PLS HURRY!!!! The total amount of water a tank can hold is 14 and one-half gallons. Raul wants to find out how many 1 and one-fourth-gallon buckets of water can be used to fill the tank. Which expressions could be used to represent this scenario? Select two options.. StartFraction 29 over 2 EndFraction divided by StartFraction 5 over 4 EndFraction StartFraction 29 over 2 EndFraction times StartFraction 5 over 4 EndFraction StartFraction 29 over 2 EndFraction times StartFraction 4 over 5 EndFraction StartFraction 2 over 29 EndFraction times StartFraction 5 over 4 EndFraction StartFraction 29 over 2 EndFraction divided by StartFraction 4 over 5 EndFraction

Answers

Answer 1

Answer:

[29 over 2 divided by 5 over 4] = 29/2 ÷ 5/4 (A)

[29 over 2 times 4 over 5] = 29/2 × 4/5 (C)

Step-by-step explanation:

The total amount of water a tank can hold is 14 and one and one-half gallons = 14½

We are to determine the number of 1/4 gallon buckets of water that can be used to fill the tank.

To find this, we would divide 14½ by 1¼ = 14½ ÷ 1¼

Convert 14½ and 1¼ to improper fraction

14½ = [(14×2)+1]/2 = 29/2

1¼ = [(1×4)+1]/4 = 5/4

14½ ÷ 1¼ =29/2 ÷ 5/4

Then we find the inverse of ¼ to convert the division to multiplication

= 29/2 × 4/5 = 116/10

= 11.6

14½ ÷ ¼ = 11.6

Therefore 11.6 gallons of ¼ buckets of water can be used to fill the tank.

But the two expressions that could be used to represent this scenario to get the answer from the options = 29/2 ÷ 5/4 (A)

[29 over 2 divided by 5 over 4]

29/2 × 4/5 (C)

[29 over 2 times 4 over 5]

Answer 2

Answer:

I believe it is A and C.


Related Questions

A number is equal to twice a smaller number plus 3. The same number is equal to twice the sum of the smaller number and 1. How many solutions are possible for this situation? (a)Infinitely many solutions exist because the two situations describe the same line. (b)Exactly one solution exists because the situation describes two lines that have different slopes and different y-intercepts. (c)No solutions exist because the situation describes two lines that have the same slope and different y-intercepts. (d)Exactly one solution exists because the situation describes two lines with different slopes and the same y-intercept.

Answers

Answer:

The correct answer option is: No solutions exist because the situation describes two lines that have the same slope and different y-intercepts.


The table shows the temperature of an amount of water set on a stove to boil, recorded every half minute.

Answers

Answer:show the table so I can help

Step-by-step explanation:


Avery wants to buy a car and has a choice between two different banks. One bank is offering a simple interest rate of 32% and the other bank is offering a rate of 3%
compounded annually. If Avery decides to deposit $7,000 for 5 years, which bank would be the better deal?

Answers

Answer:

If Avery decides to deposit $7,000 for 5 years, the bank would be the better deal would be bank is offering a rate of 3%

compounded annually

Step-by-step explanation:

In order to calculate which bank would be the better deal If Avery decides to deposit $7,000 for 5 years, we would have to make the following calculation:

simple interest rate of 32%.

Therefore, I= P*r*t

=$7,000*32%*5

=$11,200.

compound interest rate of 3%

Therefore, FV=PV(1+r)∧n

FV=$7,000(1+0.03)∧5

FV=$8,114.

If Avery decides to deposit $7,000 for 5 years, the bank would be the better deal would be bank is offering a rate of 3%

compounded annually

I need help please!!!!

Answers

Answer:

1/3( x-5)= -2/3

Multiply both sides by 3

x = 3

Step-by-step explanation:

1/3( x-5)= -2/3

Multiply both sides by 3

3*1/3( x-5)= -2/3*3

x-5 = -2

Add 5 to each side

x-5+5 = -2+5

x = 3

Answer:

1/3( x-5)= -2/3

Multiply both sides by 3

x = 3

Step-by-step explanation:

1/3( x-5)= -2/3

Multiply both sides by 3

3*1/3( x-5)= -2/3*3

x-5 = -2

Add 5 to each side

x-5+5 = -2+5

x = 3

Hope this helps!

