Question 1
List all types of intermolecular forces used in the condensed phase for hydrogen sulfide

1. Hydrogen bonding, London Dispersion Forces, Dipole-dipole

2. London Dispersion Forces, Dipole-dipole

3. Hydrogen bonding, Dipole-dipole

4. Hydrogen bonding, London Dispersion Forces

5. None of the answer choices are correct.

Answer:

Percent yield = 22.8 %

Explanation:

Step 1: Data given

Numbers of moles  copper = 0.0970 moles

Mass of copper(I) sulfide = 1.76 grams

Step 2: The balanced equation

2Cu + S ⇒ Cu2S

Step 3:  Calculate moles of Cu2S

For 2 moles Cu we need 1 mol S to produce 1 mol Cu2S

For 0.0970 moles Cu we'll hace 0.0970 / 2 = 0.0485 moles

Step 4: Calculate mass of Cu2S

Mass Cu2s = moles Cu2S * molar mass Cu2S

Mass Cu2S = 0.0485 moles * 159.16 g/mol

Mass Cu2S = 7.72 grams

Step 5: Calculate percent yield

Percent yield = (actual yield/ theoretical mass) * 100%

Percent yield = (1.76 grams / 7.72 grams)*100%

Percent yield = 22.8 %

The percentage yield of the experiment obtained by the reaction of 0.0970 mole of copper with excess sulfurs is 22.8%

We'll begin by calculating the number of mole of Cu₂S produced from the reaction. This can be obtained as follow:

2Cu + S —> Cu₂S

From the balanced equation above,

2 moles of Cu reacted to produce 1 mole of Cu₂S.

Therefore,

0.0970 mole of Cu will react to produce = [tex]\frac{0.0970}{2}[/tex] = 0.0485 mole of Cu₂S.

Next, we shall determine the theoretical yield by calculating the mass of 0.0485 mole of Cu₂S.

Molar mass of Cu₂S = (63.5×2) + 32 = 159 g/mol

Mole of Cu₂S = 0.0485 mole

Mass = mole × molar mass

Mass of Cu₂S = 0.0485 × 159

Thus, the theoretical yield of Cu₂S is 7.7115 g

Finally, we shall determine the percentage yield of Cu₂S.

Actual yield = 1.76 g

Theoretical yield = 7.7115 g

[tex]Percentage yield = \frac{Actual}{Theoretical} * 100\\\\= \frac{1.76}{7.7115} * 100\\\\[/tex]

Therefore, the percentage yield of the experiment is 22.8%

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Answer: The molarity of the borax solution is 0.107 M

Explanation:

The neutralization reaction is:

[tex]Na_2B_4O_7.10H_2O+H_2SO_4(aq)\rightarrow Na_2SO_4+4H_3BO_3+5H_2O[/tex]

According to neutralization law:

[tex]n_1M_1V_1=n_2M_2V_2[/tex]

where,

[tex]n_1[/tex] = basicity of [tex]H_2SO_4[/tex] = 2

[tex]n_2[/tex] = acidity of borax = 2

[tex]M_1[/tex] = concentration of [tex]H_2SO_4[/tex] = 1.03 M

[tex]M_2[/tex] = concentration of borax =?

[tex]V_1[/tex] = volume of [tex]H_2SO_4[/tex]  = 2.07ml

[tex]V_2[/tex] = volume of borax = 20.0 ml

Now put all the given values in the above law, we get the molarity of borax:

[tex](2\times 1.03\times 2.07)=(2\times M_2\times 20.0)[/tex]

By solving the terms, we get :

[tex]M_2=0.107M[/tex]

Thus the molarity of the borax solution is 0.107 M

Answer:

[tex]Q=9.2x10^5J[/tex]

[tex]t=614s=10.2min[/tex]

Explanation:

Hello,

In this case, we can compute the energy by using the following formula for air:

[tex]Q=nCp\Delta T[/tex]

Whereas the moles of air are computed via the ideal gas equation at room temperature inside the 5.5m x 6.5m x 3.0m-room:

[tex]n=\frac{PV}{RT}\\\\V=5.5m*6.5m*3.0m=107.25m^3*\frac{1000L}{1m^3}=107250L\\ \\n=\frac{1atm*107250L}{0.082\frac{atm*L}{mol*K}*298.15K}\\ \\n=4386.8mol[/tex]

Now, we are able to compute heat, by considering that the temperature raise is given in degree Celsius or Kelvins as well:

[tex]Q=4386.8mol*21\frac{K}{mol*K}*10K \\\\Q=9.2x10^5J[/tex]

Finally, we compute the time required for the heating by considering the heating rate and the required heat, shown below:

[tex]t=\frac{9.2x10^5J}{1.5\frac{kJ}{s}*\frac{1000J}{1kJ} } \\\\t=614s=10.2min[/tex]

Regards.

