Pls help ima mark BRAINLIST

Pls Help Ima Mark BRAINLIST

Answers

Answer 1

Answer:

23%

Step-by-step explanation:

There are 30 total students

There are 7 freshman ( 4+3)

P( freshman) = number of freshman/ total

                      =7/30

                       .2333333

                      23.3%

To the nearest whole percent

                     23%


Related Questions

Please answer it in two minutes

Answers

Answer:

2,700 degrees.

Step-by-step explanation:

17 gon is a heptadecagon.

The formula for the sum of interior angles is [tex](n-2)*180[/tex] degrees.

[tex](17-2)*180=\\15*180=\\2700[/tex]

Please answer this....​

Answers

Answer:

c)    [tex]2\frac{23}{30}[/tex]     d)[tex]1\frac{23}{24}[/tex]

7)    a.   [tex]6\frac{3}{11}[/tex]  kg                  b.   [tex]6 \frac{2}{3}[/tex]  cm               c. 20 cm

 

d.  [tex]9\frac{9}{10}[/tex] kg                  e. 10 g             f. [tex]23 \frac{1}{4}[/tex]  kg

Step-by-step explanation:

c)  [tex]8\frac{2}{3}[/tex]   -   [tex]5\frac{9}{10}[/tex]

First we will change to improper fraction and then solve

[tex]\frac{26}{3} - \frac{59}{10}[/tex]

=  [tex]\frac{260 - 177}{30}[/tex]

= [tex]\frac{83}{30}[/tex]

we will now change to mixed number

= [tex]2\frac{23}{30}[/tex]

d)  [tex]8\frac{1}{8} - 6\frac{1}{6}[/tex]

we will first change it to improper fraction and then solve

= [tex]\frac{65}{8} - \frac{37}{6}[/tex]

= [tex]\frac{390 - 296}{48}[/tex]

= [tex]\frac{94}{48}[/tex]

we can reduce the fraction

=[tex]\frac{47}{24}[/tex]

we will change it mixed number

=[tex]1\frac{23}{24}[/tex]

7)  

a.   [tex]\frac{3}{11}[/tex]   of 23

=  [tex]\frac{3}{11}[/tex]   × 23

=  [tex]\frac{69}{11}[/tex]

=[tex]6\frac{3}{11}[/tex]  kg

b. [tex]\frac{2}{3}[/tex]   of 10 cm

= [tex]\frac{2}{3}[/tex]   × 10 cm

= [tex]\frac{20}{3}[/tex]  cm

=[tex]6 \frac{2}{3}[/tex]  cm

c. [tex]\frac{5}{6}[/tex]   of 24cm

=    [tex]\frac{5}{6}[/tex]   × 24 cm

6 will divide 24

=5 × 4 cm

= 20 cm

d.  [tex]\frac{3}{10}[/tex]  of  33 kg

=  [tex]\frac{3}{10}[/tex]  ×  33 kg

=[tex]\frac{99}{10}[/tex]  kg

=[tex]9\frac{9}{10}[/tex] kg

e. [tex]\frac{2}{7}[/tex]   of  35 g

=  [tex]\frac{2}{7}[/tex]   ×  35 g

7 will go into 35

=2×5 g

=10 g

f. [tex]\frac{3}{4}[/tex]  of  31 kg

= [tex]\frac{3}{4}[/tex]  ×  31 kg

=[tex]\frac{93}{4}[/tex] kg

=[tex]23 \frac{1}{4}[/tex]  kg

how many millimeters are in a meter​

Answers

Answer:

There are 1000 millimeters in a meter.

Step-by-step explanation:

I really hope this helps in any way.

Answer:

1,000

Step-by-step explanation:

The word millimeter has the prefix of 'milli-'.

'Milli-' means a thousand.

Applying the prefix meaning to the word, a millimeter would be a thousandth of a meter.

There are 1,000 millimeters in a meter.

Brainilest Appreciated.

There is a bag filled with 5 blue, 6 red and 2 green marbles. A marble is taken at random from the bag, the colour is noted and then it is not replaced. Another marble is taken at random. What is the probability of getting 2 blues?