Sample data for the arrival delay times (in minutes) of airlines flights is given below. Determine whether they appear to be from a population with a normal distribution. Assume that this requirement is loose in the sense that the population distribution need not be exactly normal, but it must be a distribution that is roughly bell-shaped Click the icon to view the data set. Is the requirement of a normal distribution satisfied? A. No, because the histogram of the data is not bell shaped, there is more than one outlier, and line points in the normal quantile plot do not lie reasonably close to a straight line.B. Yes, because the histogram of the data is bell shaped, there are less than two outliers, and the line points in the normal quantile plot lie reasonably close to a straight line.C. Yes, because the histogram of the data is not bell shaped, there is more than one outlier, and line points in the normal quantile plot do not lie reasonably close to a straight line.D. No, because the histogram of the data is bell shaped, there are less than two outliers, and the the points in the normal quantile plot do not lie reasonably close to a straight

Answers

Answer:

(Option A) . No, because the histogram of the data is not bell shaped, there is more than one outlier, and line points in the normal quantile plot do not lie reasonably close to a straight line.

Step-by-step explanation:

After plotting the histogram, you will see that the data does not represent the normal distribution because the histogram is not bell shaped and there are two outliers.

Customers arrive at a movie theater at the advertised movie time only to find that they have to sit through several previews and prepreview ads before the movie starts. Many complain that the time devoted to previews is too long. A pre-liminary sample conducted by The Wall Street Journal showed that the standard deviation of the amount of time devoted to previews was 6 minutes. A. If we want to estimate the population mean time for previews at movie theaters with a margin of error of 72 seconds, what sample size should be used? B. If we want to estimate the population mean time for previews at movie theaters with a margin of error of 1 minute, what sample size should be used?

Answers

Answer:

Using a 90% confidence level

A. A sample size of 68 should be used.

B. A sample size of 98 should be used.

Step-by-step explanation:

I think there was a small typing mistake and the confidence level was left out. I will use a 90% confidence level.

We have that to find our [tex]\alpha[/tex] level, that is the subtraction of 1 by the confidence interval divided by 2. So:

[tex]\alpha = \frac{1-0.9}{2} = 0.05[/tex]

Now, we have to find z in the Ztable as such z has a pvalue of [tex]1-\alpha[/tex].

So it is z with a pvalue of [tex]1-0.05 = 0.95[/tex], so [tex]z = 1.645[/tex]

Now, find the margin of error M as such

[tex]M = z*\frac{\sigma}{\sqrt{n}}[/tex]

In which [tex]\sigma[/tex] is the standard deviation of the population and n is the size of the sample.

A. If we want to estimate the population mean time for previews at movie theaters with a margin of error of 72 seconds, what sample size should be used?

We have the standard deviation in minutes, so the margin of error should be in minutes.

72 seconds is 72/60 = 1.2 minutes.

So we need a sample size of n, and n is found when M = 1.2. We have that [tex]\sigma = 6[/tex]. So

[tex]M = z*\frac{\sigma}{\sqrt{n}}[/tex]

[tex]1.2 = 1.645*\frac{6}{\sqrt{n}}[/tex]

[tex]1.2\sqrt{n} = 6*1.645[/tex]

[tex]\sqrt{n} = \frac{6*1.645}{1.2}[/tex]

[tex](\sqrt{n})^{2} = (\frac{6*1.645}{1.2})^{2}[/tex]

[tex]n = 67.65[/tex]

Rounding up.

A sample size of 68 should be used.

B. If we want to estimate the population mean time for previews at movie theaters with a margin of error of 1 minute, what sample size should be used?

Same logic as above, just use M = 1.

[tex]M = z*\frac{\sigma}{\sqrt{n}}[/tex]

[tex]1 = 1.645*\frac{6}{\sqrt{n}}[/tex]

[tex]\sqrt{n} = 6*1.645[/tex]

[tex](\sqrt{n})^{2} = (6*1.645)^2[/tex]

[tex]n = 97.42[/tex]

Rounding up

A sample size of 98 should be used.

(x + 1) (x+8) multiply binomials and put in standard form.