Answer:

0.125 mg

Explanation:

The correct answer would be 0.125 mg

According to the conversion factor, one milligram of a sample is equivalent to one thousand micrograms of the same sample.

milligram = [tex]10^{-3}[/tex]

microgram = [tex]10^{-6}[/tex]

Hence,

1 milligram = 1000 micrograms or 1 microgram = [tex]10^{-3}[/tex] milligram

Therefore, 125 micrograms will be:

  125/1000 = 0.125 milligram

Answer:

c

Explanation:

it goes in lowest energy orbital

Answer: True

Explanation:

The independent variable is the one which can be changed or manipulated in an experiment. The independent variable exerts its influence on the dependent variable. The dependent variable is the result of the experiment.

The amount of sunlight, can be regulated or changed in an experiment, thus it is an independent variable. The effect of sunlight on different plants is the dependent variable.

Answer:

[tex]m_{Fe} =162.8gFe\\\\m_{Al_2O_3}=132.11gmolAl_2O_3[/tex]

Explanation:

Hello,

In this case, by the following balanced reaction:

[tex]8Al + 3Fe_3O_4 \rightarrow 4Al_2O_3 +9 Fe[/tex]

The first step is to identify the limiting reactant, for which we compute the available moles of aluminium in 225.0 g by using its atomic mass:

[tex]n_{Al}^{available}=225.0gAl*\frac{1molAl}{27gAl} =8.33molAl[/tex]

Next. we compute the consumed moles of aluminium by 225.0 g of iron (II,III) oxide by using its molar mass and the 8:3 molar ratio between them:

[tex]n_{Al}^{consumed}=225.0gFe_3O_4*\frac{1molFe_3O_4}{231.53gFe_3O_4} *\frac{8molAl}{3molFe_3O_4} =2.59molAl[/tex]

In such a way, since more Al is available, we conclude it is in excess and iron (II,III) oxide is the limiting reactant, therefore, we can compute the produced grams of both iron and aluminium oxide as shown below:

[tex]m_{Fe}=2.59molAl*\frac{9molFe}{8molAl} *\frac{55.845gFe}{1molFe} =162.8gFe\\\\m_{Al_2O_3}=2.59molAl*\frac{4molAl_2O_3}{8molAl} *\frac{101.96gmolAl_2O_3}{1molAl_2O_3} =132.11gmolAl_2O_3[/tex]

Best regards.

Answer:

1) 17.5 mL

Explanation:

Hello,

In this case, the reaction between sulfuric acid and potassium hydroxide is:

[tex]H_2SO_4+2KOH\rightarrow K_2SO_4+2H_2O[/tex]

In such a way, we notice a 1:2 molar ratio between the acid and the base, therefore, at the equivalence point we have:

[tex]2*n_{acid}=n_{base}[/tex]

And in terms of concentrations and volumes:

[tex]2*M_{acid}V_{acid}=M_{base}V_{base}[/tex]

Thus, we solve for the volume of acid:

[tex]V_{acid}=\frac{M_{base}V_{base}}{2*M_{acid}} =\frac{35mL*1.5M}{2*1.5M} \\\\V_{acid}=17.5mL[/tex]

Best regards.

Answer:

NH3(aq)

Explanation:

Gold III hydroxide is an inorganic compound also known as auric acid. It can be dehydrated at about 140°C to yield gold III oxide. Gold III hydroxide is found to form precipitates in alkaline solutions hence it is not soluble in calcium hydroxide.

However, gold III hydroxide forms an inorganic complex with ammonia which makes the insoluble gold III hydroxide to dissolve in ammonia solution. The equation of this complex formation is shown below;

Au(OH)3(s) + 4 NH3(aq) -------> [Au(NH3)4]^3+(aq) + 3OH^-(aq)

Hence the formation of a tetra amine complex of gold III will lead to the dissolution of gold III hydroxide solid in aqueous ammonia.

Answer:

B. Infrared.

Explanation:

Referring to the electromagnetic spectrum, ultraviolet rays can be measured with a frequency of 10‐⁸, infrared has a frequency of 10‐⁵, visible radiation has a frequency of 0.5 x 10‐⁶ meanwhile X-rays show a frequency of 10‐¹⁰.

