POSSIBLE POINTS: 1
After the Frisbee falls to the ground, you throw one of them back up into the tree, where it comes to rest on a branch.

Compared to when the Frisbee was on the ground, which of the following is true about the potential energy of the system?

Answer:

D.The striking foot pushes backward against the ground. The friction with the ground provides an equal and opposite force forward

Answer:

d

Explanation:

Answer:

720

Explanation:

Answer:

The two correct answers are B.) reacting quickly with water, and D.) forming bonds with other atoms.

Explanation:

I took the quiz on a.pex and these were correct.

Answer:

[tex]18.18\ \text{m/s}[/tex]

[tex]6.82\ \text{m/s}[/tex]

Explanation:

[tex]m_1[/tex] = Mass of large object = 8 kg

[tex]m_2[/tex] = Mass of smaller object = 3 kg

When large mass is moving

[tex]u_1[/tex] = 25 m/s

[tex]u_2[/tex] = 0

For completely inelastic collision we have the relation

[tex]m_1u_1+m_2u_2=(m_1+m_2)v\\\Rightarrow v=\dfrac{m_1u_1+m_2u_2}{m_1+m_2}\\\Rightarrow v=\dfrac{8\times 25+3\times 0}{8+3}\\\Rightarrow v=18.18\ \text{m/s}[/tex]

Speed of the combined mass when the larger object is moving is [tex]18.18\ \text{m/s}[/tex]

When smaller mass is moving

[tex]u_1[/tex] = 0

[tex]u_2[/tex] = 25 m/s

[tex]v=\dfrac{m_1u_1+m_2u_2}{m_1+m_2}\\\Rightarrow v=\dfrac{8\times 0+3\times 25}{8+3}\\\Rightarrow v=6.82\ \text{m/s}[/tex]

Speed of the combined mass when the smaller object is moving is [tex]6.82\ \text{m/s}[/tex]

Answer:

   ΔT = [tex]\frac{\Delta K}{(m_1+m_2) c_e }[/tex]    

Explanation:

This is an interesting problem, no data is given, so the result is a general expression.

Suppose that the disks are initially rotating with angular velocity w₁ and w₂, as well as that they have radii r₁ and r₂ and masses m₁ and m₂

we start the problem finding odl final angular velocity of the discs together, for this we define a system formed by the two discs, in this case the torques during the collision are internal and the angular momentum is conserved

initial instant. Just before the crash

           L₀ = L₁ + L₂

with

           L₁ =  I₁ w₁

the moment of inertia of a disc with an axis passing through its center is

           I₁ = ½ m₁ r₁²

we substitute

           I₀ = ½ m₁ r₁² w₁ + ½ m₂ r₂² w₂

final instant. Right after the crash

         L_f = I w

in angular momentum it is a scalar quantity, so it is additive

         I = I₁ + I₂

angular momentum is conserved

         L₀ = L_f

         I₁ w₁ + I₂ w₂ = I w

         w =  [tex]\frac{ I_1 w_1 + I_2 w_2 }{I}[/tex]            (1)

We already have the angular velocities of the system, let's find the kinetic energy of it

initial

          K₀ = K₁ + K₂ = ½ I₁ w₁² + ½ I₂ w₂²

final

          K_f = K = ½ I w²

the variation of the kinetic energy is the loss in the increase of the temperature of the system, they indicate us that we neglect the other possible losses

         ΔK = K_f -K₀

         ΔK = ½ I w² - (½ I₁ w₁² + ½ I₂ w₂²)           (2)

In this chaos we know all the values ​​for which the numerical value of ΔK can be calculated, the symbolic substitution gives expressions with complicated

Now if all this variation of energy turns into heat

         Q = ΔK

         m_{total} c_e ΔT = ΔK

where the specific heat of the bear discs must be known, suppose they are of the same material

         ΔT = [tex]\frac{\Delta K}{(m_1+m_2) c_e }[/tex]               (3)

to make a special case, we suppose some data

the discs have the same mass and radius, disc 2 is initially at rest and the discs are made of bronze that has c_e = 380 J / kg ºC

we look for the angular velocity

          I₁ = I₂ = I₀

          I = 2 I₀

we substitute in 1

           w = [tex]\frac{I_o w_1 + I_o 0 }{2I_o}[/tex] I₀ w₁ + I₀ 0 / 2Io

           w = w₁ /2

we look for the variation of the kinetic energy with 2

             ΔK = ½ (2I₀) (w₁ /2)² - (½ I₀ w₁² + ½ I₀ 0)