Answers

Answer:

x² + 9x + 8

Step-by-step explanation:

Step 1: FOIL

x² + 8x + x + 8

Step 2: Combine like terms

x² + 9x + 8

Answer:

x^2 + 9x + 8

Step-by-step explanation:

(x + 1)(x + 8)

x(x + 1) +8(x + 1)

x^2 + x + 8x +8

x^2 + 9x + 8

If f(x)=8x and g(x)=2x+1, what is (f×g)(x)

Answers

Answer:

(f * g)(x) has a final product of 16x² + 8x.

Step-by-step explanation:

When you see (f * g)(x), this means that we are going to be multiply f(x) and g(x) together.

f(x)=8x

g(x)=2x+1

Now, we multiply these terms together.

(8x)(2x + 1)

Use the foil method to multiply.

16x² + 8x

So, the product of these terms is 16x² + 8x.

The top speed you will ever need
to go in a parking lot is
O A. 20 mph
OB. 10 mph
OC. 1 mph
D. 15 mph

Answers

Answer:

10 mph

Step-by-step explanation:

The top speed you will ever need to go in a parking lot is 10 mph.

15 mph is the fastest you should ever drive in a parking lot. The right answer is D.

What is National Motorists Association?

The National Motorists Association was established in 1982 and is a divisive nonprofit advocacy group representing drivers in North America.

The Association promotes engineering standards that have been demonstrated to be effective, justly drafted and applied traffic legislation, and full due process for drivers.

Given to give information about the top speed you will ever need

to go into a parking lot is,

A group of drivers came together to form the National Motorists Association, Inc., a non-profit organization, to defend drivers' rights in the legal system, on the highways, and inside our cars.

Usually, there are marked speed limits in parking lots. Obey speed limits when you see them to avoid tickets and to keep everyone safe.

The National Motorists Association advises driving no faster than 15 miles per hour at all times when there are no written speed limits.

Therefore, the correct option is D.

For more details regarding Motorists;

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What is the m ZACB?
10°
50°
90°
180°

Answers

Answer:

50 deg

Step-by-step explanation:

In an right triangle, the acute angles are complementary. That means their measures have a sum of 90 deg.

m<C + m<B = 90

7x - 20 + 4x = 90

11x = 110

x = 10

m<ACB= 7x - 20

m<ACB = 7(10) - 20

m<ACB = 70 - 20

m<ACB = 50

Answer: m<ACB = 50 deg

The largest fish ever caught in Lake A weighed 650 pounds. This is 208.2 pounds less than seven times the weight of the largest fish ever caught in Lake B. Find the weight of the largest fish caught in Lake B nts​

Answers

Answer:

122.6 pounds

Step-by-step explanation:

Let's call the weight of the largest fish from lake A 'x', and the weight of the largest fish from lake B 'y'.

If x is 208.2 pounds less than seven times y, we have that:

[tex]x = 7y - 208.2[/tex]

We know that x is equal 650 pounds, so we can find y:

[tex]650 = 7y - 208.2[/tex]

[tex]7y = 650 + 208.2[/tex]

[tex]7y = 858.2[/tex]

[tex]y = 122.6\ pounds[/tex]

So the weight of the largest fish caught in Lake B is 122.6 pounds

Grace was given the description “three less than the quotient of a number squared and nine, increased by eight” and was asked to evaluate it when n = 6. Her work is shown below.

Step 1: 3 minus StartFraction n squared Over 9 EndFraction + 8
Step 2: 3 minus StartFraction 6 squared Over 9 EndFraction + 8
Step 3: 3 minus StartFraction 36 Over 9 EndFraction + 8
Step 4: 3 minus 4 + 8
Step 5: 7

In which step did she make an error?
step 1
step 2
step 4
step 5

Answers

Answer:

step 1

Step-by-step explanation:

when you say three less than the quotient

you put the quotient first and then subtract 3

Answer: Step 1

Step-by-step explanation: I took it on my quiz and got an 100

In a survey of 623 adults, 95 said that they regularly lie to people conducting surveys. Create a 99% confidence interval for the proportion of adults who regularly lie to people conducting surveys. Use a TI-83, TI-83 plus, or TI-84 calculator, rounding your answers to three decimal places.

