Pls help need by tomorrow.
What were the manipulated, responding, and one controlled variable from Spallanzani's
experiment?

P2 = 54.6 kPa

Explanation:

Given:

V1 = 10.0 L. V2 = 50.0 L

P1 = 273 kPa. P2 = ?

We can use Boyle's law to solve this problem.

P1V1 = P2V2

Solving for P2,

P2 = (V1/V2)P1

= (10.0 L/50.0 L)(273 kPa)

= 54.6 kPa

Answer:

b 2.00

Explanation:

I am pretty sure that is right

Answer:

6

Explanation:

6.0mol ( 1 mol H2/ 1 mol Zn ) = 6.0 mol of H2

H2 is hydrogen gas (hydrogen in the air).

Answer:

Explanation:

Because your brain and the TV are programed to do certain things. As if you're going back into a memory, and you're simply rewatching a season of Beyblade: Metal Fusion on the TV.

Answer:

0.89 L

Explanation:

Applying,

Boyle's Law,

PV = P'V'..................... Equation 1

P represent initial pressure, V represent initial volume, P' represent final pressure, V' represent final volume

Make V' the subject of the equation

V' = PV/P'.............. Equation 2

From the question,

Given: P = 150 mm Hg, V = 4.31 liters, P' = 725 mm Hg

Substitute these values into equation 2

V' = (150×4.31)/725

V' = 0.89 L

Answer:

You take the atomic, or proton number of the element, and you subtract it from the element's mass number.

Answer:

protons

Explanation:

neutrons and protons make up the mass of the atom

Answer:

divide the mass of element in 1 mole of the compound by the compound's molar mass and multiply the answer by 100.

Explanation:

take the molar mass of hydrogen in the water molecule, divide by the total molar mass of water, and multiply by 100.

does it help?

Answer:

done this before in my science class

Explanation:

the hole by the cap will have slightly more coming out at first due to all the toothpaste pushing forward, but over time, the middle will get more do to all the front end of the toothpaste being pushed out first

(sorry if that sounded confusing im tired, heres a cat)

The hole by the cap will have slightly more coming out at first due to all the toothpaste pushing forward, but over time, the middle will get more do to all the front end of the toothpaste being pushed out first.

Toothpaste is a key part of your daily oral hygiene routine. Along with your toothbrush and floss it helps to remove food debris and plaque from your teeth and gums.

Toothpastes can come in a gel, paste or powder form. While the ingredients differ slightly, all toothpastes contain the same general components.

With some help from your toothbrush, these help to remove debris and surface stains. This ingredient helps to prevent water loss, and keeps your toothpaste from drying out or getting gummy.  This is what gives your toothpaste a little bit of sweetness, and that minty fresh scent. Since these do not contain sugar, they also do not promote tooth decay.

Therefore, The hole by the cap will have slightly more coming out at first due to all the toothpaste pushing forward, but over time, the middle will get more do to all the front end of the toothpaste being pushed out first.

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Answer:It a Basic oxide

Plz trust Me

Explanation:

Answer:

Sodium oxide is a simple strongly basic oxide. It is basic because it contains the oxide ion, O2-, which is a very strong base with a high tendency to combine with hydrogen ions. Reaction with water: Sodium oxide reacts exothermically with cold water to produce sodium hydroxide solution.

Explanation:

Answer:

CATION

Explanation:

If an atom has an equal number of protons and electrons, its net charge is 0. If it gains an extra electron, it becomes negatively charged and is known as an anion. If it loses an electron, it becomes positively charged and is known as a cation.

Answer: 6.45 Joules

Explanation: I just did it

Answer:

2.04 moles

Explanation:

Since the ratio of Na2O to NaOH is 1:2, you multiply the number of moles by 2, equaling 2.04 moles.

Answer:

[tex] \huge\pink{\boxed{\mathfrak{Hola}}}[/tex]

I didn't understand the rest of your question, it's not in English or Spanish.

[tex]\huge\fbox{HôLLa}[/tex]

Answer:

The evolution of the peppered moth is an evolutionary instance of directional colour change in the moth. The frequency of dark-coloured moths increased at that time, an example of industrial melanism.