Answers

Answer:

Step-by-step explanation:

Total marbles = 5  + 6 + 2 = 13

P( getting blue ball from first draw) = 5/13

The marble is not replaced. So, Now total marbles will be 12 & number blue marbles will be 4

P( getting blue ball from second draw) = 4/12 = 1/3

P(getting two blues) = [tex]\frac{5}{13}*\frac{1}{3}\\[/tex]

                                  = 5/39

Write equation Derek will get a bonus if he sells at least 50 sets of knives in a month use k to represent the number of knives he can sell to receive his bonus

Answers

Answer: k ≥ 50

Step-by-step explanation:

From the question, we are informed that Derek will get a bonus if he sells at least 50 sets of knives in a month. We are further told to us k to represent the number of knives he can sell to receive his bonus.

Since we are told that Derek will get a bonus if he sells at least 50 sets of knives in a month, this means that k will be greater than or equal to 50. Therefore,

k ≥ 50

Match the graph with the correct equation
• y+2=(x-2)
•y+2= -(x-4)
•y+2= -(x+4)
•y-2= -(x-4)

Answers

Answer:

y + 2 = -(x-4)

Step-by-step explanation:

Here, we want to match the graph with the correct equation

the equation is generally in the form

y = mx + c since it is a straight line

Let’s start with c which is the y- intercept

c = 2 from the graph

Let’s find value of the slope using the end points

The end points at top and at bottom are as follows respectively;

(-8,10) and (10,-8)

So the slope is ; y2-y1/x2-x1 and that is ;

-8-10/(10-(-8) = -18/18 = -1

So the complete form of the line would be;

y = -1(x) + 2

y = -x + 2

or simply y = 2-x

So which of the options fit this answer?

That would be;

y+ 2 = -(x-4)

This can be written as;

y + 2 = -x + 4

y = -x + 4-2

y = -x + 2

Answer:(D) y + 2 = -(x-4)

Step-by-step explanation:

PLEASE HELP Which of the sets of ordered pairs represents a function? A = {(2, −2), (5, −5), (−2, 2), (−5, 5)} B = {(4, 2), (4, −2), (9, 3), (9, −3)} a. Only A b. Only B c. Both A and B Incorrect d. Neither A nor B

Answers

Answer: A. Only A

Step-by-step explanation:

A has exactly one output for every input but B has different outputs for an input.

Answer: only A

Explication: If there is no repeated numbers in the x axis and the y axis it is a function you can also figure this out by doing the line test if you draw a horizontal line across your function and there is no repeated numbers on the x axis or y axis it is a function

One number is 10 times as large as another, and their difference is 81. Find the numbers. If x represents the smaller number, then the larger number is x + 10 10x

Answers

Answer:

value of x=9

so value of large number is 90 and smaller number is 9

please solve it 90 POINTS please help- PLEASE HELP its Identify the following for the quadratic relations please slove it all please if you can save the picture and do it on the page -
i Will give brainliest​

Answers

Answer:

[tex]\boxed{\mathrm{view \: explanation}}[/tex]

Step-by-step explanation:

2)

a) elimination method

b) substitution method

c) substitution method

For the first part we can elimate the y variable by subtracting the equations. We can then find the value of x.

For the second part we can substitute y as 2x+5 in the second equation and solve for x.

For the third part we can substitute y as 4x+3 in the first equation and solve for x.

3)

[tex]\boxed{\mathrm{view \: attachment}}[/tex]

A car is traveling at x feet per second. The driver sees a red light ahead, and
after 1,5 seconds reaction time, the driver applies the brake. After the brake is
applied, the car takes seconds to stop, during which time the average speed
24
of the car is feet per second. If the car travels 165 feet from the time the
driver saw the red light to the time it comes to a complete stop, which of the
following equations can be used to find the value of x?
A) x2 + 48x - 3,960 = 0
B) x2 + 48x - 7,920 = 0
C) x2 + 72x - 3,960 = 0
D) x2 + 72x - 7,920 = 0

Answers

Answer:

The correct option is;

D) x² + 72·x - 7920 = 0

Step-by-step explanation:

The time it takes the car to stop = x/24 seconds

the average speed during stopping = x/2 feet per second

Given that the car was initially travelling at x feet per second and it takes the car 165 feet to stop after the driver takes 1.5 seconds at the initial speed x before the break is applied, we have;

Total distance traveled = (x/24)×(x/2) + x×1.5 = 165

= x²/48 + 1.5·x = 165

Multiply through by 48, we have;

x² + 72·x = 7920

Which gives the equation as follows;

x² + 72·x - 7920 = 0.