Hence, the largest magnitude among the rest goes to infrared rays, which makes B the correct answer.

Answer:

i have no clue imma go with c

Explanation:

Answer:

2.4 grams of ClF3

Explanation:

First let us determine the moles of Cl2 and F2,

Cl2 = (  ( 337 )( 2.05 L ) / ( 0.082 )( 298 K ) ) * ( 1 atm / 780 ),

Cl2 = ( 690 / 24.436 ) * ( 1 / 780 ),

Cl2 = ( About ) 0.036 moles of Cl2

_________________________________________________

F2 = ( ( 729 )( 2 L ) / ( 0.082 )( 298 K ) ) * ( 1 atm / 780 ),

F2 = ( 1458 / 24.436 ) * ( 1 / 780 )

F2 = ( About ) 0.078 moles of F2

Now let us identify the limiting reactant, considering the ratio between ClF3 and Cl2 / F2. In this case F2 is the limiting reactant, as it forms a smaller molar ratio;

The theoretic yield is thus performed with the limiting reactant F2,

0.078 * ( 2 / 3 ) * ( 92.45 / 2 ) = ( About ) 2.4 grams of ClF3

Answer:

The final volume of the gas is 0.112 L

Explanation:

Step 1: Data given

Pressure is constant at 13.00 atm

The initial number of moles = 0.05 moles

The  temperature = 220.00 K

Initial volume = 0.07 L

The number of moles is increased to 0.08 moles

Step 2: Calculate the new volume

V1/ n1 = V2/n2

⇒with V1 = the initial volume of the gas = 0.07 L

⇒with n1 = the initial number of moles of gas = 0.05 moles

⇒with V2 = the final volume = TO BE DETERMINED

⇒with n2 = the final number of moles of gas = 0.08 moles

0.07 L / 0.05 moles = V2 / 0.08 moles

V2 = 0.07 L * 0.08 / 0.05 moles

V2 = 0.112 L

The final volume of the gas is 0.112 L

The species to be arranged are;

Sr2+, N3-, Li+, Ne, Br-, B3+, Al3+, He, Y3+

Answer:

Group A (10 electron species)

Al^3+, Ne, N^3-

Group B (36 electron species)

Sr^2+, Y^3+, Br^-

Group C ( 2 electron species)

He, Li^+, B^3+

Explanation:

Atoms and ions that have the same electron configuration are said to be isoelectronic. The species may not belong to the same group in the periodic table but are connected by the fact that they all have the same number of electrons. Cations and anions may belong to the same group of isoelectronic species provided that they all have the same number of electrons and the same electronic configuration.

Hence, in each group of isoelectronic species, one electronic configuration can be written for all the species and it will accurately represent the number of electrons for all species in the group since they have the same number of electrons.

For instance, all group C members have the electronic configuration, 1s2. This means that they all possess only two electrons.

Answer:

filtering

Explanation:

you're pouring the mixture through muslin cloth to keep the particles and bigger peaces out of the soap.

Answer:

the entropy change for the surroundings when 1.62 moles of CH4(g) react at standard conditions is −8.343 J/K

Explanation:

The balanced chemical equation of the reaction in the question given is:

[tex]CH_{4(g)} + 2O_{2(g)} \to CO_{2(g)} + 2 H_2O _{(g)}[/tex]

Using standard thermodynamic data at 298K.

The entropy of each compound above are listed as follows in a respective order.

Entropy of (CH4(g)) = 186.264 J/mol.K

Entropy of (O2(g)) = 205.138 J/mol.K

Entropy of (CO2(g)) = 213.74 J/mol.K

Entropy of (H2O(g)) = 188.825 J/mol.K

The change in Entropy (S) of the reaction is therefore calculated as follows:

[tex]=1*S(CO2(g)) + 2*S(H2O(g)) - 1*S( CH4(g)) - 2*S(O2(g))[/tex]

[tex]=1*(213.74) + 2*(188.825) - 1*(186.264) - 2*(205.138)[/tex]

=  -5.15  J/mol.K

Given that :

the number of moles = 1.62 of CH4(g) react at standard conditions.

Then;

The change in entropy of the rxn [tex]= 1.62 \ mol * -5.15 \ J/mol.K[/tex]

= −8.343 J/K

Answer:

All ionic substances are written as separate ions in solution

All ionic substances are written as separate ions in solution in a complete ionic equation. Therefore, option (C) is correct.

A complete ionic equation can be described as a particular chemical equation where charged atoms such as ions are expressed in a given solution. The complete ionic equations always contain all ions that are formed or act during a particular chemical reaction.

