plz help me i need it today

Plz Help Me I Need It Today
Plz Help Me I Need It Today

Answers

Answer 1

Answer:

Question #3:T-Bone

Question #4:51 cars

Step-by-step explanation:

Question #3: divide each cost by 16 because 1 pound=16 oz

Question #4: 32/5 times 8=51.2 cars


Related Questions

Find the total current drawn by the following appliances by adding the currents of
each appliance. Electric iron: 4.12 amps, clock: 0.02 amps, light bulb: 0.91 amps, and a
workshop motor: 1 amp.

Answers

Answer:

The total current drawn is 6.05 amps

Step-by-step explanation:

Simply add the current that each appliance draws, to get the total current required. Notice that they are all given in the same units (amps), so there is no units conversion needed:

Electric iron  :  4.12 amps

Clock;    0.02  amps

light bulb :  0.91 amps

motor :  1 amp

Total current : 4.12  amps + 0.02 amps + 0.91 amps + 1 amp = 6.05 amps

Find
[tex]( {10x}^{2} - 11x + 8) + ( {2x}^{2} + 7x - 5 )[/tex]

Answers

Answer:

[tex]12x^2-4x+3[/tex]

Step-by-step explanation:

Parentheses do not matter in this equation.

[tex](10x^2-11x+8)+(2x^2+7x-5)=\\10x^2-11x+8+2x^2+7x-5=\\12x^2-11x+8+7x-5=\\12x^2-4x+8-5=\\12x^2-4x+3[/tex]

Our answer is [tex]12x^2-4x+3[/tex]

Select the three expressions that are equivalent to 6^{2}6 2 6, squared. a: (6^9/6^8)^2 b: 6 times 6 times 6 times 6 times 6 times 6 times 6 / 6 times 6 times 6 c: 6^4/6^2 d: 6^5 times 6^7/6^10

Answers

Question:

Select the three expressions that are equivalent to [tex]6^2[/tex]:

a: [tex](\frac{6^9}{6^8})^2[/tex]

b: [tex]\frac{6 * 6 * 6 * 6 * 6 * 6 * 6}{6 * 6 * 6 }[/tex]

c: [tex]\frac{6^4}{6^2}[/tex]

d: [tex]\frac{6^5 * 6^7}{6^{10}}[/tex]

Answer:

a: [tex](\frac{6^9}{6^8})^2[/tex]

c: [tex]\frac{6^4}{6^2}[/tex]

d: [tex]\frac{6^5 * 6^7}{6^{10}}[/tex]

Step-by-step explanation:

Given

[tex]6^2[/tex]:

Required

Find equivalent expressions

To solve this question; we'll simplify options a to do, one after the other

a: [tex](\frac{6^9}{6^8})^2[/tex]

From laws of indices;

[tex]\frac{a^m}{a^n} = a^{m-n}[/tex]

This implies that;

[tex](\frac{6^9}{6^8})^2 = (6^{9-8})^2[/tex]

[tex](\frac{6^9}{6^8})^2 = (6^{1})^2[/tex]

From laws of indices;

[tex]{a^m}^n = a^{m*n} = a^{mn}[/tex]

This implies that

[tex](\frac{6^9}{6^8})^2 = (6^{1*2})[/tex]

[tex](\frac{6^9}{6^8})^2 = 6^{2}[/tex]

Hence,  [tex](\frac{6^9}{6^8})^2[/tex] is equivalent to [tex]6^2[/tex]

b. [tex]\frac{6 * 6 * 6 * 6 * 6 * 6 * 6}{6 * 6 * 6 }[/tex]

From laws of indices;

[tex]a^m * a^n = a^{m+n}[/tex]

This implies that

[tex]\frac{6 * 6 * 6 * 6 * 6 * 6 * 6}{6 * 6 * 6 } = \frac{6^{1+1+1+1+1+1}}{6^{1+1+1}}[/tex]

[tex]\frac{6 * 6 * 6 * 6 * 6 * 6 * 6}{6 * 6 * 6 } = \frac{6^{6}}{6^{3}}[/tex]

From laws of indices;

