¿Que es el emprendimiento Técnico computacional?

Explanation:

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Answer:B. File, New, Brochures

Explanation: Just took the test

Answer:

The program in Python is as follows:

myfile = open("sensor.dat", "r")

for line in myfile:

   print(line)

myfile.close()

Explanation:

This opens the file for read operation

myfile = open("sensor.dat", "r")

This iterates through the file

for line in myfile:

Print record on each row

   print(line)

Close file

myfile.close()

Answer:

Explanation:

The following code is written in Python. It is a function called checkString that takes in a string as an argument and loops through each char in that string and checking to see if it is lowercase, uppercase, vowel, consonant, or punctuations. It adds 1 to the correct variable. At the end of the loop it prints out all of the variables. The picture below shows a test output with the string "Brainly, Question."

def checkString(word):

   uppercase = 0

   lowercase = 0

   vowel = 0

   consonants = 0

   punctuation = 0

   vowelArray = ['a', 'e', 'i', 'o','u', 'y' ]

   consonantArray = ['b', 'c', 'd', 'f', 'g', 'h', 'j', 'k', 'l', 'm', 'n', 'p', 'q', 'r', 's', 't', 'v', 'w', 'x', 'y', 'z']

   punctuationArray = ['.', '!', '?', ',', ';', '(', ')']

   for char in word:

       if char.isupper():

           uppercase += 1

       else:

           lowercase += 1

       if char.lower() in vowelArray:

           vowel += 1

       elif char.lower() in consonantArray:

           consonants += 1

       if char in punctuationArray:

           punctuation += 1

   print('Uppercase: ' + str(uppercase))

   print('Lowercase: ' + str(lowercase))

   print('Vowels: ' + str(vowel))

   print('Consonants: ' + str(consonants))

   print('Punctuations: ' + str(punctuation))

Answer:

High level programming language is a language that simplifies computer programming.

Examples are python, visual basic,java,JavaScript .It is a language with abstraction from details of the computer.

Answer:

Option D

Explanation:

An Entitlement is an option to utilize, get to or devour an application or asset, commonly for a charge. For instance, a client may buy an Entitlement to utilize an application in ceaselessness (a "unending" permit), or they may buy a period restricted option to utilize an application, (for example, a one-year membership permit).

Answer: Reverse DNS zone

Explo: a reverse DNS zone needs a PTR record since it is in charge of resolving the IP address to a domain or a hostname.

Answer:

if-then-else

switch (expr) { case value: statements ;}

Explanation:

Required

Which do not represent loop

Literally, looping means repeating an action or sequence of actions as long as a given condition is true.

For options (a) to (d), we have:

(a): if-then-else:

if statements are used to test conditions; depending on the truth or falsity of the condition, only one block of code can be executed at once.

In summary, if statements are not loops

(b): switch statements

This is an alternate to if statements and can be used in place of if statements.

Hence, switch statements are not loops

(c) and (d): for and while:

The above represent loops, because they both involve repetition of operations until the condition is no longer satisfied.

Answer:

Structured

Explanation:

A data dictionary can be defined as a centralized collection of information on a specific data such as attributes, names, fields and definitions that are being used in a computer database system.

In a data dictionary, data elements are combined into records, which are meaningful combinations of data elements that are included in data flows or retained in data stores.

This ultimately implies that, a data dictionary found in a computer database system typically contains the records about all the data elements (objects) such as data relationships with other elements, ownership, type, size, primary keys etc. These records are stored and communicated to other data user when required or needed.

A relational database can be defined as a type of database that is structured in a manner that there exists a relationship between its elements.

Hence, when a user completes a form online by providing his or her name, address, and credit card information in order to make a purchase, he or she is giving the company structured data (pre-defined and formatted to a set structure) that can be used to make up (populate) a relational database or spreadsheet.

A spreadsheet can be defined as a file or document which comprises of cells in a tabulated format (rows and columns) typically used for formatting, arranging, analyzing, storing, calculating and sorting data on computer systems.

