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Ian Uses The Rule Add 1/2 Then Multiply By 2 Starting From 0

Answer:

It would be the fourth one

Step-by-step explanation:

Answer:

I don't have the right calculator but if you type sin-1(11/60) it'll give you the answer

Answer:

Step-by-step explanation:

Answer:

y is 107° and z is 36°

Step-by-step explanation:

73° and y are supplementary angles so they add up to 180°

Answer:

y = 107

z = 36

Step-by-step explanation:

We are given that line o is parallel to line m, and we can notice line k is a transversal through them both. Using same side interior angles, we can say that:

y + 73 = 180

and

y = 107

Next, using vertical angles, we can say that:

5z - 73 = y

We already have y = 107, so we can substitute that in:

5z - 73 = 107

5z = 180

z = 36

Answer:

25.13

Step-by-step explanation:

C = 2πr

C = 2π(4)

C = 25.13

Hope this helps!

Answer:

Step-by-step explanation:

Was the latter half of this function, -64 / 2x + 14, meant to be:

-64 / 2x              +              14, or

-64 / (2x + 14)?

In the first case the vertical asymptote is x = 0.

In the second, the vertical asymptote is the root of 2x + 14, or x = -7

Use parentheses in problems such as this one, to eliminate ambiguity.

Answer:

(20, -2)

Step-by-step explanation:

Given the coordinate vectors p=(4,3) and q=(-2,7),

4p - 2q  = 4(4, 3)- 2(-2, 7)

4p - 2q  = (16, 12) - (-4, 14)

4p - 2q  = (16+4, 12-14)

4p - 2q  =(20, -2)

hence the required vector is (20, -2)

Answer:

The answer is: u-3>-6

This is because 10-3=7 and 7>-6

Step-by-step explanation:

Consider LHS

[tex] \cos(x) + \sin(x) \tan(x) = \sec(x) [/tex]

Apply quotient identies

[tex] \cos(x) + \sin(x) \times \frac{ \sin(x) }{ \cos(x) } = \sec(x) [/tex]

Multiply the fraction and sine.

[tex] \cos(x) + \frac{ \sin {}^{2} (x) }{ \cos(x) } = \sec(x) [/tex]

Make cos x a fraction with cos x as it denominator.

[tex] \cos(x) \times \cos(x) = \cos {}^{2} (x) [/tex]

so

[tex] \frac{ \cos {}^{2} (x) }{ \cos(x) } + \frac{ \sin {}^{2} (x) }{ \cos(x) } = \sec(x) [/tex]

Pythagorean Identity tells us sin squared and cos squared equals 1 so

[tex] \frac{1}{ \cos(x) } = \sec(x) [/tex]

Apply reciprocal identity.

[tex] \sec(x) = \sec(x) [/tex]

Answer:

The supplementary angle is

153°.

The complementary angle is

63°.

Step-by-step explanation:

This is very right trust mne

Mark me brainlist

The measure of the supplementary angle and the measure of a complementary angle as follows; The supplementary angle is 153°. The complementary angle is 63°.

Two angles whose sum is 90° are called complementary angles.

Two angles whose sum is 180° are called supplementary angles.

If a straight line is intersected by a line, then there are two angles form on each of the sides of the considered straight line.

Those two-two angles are two pairs of supplementary angles.

That means, if supplementary angles are aligned adjacent to each other,

their exterior sides will make a straight line.

Therefore, The supplementary angle is 153°.

The complementary angle is 63°.

Learn more about complementary angles here:

https://brainly.com/question/2882938

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Answer:

answer is D I think

Step-by-step explanation:

.............

Answer:[tex]h=\sqrt{96}in.[/tex]

Step-by-step explanation:

.

Answer:

0.6832

Step-by-step explanation:

Given :

Mean, m = 52

Standard deviation, s = 7

-1.2 standard deviation of average = 57 - 1.2(7) = 57 - 8.4 = 48.6

2 standard deviations of average = 57 + 2(7) = 57 + 14 = 71

Zscore = (48.6 - 52) / 7 = - 0.486

Zscore = (71 - 52) / 7 = 2.714

P < -0.486) = 0.31348

P < 2.714 = 0.99668

P < 2.714 - P < -0.486 = (0.99668 - 0.31348) = 0.6832

Answer:

B,E

Step-by-step explanation:

(5,0) (5=x, 0=y)

A is false because y = 0

B is true because x=5

c is false because y = 0

D is false because again y = 0

E is true because 5,0 is on the x axis

- Gage Millar, Algebra 2 tutor

Answer:

plz mark brainliest

Answer:12345678910

Step-by-step explanation:

Answer:

A. x= -5

B. x= 8

Step-by-step explanation:

A. 25 - 3x = 40

-3x = 40 - 25

-3x = 15

x= 15/-3

x= -5

B. 2 (x-10) =  -4

x-10 = -4/2

x-10 = -2

x = 8

A. 25 - 3x = 40

         -3x = 40 - 25

               = 15

            -x = 15/3

             x = -5

   Checking

    25 - 3*-5 = 40

    25 + 15 = 40

            40 = 40

       LHS = RHS

B. 2(x-10) = -4

    2x - 20 = -4

            2x = -4 +20

             x = 16/2 = 8

Hope u understand

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Thank You

Answer:

ans = <ebc= 115°

hope this will help

.

.

Answer:

48 1/4 packages

Step-by-step explanation:

Answer:

Yes

Step-by-step explanation:

We can substitute the point (2, 2) into the equation. So, in place of x would be 2 and in place of y would be 2 as well:

y = 6 - 2x

2 = 6 - 2(2)

2 = 6 - 4

2 = 2

Since the above is a true statement, the point (2, 2) must belong to the line y = 6 - 2x

Yes, the line y=6-2x passes through the point (2, 2).

