Answer:
Lithium shows anomalous behavior due to its small size. The polarizing power of lithium ion is highest of all the alkali metal ion . Because of small size, Lithium is very hard, less reactive as compare to other alkali metals like sodium and potassium.
Hope this helps:)
Calculate the molar mass of Ba(C2H3O2)2
Answer:
1. Barium Acetate.
2. Formula: Ba(C2H3O2)2.
3. Molar Mass: 255.415.
Explanation:
What is the mass of oxygen gas in a 12.2 L
container at 16.0°C and 8.15 atm?
Answer in units of g.
Answer:
grams O₂ = 134 grams
Explanation:
PV = nRT => n = PV/RT
P = 8.15atm
V = 12.2 Liters
R = 0.08206L·atm/mol·K
T = 16.0°C + 273 = 289K
n = (8.15atm)(12.2L)/(0.08206L·atm/mol·K)(289K) = 4.2 moles O₂
grams O₂ = 4.2 moles O₂ x 32g/mol = 134 grams O₂
What is the mass of 2.18 mol of Cu?
139 g Cu
General Formulas and Concepts:Math
Pre-Algebra
Order of Operations: BPEMDAS
Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to RightChemistry
Atomic Structure
Reading a Periodic TableMolesStoichiometry
Using Dimensional AnalysisExplanation:Step 1: Define
[Given] 2.18 mol Cu
[Solve] grams Cu
Step 2: Identify Conversion
[PT] Molar Mass of Cu - 63.55 g/mol
Step 3: Convert
[DA] Set up: [tex]\displaystyle 2.18 \ mol \ Cu(\frac{63.55 \ g \ Cu}{1 \ mol \ Cu})[/tex][DA] Multiply [Cancel out units]: [tex]\displaystyle 138.539 \ mol \ Cu[/tex]Step 4: Check
Follow sig fig rules and round. We are given 3 sig figs.
138.539 g Cu ≈ 139 g Cu
Which of the following can limit the growth of a population of organisms?
O Both diseases and the availability of resources can limit the growth of a population of organisms.
Diseases can limit the growth of a population of organisms, but the availability of resources cannot.
O The availability of resources can limit the growth of a population of organisms, but diseases cannot.
O Neither diseases nor the availability of resources can limit the growth of a population of organisms.
Answer: The answer is both diseases and availability of resources can limit the growth of a population of organisms which is A
Explanation:
WS 3.5 more Lewis structures
The total oxide ion charge in a formula unit of Mn2O3 is 6-. What is the charge on each manganese ion ?
Answer:
Mn= +3 charge
Explanation:
if you take what we know, and that would be the charge of oxygen, we know that oxygen has a 2- charge and there are 3 sets of O^2- so multiply the number of oxygen times the charge and you get 6-.
Next set up an equation as listed in the picture which will be 2(x)=6
and that is the charge of the Mn ion.
EASY CHEM, WILL GIVE BRAINLIEST!!
Hi there!
[tex]\large\boxed{4.04g}[/tex]
To solve, we can use dimensional analysis to convert from molecules to grams.
We must use Avogadro's number (6.02 × 10²³) in converting from molecules to moles.
After converting, multiply by the atomic mass, or grams per mole.
[tex]1.204 * 10^{24} moles *\frac{1 mol}{6.02*10^{23}moles}* \frac{2.02g}{1mol }= 4.04g[/tex]
Which of the following is TRUE if Esys = 260 J?
Answer:
Both the system and the surroundings are losing 260 J. The system is gaining 260 J, while the surroundings are losing 260 J. Both the system and the surroundings are gaining 260 J. The system is losing 260 J, while the surroundings are gaining 260 J. None of the above is true.
Somebody help me asap please giving brainliest (answer to the both of them)
Answer:
1. Causes air to vibrate 2. A hydroelectric dam generating electricity on a river
what is the oxidation state of nitrogen in a nh4f molecule
Answer:
+3
Explanation:
NH₄F
=> N + 4H + F = 0
=> N + 4(+1) + 1(-7) = 0
=> N = 7 - 4 = +3
A 0.5242-g sample of a compound known to contain only carbon, hydrogen, and oxygen was burned in oxygen to yield 0.9740 g of CO2 and 0.1994 g of H2O. What is the empirical formula of the compound?