[tex]\frac{a^m}{a^n} = a^{m-n}[/tex]

This implies that

[tex]\frac{6 * 6 * 6 * 6 * 6 * 6 * 6}{6 * 6 * 6 } = 6^{6-3}[/tex]

[tex]\frac{6 * 6 * 6 * 6 * 6 * 6 * 6}{6 * 6 * 6 } = 6^{3}[/tex]

Hence; [tex]\frac{6 * 6 * 6 * 6 * 6 * 6 * 6}{6 * 6 * 6 }[/tex] is not equivalent to [tex]6^2[/tex]

c.  [tex]\frac{6^4}{6^2}[/tex]

From laws of indices;

[tex]\frac{a^m}{a^n} = a^{m-n}[/tex]

This implies that

[tex]\frac{6^4}{6^2} = 6^{4-2}[/tex]

[tex]\frac{6^4}{6^2} = 6^{2}[/tex]

Hence, [tex]\frac{6^4}{6^2}[/tex] is equivalent to [tex]6^2[/tex]

d.  [tex]\frac{6^5 * 6^7}{6^{10}}[/tex]

From laws of indices;

[tex]a^m * a^n = a^{m+n}[/tex]

This implies that

[tex]\frac{6^5 * 6^7}{6^{10}} = \frac{6^{5+7}}{6^{10}}[/tex]

From laws of indices;

[tex]\frac{a^m}{a^n} = a^{m-n}[/tex]

This implies that

[tex]\frac{6^5 * 6^7}{6^{10}} = 6^{5+7-10}[/tex]

[tex]\frac{6^5 * 6^7}{6^{10}} = 6^{2}[/tex]

Hence, [tex]\frac{6^5 * 6^7}{6^{10}}[/tex] is equivalent to [tex]6^2[/tex]

involving the use of variables, properties, expressions, and equations

Answers

Variables: DescriptionIn mathematics, a variable is a symbol used to represent an arbitrary element of a set. In addition to numbers, variables are commonly used to represent vectors, matrices and functions.

Properties: a property is any characteristic that applies to a given set.

Expression: DescriptionIn mathematics, an algebraic expression is an expression built up from integer constants, variables, and the algebraic operations. For example, 3x² − 2xy + c is an algebraic expression. Since taking the square root is the same as raising to the power, is also an algebraic expression.

Equation: In algebra, an equation can be defined as a mathematical statement consisting of an equal symbol between two algebraic expressions that have the same value. The most basic and common algebraic equations in math consist of one or more variables.


Hope this answer is helpful


Please mark me as brainliest

A sequence is defined by the recursive function f(n+1)= f(n) -2. If f(1) =10. what is f(3)?

Answers

Answer:

f(3) is 30

Step-by-step explanation:

Answer:

6

Step-by-step explanation:

in a right triangle, what is the 3rd angle measure if an angle is 25

Answers

Answer:

65

Step-by-step explanation:

The sum of the angles in a triangle is 180. In a right triangle, there is one 90 degree angle. If the second angle is 25, and 90+25+the last angle must add up to 180, simple math can find the value of the last angle.

180-90-25=65

Answer:

65

Step-by-step explanation:

right angle=90

[tex] {90}^{0} [/tex]

therefore 90-25=the third angle 65

simplify 10+4(−8q−4)

Answers

Answer:

10 + 4(-8q - 4)

= 10 + 4 * (-8q) + 4 * (-4)     (Distribute 4)

= 10 - 32q - 16                    (Expand)

= -32q - 6                           (Combine like terms)

Answer:

[tex]-32q-6[/tex]

Step-by-step explanation:

[tex]10+4(-8q-4)[/tex]

[tex]10+4(-8q)+4(-4)[/tex]

[tex]10+-32q+-16[/tex]

[tex]-32q+-16+10[/tex]

[tex]-32q+-6[/tex]

Find the missing number in the pattern! PLEASE HELP The half-life of caffeine is 5 hours; this means that approximately 1/2 of the caffeine in the bloodstream is eliminated every 5 hours. Suppose you drink a 16-ounce drink that contains 80 mg of caffeine. Suppose the caffeine in your bloodstream peaks at 80 mg. 1. How much caffeine will remain in your bloodstream after 5 hours? 10 hours? 1 hour? 2 hours? Record your answers in the table

Answers

Answer:

After five hours, there will be 40 mg of caffeine remaining in the blood.