Consider the graph with four lines below. On a coordinate plane, line a has a positive slope and goes through points (negative 1, 0) and (1, 2), line b has a negative slope and goes through (negative 2, 2) and (negative 1, negative 1), line c has a negative slope and goes through (0, 3) and (1, 0), and line d is horizontal at y = 1. By inspection, which system would have no solution? line a and line b line a and line c line b and line c line b and line d

Answers

Answer:

C) line b and line c

Step-by-step explanation:

On edge

A line is a one-dimensional shape that is straight, has no thickness, and extends in both directions indefinitely. The system of equations that do not have any solution is line b and line c. Hence, the correct option is C.

What is the equation of a line?

A line is a one-dimensional shape that is straight, has no thickness, and extends in both directions indefinitely. The equation of a line is given by,

y =mx + c

where,

x is the coordinate of the x-axis,

y is the coordinate of the y-axis,

m is the slope of the line, and

c is the y-intercept.

The equation of line a passing through (-1,0) and (1,2) are,

m = (0-2)/(-1-1) = -2/-2 = 1

y= x + c

0 = -1 + c

c = 1

Equation of line 1, y=x+1

The equation of line b passing through (-2,2) and (-1,-1) are,

m = (2+1)/(-2+1) = 3/-1 = -3

y= -3x + c

-1 = -3(-1) + c

c = -4

Equation of line 1, y=-3x-4

The equation of line c passing through (0,3) and (1,0) are,

m = (3-0)/(0-1) = 3/-1 = -3

y= -3x + c

3 = -3(0) + c

c = 3

Equation of line 1, y=-3x+3

Also, the equation of line d is y=1

The solution of two-equation is the point at which the two equations are not intersecting. Therefore, the system of equations that do not have any solution is line b and line c.

Hence, the correct option is C.

Learn more about Equation of Line:

https://brainly.com/question/21511618

#SPJ2

Write a two-column proof. Given: <2 is congruent to <5; Segment AB is congruent to Segment DE Prove: Segment BC is congruent to Segment EC

Answers

Answer:

proof

Step-by-step explanation:

Statements

Reasons

<2 is congruent to <5; Segment AB is congruent to Segment DE

Given

<3≅<4

Vertical angle theorem

ΔCDB≅ΔCAE

AAS

Segment BC is congruent to Segment EC

CPCTC

The segment BC is congruent to segment EC and this can be proven by using the properties of a triangle and the given data.

Given :

Angle 2 is congruent to angle 5.Segment AB is congruent to Segment DE.

The following steps can be used in order to prove that segment BC is congruent to segment EC:

Step 1 - Using the triangle properties it can be proven that segment BC is congruent to segment EC.

Step 2 - According to the vertical angle theorem, angle 3 is congruent to angle 4.

Step 3 - Now, according to the AAS (Angle Angle Side) postulate, triangle CDB is similar to triangle CAE.

Step 4 - So, according to the CPCTC, segment BC is congruent to segment EC.

For more information, refer to the link given below:

https://brainly.com/question/25813512

Avalanche conditions: Winter avalanches occur for many reasons, one being the slope of the mountain. Avalanches seem to occur most often for slopes between 35° and 60° (snow gradually slides off steeper slopes). The slopes at a local ski resort have an average rise of 2000 ft for each horizontal run of 2559 ft. Is this resort prone to avalanches? Find the angle θ and respond. 2000 ft 2559 ft

Answers

Answer:

Yes, since angle θ = 38° and is between 35° and 60°, this slope is prone to avalanches.

Step-by-step explanation:

Avalanche conditions: Winter avalanches occur for many reasons, one being the slope of the mountain. Avalanches seem to occur most often for slopes between  (snow gradually slides off steeper slopes). The slopes at a local ski resort have an average rise of 2000 ft for each horizontal run of 2559 ft. Is this resort prone to avalanches? Find the angle θ and respond. 2000 ft 2559 ft

Draw a right triangle. Start with a horizontal side and label the horizontal side 2559 ft. Then at one endpoint of that side, draw a vertical side going up from the horizontal side. Label it 2000 ft. Connect the upper point of the vertical side to the other endpoint of the triangle. The acute angle at the bottom is θ.