Explanation:

I did this on Savvas Realize got it right.

Genetic variation is said to be the difference in the hereditary sequence. After the industrial revolution, the frequency of the dark-colored moth increased dramatically more than the light-colored moths.

Industrial melanism was an example of the evolutionary effect that occurred in the moths where the dark-colored species were favored over the light-colored species of peppered moths.

Before the industrial population, light-colored moths were large in number which later decreased with an increase in pollution. This occurred due to an increase in the pollutants and dust deposition that altered the environment.

As the pollution increased over time the dark-colored moths became dominant and increased their population over time. This is an example of industrial melanism as the color of the body was the determining factor in survival.

Therefore, dark-colored moths were prevalent after the industrial revolution.

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Answer:

0.151 mol

Explanation:

molar mass of KNO3 = (39.1 + 14 + 3×16) g/mol = 101.1 g/mol

number of moles = mass/molar mass

n = m/M = 15.3 g/(101.1 g/mol) = 0.151 mol

The name of the alkyne which is given in the question with structure is propyne as in that 3 carbon atoms are present.

Alkynes are those hydrocarbons in which triple bond is present between two adjacent carbon atoms.

In the given structure one triple bond is present between first two carbon atoms and then with this a single bonded carbon atom is also attached. As in the structure total three carbon atoms are present so prefix shoul be 'prop' and as this is an alkyne then name should be propyne.

Hence name of compound is propyne.

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Propyne is the chemical name for the given alkyne. Therefore, the correct option is option C.

A triple bond exists between the carbon atoms in alkynes, a group of hydrocarbon molecules. They are given names based on the IUPAC (International Union of Pure and Applied Chemistry) guidelines for systematic nomenclature. Alkyne nomenclature's primary objective is to provide each compound a precise and distinctive name that accurately captures its structure.  Based on the quantity of carbon atoms, the placement of triple bonds, and the presence of functional groups, alkyne compounds are named systematically.

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Reaction 1 → Al + Zn²⁺ ⟶ Al³⁺ + Zn

Reaction 2 → Al³⁺ + Li ⟶ Al + Li⁺

Reaction 1 :-

Substance Oxidised :- Al

Substance Reduced :- Zn²⁺

Oxidizing Agent :- Zn²⁺

Reducing Agent :- Al

Reaction 2 :-

Substance Oxidised :- Li

Substance Reduced :- Al³⁺

Oxidizing Agent :- Al³⁺

Reducing Agent :- Li

Reaction 1 :-

Al

Zn²⁺

Zn²⁺

Al

Reaction 2 :-

Li

Al³⁺

Al³⁺

Li

drag

effect

friction

parachutes

surface area

streamlined

air

water

Explanation:

It's (D), nuclear fission................

Answer:

D. ) 2H2O - 2H2 + O2

Answer:

The new concentration of the solution is 0.89 M.

Explanation:

In chemistry, dilution is the reduction in concentration of a chemical in a solution. This is accomplished by adding more solvent to the same amount of solute.

So, in a dilution, the amount of solute does not vary, but the volume of the solvent varies: as more solvent is added, the concentration of the solute decreases, as the volume (and weight) of the solution increases.

In a dilution the expression is used:

Ci*Vi = Cf*Vf

where:

In this case:

Replacing:

2.5 M* 250 mL= Cf* 700 mL

Solving:

[tex]Cf=\frac{2.5 M*250 mL}{700 mL}[/tex]

Cf= 0.89 M

The new concentration of the solution is 0.89 M.

Answer:

joules

Heat is the transfer of thermal energy from a system to its surroundings or from one object to another as a result of a difference in temperature. Heat is measured in joules (J).

Explanation: Mrk me brainliest please

Answer: Joules or calories

Answer:

Carbon in the biosphere

Explanation:

Carbon is found in the biosphere stored in plants and trees. Plants use carbon dioxide from the atmosphere to make the building blocks of food during photosynthesis. Carbon is found in the hydrosphere dissolved in ocean water and lakes. Carbon is used by many organisms to produce shells.