After 10 hours, 20 mg.

After only one hour, about 69.64 mg.

And after two hours, about 60.63 mg.

Step-by-step explanation:

We are given that one-half of the caffeine in the bloodstream is eliminated every five hours.

We are also given that the initial amount is 80 mg.

Using this information, we can write the following function:  

[tex]\displaystyle f(x)=80\left(\frac{1}{2}\right)^{\dfrac{x}{5} }[/tex]

Where x is the number of hours that has passed.

Using this function, we can evaluate for f(5), f(10), f(1), and f(2).

They evaluate to:

[tex]f(5)=40[/tex]       [tex]f(10)=20[/tex]       [tex]f(1)\approx 69.6440[/tex]     [tex]f(2) \approx 60.6287[/tex]

So, after five hours, there are 40 mg of caffeine remaining in the blood.

After 10 hours, 20 mg of caffeine.

After only one hour, about 69.64 mg.

And after two hours, about 60.63 mg.

The ratio of Tom's studying time on a weekday to his studying
time on a weekend day is 4:5. If he studies 2.4 hours each
weekday, how many hours does Tom study in total every
week?
_hours

Answers

Answer:

6 hrs

Step-by-step explanation:

4:5

2.4 : 3.2

2.4+3.2=6 hrs

Answer

6 hours

Explanation

The loudness, L, measured in decibels (Db), of a sound intensity, I, measured in watts per square meter, is defined as L = 10 log StartFraction I Over I 0 EndFraction, where I 0 = 10 Superscript negative 12 and is the least intense sound a human ear can hear. What is the approximate loudness of a rock concert with a sound intensity of 10–1?
a. 2Db
b.22Db
c. 60Db
d. 110Db

Answers

Answer:

D. 110Db

Step-by-step explanation:

Db = 10log (10^-1 / 10 ^-12)

Db = 10log(10^11)

Db = 110

(even without calculating, we could guess that it was 110Db. 70 Db is about the normal talking Db, and rock concerts are generally a lot louder than regular talking)

Answer:

D. 110Db

Step-by-step explanation:

Andy has $7,411 in a savings account. The interest rate is 11%, compounded annually.
To the nearest cent, how much interest will he earn in 2 years?
Use the formula B = P(1 + r), where B is the balance (final amount), p is the principal
(starting amount), r is the interest rate expressed as a decimal, and t is the time in years.
Submit
Please help :)

Answers

Answer:

$1720.0931 will earn as interest in 2 years

Step-by-step explanation:

Principal = $7411

Rate of interest = 11% compounded annually

Time = 2 years

Formula : [tex]A = P(1+r)^t[/tex]

[tex]A=7411(1+0.11)^2[/tex]

A=9131.0931

Interest = Amount - Interest =$9131.0931 - $7411

Interest = $1720.0931

Hence  $1720.0931 will earn as interest in 2 years

The segments shown below could form a triangle
O A. True
O B. False​

Answers

Answer:

Which value of a in the exponential function below would cause the function to stretch?

(one-third) Superscript x

0.3

0.9

1.0

1.5

Step-by-step explanation:

Answer:

This can form a triangle

Step-by-step explanation:

Taking the two smaller segments

The larger segment must be greater than the sum of the two smaller

6+5 > 8

11>8 true

whats the answer???​

Answers

Answer:The answer is C 20 cm^3

Step-by-step explanation:

You just multiply 2 by 2 and get 4 and you have 5 squares and you get 4 times 5 which is 20 cm^3

Answer:

Divide the figure into 5 squares.

then find the area 1 square and multiply with 5.

Area of square=s*s

                       =4 cm²

Then 5*4=20 cm²

so c is the correct option.

              HOPE IT HELPS!