[tex] \tan \theta = \dfrac{opp}{adj} [/tex]

[tex] \tan \theta = \dfrac{2000}{2559} [/tex]

[tex] \theta = \tan^{-1} 0.7816 [/tex]

[tex] \theta = 38^\circ [/tex]

Since the angle is between 35° and 60°, this slope is prone to avalanches.

3. Solve 6k + 9 > k – 1.
use photo for options ​

Answers

Answer:

k > - 2

Step-by-step explanation:

Given

6k + 9 > k - 1 ( subtract k from both sides )

5k + 9 > - 1 ( subtract 9 from both sides )

5k > - 10 ( divide both sides by 5 )

k > - 2

Answer:

k> -2

Step-by-step explanation:

6k + 9 > k – 16k - k > - 1 - 95k > -10k > -10/5k> -2

Which of the following is the correct factored form of the given equation? 6x^2 -13x - 8 = 0

Answers

Answer:

the 2nd

Step-by-step explanation:

Find the total surface area of this cylinder. Give your answer to one decimal place PLEASE HELP THANK YOUUUU

Answers

Answer:

Step-by-step explanation:

surface area of cylinder=2 πr²+2πrh

=2πr(r+h)

=2π×12(12+18)

=24π×30

=720π

≈2261.9 cm²

What is the 5th equivalent fraction to 1/11 ?

Answers

Answer: 5/55

Step-by-step explanation:

1/11 x 5 = 5/55

So, the fifth equivalent fraction to 1/11 is 5/55.

The 5th equivalent fraction should be [tex]5\div 55[/tex]

Calculation of the equivalent fraction:

Since the fraction is [tex]1\div 11[/tex]

So here the 5th equivalent should be

[tex]= 1\div 11 \times 5\div 5[/tex]

= [tex]5\div 55[/tex]

Here 5 represent the numerator and 55 represent the denominator.

Therefore, we can concluded that The 5th equivalent fraction should be [tex]5\div 55[/tex]

Learn more about fraction here: https://brainly.com/question/1786648

Find w please help me

Answers

Answer:

w = 77°

Step-by-step explanation:

From the picture attached,

WXYZ is a quadrilateral having 4 interior angles,

m∠y = 90°

Therefore, (2x - 10) = 90°

2x = 90 + 10

2x = 100

x = 50

Now, m∠z = (x + 15)° = 65°

m∠x = (3x - 22)° = 150 - 22

                          = 128°

Sum of interior angles of a polygon = (n - 2)×180°

where n = Number of sides of the polygon

If n = 4,

m∠u + m∠x + m∠y + m∠z = (4 - 2) × 180°

w + 128 + 90 + 65 = 360

w = 360 - 283

w = 77°

Therefore, measure of w = 77°

x is partly constant and partly varies with y. When y=3, x = 7 and when y = 6, x = 9. Find x when y = 4

Answers

Answer:

x=23/3

Step-by-step explanation:

x=c+ay

7=c+3a     | *(-1)

9=c+6a

-7=-c-3a

9=c+6a

------------

9-7=c-c+6a-3a

2=3a

a=2/3

7=c+3*2/3

7=c+2

-2   -2

5=c

so   x=5+2/3*y

when y=4 then  x=5+2/3*4=5+8/3

x=15/3+8/3

x=23/3

Line segment C X is an altitude in triangle ABC. Triangle A B C is shown. Angle A C B is a right angle. An altitude is drawn from point C to point X on side A B to form a right angle. Which statements are true? Select two options. ΔABC Is-congruent-to ΔBXC ΔAXC ~ ΔCXB ΔBCX Is-congruent-to ΔACX ΔACB ~ ΔAXC ΔCXA Is-congruent-to ΔCBA

Answers

Answer:

ΔAXC ~ ΔCXB

ΔACB ~ ΔAXC

Step-by-step explanation:

B and D are correct

Congruent triangles have equal corresponding sides.