Answers

Answer:

The 99% confidence interval for the proportion of adults who regularly lie to people conducting surveys is (0.116, 0.19).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of [tex]\pi[/tex], and a confidence level of [tex]1-\alpha[/tex], we have the following confidence interval of proportions.

[tex]\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]

In which

z is the zscore that has a pvalue of [tex]1 - \frac{\alpha}{2}[/tex].

For this problem, we have that:

[tex]n = 623, \pi = \frac{95}{623} = 0.153[/tex]

99% confidence level

So [tex]\alpha = 0.01[/tex], z is the value of Z that has a pvalue of [tex]1 - \frac{0.01}{2} = 0.995[/tex], so [tex]Z = 2.575[/tex].

The lower limit of this interval is:

[tex]\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.153 - 2.575\sqrt{\frac{0.153*0.848}{623}} = 0.116[/tex]

The upper limit of this interval is:

[tex]\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.1525 + 2.575\sqrt{\frac{0.153*0.845}{623}} = 0.19[/tex]

The 99% confidence interval for the proportion of adults who regularly lie to people conducting surveys is (0.116, 0.19).

Find the values of x and y.[tex]x = 34\sqrt3 y = 17\\x = y = 34, y = 17\sqrt3\\x= y = 17, y = 34\sqrt3\\\\\\x= 17\sqrt3 y = 34[/tex]

Answers

Answer:

The value of "x" is 34 and the value of "y" is 17.

Step-by-step explanation:

"x" is shown as 34 and "y" is shown on the rectangular shape in the number form of 17. If your trying to find the area of the rectangle the area is 578.

PLEASE HELP!!! A LOT OF POINTS AND BRAINLIEST TO CORRECT ANSWERS!!!
1. Find the area of the region enclosed by the graph of [tex]$x^2 + y^2 = 2x - 6y + 6$[/tex].

2. The line [tex]x=4[/tex] is an axis of symmetry of the graph of [tex]$y = ax^2 + bx + c.$[/tex] Find [tex]$\frac{b}{a}$.[/tex].

3. The graph of [tex]$y = ax^2 + bx + c$[/tex] is shown below. Find [tex]$a \cdot b \cdot c$[/tex]. (The distance between the grid lines is one unit, picture of graph attached.)

4. Geometrically speaking, a parabola is defined as the set of points that are the same distance from a given point and a given line. The point is called the focus of the parabola and the line is called the directrix of the parabola. Suppose [tex]$\mathcal{P}$[/tex] is a parabola with focus [tex]$(4,3)$[/tex] and directrix [tex]$y=1$[/tex]. The point [tex]$(8,6)$[/tex] is on [tex]$\mathcal{P}$[/tex] because [tex]$(8,6)$[/tex] is 5 units away from both the focus and the directrix. If we write the equation whose graph is [tex]$\mathcal{P}$[/tex] in the form [tex]$y=ax^2 + bx + c$[/tex], then what is [tex]$a+b+c$[/tex]?

5. (This is a Writing Problem - please please please explain and answer the question thoroughly!) A quadratic of the form [tex]$-2x^2 + bx + c$[/tex] has roots of [tex]$x = 3 + \sqrt{5}$[/tex] and [tex]$x = 3 - \sqrt{5}.$[/tex] The graph of [tex]$y = -2x^2 + bx + c$[/tex] is a parabola. Find the vertex of this parabola.

If you do manage to answer every single one of these correctly, THANK YOU SO MUCH and please know you are very much appreciated! :)

Answers

Answer:

1. [tex]Area=16\,\pi=50.265[/tex]

2.- [tex]\frac{b}{a} =-8[/tex]

3.  [tex]y=\frac{1}{2} x^2+3x+\frac{5}{2}[/tex]

4.  [tex]a+b+c=\frac{17}{4}[/tex]

5.   the vertex is located at: (3, 10)

Step-by-step explanation:

1. If we rewrite the formula of the conic given by completing squares, we can find what conic we are dealing with:

[tex](x^2-2x)+(y^2+6y)=6\\\,\,\,\,\,\,+1\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,+9\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,+10\\(x-1)^2+(y+3)^2=16\\(x-1)^2+(y+3)^2=4^2[/tex]

which corresponds to a circle of radius 4, and we know what the formula is for a circle of radius R, then:

[tex]Area=\pi\,R^2=\pi\,4^2=16\,\pi=50.265[/tex]

2.