Which relationships have the same constant of proportionality between y and x as in the equation y=1/2x Choose 3 answers:

This is from Khan academy. I'm stuck on it

Answers

Answer:

A and B has the same constant of proportionality

Step-by-step explanation:

[tex]y \propto x[/tex]

[tex]y = kx ----1[/tex]

Where k is the constant of proportionality

We are supposed to find Which relationships have the same constant of proportionality between y and x as in the equation [tex]y=\frac{1}{2}x[/tex]

On comparing with 1

[tex]k = \frac{1}{2}[/tex]

A)6y = 3x

[tex]y = \frac{3}{6}x\\y = \frac{1}{2}x[/tex]

So, this equation has the  same constant of proportionality

B)[tex](x_1,y_1)=(2,1)\\(x_2,y_2)=(4,2)[/tex]

To find the equation :

Formula : [tex]y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)[/tex]

So, [tex]y - 1=\frac{2-1}{4-2}(x-2)\\y-1=\frac{1}{2}(x-2)\\y-1=\frac{1}{2}x-1\\y=\frac{1}{2}x[/tex]

So, this equation has the  same constant of proportionality

C)

[tex](x_1,y_1)=(1,2)\\(x_2,y_2)=(2,4)[/tex]

To find the equation :

Formula : [tex]y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)[/tex]

So, [tex]y - 2=\frac{4-2}{2-1}(x-1)\\y - 2=2(x-1)\\y - 2=2x-2\\y=2x[/tex]

So, this equation do not has the same constant of proportionality

D)

[tex](x_1,y_1)=(2,1)\\(x_2,y_2)=(3,2.5)[/tex]

To find the equation :

Formula :[tex]y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)[/tex]

So, [tex]y - 1=\frac{2.5-1}{3-2}(x-2)[/tex]

[tex]y-1=1.5(x-2)\\y-1=1.5x-3\\y=1.5x-2[/tex]

So, this equation do not has the same constant of proportionality

Hence A and B has the same constant of proportionality

Options A and B has the same constant of proportionality.

What is Slope of Line?

The slope of the line is the ratio of the rise to the run, or rise divided by the run. It describes the steepness of line in the coordinate plane.

The slope intercept form of a line is y=mx+b, where m is slope and b is the y intercept.

The slope of line passing through two points (x₁, y₁) and (x₂, y₂) is

m=y₂-y₁/x₂-x₁

For option A,

6y=3x

y=3/6x

y=1/2x

This equation has the same constant of proportionality

For Option B

(2,1) and (4,2)

m=2-1/4-2=1/2

We have equation as y-y₁=m(x-x₁)

y-1=1/2(x-2)

y-1=1/2x-1

y=1/2x

this equation has the  same constant of proportionality

For option C

(1,2) and (2,4)

m=4-2/2-1=2

We have equation as y-y₁=m(x-x₁)

y-2=2(x-1)

y-2=2x-2

y=2x

Equation do not has the same constant of proportionality

and option D does not have same constant of proportionality

Hence options A and B has the same constant of proportionality.

To learn more on slope of line click:

https://brainly.com/question/14511992

#SPJ2


[tex]( - 8x}^{2} - 5x - 6) + ( - x { }^{2} - x + 5)[/tex]
Solve​

Answers

Answer:zooooooooooooooooooooooooooooooooom

Step-by-step explanation:

7. The probability of passing an
examination is 0.77. What is the
probability of failing the examination?
A. 0.22
B 0.23 C. 0.33
D. 0.72
E. 0.77

Answers

Answer:

Option B

Step-by-step explanation:

Total Probability = 1

Probability of passing = 0.77

Probability of failing = 1-0.77

=> 0.23

If anyone is good at math can you help me pls :/

Answers

Answer:

C

Step-by-step explanation:

An apothem is a line segment connecting the center of a regular polygon to the midpoint of its vertex.

Antonio was eating a bag of M&Ms. There were 4 green M&Ms, 20 brown M&Ms, 16 red
M&Ms, and 11 blue M&Ms. What is the probability of Antonio eating a blue M&M next?

