Plz answer fast , (it’s a picture

Answer:

D . It describes a compound being broken down into the elements from which it was formed.

Explanation:

A compound consists of two or more elements chemically combined together in a chemical reaction. The compound carbon monoxide is represented by the chemical symbol, CO. This means that it contains 1 atom of the carbon element and 1 atom of the Oxygen element.

This compound is formed when carbon is directly oxidized in a limited supply of oxygen. In the above reaction, this compound is disintegrated into its individual components, namely, carbon and oxygen.

It's ammonia (NH3).....

Answer:

A molecule with one lone pair and three bond pair

- Ammonia

Answer:

it is from the currents the movements cause

Explanation:

Answer:The greater the difference in pressure, the faster the winds. When a high- and a low-pressure air mass are far apart, air moves slowly from high to low pressure.  When a high- and a low-pressure air mass are far apart, air moves quickly from high to low pressure.

Explanation:

Answer:

P2 = 4.76 atm

Explanation:

Given:

T1 = 235K. P1 = 3.80 atm

T2 = 298K. P2 = ?

Here, we use Gay-Lussac's law:

P1/T1 = P2/T2

Solving for P2, we get

P2 = (T2/T1)P1

= (298K/238K)(3.80 atm)

= 4.76 atm

Answer:

A. 5.3 X 10^-2

Explanation:

I got 100 on PLATO

Carbon dioxide is released when limestone is heated during the production of [tex]\sf\purple{cement}[/tex]. ✔

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Explanation:

amount of baking soda = 2.01 g

---> 2.01 g NaHCO3 × (1 mol NaHCO3/84.007 g NaHCO3)

= 0.024 mol NaHCO3

mass of the product = 1.28 g

Possible reactions:

NaHCO3(s) ---> NaOH(s) + CO2(g)

0.024 mol NaHCO3 × (1 mol NaOH/1 mol NaHCO3)

= 0.024 mol NaOH × (39.997 g NaOH/1.mol NaOH)

= 0.96 g NaOH

2NaHCO3(s) ---> Na2O(s) + 2CO2(g) + H2O(g)

0.024 mol NaHCO3 × (1 mol Na2O/2 mol NaHCO3)

= 0.012 mol Na2O × (61.9789 g Na2O)

= 0.73 g Na2O

2NaHCO3(s) ---> Na2CO3(s) + CO2(g) + H2O(g)

0.024 mol NaHCO3 × (1 mol Na2CO3/2 mol NaHCO3)

= 0.012 mol Na2CO3 × (105.9888 g Na2CO3/1 mol Na2CO3)

= 1.27 g Na2CO3

Conclusion:

Based on the mass of the product in the crucible and comparing it with the predicted product mass in different reactions, I conclude that Na2CO3 is the most likely product in the crucible.

Answer:

"0.24 J/g.k" is the appropriate solution.

Explanation:

Mass of substance,

m = 110.00 g

Heat,

q = 396 J

Change in temperature,

ΔT = 15.0°C  

Now,

The specific heat will be:

⇒  [tex]q=ms \Delta T[/tex]

On putting the given values, we get

⇒  [tex]396=110.00\times s\times 15.0[/tex]

⇒  [tex]396=s\times 1650[/tex]

⇒      [tex]s=\frac{396}{1650}[/tex]

⇒         [tex]=0.24 \ J/g.k[/tex]

Answer:

Explanation:

This is an example of a limiting reactant question, and is very common as a general chemistry problem.

We first see the balanced equation, that is:

2CuCl2+4KI→2CuI+4KCl+I2

We first need to find the limiting reactant

We see that 0.56 g of copper(II) chloride (CuCl2) reacts with 0.64 g of potassium iodide (KI) . So, let's convert those amounts into moles.

Copper(II) chloride has a molar mass of

134.45 g/mol . So in 0.56 g of copper(II) chloride, then there exist

0.56g134.45g/mol≈4.17⋅10−3 mol

Potassium iodide has a molar mass of

166 g/mol . So, in 0.64 g of potassium iodide, there exist

if it wrong i am sorry

Answer:

The arrangement of electrons within an atom is called electron configuration

If I help you, will you help other people?

Actually "this is the worst question i've ever seen use the internet bud" why don't you do that.

Answer:

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The activity of four unknown metals based on their chemical changes is option B.

Chemical changes are defined as changes which occur when a substance combines with another substance to form a new substance.Alternatively, when a substance breaks down or decomposes to give new substances it is also considered to be a chemical change.

There are several characteristics of chemical changes like change in color, change in state , change in odor and change in composition . During chemical change there is also formation of precipitate an insoluble mass of substance or even evolution of gases.

There are three types of chemical changes:

1) inorganic changes

2)organic changes

3) biochemical changes

During chemical changes atoms are rearranged and changes are accompanied by an energy change as new substances are formed.