Answer:

Follows are the code to the given question:

def steps_to_miles(user_steps):#defining a method steps_to_miles that takes a variable user_steps

   return user_steps/2000#use return to calculate the steps

user_steps = int(input())#defining a variable user_steps that holds value from the user-end

print('%0.2f' % steps_to_miles(user_steps))#defining print that calls the steps_to_miles method

Output:

5345

2.67

Explanation:

In this code a method "steps_to_miles" that takes "user_steps" in the parameter inside the method a return keyword is used that calculates the user steps and return its values.

Outside the method, a "user_steps" variable is declared that inputs the value from the user-end pass into the method and prints its value.

Answer:

To make the value 10 also part of the loop, the while statement must be "while x<=10" otherwise 10 is excluded. To have only even numbers, x should be increased by 2, not 1, i.e.: "x = x + 2".

Answer:

The programs are written in python:

Version 1:

n = int(input("Numbers: "))

for i in range(n):

   num = int(input("Input integer: "))

   mylist = []

   while num>0:

       mylist.append(num%10)

       num= int(num/10)

   mylist.reverse()

   for i in mylist:

       print(i,end=" ")

   print()

Version 2:

num = int(input("Input integer: "))

while num > 0:

   mylist = []

   while num>0:

       mylist.append(num%10)

       num= int(num/10)

   mylist.reverse()

   for i in mylist:

       print(i,end=" ")

   print()

   num = int(input("Input integer: "))

Explanation:

Version 1:

This gets the number of inputs from the user, n

n = int(input("Numbers: "))

This iterates through n

for i in range(n):

For each iteration, this gets the integer input from the user, num

   num = int(input("Input integer: "))

This initializes a list

   mylist = []

This loop is repeated until num is 0

   while num>0:

This gets the individual digit and appends it to a list

       mylist.append(num%10)

This gets the other numbers

       num= int(num/10)

This reverses the list

   mylist.reverse()

This prints the individual digits from the list

   for i in mylist:

       print(i,end=" ")

Print a new line for the next integer input

   print()

Version 2:

The difference in both versions are the following lines

This gets the integer input from the user

num = int(input("Input integer: "))

This loop enables the user to input as many numbers as possible. But once the user inputs 0, the program will stop

while num > 0:

Unlike version 1 where the number of inputs in known at the initial stage of the program

Answer:

Explanation:

The following code is written in Java. It creates the Bug class with the position and direction variables. Then it creates a constructor, move method, turn method, and getPosition method. Finally, a bug object called bugsy is created in the main method, and we move it once to the right, then again to the right, and then we turn it and move it 5 times to the left, printing out the position when it is done moving. Output can be seen in the attached picture below.

class Brainly {

   public static void main(String[] args) {

       Bug bugsy = new Bug(10);

       bugsy.move();

       System.out.println("Current bug position: " + bugsy.getPosition());

       bugsy.move();

       System.out.println("Current bug position: " + bugsy.getPosition());

       bugsy.turn();

       bugsy.move();

       bugsy.move();

       bugsy.move();

       bugsy.move();

       bugsy.move();

       System.out.println("Current bug position: " + bugsy.getPosition());

   }

}

class Bug {

   char direction = 'r';

   int position = 0;

   public Bug(int initialPosition) {

       this.position = initialPosition;

   }

   public void turn() {

       if (this.direction == 'r') {

           this.direction = 'l';

       } else {

           this.direction = 'r';

       }

   }

   public void move() {

       if (this.direction == 'r') {

           this.position += 1;

       } else {

           this.position -= 1;

       }

   }

   public int getPosition() {

       return this.position;

   }

}

In this exercise we want to use computer and Java knowledge to write the code correctly, so it is necessary to add the following to the informed code:

Output can be seen in the attached picture below

The following secret language system exist composed fashionable Java. It develop in mind or physically the bug class accompanying the position and direction variables. Then it develop in mind or physically a builder, move arrangement, turn means, and catch position procedure.