The true statements are: ΔAXC ~ ΔCXB ; and ΔACB ~ ΔAXC  

From the figure (see attachment), we have the following highlights

Triangles AXC and CXB are similar by SASTriangles ACB and AXC are also similar by SAS

This means that we have the following similarities statements:

ΔAXC ~ ΔCXB ; and ΔACB ~ ΔAXC  

Hence, the true options are: (b) and (d)

Read more about congruent triangles at:

https://brainly.com/question/3807969

EXCELLENT VOTE!! (only if u give the CORRECT answer)

Answers

Answer:

Option C

Step-by-step explanation:

Answer:

B.

You need to subtract 1 term because you don't include the starting 5

4^10 - 1 =  4^9

You multiply 5 by 4 each time for 9 times so it is 5 x 4^9

Hope this helps

Step-by-step explanation:

Drag the tiles to the boxes to form correct pairs. Not all tiles will be used. Match the circle equations in general form with their corresponding equations in standard form. x2 + y2 − 4x + 12y − 20 = 0
(x − 6)2 + (y − 4)2 = 56
x2 + y2 + 6x − 8y − 10 = 0
(x − 2)2 + (y + 6)2 = 60
3x2 + 3y2 + 12x + 18y − 15 = 0
(x + 2)2 + (y + 3)2 = 18
5x2 + 5y2 − 10x + 20y − 30 = 0
(x + 1)2 + (y − 6)2 = 46
2x2 + 2y2 − 24x − 16y − 8 = 0
x2 + y2 + 2x − 12y − 9 = 0

Answers

Answer:

1) For [tex]x^2 + y^2 - 4x + 12y - 20 = 0[/tex], the standard form is [tex](x-2)^2 + (y+6)^2 = 60\\[/tex]

2) For [tex]x^2 + y^2 + 6x - 8y - 10 = 0[/tex], the standard form is [tex](x + 3)^2 + (y - 4)^2 = 35\\[/tex]

3) For [tex]3x^2 + 3y^2 + 12x + 18y - 15 = 0[/tex],  the standard form is [tex](x + 2)^2 + (y+ 3)^2 = 18\\[/tex]

4) For [tex]5x^2 + 5y^2 - 10x + 20y - 30 = 0[/tex],  the standard form is [tex](x - 1)^2 + (y+ 2)^2 = 11\\[/tex]

5) For [tex]2x^2 + 2y^2 - 24x - 16y - 8 = 0[/tex],  the standard form is [tex](x - 6)^2 + (y+ 4)^2 = 56\\[/tex]

6) For[tex]x^2 + y^2 + 2x - 12y - 9 = 0[/tex], the standard form is [tex](x+1)^2 + (y-6)^2 = 46\\\\[/tex]

Step-by-step explanation:

This can be done using the completing the square method.

The standard equation of a circle is given by [tex](x - a)^2 + (y-b)^2 = r^2[/tex]

1) For [tex]x^2 + y^2 - 4x + 12y - 20 = 0[/tex]

[tex]x^2 - 4x + y^2 + 12y = 20\\x^2 - 4x + 2^2 + y^2 + 12y + 6^2 = 20 + 4 + 36\\(x-2)^2 + (y+6)^2 = 60\\[/tex]

Therefore, for [tex]x^2 + y^2 - 4x + 12y - 20 = 0[/tex], the standard form is [tex](x-2)^2 + (y+6)^2 = 60\\[/tex]

2) For [tex]x^2 + y^2 + 6x - 8y - 10 = 0[/tex]

[tex]x^2 + 6x + y^2 - 8y = 10\\x^2 + 6x + 3^2 + y^2 - 8y + 4^2 = 10 + 9 + 16\\(x + 3)^2 + (y- 4)^2 = 35\\[/tex]

Therefore, for [tex]x^2 + y^2 + 6x - 8y - 10 = 0[/tex], the standard form is [tex](x + 3)^2 + (y - 4)^2 = 35\\[/tex]

3)  For [tex]3x^2 + 3y^2 + 12x + 18y - 15 = 0[/tex]

Divide through by 3

[tex]x^2 + y^2 + 4x + 6y = 5[/tex]

[tex]x^2 + y^2 + 4x + 6y = 5\\x^2 + 4x + 2^2 + y^2 + 6y + 3^2 = 5 + 4 + 9\\(x + 2)^2 + (y+ 3)^2 = 18\\[/tex]

