Pls answer ASAP pls bc I’m tryna get my grade up please

Answer:

Let’s substitute in our givens.

(0.002 kg)(700 m/s) + (5 kg)(0 m/s) = vf(0.002 kg + 5 kg)

I assume you are proficient in algebra I, so I will not include the steps to simplify this equation.

Note that I have considered the bullet’s velocity to be in the positive direction,

The answer is vf = 0.280 m/s

Answer:Let’s assume that, after the soccer ball is kicked and moves through its trajectory, it first makes contact with level ground a horizontal distance of 35 meters from where it was kicked. Let’s also assume that we can neglect air resistance. The time, t, that the soccer ball is in the air until it first contacts the ground can be found from the equation h = (1/2)gt^2 which can be rewritten as t = sqrt(2h/g) where h is the vertical distance the ball falls which is the height of the hill since the ball was kicked horizontally, and g is the acceleration of gravity which is 9.8 m/s^2. So t = sqrt(2(22)/9.8) = 2.12 seconds. In that time, the ball travelled 35 meters so its horizontal velocity was 35 meters/2.12 seconds = 16.5 meters/second.

Explanation:

Answer:

pressure = force / area

then pressure = 25 / 5 = "5" N/m^2

solution:

the formula is T = F * r * sin(theta) so just input the numbers and solve it.

Explanation:

Torque is the twisting force that tends to cause rotation. The point where the object rotates is known as the axis of rotation. Mathematically, torque can be written as T = F * r * sin(theta), and it has units of Newton-meters

Answer:

[tex]\huge\boxed{\sf a = 1200\ m/s\²}[/tex]

Explanation:

Given Data:

Initial Velocity = Vi = 40 m/s

Final Velocity = Vf = 80 m/s

Distance = S = 200 m

Required:

Acceleration = a = ?

Formula:

2aS = Vf² - Vi² (THIRD EQUATION OF MOTION)

Solution:

2a (200) = (80)² - (40)²

400a = 6400 - 1600

400a = 4800

Divide 400 to both sides

a = 4800 / 400

a = 1200 m/s²

[tex]\rule[225]{225}{2}[/tex]

Hope this helped!

[tex]\text{Given that,}\\\\\text{Initial velocity,} ~v_0 = 0~ \text{m~s}^{-1}\\\\\text{Time, t = 1.3~sec}\\\\\text{Acceleration, a = 9.1 m s}^{-2}\\\\\\\\\text{Velocity,}\\\\v = v_0 +at\\\\\implies v = 0 + 9.1 \times 1.3 = 11.83~~ \text{m~s}^{-1}[/tex]

Hi there!

Impulse = Change in momentum

I = Δp = mΔv = m(vf - vi)

Where:

m = mass of object (kg)

vf = final velocity (m/s)

vi = initial velocity (m/s)

Begin by converting grams to kilograms:

1 kg = 1000g ⇒ 145g = .145kg

Now, plug in the given values. Remember to assign directions since velocity is a vector. Let the initial direction be positive and the opposite be negative.

I = (.145)(-20 - 17) = -5.365 Ns

The magnitude is the absolute value, so:

|-5.365| = 5.365 Ns

The total distance traveled by the car at the given velocity and time is 900 m.

The given parameters:

The final time of motion of car before coming to rest is calculated as follows;

[tex]v_f = v_0 -at\\\\0 = 20 - 2t\\\\t = 10 \ s[/tex]

The graph of the car's motion is in the image uploaded.

The total distance traveled by the car is calculated as follows;

[tex]total \ distance = A \ + B \ + C\\\\total \ distance = (\frac{1 }{2} \times 20 \times 20) \ + (20 \times 30) \ + (\frac{1}{2}\times 10 \times 20)\\\\total \ distance = 900 \ m[/tex]

Thus, the total distance traveled by the car at the given velocity and time is 900 m.

Learn more about velocity-time graph here: https://brainly.com/question/24874645

Answer:

i don't know but my father i think he can't answer this

Answer:

Your parents or anyone in your ancestry.

Explanation:

Answer:

Explanation:

ASSUMING that the dart is fired horizontally so that gravity potential energy considerations are not needed. Also ignoring friction work.

The spring potential will convert to kinetic.

KE = PS

½mv² = ½kx²

     v = [tex]\sqrt{kx^2/m}[/tex]

     v = [tex]\sqrt{1115(0.05^2)/0.025}[/tex]

     v = 10.55935...

     v = 11 m/s

Answer:

geothermal energy

Explanation:

the energy is obtained from the heat within the surface of earth

Answer:

heat energy

Explanation:

Answer:

1)The position change of almost any manually operated room light switch.

2) Sunlight striking a point on the ground on a partly cloudy and windy day

Explanation:

Answer: The forces of gravity

Explanation:  The consequence of this phenomenon is that every mass exerts a so-called "force of mutual attraction" on every other mass. The attractive force that the celestial bodies exert on other masses by virtue of their total mass is called the force of gravity.

Hope this helps

Answer:

An electric current flows in a loop,powering bulbs or other electric COMPONENTS. The loop is an electric circuit. A circuit is made up of various components linked together by wires. The current is driven around the circuit by a power source, such as a BATTERY.