Learn more about chemical change,here:

https://brainly.com/question/23693316

#SPJ3

The nitrogen gas and the oxygen gas will both occupy 50 liters.

Let us recall form the kinetic theory of gases that a gas is in constant random motion. The gas does not have a specific volume but takes on the volume of the container since it will expand and fill the container.

The volume occupied by the two gases will be the same as the volume of the container. Hence, the nitrogen gas and the oxygen gas will both occupy 50 liters.

Learn more about volume of a gas: https://brainly.com/question/4519953

Answer:

B. The entire container because gases will expand to fill it.

Explanation:

I took to test, plus it directly says this in the lesson

Answer: The molar mass of the gas is 9.878 g/mol.

Explanation:

According to Graham's law, the rate of diffusion is inversely proportional to square root of molar mass of gas.

[tex]Rate = \frac{1}{\sqrt{M}}[/tex]

where,

M = molar mass of gas

As given gas diffuses 1/7 times faster than hydrogen gas. So, its molar mass is calculated as follows.

[tex]\frac{R_{1}}{R_{2}} = \sqrt{\frac{M_{2}}{M_{1}}}\\[/tex]

where,

[tex]M_{1}[/tex] = molar mass of hydrogen gas

[tex]M_{2}[/tex] = molar mass of another given gas

[tex]R_{1}[/tex] = rate of diffusion of hydrogen

[tex]R_{2}[/tex] = rate of diffusion of another given gas = [tex]\frac{1}{7}R_{1}[/tex]

Substitute the values into above formula as follows.

[tex]\frac{R_{1}}{R_{2}} = \sqrt{\frac{M_{2}}{M_{1}}}\\\frac{R_{1}}{\frac{1}{7}R_{1}} = \sqrt{\frac{M_{2}}{2}}\\7 \times 1.414 = M_{2}\\M_{2} = 9.878 g/mol[/tex]

Thus, we can conclude that the molar mass of the gas is 9.878 g/mol.

Answer:

98.78 g/mol

Explanation:

Just took the test

Answer:

The respiratory system is the network of organs and tissues that help you breathe. basically your airways, lungs, and blood vessels so you quite literally need these to survive I mean your muscles need oxygen to function and your brain needs oxygen to function so without your respiratory system you wouldn't be able to move much and you would quickly pass out and die from the lack of oxygen to your brain there are other body processes that need oxygen as well but these are just two examples.

Explanation:

Answer:

Maybe it’s dark ??????????????

Explanation:

Hm

Answer:

Electrical resistivity is a property of a material that tells you how much it resists the flow of electric current, while conductivity quantifies how easily current flows.

Answer:

100 L

Explanation:

Use Boyle's Law, p1v1 = p2v2.

p1 = 4 atm

v1 = 50L

p2 = 2 atm

v2 = ?

p1v1 = p2v2

(4 atm) (50L) = (2 atm) (v2)

v2 = (4 atm)(50L) / (2 atm) = 100 L

Equation balance:

2Al(OH)3 + 3H2SO4 → Al2(SO4)3 + 6H2O

2Al(OH)3+3H2SO4

H=12

SO4=3

O=6

Al=2

Al2(SO4)3+6H2O

H=12

SO4=3

O=6

Al=2

Answer:

4.17M

Explanation:

m1v1/m2v2=n1/n2

Answer:

II would say there is co2 so i would say 30.4

Explanation:

Hope this helps

Answer:

Explanation:

Step 1: Calculate the amount of sodium hydroxide in moles

Volume of sodium hydroxide solution = 25.0 ÷ 1,000 = 0.0250 dm3

Rearrange:

Concentration in mol/dm3 =

Amount of solutein mol = concentration in mol/dm3 × volume in dm3

Amount of sodium hydroxide = 0.100 × 0.0250

= 0.00250 mol

Step 2: Find the amount of hydrochloric acid in moles

The balanced equation is: NaOH(aq) + HCl(aq) → NaCl(aq) + H2O(l)

So the mole ratio NaOH:HCl is 1:1

Therefore 0.00250 mol of NaOH reacts with 0.00250 mol of HCl

Step 3: Calculate the concentration of hydrochloric acid in mol/dm3

Volume of hydrochloric acid = 20.00 ÷ 1000 = 0.0200 dm3

Concentration in mol/dm3 =

Concentration in mol/dm3 =

= 0.125 mol/dm3

Step 4: Calculate the concentration of hydrochloric acid in g/dm3

Relative formula mass of HCl = 1 + 35.5 = 36.5

Mass = relative formula mass × amount

Mass of HCl = 36.5 × 0.125

= 4.56 g

So concentration = 4.56 g/dm3

Answer:

B. 2.2

Explanation:

Explanation:

asexual reproduction involves 1 parent and produces offspring that are genetically identical to each other and parent.