Answer:
C₃H₃O₂
Explanation:
From the question given above, the following data were obtained:
Mass of compound = 0.5242 g
Mass of CO₂ = 0.9740 g
Mass of H₂O = 0.1994 g
Empirical formula =?
Next, we shall determine the mass of carbon, hydrogen and oxygen present in the compound. This can be obtained as follow:
For carbon, C:
Mass of CO₂ = 0.9740 g
Molar mass of CO₂ = 12 + (16×2)
= 12 + 32 = 44 g/mol
Mass of C = 12/44 × 0.9740
Mass of C = 0.2656 g
For hydrogen, H:
Mass of H₂O = 0.1994 g
Molar mass of H₂O = (2×1) + 16
= 2 + 16 = 18 g/mol
Mass of H = 2/18 × 0.1994
Mass of H = 0.0222 g
For oxygen, O:
Mass of compound = 0.5242 g
Mass of C = 0.2656 g
Mass of H = 0.0222 g
Mass of O =?
Mass of O = (Mass of compound) – (Mass of C + Mass of H)
Mass of O = 0.5242 – (0.2656 + 0.0222)
Mass of O = 0.5242 – 0.2878
Mass of O = 0.2364 g
Finally, we shall determine the empirical formula. This can be obtained as follow:
Mass of C = 0.2656 g
Mass of H = 0.0222 g
Mass of O = 0.2364 g
Divide by their molar mass
C = 0.2656 /12 = 0.0221
H = 0.0222 /1 = 0.0222
O = 0.2364 /16 = 0.0148
Divide by the smallest
C = 0.0221 / 0.0148 = 1.5
H = 0.0222 / 0.0148 = 1.5
O = 0.0148 / 0.0148 = 1
Multiply through by 2 to express in whole number.
C = 1.5 × 2 = 3
H = 1.5 × 2 = 3
O = 1 × 2 = 2
Empirical formula => C₃H₃O₂
type of environmental factors such as the presence of a hormone that might affect an organism's phenotype is __________
about the door is locked and I think I have a few questions about the door is locked and I think I have
Explanation:
can you tell me what the door is locked and I think I have a few questions about the door is locked and I think I have a few questions
9.
Calculate the mass of a liquid with a density of 3.2 g/mL and a volume of 24 mL.
4. How many moles of gold (Au) are in a pure gold nugget having a mass of 25.0 grams.
0.127 mol Au
General Formulas and Concepts:Math
Order of Operations: BPEMDAS
BracketsParenthesisExponentsMultiplicationDivisionAdditionSubtractionLeft to RightChemistry
Atomic Structure
Reading a Periodic TableMolesStoichiometry
Using Dimensional AnalysisExplanation:Step 1: Define
[Given] 25.0 g Au
[Solve] moles Au
Step 2: Identify Conversions
[PT] Molar Mass of Au - 196.97 g/mol
Step 3: Convert
[DA] Set up: [tex]\displaystyle 25.0 \ g \ Au(\frac{1 \ mol \ Au}{196.97 \ g \ Au})[/tex][DA] Multiply/Divide [Cancel out units: [tex]\displaystyle 0.126923 \ mol \ Au[/tex]Step 4: Check
Follow sig fig rules and round. We are given 3 sig figs.
0.126923 mol Au ≈ 0.127 mol Au
Answer:
[tex]\boxed {\boxed {\sf 0.127 \ mol \ Au}}[/tex]
Explanation:
To convert from mass to moles, the molar mass must be used. This can be found on the Periodic Table.
Gold (Au): 196.96657 g/molUse this number as a ratio.
[tex]\frac {196.96657 \ g\ Au }{1 \ mol \ Au}[/tex]
Multiply by the given number of grams.
[tex]25.0 \ g \ Au*\frac {196.96657 \ g\ Au }{1 \ mol \ Au}[/tex]
Flip the fraction so the grams of gold will cancel.
[tex]25.0 \ g \ Au*\frac {1 \ mol \ Au}{196.96657 \ g\ Au }[/tex]
[tex]25.0*\frac {1 \ mol \ Au}{196.96657 }[/tex]
[tex]\frac {25.0 \ mol \ Au}{196.96657 }[/tex]
[tex]0.1269250919 \ mol \ Au[/tex]
The original measurement has 3 significant figures, so the answer must have the same. For the number we calculated that is the thousandth place. The 9 in the ten thousandth place tells us to round the 6 to a 7.