Voltage: is the energy given to each unit of charge that flows in a circuit

Current: is the amount of electric charge flowing past a point in a circuit each second

Wattage: is the amount of electrical energy a circuit uses each second

Answer:

magnetic force.

Explanation:bc it makes sense, and can i please get brainliest answer i never asked. its ok if you say no. have a great day <3.

Answer:

An orbit of a spacecraft from which the spacecraft or another vehicle may be launched on a new trajectory.

Answer:

The frictional force producing this deceleration would have a magnitude of [tex]4\; \rm N[/tex].

Explanation:

The velocity of this object changed by [tex]\Delta v = (-10\; \rm m\cdot s^{-1})[/tex] in [tex]\Delta t = 5\; \rm s[/tex]. The acceleration of this object would be:

[tex]\begin{aligned}a &= \frac{\Delta v}{\Delta t} \\ &= \frac{-10\; \rm m\cdot s^{-1}}{5\; \rm s} = -2\; \rm m\cdot s^{-2}\end{aligned}[/tex].

Let [tex]m[/tex] denote the mass of this object. By Newton's Second Law of Motion, the net force on this object would be:

[tex]\begin{aligned}F &= m \, a \\ &= 2\; \rm kg \times (-2\; \rm m\cdot s^{-2}) \\ &= -4\; \rm N\end{aligned}[/tex].

([tex]1\; {\rm kg \cdot m \cdot s^{-2} = 1\; {\rm N}[/tex].)

If the floor is level, friction would be the only unbalanced force on this object. Thus, the magnitude of the frictional force on this object would also be [tex]4\; {\rm N}[/tex], same as the magnitude of the net force on this object.

Answer:

this is the answer

Explanation:

hope it's clear

pls Mark me as the brainliest pls

Answer:

Diffusion in gases is quick because the particles in a gas move quickly. It happens even faster in hot gases because the particles of gas move faster.

Answer:

Speed of waves on the rope is 21 m/s

Explanation:

Length of the rope (l) = 5.0 m

Mass of the rope (m) = 0.52 kg

Tension in the rope (T) = 46 N

Formula of speed of waves on the rope:

[tex] \bold{v = \sqrt{\dfrac{T}{\mu}}} [/tex]

[tex] \mu [/tex] = Mass per unit length of the rope (m/l)

By substituting the values in the formula we get:

[tex] \implies \rm v = \sqrt{\dfrac{T}{ \dfrac{m}{l} }} \\ \\ \implies \rm v = \sqrt{\dfrac{Tl}{m}} \\ \\ \implies \rm v = \sqrt{ \dfrac{46 \times 5}{0.52} } \\ \\ \implies \rm v = \sqrt{ \dfrac{230}{0.52} } \\ \\ \implies \rm v = \sqrt{442.3} \\ \\ \implies \rm v = 21 \: m {s}^{ - 1} [/tex]

Speed of waves on the rope (v) = 21 m/s

Answer:

Explanation:

I will ASSUME this means torque about the dot.

3) 20(3) + 10(6) - 30(4) = 0 N•m

4) 10(0.5) - 6sin45(1) = -0.7573593... or about 0.76 N•m CCW

5) 25(3) - 40sin30(4) = -5 N•m or 5 N•m CCW

6) 15(3) - 12(2) - 10sin45(6) = -21.4264068... or about 21 N•m CCW

Answer:

Explanation:

momentum is mass times velocity

p = mv

so take the momentum of the truck in question 17 and divide by the mass of this car

v = p/m = p / 1400

Answer:

Essentially all of it

Explanation:

The potential energy was

PE = mgh = 6.36(9.81)(2.05) = 127.90278 = 128 J

ignoring air resistance, this PE converts to KE

With no rebound final velocity is zero, so Kinetic energy lost = 128 J

answer = 6n to the right

Explanation:

2n plus 4n equals 6n

since 6n is more than 5n it goes 6n to the right

Answer:

Explanation:

The balloon would require a time of

t = d/v = 13.5/ (23.6cos38) = 0.7259...s

to travel the horizontal distance.

the vertical position relative to the throw point at that time is

h = 0 + (23.6sin38)(0.7259) + ½(-9.8)(0.7259²)

h = 7.9652...

so as long as the adjacent building is at least 8.0 m higher than the student position, the balloon is in the air for 0.726 s.

If the building is shorter than 8.0 m above the student, the balloon will land on the building roof and will be in the air for a longer period of time

Hi there!

In this instance, the object's centripetal force is provided by the horizontal component of the tension, so:

Tsinθ = mv²/r

**We use sine because in this situation, the angle is with the vertical**

We can plug in the known values for tension and theta:

60sin(60) = mv²/r

51.96 = mv²/r

The radius is equivalent to the sine of the string in respect to theta:

sin(60) = O/H = r/L

2sin(60) = 1.732 m

Now, solve for the velocity:

51.96 = mv²/r

51.96r / m = v²

51.96(1.732)/.400 = v²

v² = 225

v = 15 m/s