The net ionic equation can be described as an equation that provides information about ions that exists in an aqueous medium. Salts get dissolved in polar solvents such as water which are present as cations and anions in their dissolved state.

The ionic equation shows the chemical species that undergo a chemical change. The ions which are present on both sides of the equation are considered to be spectator ions. Therefore, in order to obtain the net ionic equation we can eliminate them.

Learn more about complete ionic equations, here:

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Answer:

(a) a first order reaction = s^-1.

(b) a second-order reaction = L(mol·s)

(c) a third-order reaction = s⁻¹M⁻²

Explanation:

Okay, this question is a question that has to do with kinetics that is how reaction occurs.

So, the RATE LAW is one of the concept that is being used in determining conditions of chemical reactions. The relationship between the the reactants molarity and the reaction rate is known as rate law. That is to say;

Rate law = K × Molarity.

So, In this question we are given that the concentrations measured in moles per liter, and time in seconds.

The FIRST ORDER REACTION has its unit for rate constant as per seconds(s^-1).

That is from; Rate law = k

Molarity/s = k × Molarity.

k = s^-1

(b) a second-order reaction;

Rate law= k × (molarity)^2.

Molarity/s = k × (Molarity)^2.

k = L(mol·s)

(c) A third-order reaction = s⁻¹M⁻²

Same thing applies.

Answer:

The rate constant has units of

a) s⁻¹ or /s for a first order reaction.

b) /sM or (s⁻¹M⁻¹) or (L/s.mol) or (L.s⁻¹mol⁻¹) for a second order reaction.

c) /sM² or s⁻¹M⁻² or (L²/s.mol²) or (L².s⁻¹mol⁻²) for a third order reaction.

Explanation:

The rate of a chemical reaction is defined as the amount (in concentration terms) of reactant used up or products formed per unit time. It's units generally is given in the units of concentration per unit time.

Rate = M/s or written extensively as mol/L/s = mol/L.s

And for all types of orders of reactions, the rate of reaction is given as

Rate = kCⁿ

k = Reaction rate constant

C = concentration of specie involved in the reaction

where n is the order of reaction.

Note that the units of the rate of the reaction still has to be mol/L.s or M/s regardless of its order.

M = mol/L

a) For a first order reaction

Rate = kC

M/s = k × M

K = (1/s)

Hence, the rate constant has a unit of /s or s⁻¹

b) Second order reaction

Rate = kC²

M/s = k × M²

k = (1/Ms)

Units of /sM or s⁻¹M⁻¹ or (L/s.mol)

c) Third order reaction

Rate = kC³

M/s = k × M³

k = (1/sM²)

Units of /sM² or s⁻¹M⁻² or (L²/s.mol²)

Hope this Helps!!!

Answer:

Ca₃(AsO₃)₂

Explanation:

Sodium arsenite, with the chemical formula Na₃AsO₃, is formed  by the cation Na⁺ and the anion AsO₃³⁻. For the molecule to be neutral, 3 cations Na⁺ and 1 anion AsO₃³⁻ are required.

Calcium arsenite would be formed by the cation Ca²⁺ and the anion AsO₃³⁻. For the molecule to be neutral, we require 3 cations Ca²⁺ and 2 anions AsO₃³⁻. The resulting chemical formula is Ca₃(AsO₃)₂.

Answer:

-30.7 kj/mol

Explanation:

The standard free energy for the given reaction that is the hydrolysis of ATP is calculated using the formula:  ∆Go ’= -RTln K’eq

where,  

R = -8.315 J / mo

T = 298 K

For reaction,

1. K′eq1=270,

∆Go ’= -RTln K’eq

= - 8.315 x 298 x ln 270

=  - 8.315 x 298 x 5.59

= - 13,851.293 J / mo

= - 13.85 kj/mol

2. K′eq2=890

∆Go ’= -RTln K’eq

= - 8.315 x 298 x ln 890

=  - 8.315 x 298 x 6.79

=  - 16.82 kj/mol

therefore, total standard free energy

= - 13.85 + (-16.82)

=  -30.7 kj/mol

Thus, -30.7 kj/mol is the correct answer.