Therefore, for [tex]3x^2 + 3y^2 + 12x + 18y - 15 = 0[/tex],  the standard form is [tex](x + 2)^2 + (y+ 3)^2 = 18\\[/tex]

4)  For [tex]5x^2 + 5y^2 - 10x + 20y - 30 = 0[/tex]

Divide through by 5

[tex]x^2 + y^2 - 2x + 4y = 6[/tex]

[tex]x^2 + y^2 -2x + 4y = 6\\x^2 - 2x + 1^2 + y^2 + 4y + 2^2 = 6 + 1 + 4\\(x - 1)^2 + (y+ 2)^2 = 11\\[/tex]

Therefore, for [tex]5x^2 + 5y^2 - 10x + 20y - 30 = 0[/tex],  the standard form is [tex](x - 1)^2 + (y+ 2)^2 = 11\\[/tex]

5) For [tex]2x^2 + 2y^2 - 24x - 16y - 8 = 0[/tex]

Divide through by 2

[tex]x^2 + y^2 - 12x - 8y = 4[/tex]

[tex]x^2 + y^2 - 12x - 8y = 4\\x^2 - 12x + 6^2 + y^2 - 8y + 4^2 = 4 + 36 + 16\\(x - 6)^2 + (y+ 4)^2 = 56\\[/tex]

Therefore, for [tex]2x^2 + 2y^2 - 24x - 16y - 8 = 0[/tex],  the standard form is [tex](x - 6)^2 + (y+ 4)^2 = 56\\[/tex]

6) For [tex]x^2 + y^2 + 2x - 12y - 9 = 0[/tex]

[tex]x^2 + 2x + y^2 - 12y = 9\\x^2 + 2x + 1^2 + y^2 - 12y + 6^2 = 9 + 1 + 36\\(x+1)^2 + (y-6)^2 = 46\\[/tex]

Therefore, for[tex]x^2 + y^2 + 2x - 12y - 9 = 0[/tex], the standard form is [tex](x+1)^2 + (y-6)^2 = 46\\\\[/tex]

For Plato / Edmentum

Just to the test and got it right ✅

A winter recreational rental company is fencing in a new storage area. They have two options. They can set it up at the back corner of the property and fence it in on four sides. Or, they can attach it to the back of their building and fence it in on three sides. The rental company has decided that the storage area needs to be 100 m2 if it is in the back corner or 98 m2 if it is attached to the back of the building. Determine the optimal design for each situation.

Answers

Answer:

Rectangular area attached to the back of the building

two sides of legth 7 m and one side of 14 m

Step-by-step explanation:

We need to compare quantity of fencing material to be used in both cases

1.Option

A = 100 m²          dimensions of storage area  "x"    and "y"

x*y = 100     y = 100/x

The perimeter of the storage area is

p = 2*x + 2*y       ⇒ p = 2*x + 2*100/x

p(x) = 2*x + 200/x

Taking drivatives on both sides of the equation

p´(x) = 2 - 200/x²

p´(x) = 0         ⇒        2 - 200/x² = 0

2*x² - 200 = 0       x² = 100

x = 10 m

and  y = 100/10      

y = 10 m

Required fencing material in first option

2*10 + 2*10  =  40 m

2.-Option

Following the same procedure

A = 98 m²       y = A/x         y = 98/x

p = 2*x + y             p(x) =  2*x  +  98/x

p´(x)  = 2 - 98/x²             p ´(x) = 0

2 - 98/x²  = 0

2*x²  = 98           x² =  49

x = 7 m       and        y   =  98/ 7         y  = 14 m

Total quantity of fencing material

p = 2* 7 + 14         p = 28

Therefore option 2 is more convinient from economic point of view

Optimal design rectangular storage area with two sides of 7 m and one side of 14 m

Pls ppl answer dis question PLS PLS PLS No scaming pls
4√3 x^2+5x-2√3

Answers

Answer:

\the zeroes are (2√3)/ 3, (√3)/4,

or -1.15, 0.43 to the nearest hundredth.