             ΔK = ¼ I₀ w₁² -½ I₀ w₁²

             ΔK = - ¼ I₀ w₁²

the negative sign indicates that the kinetic energy decreases

We look for the change in Temperature with the expression 3

              ΔT = [tex]\frac{ \Delta K}{(m_1 +m_2) c_e}[/tex]ΔK / (m1 + m2) ce

              ΔT = [tex]\frac{ \frac{1}{4} I_o w_1^2 }{ 2m c_e}[/tex]

              ΔT =  [tex]\frac{1}{8} \frac{ (\frac{1}{2} m r_1^2 ) w_1^2 }{ m c_e}[/tex]

              ΔT = [tex]\frac{1}{16} r_1^2 w_1^2 / c_e[/tex]

in this expression all the terms are contained

The increase in internal energy of the disks will be [tex]\rm \triangle E= mc\frac{\triangle k }{(m_1+m_2)c_e}[/tex].

The energy contained within a thermodynamic system is known as its internal energy. It's the amount of energy required to build or prepare a system in any given internal state.

The given data in the problem is;

[tex]\rm \omega_1[/tex]  is the angular velocity of  disk 1

[tex]\rm \omega_2[/tex] is the  angular velocity of disk 2

r₁ is the radius of  disk 1

r₂ is the radius of  disk 2

m₁ is the mass of disk 1

m₂ is the mass of disk 2

Momentum before the collision;

[tex]\rm L_1 = I_1 \omega_1[/tex]

The moment of inertia of disc 1

[tex]\rm i_1 = \frac{1}{2} m_1r_1^2[/tex]

The momentum gets conserved;

[tex]\rm L_0 = L_f \\\\ I_1 \omega_1 + I_2\omega_2 = I \omega \\\\ \rm \omega= \frac{I_1 \omega_1 + I_2\omega_2}{I}[/tex]

The change in the kinetic energy is;

[tex]\traingle KE= K_f - K_0 \\\\ \traingle KE= \frac{1}{2} I \omega^2-(\frac{1}{2} I_1\omega_1^2 + (\frac{1}{2} I_2\omega_2^2 )[/tex]

The change in the energy gets converted into heat;

[tex]\rm Q= \triangle k \\\\\ m_{total } c_e dt = \triangle k[/tex]

The change in the temperature is

[tex]\triangle T= \frac{\triangle k }{(m_1+m_2)c_e}[/tex]

The internal energy change is found by;

[tex]\rm \triangle E = mc_v dt[/tex]

[tex]\rm \triangle E= mc\frac{\triangle k }{(m_1+m_2)c_e}[/tex]

Hence the increase in internal energy of the disks will be [tex]\rm \triangle E= mc\frac{\triangle k }{(m_1+m_2)c_e}[/tex].

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31kg

Explanation:

F = ma

m = F/a

m = 744N/24m/s^2

m = 31kg

(*Newton's Second Law*)

Answer:

35/2 J/s

Explanation:

Just use the 2 formulas

Work done = Force * distance moved

Power = Work done/time

WD = 7 * 50  = 350

Power = 350 / 20

= 35/2 J/s

Answer:

A mass of 10 kilograms lifted 10 meters in 5 seconds.

Explanation:

Power can be defined as the energy required to do work per unit time.

Mathematically, it is given by the formula;

[tex] Power = \frac {Energy}{time} [/tex]

But Energy = mgh

Substituting into the equation, we have

[tex] Power = \frac {mgh}{time} [/tex]

Given the following data;

Mass = 10kg

Height = 10m

Time = 5 seconds

We know that acceleration due to gravity is equal to 9.8 m/s²

[tex] Power = \frac {10*9.8*10}{5} = 490 Watts [/tex]

Hence, a mass of 10 kilograms lifted 10 meters in 5 seconds would produce the most power.

Answer:

The velocity of the center of mass of the two-ball system is 13.1 m/s.