Sexual reproduction involves 2 parents and produces offspring that are genetically unique.

Answer:

6.1 M

Explanation:

Step 1: Calculate the moles of HNO₃ in the initial solution

A student has 475 mL (0.475 L) of a 4.5 M HNO₃ (4.5 mol HNO₃/ L) solution.

0.475 L × 4.5 mol HNO₃/ L = 2.1 mol HNO₃

He leaves the top of the container open, so water will evaporate, but the moles of HNO₃ will remain the same.

Step 2: Calculate the final concentration of the solution

2.1 moles of HNO₃ are in 347 mL (0.347 L) of solution.

[HNO₃] = 2.1 mol / 0.347 L = 6.1 M

Answer:

2C₄H₁₀(g) + 13O₂(g) —> 8CO₂(g) + 10H₂O(g)

Explanation:

The balanced equation for the reaction between butane and oxygen to produce carbon dioxide and water can be written as follow:

C₄H₁₀ + O₂ —> CO₂ + H₂O

Next, we shall balanced the equation. This is illustrated below:

C₄H₁₀ + O₂ —> CO₂ + H₂O

There are 4 atoms of C on the left side and 1 atom on the right side. It can be balance by writing 4 before CO₂ as shown below:

C₄H₁₀ + O₂ —> 4CO₂ + H₂O

There are 10 atoms of H on the left side and 2 atoms on the right side. It can be balance by writing 5 before H₂O as shown below:

C₄H₁₀ + O₂ —> 4CO₂ + 5H₂O

There are 2 atoms of O on the left side and a total of 13 atoms on the right side. It can be balance by writing 13/2 before O₂ as shown below:

C₄H₁₀ + 13/2O₂ —> 4CO₂ + 5H₂O

Multiply through by 2 to express in whole number ratio.

2C₄H₁₀(g) + 13O₂(g) —> 8CO₂(g) + 10H₂O(g)

Thus, the equation is balanced.

Solution :

[tex]$H_2 +I_2\rightleftharpoons 2HI$[/tex]

Initial concentration               Equilibrium concentration           [tex]$K_c=\frac{[HI]^2}{[H_2][I_2]}$[/tex]

  (mol/L)                                           (mol/L)

[tex]$[H_2]$[/tex]                 [tex]$[I_2]$[/tex]            [tex]$[HI]$[/tex]    [tex]$[H_2]$[/tex]                 [tex]$[I_2]$[/tex]            [tex]$[HI]$[/tex]

[tex]$2.4 \times 10^{-2}$[/tex]     [tex]$1.38 \times 10^{-2}$[/tex]  0     [tex]$1.14 \times10^{-2}$[/tex]    [tex]$0.12 \times 10^{-2}$[/tex]  [tex]$2.52 \times 10^{-2}$[/tex]        46.42

[tex]$2.4 \times 10^{-2}$[/tex]     [tex]$1.68 \times 10^{-2}$[/tex]  0     [tex]$0.92 \times10^{-2}$[/tex]    [tex]$0.20 \times 10^{-2}$[/tex]  [tex]$2.96 \times 10^{-2}$[/tex]        47.61

[tex]$2.4 \times 10^{-2}$[/tex]     [tex]$1.98 \times 10^{-2}$[/tex]  0     [tex]$0.77 \times10^{-2}$[/tex]    [tex]$0.31 \times 10^{-2}$[/tex]  [tex]$3.34 \times 10^{-2}$[/tex]        46.73

[tex]$2.4 \times 10^{-2}$[/tex]     [tex]$1.76 \times 10^{-2}$[/tex]  0     [tex]$0.92 \times10^{-2}$[/tex]    [tex]$0.22 \times 10^{-2}$[/tex]  [tex]$3.08 \times 10^{-2}$[/tex]        46.86

[tex]$0$[/tex]                  [tex]$0$[/tex]        [tex]$3.04 \times 10^{-2}$[/tex]     [tex]$0.345 \times10^{-2}$[/tex]    [tex]$0.345 \times 10^{-2}$[/tex]  [tex]$2.35 \times 10^{-2}$[/tex] 46.39

[tex]$0$[/tex]                  [tex]$0$[/tex]        [tex]$7.58 \times 10^{-2}$[/tex]     [tex]$0.86 \times10^{-2}$[/tex]    [tex]$0.86 \times 10^{-2}$[/tex]  [tex]$5.86 \times 10^{-2}$[/tex]     46.42

Average [tex]$K_c=46.738$[/tex]

Answer:

1045 J

Explanation:

By using the formula Eh= mass×specific heat capacity × change in tempreture

With it being a known fact that the specific heat capacity of water is 4.16g/j/°c