Step-by-step explanation:

I am assuming you want to find the zeroes of this function:

4√3 x^2+5x-2√3 = 0

Using the quadratic formula:

x = [ -5 +/- √((5)^2 - 4 * 4√3  * -2√3) ]  / (2 * 4√3 )

=  ( - 5 +/- √(25 - (-32*3)) / 8√3

= (-5 +/- √ 121) / 8√3

= (-5 - 11) / 8√3 or  (-5 + 11) / 8√3

=  -16/8√3 or 6/8√3

= -16√3/ 24 or  6√3 / 24

= -2√3/ 3 or √3/4.

( brainliest to the correct answer) worth 13 points

Can someone solve this for me I need to finish this assignment today (:

Thank youuuuu

Answers

Answer:

8.66 billion?

explanation: 7.1+1.1% X 20=8.662

Line A has an x-intercept of -4 and a y-intercept of 8. What is its slope?

Answers

Answer:

Step-by-step explanation:

We can use the intercept form of the equation of a line, then solve for y.

Intercept form

  x/(x-intercept) +y/(y-intercept) = 1

  x/-4 +y/8 = 1

__

Solving for y, we have ...

  -2x +y = 8 . . . . multiply by 8

  y = 2x +8 . . . .  add 2x

The coefficient of x is 2, so the slope is 2.

__

The graph shows you the rise is 8 for a run of 4, so ...

  slope = rise/run = 8/4

  slope = 2

Click to review the online content. Then answer the question(s) below, using complete sentences. Scroll down to view additional
questions.
Online Content: Site 1
Suggest changing to "On the graph of an exponential function representing growth, what happens to the slope of the graph as x
increases?"

Answers

Answer:

The slope also increases

Step-by-step explanation:

The slope of a function is the ratio of change in y to change in x. For an exponential function f(x) = e^x, the slope of the function is equal to the function, i.e slope = e^x.

For a function represented by [tex]y=2^x[/tex], this is an exponential function representing growth, the slope of  [tex]y=2^x[/tex] is also  [tex]2^x[/tex], therefore as the value of x increases, the value of the slope also increases.

At x = 1, slope = 2^1 = 2, At x = 4, slope = 2^4 = 16.

Determine if each statement is always, sometimes, or never true.
1. Parallel lines are
coplanar.
2. Perpendicular lines are
coplanar.
3. Distance around an unmarked circle can
be measured.

Answers

Answer:

Determine if each statement is always, sometimes, or never true.

1. Parallel lines are

coplanar: Always true

2. Perpendicular lines are

coplanar: Always true

3. Distance around an unmarked circle can be measured: Never true

Step-by-step explanation:

When we are say that lines are coplanar, this means that those lines happen to be or lie in the same plane , a flat surface or a 3- dimensional surface.

Co planar lines may or may not intersect with one another.

Parallel lines and Perpendicular lines are coplanar lines because they are found to be in the same plane. One of their differences is Parallel lines do not intersect with one another while Perpendicular lines intersect with one another.

Hence the statements:

Parallel lines and Perpendicular lines are coplanar is ALWAYS TRUE

Distance around an unmarked circle can be measured. This statement is never true

This is because a circle has to be marked in other to be able to measure it's distance properly. A marked circle will have its diameter and the diameter of a circle is also known as the distance around a circle.

which of the following angles is coterminal with 5pi/3? pi/3, 2pi/3, 4pi/3, 5pi/3

Answers

Answer:

5pi/3

Step-by-step explanation:

For two angles to be co-terminal, one must differ from the other by a multiple of 2pi.

The angle of consideration is 5pi/3

Let us consider the options one by one and see if they differ from the angle of consideration by a multiple of 2pi.

5pi/3 - pi/3 = 4pi/3

5pi/3 - 2pi/3 = 3pi/3 = pi

5pi/3 - 4pi/3 = pi/3

5pi/3 - 5pi/3 = 0 = 0(2pi)

5pi/3 is co-terminal with itself

What is the slope of a line perpendicular to the line whose equation is
x - 5y = -10. Fully reduce your answer

Answers

Answer:

The slope or incline is -5

Step-by-step explanation:

rewrite to get the form

y = ...

x - 5y = -10

- 5y = -10 -x

divide left and right if the = sign by -5 gives:

(-5/-5)y = (-1/-5)x + (-10/-5)

y = 1/5x +2

So the incline is 1/5

a perpendicular line has an incline of -1 *5/1 = -5

The slope or incline is -5

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