Explanation:

Given;

mass of the first ball, m₁ = 0.5 kg

mass of the second ball, m₂ = 0.25 kg

initial velocity of the second ball, u₂ = 19.6 m/s

At the highest point the velocity of the second ball, v₂ = 0

The highest point reached by the second ball is calculated as;

v₂² = u₂² - 2gh

0 = u₂² - 2gh

2gh = u₂²

h = u₂² / 2g

h = (19.6²) / (2 x 9.8)

h = 19.6 m

The final velocity of the first ball when it had traveled 19.6 m down;

v₁² = u₁² + 2gh

v₁² = 0 + 2gh

v₁ = √2gh

v₁ = √(2 x 9.8 x 19.6)

v₁ = 19.6 m/s

The velocity of the center of mass of the two-ball system is calculated as;

[tex]v = \frac{m_1v_1 \ + \ m_2v_2}{m_1 \ + \ m_2} \\\\v = \frac{0.5\times 19.6 \ + \ 0.25\times 0}{0.5 \ + \ 0.25} \\\\v = 13.1 \ m/s[/tex]

Answer:

[tex]1.714\ \text{A}[/tex]

Explanation:

F = Magnetic force = 0.018 N

B = Magnetic field = 0.03 T

L = Length of wire = 35 cm

[tex]\theta[/tex]  = Angle between current and magnetic field = [tex]90^{\circ}[/tex]

Magnetic force is given by

[tex]F=IBL\sin\theta\\\Rightarrow I=\dfrac{F}{BL\sin\theta}\\\Rightarrow I=\dfrac{0.018}{0.03\times 35\times 10^{-2}\times \sin90^{\circ}}\\\Rightarrow I=1.714\ \text{A}[/tex]

The magnitude of the current is [tex]1.714\ \text{A}[/tex].

Answer:

The mass of the rod is 16 kg.

Explanation:

Given that,

The length of a rod, L = 3 m

The moment of inertia of the rod, I = 12 kg-m²

We need to find the mass of the rod. The moment of inertia of the rod of length L is given by :

[tex]I=\dfrac{ML^2}{12}[/tex]

Where

M is mass of the rod

[tex]M=\dfrac{12I}{L^2}\\\\M=\dfrac{12\times 12}{(3)^2}\\\\M=16\ kg[/tex]

So, the mass of the rod is 16 kg.

Answer:

(b) both the temperature and pressure of the gas decrease.

Explanation:

An ideal gas undergoes an adiabatic expansion, a process in which no heat flows into or out of the gas. As a result, both the temperature and pressure of the gas decrease.

Gay Lussac states that when the volume of an ideal gas is kept constant, the pressure of the gas is directly proportional to the absolute temperature of the gas.

Mathematically, Gay Lussac's law is given by;

[tex] PT = K[/tex]

Also, according to the first law of thermodynamics which states that energy cannot be created or destroyed but can only be transformed from one form to another. Thus, the ideal gas does work on the environment with respect to the volume and temperature.

Answer:

B. False

A concave mirror and a converging lens will only produce a real image if the object is located beyond the focal point.

~Hoped this helped~

~Brainiliest?~

Answer:

[tex]2625.156\ \text{N}[/tex]

Explanation:

Dimensions of mattress 100 cm by 194 cm by 14 cm

[tex]m_m[/tex] = Mass of mattress = 4 kg

[tex]\rho[/tex] = Density of water = [tex]1000\ \text{kg/m}^3[/tex]

g = Acceleration due to gravity = [tex]9.81\ \text{m/s}^2[/tex]

Volume of mattress

[tex]V=100\times 194\times 14=271600\ \text{cm}^3=0.2716\ \text{m}^3[/tex]

Weight of water displaced is equal to the buoyant force

Mass of water

[tex]m=\rho V\\\Rightarrow m=1000\times 0.2716\\\Rightarrow m=271.6\ \text{kg}[/tex]

Mass of person would be

[tex]m_p=m-m_m=271.6-4\\\Rightarrow m_p=267.6\ \text{kg}[/tex]

Weight of the person would be

[tex]w=m_pg\\\Rightarrow w=267.6\times 9.81\\\Rightarrow w=2625.156\ \text{N}[/tex]

The air mattress could hold a person that weighs up to [tex]2625.156\ \text{N}[/tex].

Answer:

C?

Explanation:

Yep,It's C all right.

Answer:

Yep,It's C all right.

Explanation:

Explanation:

step 1. a diverging lens is "concave" on both side and always has a negative focal length

step 2. so 1/f = 1/s + 1/s' where f is the focal length, s is the object location, and s' is the image location (f, s, s' are all on the left side of the lens)

step 3. 1/-15 = 1/s + 1/-9 (image is virtual (negative))

step 4. 3/-45 = 1/s + 5/-45

step 5. s = 22.5cm (object is 22.5cm from lens)

step 6. s'/s = 9/22.5 ÷ 0.4 (magnification)

step 7. if the object is 4.5cm then the image is 4.5(0.4) = 1.8cm tall.