If x=4 is the axis of symmetry of the parabola

[tex]y=ax^2+bx+c[/tex]

then recall the formula to obtain the position of the x-value of the vertex:

[tex]x_{vertex}=-\frac{b}{2a} \\4=-\frac{b}{2a}\\4\,(-2)=\frac{b}{a} \\\frac{b}{a} =-8[/tex]

3.  

From the graph attached, we see that the vertex of the parabola is at the point: (-3, -2) on the plane, so we can write the general formula for a parabola in vertex form:

[tex]y-y_{vertex}=a\,(x-x_{vertex})^2\\y-(-2)=a\,(x-(-3))^2\\y+2=a(x+3)^2[/tex]

and now find the value of the parameter "a" by requesting the parabola to go through another obvious point, let's say the zero given by (-1, 0) at the crossing of the x-axis:

[tex]y+2=a\,(x+3)^2\\0+2=a(-1+3)^2\\2=a\,2^2\\a=\frac{1}{2}[/tex]

So the equation of the parabola becomes:

[tex]y+2=\frac{1}{2} (x+3)^2\\y+2=\frac{1}{2} (x^2+6x+9)\\y+2=\frac{1}{2} x^2+3x+\frac{9}{2} \\y=\frac{1}{2} x^2+3x+\frac{9}{2} -2\\y=\frac{1}{2} x^2+3x+\frac{5}{2}[/tex]

4.

From the location of the focus of the parabola as (4, 3) and the directrix as y=1,  we conclude that we have a parabola with dominant vertical axis of symmetry, displaced from the origin of coordinates, and responding to the following type of formula:

[tex](x-h)^2=4\,p\,(y-k)[/tex]

with focus at: [tex](h,k+p)[/tex]

directrix given by the horizontal line [tex]y=k-p[/tex]

and symmetry axis given by the vertical line [tex]x=h[/tex]

Since we are given that the focus is at (4, 3), we know that [tex]h=4[/tex], and that [tex]k+p=3[/tex]

Now given that the directrix is: y = 1, then:

[tex]y=k-p\\1=k-p[/tex]

Now combining both equations with these unknowns:

[tex]k+p=3\\k=3-p[/tex]

[tex]1=k-p\\k=1+p[/tex]

then :

[tex]1+p=3-p\\2p=3-1\\2p=2\\p=1[/tex]

and we now can solve for k:

[tex]k=1+p=1+1=2[/tex]

Then we have the three parameters needed to write the equation for this parabola:

[tex](x-h)^2=4\,p\,(y-k)\\(x-4)^2=4\,(1)\,(y-2)\\x^2-8x+16=4y-8\\4y=x^2-8x+16+8\\4y=x^2-8x+24\\y=\frac{1}{4} x^2-2x+6[/tex]

therefore: [tex]a=\frac{1}{4} , \,\,\,b=-2,\,\,and\,\,\,c=6[/tex]

Then [tex]a+b+c=\frac{17}{4}[/tex]

5.

The vertex of a parabola can easily found because they give you the roots of the quadratic function, which are located equidistant from the symmetry axis. So we know that is one root is at [tex]x=3+\sqrt{5}[/tex]and the other root is at [tex]x=3-\sqrt{5}[/tex]

then the x position of the vertex must be located at x = 3 (equidistant from and in the middle of both solutions. Then we can use the formula for the x of the vertex to find b:

[tex]x_{vertex}=-\frac{b}{2a}\\3=-\frac{b}{2\,(-2)}\\ b=12[/tex]

Now, all we need is to find c, which we can do by using the rest of the quadratic formula for the solutions [tex]x=3+\sqrt{5}[/tex]  and [tex]x=3-\sqrt{5}[/tex] :

[tex]x=-\frac{b}{2a} +/-\frac{\sqrt{b^2-4\,a\,c} }{2\,a}[/tex]

