please hurry i’ll give you 15 points

Please Hurry Ill Give You 15 Points

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Answer 1

Answer:

measures, dissolves, liquid, carbon dioxide, evaporates, water vapor, mold, decompose


Related Questions

For three control stations,there should be how many start buttons in parallel with the suxiliary contact

Answers

The three load contacts connected between the three-phase power line and the motor close to connect the motor to the line. The normally open auxiliary contact connected in parallel with the two Start buttons closes to maintain the circuit to M coil when the Start button is released.

A reservoir is 1 km wide and 10 km long and has an average depth of 100m. Every hour, 0.1% of the reservoir's volume drops through a vertical height of 100 m and passes through turbines to produce electricity with an efficiency of 92%. What is the electrical power output of this facility?

Answers

Answer:

250.7mw

Explanation:

Volume of the reservoir = lwh

Length of reservoir = 10km

Width of reservoir = 1km

Height = 100m

Volume = 10x10³x10³x100

= 10⁹m³

Next we find the volume flow rate

= 0.1/100x10⁹x1/3600

= 277.78m³/s

To get the electrical power output developed by the turbine with 92 percent efficiency

= 0.92x1000x9.81x277.78x100

= 250.7MW

A continuous function y = ƒ(x) is known to be negative at x = 0 and positive at x = 1. Why does the equation ƒ(x) = 0 have at least one solution between x = 0 and x = 1? Illustrate with a sketch

Answers

Answer:

69

Explanation:

69420=420659782

fjkdod

A ramjet operates by taking in air at the inlet, providing fuel for combustion, and exhausting the hot air through the exit. Th e mass fl ow at the inlet and outlet of the ramjet is 60 kg/s (the mass fl ow rate of fuel is negligible). Th e inlet velocity is 225 m/s. Th e density of the gases at the exit is 0.25 kg/m3 , and the exit area is 0.5 m2 . Calculate the thr

Answers

Answer:

15300 N

Explanation:

[tex]\rho_i[/tex] = Density of air at inlet

[tex]\dfrac{m}{t}[/tex] = Mass flow rate = 60 kg/s

[tex]v_i[/tex] = Inlet velocity = 225 m/s

[tex]\rho_o[/tex] = Density of gas at outlet = [tex]0.25\ \text{kg/m}^3[/tex]

[tex]A_i[/tex] = Inlet area

[tex]A_o[/tex] = Outlet area = [tex]0.5\ \text{m}^2[/tex]

Since mass flow rate is the same in the inlet and outlet we have

[tex]\rho_iv_iA_i=\rho_ov_oA_o\\\Rightarrow v_o=\dfrac{\dfrac{m}{t}}{\rho_oA_o}\\\Rightarrow v_o=\dfrac{60}{0.25\times 0.5}\\\Rightarrow v_o=480\ \text{m/s}[/tex]

Thrust is given by

[tex]F=\dfrac{m}{t}(v_o-v_i)\\\Rightarrow F=60\times (480-225)\\\Rightarrow F=15300\ \text{N}[/tex]

The thrust generated is 15300 N.

How do I answer all the questions on this page?

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Answer:

Create a google docs copy everything and paste hope this helps! :)

Explanation:

CAD(computer-aided design) software and is used in__________and __________that show how to construct an object. Technical drawings show in detail how the pieces of something relate to each other.

Answers

Answer:

Plans; blueprints.

Explanation:

In Engineering, it is a common and standard practice to use drawings and models in the design and development of various tools or systems that are being used for proffering solutions to specific problems in different fields such as engineering, medicine, telecommunications and industries.

Hence, a design engineer make use of drawings such as pictorial drawings, sketches, or technical drawing to communicate ideas about a design to others, to record and retain informations (ideas) so that they're not forgotten and to analyze how different components of a design work together.

Technical drawing is mainly implemented with CAD (computer-aided design) software and is typically used in plans and blueprints that show how to construct an object.

Additionally, technical drawings show in detail how the pieces of something (object) relate to each other, as well as accurately illustrating the actual (true) shape and size of an object in the design and development process.

Pyramid is a type of ___________ structure.

Answers

it is a triangle structure

Answer:

Massive or linteled

Explanation:

Pyramid is a type of massive or linteled structure.

These structures do no have not much internal spaces and they are huge edifices.

A pyramid is a solid body with outer triangular faces that converges on top. To construct a pyramid, large amounts of materials are usually involved. Pyramids were more prominent in times past before this present civilization.