Answers

Answer:

11/51 or 0.21468627

Step-by-step explanation:

Need help if you can, help please help

Answers

Answer:

4.4 km/h

Step-by-step explanation:

From the graph you can see she was at the shop after 30 minutes. If you travel 2.2 km in 30 minutes, your speed is 2.2 / 0.5 = 4.4 km/h

So the trick is to express the 30 minutes as 1/2 hour.

Answer:

4.4 km/h

Step-by-step explanation:

Which scatterplot correctly represents the table of values below? Number of years collecting stamps Number of stamps in collection 2 100 5 175 4 150 3 125 4 175 3 100 A graph titled Years Collecting Stamps versus Stamps in Collection has years collecting stamps on the x-axis and stamps in collection on the y-axis. Points are at (2, 100), (3, 100), (3, 125), (4, 150), (4, 175), (5, 200). A graph titled Years Collecting Stamps versus Stamps in Collection has years collecting stamps on the x-axis and stamps in collection on the y-axis. Points are at (2, 100), (3, 100), (3, 150), (4, 150), (4, 175), and (5, 175). A graph titled Years Collecting Stamps versus Stamps in Collection has years collecting stamps on the x-axis and stamps in collection on the y-axis. Points are at (2, 100), (3, 100), (3, 125), (4, 150), (4, 175), (5, 175). A graph titled Years Collecting Stamps versus Stamps in Collection has years collecting stamps on the x-axis and stamps in collection on the y-axis. Points are at (2, 75), (3, 100), (3, 125), (4, 150), (4, 175), and (5, 175).

Answers

Answer:

C. A graph titled Years Collecting Stamps versus Stamps in Collection has years collecting stamps on the x-axis and stamps in collection on the y-axis. Points are at (2, 100), (3, 100), (3, 125), (4, 150), (4, 175), (5, 175)

Step-by-step explanation:

In the x-axis goes the values from the column 'Number of years collecting stamps' of the table. And In the y-axis goes the values from the column 'Number of stamps in collection' of the table.

To make the graph identify each pair of values in the plane and mark it.

Answer:

c

Step-by-step explanation:

its corect on edge

Find all possible values of the fraction below. (Assume different letters are different digits, and the same letters are the same digits.) (G*R*O*U*N*D)/(B*A*S*E)

Answers

Answer:

there is one possible value: 0.

Step-by-step explanation:

We have 10 different letters in this fraction {G,R,O,U,N,D,B,A,S,E} and only 10 different digits {0,1,2,3,4,5,6,7,8,9}. It means that some letter must be equal to 0. Consider two cases:

I case:

[tex]0 \in \{G, R, O, U, N, D\}[/tex]. Then enumerator of fraction must be equal to zero (because product of numbers with zero among them always zero).

So [tex]\frac{GROUND}{BASE} = \frac{0}{BASE} = 0[/tex] in this case.

II case:

[tex]0 \in \{B,A,S,E\}[/tex]. Then for the same reasons as in I case denominator of fraction is equal to zero. And we know that fraction

[tex]\frac{BASE}{0}[/tex] is not well-defined.

The vertex of this parabola is at (2,-1). When the y value is 0, the value is 5.
What is the coefficient of the squared term in the parabola's equation?
(2.-1)
A.-3
B. -4
c. 4
D. 3

Answers

Answer:

Option D.

Step-by-step explanation:

The vertex form of a parabola along y-axis is

[tex]y=a(x-h)^2+k[/tex]

where, (h,k) is vertex and, a is constant and it is equal to coefficient of the squared term in the parabola's equation.

The vertex of the parabola is (2,-1). So, h=2 and k=-1.

[tex]y=a(x-2)^2-1[/tex]

The graph passes through (5,0). So,

[tex]0=a(5-2)^2-1[/tex]

[tex]1=9a[/tex]

[tex]\dfrac{1}{9}=a[/tex]

It means coefficient of the squared term is 1/9, which is not the option. So, parabola must be along the x-axis.

The vertex form of a parabola along x-axis is

[tex]x=a(y-k)^2+h[/tex]

where, (h,k) is vertex and, a is constant and it is equal to coefficient of the squared term in the parabola's equation.