Therefore the amount [tex]\frac{\sqrt{b^2-4\,a\,c} }{2\,a}[/tex],  should give us [tex]\sqrt{5}[/tex]

which means that:

[tex]\sqrt{5}=\frac{\sqrt{b^2-4\,a\,c} }{2\,a} \\5=\frac{b^2-4ac}{4 a^2} \\5\,(4\,(-2)^2)=(12)^2-4\,(-2)\,c\\80=144+8\,c\\8\,c=80-144\\8\,c=-64\\c=-8[/tex]

Ten the quadratic expression is:

[tex]y=-2x^2+12\,x-8[/tex]

and the y value for the vertex is:

[tex]y=-2(3)^2+12\,(3)-8=-18+36-8=10[/tex]

so the vertex is located at: (3, 10)

The first four terms of a sequence are shown below 9,5,1,-3
Which of the following functions best defines this sequence?
A. f(1)=9, f(n+1)=f(n)-4 for n> or equal to 1

B. f(1)=9, f(n+1)=f(n)+4 for n> or equal to 1

C. f(1)=9, f(n+1)=f(n)-5 for n> or equal to 1

D. f(1)=9, f(n+1)=f(n)+5 for n> or equal to 1

Answers

Answer:

A. f(1)=9, f(n+1)=f(n)-4 for n> or equal to 1

Step-by-step explanation:

Given the sequence:

9, 5, 1, -3

We can easily calculate the difference of terms:

-3- 1= 1- 5= 5-9= -4

As the difference of terms is same and equal to -4, it is the AP (arithmetic progression)

This sequence can be defined In the form of function as:

f(1)= 9, as the first term is 9f(n+1)= f(n)- 4, as it is decreasing function with the difference of -4n ≥ 1, as we count from the first term on

All the above matches the first answer choice:

A. f(1)=9, f(n+1)=f(n)-4 for n> or equal to 1

which inequality represents the statement? the number of new cars(C) a ship carries cant exceed 975.
A. c<975
B. c>975
C. c<(—under<)975
D. c>(—under>)975

Answers

"can't exceed 975" means this is the largest value possible for C. So we could have C = 975 or smaller. We write this as [tex]C \le 975[/tex] which is read as "C is less than or equal to 975".

Answer: Choice C. [tex]C \le 975[/tex]

Answer:

5

Step-by-step explanation:

Individuals filing federal income tax returns prior to March 31 received an average refund of $1056. Consider the population of "last-minute" filers who mail their tax return during the last five days of the income tax period (typically April 10 to April 15).
a. A researcher suggests that a reason individuals wait until the last five days is that on average these individuals receive lower refunds than do early filers. Develop appropriate hypotheses such that rejection of H0 will support the researcher’s contention.
b. For a sample of 400 individuals who filed a tax return between April 10 and 15, the sample mean refund was $910. Based on prior experience a population standard deviation of σσ = $1600 may be assumed. What is the p-value?
c. At αα = .05, what is your conclusion?
d. Repeat the preceding hypothesis test using the critical value approach.

Answers

The α = 0.05 and the p-value (0.034) is less than α, we reject the null hypothesis. There is sufficient evidence to support the researcher's contention that last-minute filers  receive lower average tax refunds than early filers. Since the test statistic is more extreme than the critical value, we reject the null hypothesis.

a.

Hypotheses:

Null Hypothesis [tex](H_0)[/tex]: There is no difference in the average tax refund amount between early filers and last-minute filers .

Alternative Hypothesis [tex](H_a)[/tex]: Last-minute filers  receive lower average tax refunds than early filers.

Mathematically:

[tex]H_0[/tex]: μ_last_minute = μ_early

[tex]H_a[/tex]: μ_last_minute < μ_early

where:

μ_last_minute = population mean refund for last-minute filers

μ_early = population mean refund for early filers

b.

Given information:

Sample mean for last-minute filers = $910

Population standard deviation (σ) = $1600

Sample size (n) = 400

To calculate the test statistic and the p-value, use the formula:

[tex]z = (\bar x - \mu) / (\sigma / \sqrt n)[/tex]

Where:

[tex]\bar x[/tex] = sample mean

μ = hypothesized population mean under the null hypothesis

σ = population standard deviation

n = sample size

Plugging in the values:

z = ($910 - $1056) / ($1600 / √400)

z = ($910 - $1056) / ($1600 / 20)

z = -$146 / 80

z ≈ -1.825

c.

