Ohm’s law is that the current through a resistor is proportional to the voltage across the resistor and inversely proportional to the resistance. In this experiment you will see if Ohm’s law is applicable by generating experimental data using a PhET Simulation:_____________.
Show us the experiment then
A car is moving along an open road. Suddenly, a sheep walks into the road. The braking distance for the car is 35m. If the stopping distance is 50m, how far did the car travel before the driver put their foot on the brakes?
Answer:
15 m
Explanation:
The distance travelled by the driver before they put their foot on the brakes can be derived from the stopping distance and the braking distance of the car.
d = stopping distance - braking distance
Stopping distance = 50 m
Braking distance = 35 m
d = 50 - 35 m
d = 15 m
The distance travelled by the driver before they put their foot on the brakes is 15 m
Question 1 of 10
2 Points
What is the SI unit for gravitational potential energy?
A. Newton
B. Joule
C. Meter
D. Watt
Answer:
Joule
Explanation:
As any unit of energy (kinetic, potential, etc.), the gravitational potential energy has SI units of Joule. This s the work done by a force of 1 Newton to displace an object 1 meter in the direction of application of the force.
If a car is travelling with a positive velocity, and after it collides with another car moving with a negative velocity, it is still moving with a positive velocity, in which direction could the second car be moving? (Select all that apply)
Answer: In the direction of the first car.
Explanation:
Let the initial velocity of the first car be equal to U1 and the initial velocity of the second car be equal to U2
Given that the car is travelling with a positive velocity, and after it collides with another car moving with a negative velocity, the momentum before collision will be
M1U1 - M2U2
If the first car is still moving with a positive velocity, the second car will also be moving in the direction of the first car if the collision is inelastic collision.
Therefore, the direction of the second car will be positive direction if the collision is inelastic collision.
The air in a ballon is type of
Answer:
A balloon can be defined as an inflatable flexible bag filled with a gas, such as helium, hydrogen, nitrous oxide, oxygen, or air.
Explanation:
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what are the necessary condition for the production of sound
Explanation:
You need two, maybe three things - something that's vibrating, a medium for those vibrations to propagate in, and a listener to hear it or recording equipment to pick it up
Answer:
You must not be inside a vacuum.
Explanation:
If you are inside a vacuum, then sound will be unable to travel as it requires the vibration of other molecules in order to spread.
Oil at 150 C flows slowly through a long, thin-walled pipe of 30-mm inner diameter. The pipe is suspended in a room for which the air temperature is 20 C and the convection coefficient at the outer tube surface is 11 W/m2 K. Estimate the heat loss per unit length of tube.
Answer:
1.01 W/m
Explanation:
diameter of the pipe d = 30 mm = 0.03 m
radius of the pipe r = d/2 = 0.015 m
external air temperature Ta = 20 °C
temperature of pipe wall Tw = 150 °C
convection coefficient at outer tube surface h = 11 W/m^2-K
From the above, we assumed that the pipe wall and the oil are in thermal equilibrium.
area of the pipe per unit length A = [tex]\pi r ^{2}[/tex] = [tex]7.069*10^{-4}[/tex] m^2/m
convectional heat loss Q = Ah(Tw - Ta)
Q = 7.069 x 10^-4 x 11 x (150 - 20)
Q = 7.069 x 10^-4 x 11 x 130 = 1.01 W/m
The heat loss per unit length of tube should be considered as the 1.01 W/m.
Calculation of the heat loss:Since
diameter of the pipe d = 30 mm = 0.03 m
radius of the pipe r = d/2 = 0.015 m
external air temperature Ta = 20 °C
temperature of pipe wall Tw = 150 °C
convection coefficient at outer tube surface h = 11 W/m^2-K
Now
area of the pipe per unit length A should be
= πr^2
= 7.069*10^-4 m^2/m
Now
convectional heat loss Q = Ah(Tw - Ta)
Q = 7.069 x 10^-4 x 11 x (150 - 20)
Q = 7.069 x 10^-4 x 11 x 130
= 1.01 W/m
hence, The heat loss per unit length of tube should be considered as the 1.01 W/m.
Learn more about heat here: https://brainly.com/question/15170783
SPEAR is a storage ring at the Stanford Linear Accelerator which has a circulating beam of electrons that are moving at nearly the speed of light (2.998 108 m/s). If a similar ring is about 80.0 m in diameter and has a 0.59 A beam, how many electrons are in the beam
Answer:
n = 3.1x10¹²
Explanation:
To find the number of electrons we need to find first the charge (q):
[tex] I = \frac{q}{\Delta t} \rightarrow q = I*\Delta t [/tex] (1)
Where:
I: is the electric current = 0.59 A
t: is the time
The time t is equal to:
[tex]v = \frac{\Delta x}{\Delta t} \rightarrow \Delta t = \frac{\Delta x}{v}[/tex] (2)
Where:
x: is the displacement
v: is the average speed = 2.998x10⁸ m/s
The displacement is equal to the perimeter of the circumference:
[tex] \Delta x = 2\pi*r = \pi*d [/tex] (3)
Where d is the diameter = 80.0 m
By entering equations (2) and (3) into (1) we have:
[tex]q = I*\Delta t = I*\frac{\Delta x}{v} = \frac{I\pi d}{v} = \frac{0.59 A*\pi*80.0 m}{2.99 \cdot 10^{8} m/s} = 4.96 \cdot 10^{-7} C[/tex]
Now, the number of electrons (n) is given by:
[tex] n = \frac{q}{e} [/tex]
Where e is the electron's charge = 1.6x10⁻¹⁹ C
[tex] n = \frac{q}{e} = \frac{4.96 \cdot 10^{-7} C}{1.6 \cdot 10^{-19} C} = 3.1 \cdot 10^{12} [/tex]
Therefore, the number of electrons in the beam is 3.1x10¹².