Given that, the line y=6-2x passes through the point (2, 2).

The slope intercept form of a straight line is one of the most common forms used to represent the equation of a line. The slope intercept formula can be used to find the equation of a line when given the slope of the straight line and the y-intercept.

Here, substitute (x, y)=(2, 2) is the given line y=6-2x, we get

2 = 6-2(2)

2 = 2

Since, LHS = RHS

Yes, the line y=6-2x passes through the point (2, 2).

To learn more about the slope intercept form visit:

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Answer:

33

Step-by-step explanation:

3n but n is 11 means 3x11

Answer:

3n = 33 when n = 11

Step-by-step explanation:

n = 11

therefore

3(11)

which means 3 times 11

Answer = 33

Hope this helps!

Answer:

See the three attached images.

Step-by-step explanation:

image1 shows the intersection of b and c:  [tex]b \cap c[/tex]. (green "football")

image2 shows the complement of a (outside a):  [tex]a'[/tex]  (yellow)

image3 shows the intersection of those sets:  [tex]a'\cap (b\cap c)[/tex] (green "football with a bite out of it")   :-)

Answer:

x=0

y= x + 8

Step-by-step explanation:

find the oblique asymptotes using long polynomial divison

Answer:

[tex]\frac{2}{13}[/tex]

Step-by-step explanation:

Since there are 26 students in the class and 6 play basketball, 15 play baseball, and 9 play neither, we need to find the intersection ([tex]\cap[/tex]) of the students who play basketball and the students who play baseball to find the number of students who play both.

Since it would appear that we would have 30 students total if we added up the ones who play basketball, baseball or neither, the intersection will be the difference between this total and the actual number of students in the class (26).

Therefore, the number of students who play both sports is [tex]6+15+9-26=4\:\text{students}[/tex]

Since there are 26 students in the class, the probability of randomly choosing one that plays both sports is:

[tex]\frac{4}{26}=\boxed{\frac{2}{13}}[/tex]

Answer:

18

Step-by-step explanation:

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18

Answer:

144 ounces

Step-by-step explanation:

Answer:

Area of a circle = πr^2 if pi here = 3

then (3 × 81) in^2 = 243 in^2

Hope it helps

Answer:

The area of circle is 254.34 in².

Step-by-step explanation:

Given :

To Find :

Using Formulas :

[tex]\star{\small{\underline{\boxed{\sf{\pink{R = \dfrac{D}{2}}}}}}}[/tex]

[tex]\star{\small{\underline{\boxed{\sf{\pink{Area_{(Circle)} = \pi{r}^{2} }}}}}}[/tex]

Solution :

Here we have given that diameter of circle is 18 in. So, finding the radius of circle :

[tex]\implies{\sf{Radius = \dfrac{D}{2}}}[/tex]

[tex]\implies{\sf{Radius = \dfrac{18}{2}}}[/tex]

[tex]\implies{\sf{Radius = \cancel{\dfrac{18}{2}}}}[/tex]

[tex]\implies{\sf{Radius = 9 \: in}}[/tex]

[tex]\star{\underline{\boxed{\sf{\red{Radius = 9 \: in}}}}}[/tex]

Hence, the radius of circle is 9 in.

[tex]\rule{200}2[/tex]

Now, we know the radius of circle is 9 in. So, finding the area of circle by substituting the values in the formula :

[tex]\implies{\sf{Area_{(Circle)} = \pi{r}^{2}}}[/tex]

[tex]\implies{\sf{Area_{(Circle)} = 3.14\times {(9)}^{2}}}[/tex]

[tex]\implies{\sf{Area_{(Circle)} = 3.14\times {(9 \times 9)}}}[/tex]

[tex]\implies{\sf{Area_{(Circle)} = 3.14\times (81)}}[/tex]

[tex]\implies{\sf{Area_{(Circle)} = \dfrac{314}{100} \times 81}}[/tex]

[tex]\implies{\sf{Area_{(Circle)} = \dfrac{314 \times 81}{100}}}[/tex]

[tex]\implies{\sf{Area_{(Circle)} = \dfrac{25434}{100}}}[/tex]

[tex]\implies{\sf{Area_{(Circle)} = 254.34 \: {in}^{2} }}[/tex]

[tex]{\star{\underline{\boxed{\sf{\red{Area_{(Circle)} = 254.34 \: {in}^{2}}}}}}}[/tex]

Hence, the area of circle is 254.34 in².

[tex]\rule{300}{1.5}[/tex]

Answer:

I think its 132.

The total surface area of the triangular prism is 200 cm².

Surface area = (Perimeter of the base × Length of the prism) + (2 × Base Area)

First, find the height of the prism.

Let h is the height of the prism

Use the pythagoras theorem

then

5² = (6/2)² + h²

5² = 3² + h²

25 = 9 + h²

h² = 25 - 9

h² = 16

h =4

Now apply the surface area formula

total surface area = ( 5 + 5 + 6) 11 + 6×4

                             = 16 × 11 + 24

                             = 176 +24

                             = 200 cm²

Hence the surface area is 200 cm²

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Answer:

 ^^

Step-by-step explanation:

Answer:

You didn't add the range. I'll use (0<x<2π)

cosx = -1/2

x=-cos-¹(1/2)

x= -60°

Cosine is negative in the second and 3rd quadrants

180-x ---- Second quadrant

x+180 ----- 3rd quadrant

So

Our answer

180-(-60)=240° or 4π/3 second quad

180+(-60) = 120° or 2π/3---- 3rd quad