[tex]0.127 \ mol \ Au[/tex]
25.0 grams of gold is about 0.127 moles of gold.
Pleaaase argent !!! Explain ur answers
Consider the following reaction:
Fe3+(aq) + SCN-(aq) ↔︎ [Fe(SCN)]2-(aq)
1)Explain what is meant by the term dynamic equilibrium.
2)Write the equilibrium expression for the reaction.
3) The numerical value of Kc at 298K is about 1000 for the reaction. What does this tell you about the position of the equilibrium at 298K?
Answer:
1. Dynamic equilibrium is a equilibrium in which the rate of forward direction is equal to the rate of backward direction. It is represented by a right left arrow.
2) Equilibrium constant is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric ratios. It is expressed as [tex]K_c[/tex]
For the given chemical reaction:
[tex]Fe^{3+}(aq)+SCN^-(aq)\rightleftharpoons [Fe(SCN)]^{2-}(aq)[/tex]
The expression for [tex]K_c[/tex] is written as:
[tex]K_c=\frac{[[Fe(SCN)]^{2-}]}{[Fe^{3+}][SCN^-]}[/tex]
3) The value of [tex]K_c[/tex] is 1000 , which means the products are more favoured as compared to reactants and that the equilibrium lies more towards product side.
in which of the following aqueous solutions would you expect AgCl to have the HIGHEST solubility?a) Pure Waterb) 0.015 M NaClc) 0.020 M AgNO3d) 0.020 M KCle) 0.020 M BaCl2
Answer:
Pure Water
Explanation:
The common ion effect describes the effect on equilibrium that occurs when a common ion (an ion that is already contained in the solution) is added to a solution. The common ion effect generally decreases solubility of a solute(Khan Academy).
NaCl, AgNO3, KCl, BaCl2 solutions all have a common ion with AgCl. As a result of this, AgCl will be much less soluble in these solvents than it is in pure water.
Therefore, AgCl will have the highest solubility in pure water compared to all the solutions listed above.
How many microliters are in 41.0 mL
Answer:
41000 is the answer
The amount of microliters in 41.0 mL is 41,000 microliters
How to find the volume in microlitersTo convert milliliters (mL) to microliters (µL), you need to multiply the value in milliliters by 1000 because there are 1000 microliters in 1 milliliter.
So, to convert 41.0 mL to microliters:
41.0 mL * 1000 = 41,000 µL
Therefore, there are 41,000 microliters in 41.0 mL.
Learn more about microliters at
https://brainly.com/question/32138755
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Do all living things depend on nonliving things to survive? Support your answer with an example.
Answer:
Living things need nonliving things to survive. Without food, water, and air, living things die. Sunlight, shelter, and soil are also important for living things. ... Plants use water from the soil, carbon dioxide from the air, and energy from sunlight to make their own food.
Explanation:
Answer: yes they do here are is an example a tree depends on water to keep it hydrated.
Explanation:
A certain electromagnetic wave a wavelength of 415 nm. What is the frequency of the wave in hz?
Answer:
The frequency of the electromagnetic wave is 7.22891566 × 10¹⁴ Hz
Explanation:
The wavelength of the electromagnetic wave, λ = 415 nm
The speed of an electromagnetic wave, c ≈ 3.0 × 10⁸ m/s
Given that an electromagnetic wave is a periodic wave, we have;
The speed of the electromagnetic wave, c = f×λ
Where;
f = The frequency of the electromagnetic wave
Therefore, we have;
f = c/λ
From which we have;
f = (3.0 × 10⁸ m/s)/(415 nm) = 7.22891566 × 10¹⁴ /s = 7.22891566 × 10¹⁴ Hz
The frequency of the electromagnetic wave, f = 7.22891566 × 10¹⁴ Hz
Convert to moles 12.06 x 10^22 molecules
Answer:
0.2 mole
Explanation:
From the question given above, the following data were obtained:
Number of molecules = 12.06×10²²
Number of mole =?
From Avogadro's hypothesis,
6.02×10²³ molecules = 1 mole
Therefore,
12.06×10²² molecules = 12.06×10²² / 6.02×10²³
12.06×10²² molecules = 0.2 mole
Thus, 12.06×10²² molecules is equivalent to 0.2 mole
can someone please help!!
Answer:
1:aerobic
2:anaerobic
3:aerobic
Which of the following wavelengths penetrate earth's atmosphere?