Finally, a bug object named bugsy happen develop in mind or physically usually pattern, and we fast once to the right, therefore another time to the right, and before we turn it and speedy 5 period to the abandoned, a process of reproduction out the position when it exist thoroughly cooked mobile. We have that:

class Brainly {

  public static void main(String[] args) {

      Bug bugsy = new Bug(10);

      bugsy.move();

      System.out.println("Current bug position: " + bugsy.getPosition());

      bugsy.move();

      System.out.println("Current bug position: " + bugsy.getPosition());

      bugsy.turn();

      bugsy.move();

      bugsy.move();

      bugsy.move();

      bugsy.move();

      bugsy.move();

      System.out.println("Current bug position: " + bugsy.getPosition());

  }

}

class Bug {

  char direction = 'r';

  int position = 0;

  public Bug(int initialPosition) {

      this.position = initialPosition;

  }

  public void turn() {

      if (this.direction == 'r') {

          this.direction = 'l';

      } else {

          this.direction = 'r';

      }

  }

  public void move() {

      if (this.direction == 'r') {

          this.position += 1;

      } else {

          this.position -= 1;

      }

  }

  public int getPosition() {

      return this.position;

  }

}

See more about computer at brainly.com/question/950632

Answer:

Quick Analysis toolbar

Explanation:

it appears with the options formatting, chart, total, table, sparklines

Answer:

Here the given problem is modeled as a Graph problem.

Explanation:

Input:-  n, k and the function d(pi,pj) which outputs an integer between 1 and n2

Algorithm:-We model each student as a node. So, there would be n nodes. We make a foothold between two nodes u and v (where u and v denote the scholars pu and pv respectively) iff d(pu,pv) > k. Now, Let's call the graph G(V, E) where V is that the vertex set of the graph ( total vertices = n which is that the number of students), and E is that the edge set of the graph ( where two nodes have edges between them if and only the drama between them is bigger than k).

We now need to partition the nodes of the graph into two sets S1 and S2 such each node belongs to precisely one set and there's no edge between the nodes within the same set (if there's a foothold between any two nodes within the same set then meaning that the drama between them exceeds k which isn't allowed). S1 and S2 correspond to the partition of scholars into two buses.

The above formulation is akin to finding out if the graph G(V,E) is a bipartite graph. If the Graph G(V, E) is bipartite then we have a partition of the students into sets such that the total drama <= k else such a partition doesn't exist.

Now, finding whether a graph is bipartite or not is often found using BFS (Breadth First algorithm) in O(V+E) time. Since V = n and E = O(n2) , the worst-case time complexity of the BFS algorithm is O(n2). The pseudo-code is given as

PseudoCode:

// Input = n,k and a function d(pi,pj)

// Edges of a graph are represented as an adjacency list

1. Make V as a vertex set of n nodes.

2. for each vertex  u ∈ V

[tex]\rightarrow[/tex]  for each vertex v ∈ V

[tex]\rightarrow\rightarrow[/tex]if( d(pu, pj) > k )

[tex]\rightarrow\rightarrow\rightarrow[/tex] add vertex u to Adj[v]   // Adj[v] represents adjacency list of v

[tex]\rightarrow\rightarrow\rightarrow[/tex] add vertex v to Adj[u] // Adj[u] represents adjacency list of u

3.  bool visited[n] // visited[i] = true if the vertex i has been visited during BFS else false

4. for each vertex u ∈ V

[tex]\rightarrow[/tex]visited[u] = false

5. color[n] // color[i] is binary number used for 2-coloring the graph  

6. for each vertex u ∈ V  

[tex]\rightarrow[/tex] if ( visited[u] == false)

[tex]\rightarrow\rightarrow[/tex] color[u] = 0;

[tex]\rightarrow\rightarrow[/tex] isbipartite = BFS(G,u,color,visited)  // if the vertices reachable from u form a bipartite graph, it returns true

[tex]\rightarrow\rightarrow[/tex] if (isbipartite == false)

[tex]\rightarrow\rightarrow\rightarrow[/tex] print " No solution exists "

[tex]\rightarrow\rightarrow\rightarrow[/tex] exit(0)