Answer:

diameter     of       the  wire   =  0.05  in  =0.05 /12   =4.167 *10 ^-3  ft

area   of cross  section    of the  wire  = A =  22/7 *  ( d /2 ) ^2  =0.786 *  (  4.167 *10 ^-3 ) ^2  =1.365 *10 ^-5  ft2  

E  =...

Explanation:

Answer:

Graph 1 matches with B, 2 with A, and 3 with C.

Explanation:

Graph 2 shows a car whose distance part of the graph is not going up or down, while the time going up. That means that the car is stopped. Graph 1 shows a straight line, meaning that the car is traveling at a constant speed. Graph 3 is a curved line, meaning the speed of the car is changing somehow, and since the line is becoming more horizontal, the car is getting slower.

Answer:

The amount of torque is 0.03 N.m.

Explanation:

To find the amount of torque we need to use the following equation:

[tex] \tau = \vec {r} \times \vec{F} = rFsin(\theta) [/tex]   (1)

Where:

r: is the radius = 1x10⁻² m

F: is the force = 6 N

θ: is the angle = 30°

By entering the above values into equation (1) we have:

[tex]\tau = 1 \cdot 10^{-2} m*6 N*sin(30) = 0.03 N.m[/tex]  

Therefore, the amount of torque is 0.03 N.m.

I hope it helps you!

Answer:

 t = 1.62 h

Explanation:

A flat mirror fulfills the law of reflection where the incident angle is equal to the reflected angle.

          θ_i = θ_r

If we use trigonometry to find the angles, the mirror is at a height of L = 1.87 m,   and the reflected rays reach a distance x1 = 3.56 m

         tan θ₁ = x₁ / L

         tan θ₁ = [tex]\frac{3.56}{1.87}[/tex]

         θ₁ = tan⁻¹  1.90

         θ₁ = 62.29º

for the second case x₂ = 1.46 m

        tan θ₂ = x₂ / L

        θ₂ = tan⁻¹  [tex]\frac{1.46}{1.87}[/tex]

        θ₂ = 37.98º

the difference in degree traveled is

         Δθ = θ₁- θ₂

          Δθ = 62.29 - 37.98

          Δθ = 24.31º

as in the exercise they indicate that every 15º there is an hour

         t = 24.31º (1h / 15º)

         t = 1.62 h

Answer:

transfer it to a new position

Answer:

The answer is letter B hope it helps

Answer:

[tex]\tau=0.03\ N-m[/tex]

Explanation:

Given that,

Force acting, F = 6N

The radius of the path, [tex]r=10^{-2}\ m[/tex]

Angle, [tex]\theta=30^{\circ}[/tex]

We need to find the amount of torque acting on the object. The formula for torque is given by :

[tex]\tau=Fr\sin\theta\\\\\tau=6\times 10^{-2}\times \sin(30)\\\\\tau=0.03\ N-m[/tex]

So, the required torque is equal to 0.03 N-m.

Answer:

true

Explanation:

normally -No system has ever performed well with one object.

A system must contain more than one object is a true statement.

A system is a group of interacting or interrelated objects that act according to a set of rules to form a unified whole.

Normally, no system has ever performed well with one object.

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Answer:

B: Amplitude

Explanation:

When a wave travels from one medium to the other from an angle, the things that change are amplitude, wavelength, intensity and velocity.

The frequency doesn't change because the frequency depends upon the source of the wave and not the medium by which the wave is propagated.

Answer:

The angle

Explanation:

Answer:

See explanation

Explanation:

Let us recall that temperature is a measure of the average kinetic energy of the molecules of a body.The higher the temperature, the higher the kinetic energy of the molecules of the body.

As temperature decreases, the kinetic energy of the molecules of a substance also decreases rapidly and the magnitude of intermolecular interaction between molecules of the substance increases.

Hence, as argon gas is cooled from 20°C to -190°C the kinetic energy of the gas molecules decreases an the magnitude of intermolecular interaction increases hence the gas changes into liquid and subsequently changes into a solid at -190°C.

Answer:

B

Explanation:

Because of the voltage attached to the iron nail