Answer:

1. frequency = 7.39 * 10¹⁴ Hz

2. wavelength = 1.44 * 10⁸ nm

Explanation:

The speed, frequency and wavelength of waves are related by the formula;

speed = wavelength * frequency

1. wavelength of light = 406 nm = 4.06 * 10⁻⁷ m

speed of light is a constant = 3.0 * 10⁸ m/s

From the formula above, frequency = speed / wavelength

therefore, frequency = (3.0 * 10⁸ m/s) / 4.06 * 10⁻⁷ m

frequency = 7.39 * 10¹⁴ Hz

2. From the equation above, wavelength = speed/frequency

speed of radiation = 3.0 * 10⁸ m/s

frequency = 2.09 * 10⁹ Hz or 2.09 * 10⁹ s⁻¹

therefore, wavelength = (3.0 * 10⁸ m/s) / 2.09 * 10⁹ s⁻¹

wavelength = 1.44 * 10⁸ nm

Answer:

Rate of diffusion is same .

Explanation:

As we know that Rate of the diffusion is directly proportional to the [tex]\frac{1}{\sqrt{M} }[/tex] .They have same mass if there is same rate and similar condition therefore the mass of carbon (iv) oxide,propane and nitrogen (i) oxide will be similar.

Answer:

2.0 g Na

Explanation:

Stoichiometry.

8.4g sodium hydrogen citrate x (1 mol sodium hydrogen citrate / 192 g sodium hydrogen citrate) x (2 mol Na/1 mol sodium hydrogen citrate) x (23g Na/1 mol Na)

^write it out it makes more sense that way

Answer:

Centripetal acceleration of the wheel is [tex]0.145\ m/s^2[/tex].

Explanation:

We have,

Diameter of a Ferris wheel is 60 m

Radius of the wheel is 30 m

Speed of the wheel is 2.09 m/s

It is required to find the centripetal  acceleration of the wheel. The formula of centripetal acceleration is given by :

[tex]a=\dfrac{v^2}{r}\\\\a=\dfrac{(2.09)^2}{30}\\\\a=0.145\ m/s^2[/tex]

So, the centripetal acceleration of the wheel is [tex]0.145\ m/s^2[/tex].

Answer:

Its not balanced

4NH₃ + 7O₂ ⇒ 4NO + 6H₂O

Explanation:

Kp remains constant (if T=const.).

If Q<Kp, more reactants are consumed (the direct reaction is in progress). If Q>Kp the reverse reaction is in progress (the products are consumed).

1. A reaction will occur in which PCl5 (g) is consumed

A. If Kp > Qp  then 1,2,3 and 5 are F.  4 is T

B. Kc > Qc then 1,3 are T. 2,4,5 are F.

C. Qp > Kp then 1.3.4 are T. 2,5 are F.

Answer:

         H

         ° *         . .

H  ° *   C  * ·    Cl :

           * ·           . .

       :  Cl :

          . .

Explanation:

Carbon has 4 valent electrons

  *

 *C*

   *

Hydrogen has 1 electron

H°

Cl has 7 electrons on the last level.

 . .

: Cl·

 . .

         H

         ° *         . .

H  ° *   C  * ·    Cl :

           * ·           . .

       :  Cl :

          . .

The Lewis dot structure for [tex]H_2CCl_2[/tex] is explained in the explanation part below.

A Lewis structure is a symbolic depiction of a molecule or ion that depicts the arrangement of atoms and valence electrons.

It is also known as a Lewis dot structure or electron dot structure. Gilbert N. Lewis, an American chemist, invented it.

The total number of valence electrons in the molecule must be determined before writing the Lewis dot structure for H2CCl2 (dichloroethylene).

H has one valence electron, while C has four.

Cl has seven valence electrons.

Thus, the Lewis dot structure for the given compound is attached below as image.

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Answer:

1.) zinc and aluminum

2.)

a.) The old coating was made of tin.

b.) Aluminum would be a good choice for repairing the fracture.

Answer:

The correct answer is 0.047 mol/L

Explanation:

The atmospheric air is a mixture of gases. We can assume an ideal behavior of the gas and use the ideal gas equation:

PV= nRT

where P is the pressure, V is the volume, n is the number of moles, R is a constant (0.082 L.atm/K.mol) and T is the temperature in K.

We have to first convert the pressure from Torr to atm:

760 Torr= 1 atm

⇒ 718 Torr x 1 atm/760 Torr = 0.945 atm

Then, we convert the temperature from ºC to K:

0ºC = 273 K

⇒ -29ºC+273= 244 K

Finally, we introduce the data in the equation and calculate de densitiy, which is the moles per liters of gas (n/V):

PV = nRT

n/V= P/RT

n/V = (0.945 atm)/(0.082 L.atm/K.mol x 244 K) = 0.047 mol/L