7.  for each vertex u ∈V

[tex]\rightarrow[/tex] if (color[u] == 0 )

[tex]\rightarrow\rightarrow[/tex] print " Student u is assigned Bus 1"

[tex]\rightarrow[/tex]else

[tex]\rightarrow\rightarrow[/tex] print " Student v is assigned Bus 2"

BFS(G,s,color,visited)  

1. color[s] = 0

2. visited[s] = true

3. Q = Ф // Q is a priority Queue

4. Q.push(s)

5. while Q != Ф {

[tex]\rightarrow[/tex] u = Q.pop()

[tex]\rightarrow[/tex] for each vertex v ∈ Adj[u]

[tex]\rightarrow\rightarrow[/tex] if (visited[v] == false)

[tex]\rightarrow\rightarrow\rightarrow[/tex] color[v] = (color[u] + 1) % 2

[tex]\rightarrow\rightarrow\rightarrow[/tex] visited[v] = true

[tex]\rightarrow\rightarrow\rightarrow[/tex] Q.push(v)

[tex]\rightarrow\rightarrow[/tex] else

[tex]\rightarrow\rightarrow\rightarrow[/tex] if (color[u] == color[v])

[tex]\rightarrow\rightarrow\rightarrow\rightarrow[/tex] return false // vertex u and v had been assigned the same color so the graph is not bipartite

}

6. return true

Answer:

Procreate

Explanation:

Answer:

The program in Python is as follows:

mnths = ["january","february","march","april","may","june","july","august","september","october","november","december"]

days = int(input("Day: "))

month = input("Month: ")

if not(month.lower() in mnths):

   print("Invalid")

else:

   month_index = mnths.index(month.lower())

   if month_index == 0:

       if days<1 or days>31:            print("Invalid")

       else:            print("Winter")

   elif month_index == 1:

       if days<1 or days>28:            print("Invalid")

       else:            print("Winter")

   elif month_index == 2:

       if days<1 or days>31:            print("Invalid")

       elif days<= 19:            print("Winter")

       else:            print("Spring")

   elif month_index == 3:

       if days<1 or days>30:            print("Invalid")

       else:            print("Spring")

   elif month_index == 4:

       if days<1 or days>31:            print("Invalid")

       else:            print("Spring")

   elif month_index == 5:

       if days<1 or days>30:            print("Invalid")

       elif days<= 20:            print("Spring")

       else:            print("Summer")

   elif month_index == 6:

       if days<1 or days>31:            print("Invalid")

       else:            print("Summer")

   elif month_index == 7:

       if days<1 or days>31:            print("Invalid")

       else:            print("Summer")

   elif month_index == 8:

       if days<1 or days>31:            print("Invalid")

       elif days<= 21:            print("Summer")

       else:            print("Autumn")

   elif month_index == 9:

       if days<1 or days>31:            print("Invalid")

       else:            print("Autumn")

   elif month_index == 10:

       if days<1 or days>30:            print("Invalid")

       else:            print("Autumn")

   elif month_index == 11:

       if days<1 or days>31:            print("Invalid")

       elif days<21:            print("Autumn")

       else:            print("Winter")

Explanation:

See attachment for complete source file, where comments are used to explain difficult lines

Answer:

hope it is helpful to you

stay safe, happy and healthy

Formatted the text in a document can draw the reader's attention to specific parts of a document and it also emphasize important information. In the word file, a person may have several options for adjusting the text, including font, size, and color.

Document formatting can be referred to as the way in which a document is laid out on the page, it is the way in which it looks and is visually organized and it addresses all the things such as font selection, font size and presentation like bold or italics font, spacing, margins, alignment, columns, indentation, and lists.

Document formatting is the mechanics of how the words appear on the page or the document. A well formatting document is consistent, and it is correct in terms of meeting any stated requirements, and easy to be read by anyone.

Learn more about Document formatting here:

https://brainly.com/question/21934838

#SPJ2

The protocol is indeed a set of rules and principles for data transmission and the further discussion can be defined as follows:

Therefore, the answer is Option "b,d,f, and g".