An annealed copper strip of 228 mm wide and 25 mm thick being rolled to a thickness of 20 mm, in one pass. The roll radius is 300 mm, and the rolls rotate at 100 rpm. Calculate the roll force and the power required in this operation

Answers

Answer:

The roll force is 1.59 MN

The power required in this operation is 644.96 kW

Explanation:

Given;

width of the annealed copper, w = 228 m

thickness of the copper, h₀ = 25 mm

final thickness, hf = 20 mm

roll radius, R = 300 mm

The roll force is given by;

[tex]F = LwY_{avg}[/tex]

where;

w is the width of the annealed copper

[tex]Y_{avg}[/tex] is average true stress of the strip in the roll gap

L is length of arc in contact, and for frictionless situation it is given as;

[tex]L = \sqrt{R(h_o-h_f)} \\\\L = \sqrt{300(25-20)}\\\\L = 38.73 \ mm[/tex]

Now, determine the average true stress, [tex]Y_{avg}[/tex], for the annealed copper;

The absolute value of the true strain, ε = ln(25/20)

ε = 0.223

from true stress vs true strain graph; at true strain of 0.223, the true stress is 280 MPa.

Then, the average true stress = ¹/₂(280 MPa.) = 180 MPa

Finally determine the roll force;

[tex]F = LwY_{avg}[/tex]

[tex]F = (\frac{38.73 }{1000})(\frac{228}{1000})*180 \ MPa\\\\F = 1.59 \ MN[/tex]

The power required in this operation is given by;

[tex]P = \frac{2\pi FLN}{60}\\\\P = \frac{2\pi (1.59*10^6)(0.03873)(100)}{60}\\\\P = 644955.2 \ W\\\\P = 644.96 \ kW[/tex]

Of the core elements of successful safety and health programs, Management Leadership, Worker Participation, and what else relate to individuals' roles?

Answers

Answer:

Education and training I did the TEST and got it right.

Of the core elements of successful safety and health programs, the other one aside the given two that relates to individual roles is;

Education and Training Program.

According to OSHA(Occupational Safety and Health Administration), there are 7 core elements of an effective safety and health program.

These 7 core elements are namely;

1) Management Leadership.

2) Worker Participation.

3) Hazard Identification & Assessment.

4) Hazard Prevention & Control.

5) Education & Training Program.

6) Evaluation & Improvement.

7) Management of Contractors / Staffed Employees.

Now, we have been given 2 of the 7 which are Management leadership and

worker participation. However, we are told to find another one that relates

to individual roles. The only other one that is individual specific is Education

and Training program because it is the responsibility of every staff from top

to bottom to know all about safety.

Read more at; https://brainly.com/question/21555575

Expert Review is done by end users.

Answers

Answer:nononononono

Explanation:

Do you think we would have a use for a technology that would mimic the flight of a hummingbird?

Answers

Answer:

I think we would.

Explanation:

Only if u invent it.

answer

i don't think so

but it will take a lot of thinking if it is

possible

If a weld is laying into a joint with a concave weld contour with undercutting issues, what might be the cause?

A. Spatter build up on the gun parts

B. Not enough gel applied to the top

C. Base metal in not cooled properly

D. Voltage of the machine is set too high

Answers

Answer:bbbb

Explanation:

An automotive fuel cell consumes fuel at a rate of 28m3/h and delivers 80kW of power to the wheels. If the hydrogen fuel has a heating value of 141,790 kJ/kg and a density of 0.0899 kg/m3, determine the efficiency of this fuel cell.

Answers

Answer:

The efficiency of this fuel cell is 80.69 percent.

Explanation:

From Physics we define the efficiency of the automotive fuel cell ([tex]\eta[/tex]), dimensionless, as:

[tex]\eta = \frac{\dot W_{out}}{\dot W_{in}}[/tex] (Eq. 1)

Where:

[tex]\dot W_{in}[/tex] - Maximum power possible from hydrogen flow, measured in kilowatts.

[tex]\dot W_{out}[/tex] - Output power of the automotive fuel cell, measured in kilowatts.

The maximum power possible from hydrogen flow is:

[tex]\dot W_{in} = \dot V\cdot \rho \cdot L_{c}[/tex] (Eq. 2)

Where:

[tex]\dot V[/tex] - Volume flow rate, measured in cubic meters per second.

[tex]\rho[/tex] - Density of hydrogen, measured in kilograms per cubic meter.

[tex]L_{c}[/tex] - Heating value of hydrogen, measured in kilojoules per kilogram.