The vertex of the parabola is (2,-1). So, h=2 and k=-1.

[tex]x=a(y+1)^2+2[/tex]

The graph passes through (5,0). So,

[tex]5=a(0+1)^2+2[/tex]

[tex]5-2=a[/tex]

[tex]3=a[/tex]

It means coefficient of the squared term is 3.

Therefore, the correct option is D.

The composite figure is made up of a triangle, a square and a trapezoid find the area

Answers

Answer:   65 square units

===============================================

Work Shown:

P = area of triangle

P = 0.5*base*height

P = 0.5*5*4

P = 10 square units

----------------

Q = area of square

Q = side*side

Q = 5*5

Q = 25 square units

----------------

R = area of trapezoid

R = height*(base1+base2)/2

R = 5*(7+5)/2

R = 5*12/2

R = 60/2

R = 30

----------------

T = total area of the entire figure

T = P+Q+R

T = 10+25+30

T = 65 square units

Answer: 71 sq. units

Step-by-step explanation:

formula: 1/2bh + lw + 1/2h(b1+b2)

1/2(20) + (25) + 1/2 (6) (12)

10 + 25 + (3) (12)

10+ 25 + 36 = 71


Help please For the following function, construct a table.



Answers

Answer:

See the attachment below.

Step-by-step explanation:

Best Regards!

graph of a cubic polynomial that falls to the left and rises to the right with x intercepts negative 3, negative 2, and 2 Which of the following functions best represents the graph? f(x) = (x − 2)(x − 3)(x + 2) f(x) = (x + 2)(x + 3)(x + 12) f(x) = (x + 2)(x + 3)(x − 2) f(x) = (x − 2)(x − 3)(x − 12)

Answers

Answer:

i would say  f(x) = (x-2)(x-3)(x+2) but i could be wrong its a confusing question the way it's worded

Step-by-step explanation:

jessica put 4 tables together for the Pie day sale. Each table is 42 inches long. What is the total length of the tables expressed in feet and inches

Answers

Answer:

14 feet OR 168 inches

Step-by-step explanation:

4 tables multiplied by 42 inches equals 168 inches total

168 inches divided by 12 inches per feet equals 14 feet.

Solve for x: [tex]22y\3x=8[/tex]

Answers

Answer:

x = 4/(11y)

Step-by-step explanation:

22yx = 8

Solve for x so divide each side by 22y

22xy/22y = 8/22y

x = 4/(11y)

The answer is x=4/(y)

Use a calculator to find tan 72°. Round to the nearest thousandth.

Answers

Answer:

3.078

Step-by-step explanation:

tan 72° = 3.078

Answer:

tan 72 = 3.078

Step-by-step explanation:

rounded like requested

If y varies directly as x, and y is 6 when x is 72, what is the value of y when x is 8?
1/9
2/3
54
96

Answers

Answer:

Y=2/3

Step-by-step explanation:

Y varies directly as X

Y=k x

K is a constant

6=k72

K=1/12

Y=1/12x

Y=1/12×8

y=2/3

Given:
MNOP is a parallelogram
Prove:
PM  ON
(For this proof, use only the definition of a parallelogram; don’t use any properties)

Answers

Answer:

[tex]\overline{PM}\cong\overline{ON}[/tex]:, Segment subtended by the same angle on two adjacent parallel lines are congruent

Step-by-step explanation:

Statement,                                              Reason

MNOP is a parallelogram:,                     Given

[tex]\overline{PM}\left | \right |\overline{ON}[/tex]:,                                               Opposite sides of a parallelogram

∠PMO ≅ ∠MON:,                                    Alternate Int. ∠s Thm.

[tex]\overline{MN}\left | \right |\overline{PO}[/tex]:,                                               Opposite sides of a parallelogram

∠POM ≅ ∠NMO:,                                    Alternate Int. ∠s Thm.

OM ≅ OM:,                                               Reflexive property

[tex]\overline{PM}\cong\overline{ON}[/tex]:,                                               Segment subtended by the same                                                                                                                              angle and on two adjacent parallel lines are congruent

Other Questions
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