To find the p-value associated with the test statistic, use a standard normal distribution table. For a one-tailed test with a z-score of -1.825, the p-value is approximately 0.034.

d.

Critical value approach:

To perform the hypothesis test using the critical value approach, we first need to find the critical value corresponding to α = 0.05 and a one-tailed test.

For a significance level (α) of 0.05, the critical value is approximately -1.645.

Now, the test statistic we calculated previously was -1.825.

Conclusion: The p-value is less than α, we reject the [tex](H_0)[/tex].There is sufficient evidence to support the researcher's contention that last-minute filers  receive lower average tax refunds than early filers. Since the test statistic is more extreme than the critical value, we reject the null hypothesis.

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Find the value of x and simplify completely.

Answers

Answer:

x=910

Given: A right triangle in which an altitude is drawn from the right angle vertex to the hypotenuse.

To find: 'x' the larger leg of triangle

Solution,

Using let rule for similarity in right triangle:

[tex] \frac{leg}{part} = \frac{hypotenuse}{leg} \\ or \: \frac{x}{27} = \frac{3 + 27}{x} \\ or \: x \times x = 27(3 + 27) \\ or \: x \times x = 81 + 729 \\ or \: {x}^{2} = 810 \\ or \: {x}^{2} = 81 \times 10 \\ or \: {x} = \sqrt{81 \times 10} \\ or \: x = \sqrt{81} \times \sqrt{10} \\ or \: x = \sqrt{ {(9)}^{2} } \times \sqrt{10} \\ \: x = 9 \sqrt{10} [/tex]

Hope this helps...

Good luck on your assignment..

THE VALUE OF (-3)raised to 4 is

Answers

Step-by-step explanation:

81

I think this should be the answer

Lee watches TV for 2 hours per day. During that time, the TV consumes 150 watts per hour. Electricity costs (12 cents)/(1 kilowatt-hour). How much does Lee's TV cost to operate for a month of 30 days?

Answers

Answer:

$1.08

Step-by-step explanation:

30 days × (2 hrs/day) × (150 W) × (1 kW / 1000 W) × (0.12 $/kWh) = $1.08

Eight times the difference of y and nine

Answers

Answer:

(y-9)8

Step-by-step explanation:

you first solve 8-9, and then multiply is by 8.

Eight times the difference of y and nine will be 8(y - 9).

It should be noted that eight times the difference of y and nine simply means that one has to subtract 9 from y and then multiply the difference by 8.

Therefore, eight times the difference of y and nine will be 8(y - 9).

In conclusion, the correct option is 8(y - 9).

Read related link on:

https://brainly.com/question/16081696

Please answer this correctly

Answers

Answer:

2/3

Step-by-step explanation:

There are 4 numbers that fit the rule, 3, 4, 7, 8 since they are either less than 5 or greater than 6. There are 6 numbers so the chance would be 4/6 or simplified, 2/3.

Answer:

2/3

Step-by-step explanation:

There are 6 options, 2 of them > 6 and 2 of them < 5

P (greater than 6 or less than 5)= 4/6= 2/3

The population of Adamsville grew from 6000 to 13000 in 7 years. Assuming uninhibited exponential growth, what is the expected population in an additional 3 years?

Answers

Answer:

18107.32

Step-by-step explanation:

Set up the exponential function in the form:

       [tex]P = P_0(R)^t[/tex]

so P is the new population, [tex]P_0[/tex] is the original population, R is the rate of increase in population, and t is the time in years.

You have to use the information given to find the rate that the population is increasing and then use that rate to find the new population after more time passes.

[tex]13000 = 6000(R)^7\\\\\\frac{13000}{6000} = R^7\\\\\sqrt[7]{\frac{13000}{6000} } = R\\\\\\ R = 1.116786872[/tex]

Now that you found the rate, you can use the function to find the population after another 3 years.