Learn more protocol operating:

brainly.com/question/14681103

Answer:

Those movies have inapropirate parts and it is really scary. Also, those movies are not meant for little kids.

Explanation:

Answer:

B

Explanation:

Adding Web pages helps Web designers Organize information. The correct option is B)

A website should be made such that anyone using it can quickly find what they're searching for and understand what each feature on the page performs without having to ask for assistance or go through a lengthy tutorial.

When users access the website for the first time, they should be able to do so right away and do so as frequently as they have in the past. Additionally, the website needs to be responsively constructed. Web design is crucial because it affects how potential customers see your company.

The first impression you provide them will determine whether they stay on your page to learn more about your company, or whether they click on a competitor's page instead.

Therefore, the correct option is B) Organize information.

To learn more about a web page, refer to the link:

https://brainly.com/question/22775095

#SPJ2

Answer:

SEO stands for “search engine optimization.” In simple terms, it means the process of improving your site to increase its visibility for relevant searches.

SEM, or search engine marketing, is the act of using paid strategies to increase search visibility.

Explanation:

its a laptop ☺️. . . . . .. . .

Answer and Explanation:

Using Javascript:

We could just use ES6 syntax and quickly get our result with no long coding. ECMA script 2015, the sixth version of javascript programming language has an array method that returns the unique values of an array in a new array.

var allValues = [ 1,3,4,1,3,9 ];

let uniqueValues = [...new Set(allValues)];

console.log(uniqueValues);

This will output only the unique values 1,3,4,9

Answer:

video - includes file formats AVI and WMV

graphics - includes maps and photographs  

animation - includes a rapid display of a sequence of static images

audio - includes file formats WAV and MPEG 3

Explanation:

The given elements of a web page have correctly been matched with their descriptions in order to define them adequately. The element that characterizes video data involves a common format of files like AVI(in Microsoft) and WMV(windows media video). While Graphics are described as the pictorial representation and manipulation of data and hence, it involves pictures, along with, photos. Animation involves the process of giving inanimate objects or drawings a motion form and hence, it includes a series of static images to show the movement. While audio lays focus on audible sound with formats like MPEG 3(audio file).

Answer:

video - includes file formats AVI and WMV

graphics - includes maps and photographs  

animation - includes a rapid display of a sequence of static images

audio - includes file formats WAV and MPEG 3

Explanation

Edmentum.

Answer:to allow many programs, through the efficient use of computing resources including processors and memory, to operate on a single hardware package.

Explanation:

Answer:

a. True

Explanation:

A computer can be defined as an electronic device that is capable of receiving of data in its raw form as input and processes these data into information that could be used by an end user. Computers can be classified on the basis of their size and capacity as follows;

I. Supercomputers.

II. Mainframe computers.

III. Mini computers.

IV. Micro computers.

Mainframe computers were developed and introduced in the early 1950s.

Mainframe computers are specifically designed to be used for performing multi-programming because they are high-performance computers with the ability to handle multiple users. As a result, it simply means that mainframe computers can be used to effectively and efficiently perform the work of over one hundred (100) users at a time on the computer. Some examples of mainframe computers include the following; IBM Es000 series, CDC 6600 and ICL39 Series.

Furthermore, mainframe computers are mostly or commonly used by large companies, business firms or governmental institutions for performing various complex tasks such as census, financial transactions, e-commerce, data sequencing, enterprise resource planning, etc.

Answer:

a. True

Explanation:

A mainframe computer, informally called a mainframe or big iron, is a computer used primarily by large organizations for critical applications, bulk data processing (such as the census and industry and consumer statistics, enterprise resource planning, and large-scale transaction processing).

Answer:

True

Explanation:

The Huawei developed Nanomemory Card (used for phones) can also be used for computers. A nanomemory card is just like an SD card, it provides you with extra storage space. Computer memory is also measured in nanomemory, so it can be used. Therefore, the answer to the question is True.

Best of Luck!