O Microwaves
O Gamma rays
O Radio waves
O X-rays
Answer:
Radio waves are able to penetate the earth's atmosphere due to their low frequency and long wavelength.
Let me know if this helps!
EXPERIMENT 1: Identify the oxidation and reduction half-reactions that occur in
Cell 5: Mn(s) | Mn(NO3)2 (aq) || Zn(NO3)2(aq) | Zn(s)
Remember to use proper formatting and notation.
Answer:
Cathode: Mn → Mn²⁺ + 2e⁻ (Oxidation)
Anode: Zn²⁺ + 2e⁻ → Zn (Reduction)
Mn | Mn²⁺ || Zn²⁺ | Zn
Explanation:
To identify the half reaction we need to see the oxidation states.
Mn(s) → Ground state → Oxidation state = 0
Mn(NO₃)₂ → Mn²⁺ → The oxidation state has increased.
This is the oxidation reaction. It has released two electrons:
Mn → Mn²⁺ + 2e⁻
Zn(NO₃)₂ → Zn²⁺
Zn → Ground state → The oxidation state was decreased.
This is the reduction reaction. It has gained two electrons:
Zn²⁺ + 2e⁻ → Zn
Cathode: Mn → Mn²⁺ + 2e⁻
Anode: Zn²⁺ + 2e⁻ → Zn
Mn | Mn²⁺ || Zn²⁺ | Zn
La
Nd
Pm
Sm
Tb
Но
Er
Tm
Yb
Lu
Ac
Np Pu Am Cm Bk
CH
Es
Fm Md No
100 g of acetic acid (CH, COOH) is dissolved in a 500.0 ml solution. What is the molarity? Report your answer with the
correct number of significant figures
Answer:
3.34 M
Explanation:
Step 1: Given data
Mass of acetic acid: 100 gVolume of solution (V): 500.0 mL (0.5000 L)Step 2: Calculate the moles of acetic acid
The molar mass of acetic acid is 60.05 g/mol.
100 g × 1 mol/60.05 g = 1.67 mol
Step 3: Calculate the molarity of acetic acid
The molarity is equal to the moles of solute divided by the liters of solution.
M = n/V
M = 1.67 mol/0.5000 L = 3.34 M
2NaN3 produces 2Na+3N2 How many moles of each product are produced when 6 moles of NaN3 react?
Answer:
[tex]6molNa\\\\9molN_2[/tex]
Explanation:
Hello there!
In this case, given the chemical reaction:
[tex]2NaN_3\rightarrow 2Na+3N2[/tex]
It is possible to evidence the 2:2 mole ratio of the reactant to Na and the 2:3 mole ratio of the reactant to the N2; therefore, the following setups allows us to compute the moles of products:
[tex]6molNaN_3*\frac{2molNa}{2molNaN_3}=6molNa\\\\6molNaN_3*\frac{3molN_2}{2molNaN_3}=9molN_2[/tex]
Best regards!
how partition of Bengal mobilize
please help me
What would happen if cell differentiation did not happen during the
development of the embryo?
Answer:
Without the process of cell differentiation, multicellular organisms would not be possible.
Consider these compounds:
a. CuCO3
b. ZnS
c. Ni(CN)2
d. Ag2CrO4
Complete the following statements by entering the letter corresponding to the correct compound. Without doing any calculations it is possible to determine that silver carbonate is more soluble than _________ , and silver carbonate is less soluble than ____________. It is not possible to determine whether silver carbonate is more or less soluble than _______________ by simply comparing Ksp values.
Explanation:
If we compare its solubility products without any calculation then, Magnesium hydroxide is more soluble than compound A and C. Magnesium hydroxide is less soluble than compound D.
- The solubility product of magnesium hydroxide and zinc carbonate is same so it is not possible to determine whether it is more or less soluble than compound B
A 15 g sample of steam at 100°C is emitted from a volcano. It condenses, cools, and falls as snow at 0°C. How many kilojoules of heat were released? [Specific heat of liquid water = 1.00 cal/g°C or 4.184 J/g°C); solid water 0.485 cal/g°C or 2.03 J/g°C]
Answer:
q= -40.236 or 40.236 KJ of heat released
Explanation:
I attached a picture + a cooling curve.
What can wind energy be transformed or converted into?
Answer:
Electrical energy
Explanation:
The wind Mill is an example of a device that converts wind energy into electrical energy