[tex]P = 13000(1.116786872)^3\\P = 18107.32317\\[/tex]

So the population is 18107, rounded to the nearest whole number.

Select the fraction that is equivalent to 2/6 ?

Answers

Answer:

The fraction that is equivalent to 2/6 is 1/3

True or False?
2 is a solution to 8m - 6 < 10
True
False

Answers

Answer:

2 is not a solution

False

Step-by-step explanation:

8m - 6 < 10

Add 6 to each side

8m -6+6 < 10+6

8m < 16

Divide by 8

8m/8 <16/8

m < 2

m must be less than 2

2 is not a solution

Answer:

FALSE

Step-by-step explanation:

Trust Me

Monique only has $36 to buy pens and notebooks. Each pen costs $2. Each
notebook costs $3. Which of the following graphs represents the possible
combinations of pens and notebooks that she may purchase?

Answers

Answer:

B.

Step-by-step explanation:

Let's call x the number of pens and y the number of notebooks that Monique can buy.

If each pen costs $2 and each notebook costs $3, so she is going to spend 2*x on pens and she is going to spend 3*y on notebooks.

Additionally, she is going to spend a maximum of $36. so:

2x + 3y [tex]\leq[/tex] 36

It means that the line that  separated the region is:

2x + 3y = 36

This is the same that a line that passes for the points (0,12) and (18,0) or the line of the region B

El costo de pintar un muro se calcula con un tercio del doble del área por el triple del numero de trabajadores. Si se planea pintar un muro de 1200m² y se contrataran a 3 trabajadores. ¿Cuanto se pagara?

Answers

Answer:

Se pagará $7200.

Step-by-step explanation:

La ecuación del costo puede descomponerse en dos factores que luego se multiplican:

1) Siendo A el area del del muro, la parte del costo que depende del área se calcula como un tercio (1/3) del doble (2) del área A. Este factor se puede escribir como:

[tex]C_1=(1/3)\cdot 2 \cdot A=(2/3)\cdot A[/tex]

2) Siendo T el número de trabajadores, el siguiente factor es el triple del numero de trabajadores T. Esto es:

[tex]C_2=3T[/tex]

Multiplicando ambos factores, tenemos la ecuacion del costo en función de A y T:

[tex]C=C_1\cdot C_2=(2/3)A\cdot 3T=2 AT[/tex]

Si se planea pintar un muro de 1200m² y se contrataran a 3 trabajadores, el costo será:

[tex]C=2AT=2(1200)(3)=7200[/tex]

A coin will be flipped repeatedly until the sequence TTH (tail/tail/head) comes up. Successive flips are independent, and the coin has probability p of coming up heads. Let N,TTH be the number of coin flips until TTH first appears. What value of p minimizes Ex[N,TTH]

Answers

Answer:

[tex]P = \frac{1}{3}[/tex]

Step-by-step explanation:

The calculation of the value of p minimizes is shown below:-

We will assume the probability of coming heads be p

p(H) = p

p(T) = 1 - P

Now, H and T are only outcomes of flipping a coin

So,

P(TTH) = (1 - P) = (1 - P) (1 - P) P

= (1 + P^2 - 2 P) P

= P^3 - 2P^2 + P

In order to less N,TTH

we need to increase P(TTH)

The equation will be

[tex]\frac{d P(TTH)}{dP} = 0[/tex]

3P^2 - 4P + 1 = 0

(3P - 1) (P - 1) = 0

P = 1 and 1 ÷ 3

For P(TTH) to be maximum

[tex]\frac{d^2 P(TTH)}{dP} < 0 for\ P\ critical\\\\\frac{d (3P^2 - 4P - 1)}{dP}[/tex]

= 6P - 4

and

(6P - 4) is negative which is for

[tex]P = \frac{1}{3}[/tex]

A market researcher finds the price of several brands of fabric softener. What is the level of measurement of the data?

Answers

Answer:

  ratio

Step-by-step explanation:

The levels of measurement are ...

NominalOrdinalIntervalRatio

Both interval and ratio level measurements deal with numerical data. The difference is that ratio-level measurements use a numerical scale that includes an absolute zero, and scale values are proportional to the quantity they represent.

Price data is a ratio level of measurement.

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