I hope it helps you!
need only group b 1st question
Answer:
49 m/s
Explanation:
This is the question from the document:
1. A bag dropped from a helicopter falls with an acceleration of 9.8m/s2. What is its velocity after 5s?
We can find the answer by using the equation a = (v-u) / t
Acceleration a = 9.81m/s2
initial velocity u = 0 m/s (the bag is only dropped, so there's no initial velocity already existing)
time t= 5s
final velocity v = unknown
9.8 = (v -0) / 5
v - 0 = 9.8x5
v = 49 m/s
A light, rigid rod is 51.4 cm long. Its top end is pivoted on a frictionless horizontal axle. The rod hangs straight down at rest with a small, massive ball attached to its bottom end. You strike the ball, suddenly giving it a horizontal velocity so that it swings around in a full circle. What minimum speed at the bottom is required to make the ball go over the top of the circle?
Answer:
4.489 m/s
Explanation:
We are given;
Length of rod;L = 51.4 cm = 0.514 m
When the ball is at the top end, it's velocity will be zero and it's kinetic energy will be transformed to potential energy.
Thus; ½mv² = mgh
m will cancel out to give;
v² = 2gh
Where:
g is acceleration due to gravity = 9.8 m/s²
h is the maximum height of the ball which is equal to twice the length of the rod.
Thus, h = 2(0.514) = 1.028 m
v² = 2 × 9.8 × 1.028
v = √20.1488
v = 4.489 m/s
which of the following distinguishes electromagnetic waves from mechanical waves
Answer:
Explanation:
1. Mechanical waves require material medium for their propagation while electromagnetic waves do not require material medium for their propagation.
2. Mechanical waves can either be transverse or longitudinal while electromagnetic waves are transverse.(Transverse waves are waves in which the vibration of the particules of the medium is perpendicular to the direction of the motion of wave. E.g water waves, waves of a plucked string and all electromagnetic waves RIVUXG . Longitudinal waves are waves whose vibration are parallel to the direction of the motion of the medium e.g waves in strings, sound waves.e.t.c)
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the last one is the light will move in some manner not determined by the information here.
Light bends away from the normal, because it's moving from higher to lower refractive index.
Same bend-direction as when it goes from water into air.
A toaster oven draws 300.0 watts of power. If it is plugged into an outlet with a voltage of 115 volts, what current is in the toaster's circuit?
OA 3.45 10% amps
ОВ.
415 amps
Ос.
285 amps
OD
2.61 amps
Answer:
I = 2.61 A
Explanation:
It is given that,
Power of a toaster is 300 watts
It is plugged into an outlet with a voltage of 115 volts
We need to find the current in the toaster's circuit.
The electrical power is given by the formula as follows :
P = V I
I is electric current
[tex]I=\dfrac{P}{V}\\\\I=\dfrac{300}{115}\\\\I=2.61\ A[/tex]
So, 2.61 A of current is in the toaster's circuit.
Answer: D.
2.61 amps
Explanation: edmentum
as the mass of the cart increases, the acceleration of the cart
Answer:
decrease
Explanation:
as the mass of the cart increase the acceleration of the cart decrease
Question 2 (Multiple Choice Worth 2 points)
(03.06 LC)
Which of the following is a common groundwater contaminant?
O Ozone
O Nuclear waste
O Carbon monoxide
O Fertilizers
Question 3(Multiple Choice Worth 2 points)
10 M
Answer:
The common groundwater contaminant are fertilizers.
Explanation:
Answer:
The answer would be D( Fertilizers)
Explanation:
A fertilizers or fertilizer is any material of natural or synthetic origin that is applied to soil or to plant tissues to supply one or more plant nutrients essential to the growth of plants. Many sources of fertilizer exist, both natural and industrially produced.
An electromagnetic wave has a frequency of 1.0 < 1014 Hz. What is the
wavelength of the wave? Use the equation 1 = and the speed of light as
V
f
3.0 x 108 m/s.
O A. 3.3 x 10-8 m
B. 3.0 x 1022 m
C. 3.3 x 105 m
0
D. 3.0 x 10-6 m
Answer:
D. 3.0 × 10^-6 m
Explanation:
Wavelength is found by dividing the speed of light by the frequency:
λ = c/f = (3·10^8 m/s)/(1.0·10^14 Hz) = 3.0·10^-6 m
Consider a satellite in a circular orbit around the earth. Why is it important to give a satellite a horizontal speed when placing it in orbit? What will happen if the horizontal speed is too small? What will happen if the speed is too large?
Answer:
In this case, the horizontal velocity of the rocket starts from the acceleration, so if its velocity drops to zero,
Explanation:
When a satellite is in orbit the most important force is the docking of gravity with the Earth
F = m a
where the acceleration is centripetal and F is the force of universal attraction
centripetal acceleration is
a = v² / r
F = m v² / r
In this case, the horizontal velocity of the rocket starts from the acceleration, so if its velocity drops to zero, the force also drops to serious and the satellite steels to Earth.
The speed of the satellite is provides the speed, by local for smaller speeds in satellite, it descends in its orbits and when the speed is amate you have the energy to stop an orb to go to a higher orbit.
Which change increases the electric forcWhich change increases the electric force between objects?e between objects?
Answer:
b
Explanation: