The force of gravity points straight down, but a ball rolling down a ramp doesn't go straight down, it follows the ramp. Therefore, only the component of the gravitational force which points along the direction of the ball's motion can accelerate the ball. The other component pushes the ball into the ramp, and the ramp pushes back, so there is no acceleration of the ball into the ramp. If the ramp is horizontal, then the ball does not accelerate, as gravity pushes the ball into the ramp and not along the surface of the ramp. If the ramp is vertical, the ball just drops with acceleration due to gravity. These arguments are changed a bit by the fact that the ball is rolling and not sliding, but that only affects the magnitude of the acceleration but not the fact that it increases with ramp steepness.
When a sample of gas was placed in a sealed container with a volume of 3.35 L and heated to
75°C, the gas vaporized and the resulting pressure inside the container was 17atm. How
many moles of the gas were present?. Single line text.
Answer:
Explanation:What is the demand factor for three commercial ranges?
A sealed 1.0L flask is filled with 0.500 mols of I_2 and 0.500 mols of Br_2. When the container achieves equilibrium the equilibrium constant is 1.10x10^{-2}. What is the equilibrium concentration of the product, IBr?
Answer:
[IBr] = 0.049 M.
Explanation:
Hello there!
In this case, according to the balanced chemical reaction:
[tex]I_2+Br_2\rightarrow 2IBr[/tex]
It is possible to set up the following equilibrium expression:
[tex]K=\frac{[IBr]^2}{[I_2][Br_2]} =0.0110[/tex]
Whereas the the initial concentrations of both iodine and bromine are 0.50 M; and in terms of [tex]x[/tex] (reaction extent) would be:
[tex]0.0110=\frac{(2x)^2}{(0.50-x)^2}[/tex]
Which can be solved for [tex]x[/tex] to obtain two possible results:
[tex]x_1=-0.0277M\\\\x_2=0.0245M[/tex]
Whereas the correct result is 0.0245 M since negative results does not make any sense. Thus, the concentration of the product turns out:
[tex][IBr]=2x=2*0.0249M=0.049M[/tex]
Regards!
Which answer would represent 0.001 moles?
Answer:
Which answer would represent 0.001 moles?
Hydrochloric acid reacts with sodium hydroxide to form water and sodium chloride. Hydrochloric acid is an extremely acidic, clear, corrosive liquid. Sodium hydroxide is a very basic white solid.
What can be known about the reactants of this reaction?
They will be clear.
They will not have the properties of sodium hydroxide or hydrochloric acid.
They will be corrosive.
They will have the properties of sodium hydroxide or hydrochloric acid.
The answer is C.
You're welcome!
"How many grams of CaCl2 would be dissolved in 1.0 L of a 0.10 M solution of CaCl2? "
Answer:
2365 g
Explanation:
The mass of CaCl₂ will be 110.98 grams, this can be calculated by using the molarity formula.
MolarityIt is defined as the ratio of a number of moles of solute to the volume of solution in liters.
It is given by:
M= n/V
What information do we have?
V= 1.0 L
M= 1.0 M
Molar mass of CaCl₂ = 110.98g/mol
To find:
m=?
M= n/V
n= M/V
n= 1 mole
A Number of moles is the ratio of mass over the molar mass.
n = m/ M
1 mole= m / 110.98 g/mol
m= 110.98 grams
Thus, the mass of calcium chloride is 110.98 grams.
Find more information about Molarity here:
brainly.com/question/17138838
What is the result of wave motion on water particles?
A. Water particles barely move forward; they move in a circular pattern.
B. Water particles barely move forward as they move up and down.
C. Water particles are pushed forward as they move up and down.
D. Water particles are pushed down as they move side to side.
Answer:
A. Water particles barely move forward; they move in a circular pattern.
Answer:
For k-12 its:
Explanation:
Water particles barely move forward; they move in a circular pattern.
^^
Hydrogen peroxide with a concentration of 3.0 percent (3.0 g of H2O2 in 100 mL of solution) is sold in drugstores for use as an antiseptic. For a 10.0-mL 3.0 percent H2O2 solution, calculate (a) the oxygen gas produced (in liters) at STP when the compound undergoes complete decomposition and (b) the ratio of the volume of O2 collected to the initial volume of the H2O2 solution.
Answer:
a) 0.099 L
b) 9.9
Explanation:
Now, given the equation for the decomposition of H2O2;
2H2O2(l) ------> 2H2O(l) + O2(g)
Mass of H2O2;
percent w/v concentration = mass/volume * 100
volume = 10.0-mL
percent w/v concentration = 3.0 percent
mass of H2O2 = x
3 = x/ 10 * 100
30 = 100x
x = 30/100
x = 0.3 g of H2O2
Number of moles in 0.3 g of H2O2 = mass/ molar mass
Molar mass of H2O2 = 34.0147 g/mol
Number of moles in 0.3 g of H2O2 = 0.3g/34.0147 g/mol
= 0.0088 moles
From the reaction equation;
2 moles of H2O2 yields 1 mole of oxygen
0.0088 moles of H2O2 = 0.0088 * 1/2 = 0.0044 moles of oxygen
If 1 mole of oxygen occupies 22.4 L
0.0044 moles of oxygen occupies 0.0044 * 22.4/1
= 0.099 L
b) initial volume of the H2O2 solution = 10 * 10-3 L
Hence, ratio of the volume of O2 collected to the initial volume of the H2O2 solution = 0.099 L/10 * 10-3 L = 9.9
How does air flow when a low-pressure center occurs in the
atmosphere?
Answer:
A
Explanation:
It is so because the low air pressure create vacuum and the air from high pressure area move toward the low air pressure.
Set of degenerate orbital in germanium
Answer:
Which set of orbitals are degenerate?
Degenerate is used in quantum mechanics to mean 'of equal energy. ' It usually refers to electron energy levels or sublevels. For example, orbitals in the 2p sublevel are degenerate - in other words the 2px, 2py, and 2pz orbitals are equal in energy, as shown in the diagram.
Explanation:
Answer:
Electron orbitals having the same energy levels are called degenerate orbitals, For example, orbitals in the 2p sublevel are degenerate - in other words the 2px, 2py, and 2pz orbitals are equal in energy.
Which one is not an ore of copper
1 Azurite
2 Malachite
3 Haematite
4 Chalcopyrite
i need help with this please
Answer:
owa owa owa owa
Explanation:
owa owa owa owa owa owa owa
What is the skin's natural oil?
a. sweet
b. Melanin
c. sebum
d. vegetable oil
help
Answer:
C. Sebum
Explanation:
C. Sebum