Answer:

Q = 20377.5 Joules

Explanation:

Given the following data;

Mass = 75g

Initial temperature = 65°C

Final temperature = 0°C

Specific heat capacity of water = 4.18 J/g°C.

To find the quantity of heat released;

Heat capacity is given by the formula;

[tex] Q = mcdt[/tex]

Where;

Q represents the heat capacity or quantity of heat.

m represents the mass of an object.

c represents the specific heat capacity of water.

dt represents the change in temperature.

Substituting into the equation, we have;

[tex] Q = 75 * 4.18 * 65 [/tex]

Q = 20377.5 Joules

Answer:

A toad on lily pad

Explanation:

have a great day

Answer:

The force applied to the object is an external force, from outside the system. When it does positive work it increases the gravitational potential energy of the system. Because gravitational potential energy depends on relative position, we need a reference level at which to set the potential energy equal to 0.

If an object is on top of a hill or in a position raised above the ground, it must have gravitational potential energy.

In physics, potential energy is the energy held by an object because of its position relative to other objects, stresses within itself, its electric charge, or other factors

If an object is lifted, work is done against the force of gravity.

When work is done energy is transferred to the object and it gains gravitational potential energy.

If the object falls from that height, the same amount of work would have to be done by the force of gravity to bring it back to the Earth’s surface.

Due to the Principle of Conservation of Energy we can say that:

Gravitational potential energy at the top = kinetic energy at the bottom

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Answer:

Explanation:

sheesh i wouldn’t know

Answer:

Hypothesis is the answer

Answer:

weight of H₂O formed = 2.3 grams H₂O (2 sig. figs.)

Explanation:

Rxn:                  CH₄(g)         +      2O₂(g)          =>     CO₂(g)           +  2H₂O(g)

Given:                 1.16g                   4.16g                     3.52g                  ? (g)

Moles:         1.16g/16g·mol⁻¹    4.16g/32g·mol⁻¹    3.52g/44g·mol⁻¹

                     = 0.0725mol.        = 0.13mol.             = 0.08mol.    => ? (moles)

Limiting Reactant: Divide each mole value by related coefficient of balanced standard equation (that is, balanced with coefficients in lowest whole number ratios). The smaller value is the limiting reactant.

                    0.0725/1                   0.13/2                0.080/1

                    = 0.0725                 = 0.065              = 0.080

Limiting Reactant is O₂(g) => 0.065 is smaller value after dividing each mole value by related coefficient of balanced equation.

NOTE: When working problem, however, one must use the mole value calculated from given amount in grams. That is, in this case 0.13 mole O₂. The 'divide by related coefficient and check smaller value' is ONLY for identifying the limiting reactant. This trick works for ALL general chemistry problems.

Moles H₂O formed: Since the coefficient of the limiting reactant (O₂) equals the coefficient of water (H₂O), then the moles of water formed is 0.065 mole H₂O.

Weight (in grams) of H₂O formed:

Grams H₂O = moles H₂O  x  formula weight H₂O

                   = 0.13 mole H₂O  x  18 g H₂O/mole H₂O

                   = 2.34 g H₂O  (calculator answer)

                   = 2.3 g H₂O  (final answer should be rounded to  2 sig. figs.)                                                                                                                                        => form of final answer should be based on data in final computation having the least number of sig. figs.                                      

Review: Sequence of calculations

       =>  moles of limiting reactant / coefficient of same cpd. in std. equation               = unknown (X) / coefficient of same (unknown) cpd. in std. equation

       => cross multiply and solve for unknown (X)

       => L.R.(moles) / eqn. coef. of L.R. = X / eqn. coef. of X  

       => (L.R.(calc'd moles)(eqn. coef. of X) = (X)(eqn. coef. of L.R.)

       => X (in moles) = (L.R.(calc'd. moles)(eqn. coef. of X) / (eqn. coef. of L.R.)

        => grams = moles x formula wt.                                                                

        => volume (L) = moles x std. volume (= 22.4L/mole)                                  

        => #particles = moles x Avogadro's Number (= 6.02 x 10²³ parts/mole)