If we know that [tex]\dot V = \frac{28}{3600}\,\frac{m^{3}}{s}[/tex], [tex]\rho = 0.0899\,\frac{kg}{m^{3}}[/tex], [tex]L_{c} = 141790\,\frac{kJ}{kg}[/tex] and [tex]\dot W_{out} = 80\,kW[/tex], then the efficiency of this fuel cell is:

(Eq. 1)

[tex]\dot W_{in} = \left(\frac{28}{3600}\,\frac{m^{3}}{s}\right)\cdot \left(0.0899\,\frac{kg}{m^{3}} \right)\cdot \left(141790\,\frac{kJ}{kg} \right)[/tex]

[tex]\dot W_{in} = 99.143\,kW[/tex]

(Eq. 2)

[tex]\eta = \frac{80\,kW}{99.143\,kW}[/tex]

[tex]\eta = 0.807[/tex]

The efficiency of this fuel cell is 80.69 percent.

Phosphorous is added to make an n-type silicon semiconductor with an electrical conductivity of 1.75 (Ωm)-1 . Calculate the necessary number of charge carriers required

Answers

Answer:

The necessary number of electron charge carriers required is:

8.1019 × 10¹⁹ electrons/m³

Explanation:

The necessary number of charge carriers required can be determined from the resistivity. Given that, the phosphorus  make an n-type of silicon semiconductor;

Resistivity [tex]\rho = \dfrac{1}{\sigma}[/tex]

[tex]\rho = \dfrac{1}{q \mu _n n_n}[/tex]

where;

The number of electron on the charge carriers [tex]n_n[/tex] is unknown??

The charge of the electron q = [tex]1.6 \times 10^{-19} \ C[/tex]

The electron mobility  [tex]\mu_n[/tex] = 0.135 m²/V.s

The electrical conductivity [tex]\sigma[/tex] = 1.75 (Ωm)⁻¹

Making  [tex]n_n[/tex]  the subject from the above equation:

Then;

 [tex]n_n = \dfrac{\sigma }{q \mu_n}[/tex]

[tex]n_n = \dfrac{1.75 \ \Omega .m^{-1} }{1.6 \times 10^{-19} \times 0.135 \ m^2/V.s}[/tex]

[tex]n_n =8.1019 \times 10^{19}[/tex] electrons/m³

Thus; the necessary number of electron charge carriers required is:

8.1019 × 10¹⁹ electrons/m³

PLEASE ANSWER SOON

In a science lab, Cash mixes two clear liquids together in a beaker. Bubbles are produced, and a white solid forms and settles to the bottom. Which statement below describes what happened?


a

A physical change occurred, a gas and precipitate was produced

b

A physical change occurred, only a gas was produced

c

A chemical change occurred, only a gas was produced

d

A chemical change occurred, a gas and precipitate was produced

Answers

Answer:

I think it is D

Explanation:

I did a couple mins of research on this topic but there is no clear line that separates a physical and chemical reaction, so do with that as you will. i hope I somewhat helped.

Assume that Randy’s photocopying Service charges $.10 per photocopy. If fixed costs are

$27000 a year and variable costs are $0.04 per copy.

1. How Randy can compute his breakeven point? Show the result in graph.

2. How many photocopies are required to earn $ 500 profit?

3. Identify the safety margin at breakeven point.

Answers

Answer:

1) 739 copies (739.7260273972603).

2) 5000 copies.

Explanation:

27000/365 = 73.97260273972603 (Their daily wins). How much times $.10 is equal to 73.97260273972603?

I used a two step equation to get it.

0.10 * x = 73.97260273972603/0.10     = /0.10         x = 739.7260273972603

They need to sell 739.7260273972603 copies a day to get 27000$ a year.

an equation (y = mx+b) can be

y = 739.7260273972603x

To earn a 500$ profit we need to do the same two-step equation but instead of 73.97260273972603 use 500.

0.10 * x = 500/0.10     = /0.10         x = 5000

5000 copies needs to be sold to get a 500$ profit.

The last question I don't understand but I hope those 2 questions helped

pls help!!! will give brainly!!!
What is the difference between a short-term goal and a long-term goal? Give an example of each.

Answers

Short-term goals are planned for the near future while long-term goals will take longer to complete. An example of a short-term goal is trying to get into a certain college. A long-term goal is wanting to have a big family.

Convert 273.15 mL at 166.0 mm of Hg to its new volume at standard pressure.​

Answers

Answer:

(166.0 mm Hg) (273.15 mL) = (760.0 mm Hg) (x)

A function is different from a procedure because a functiondoes not contain a set of instructions.can have only a limited number of steps.returns a value.is mathematical.​

Answers

Answer: A function returns a value and a procedure just executes commands.

Explanation:

Answer:

c - returns a value.

Explanation:

on edge pls mark brainiest

An earth station at latitude 30°S is in communication with an earth station on the same longitude at 30°N, through a geostationary satellite. The satellite longitude is 20° east of the earth stations. Calculate the antenna-look angles for each earth station and the round-trip time, assuming this consists of propagation delay only..

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I have a lot going around here and I’m going so much to sleep in a few days lol I’m not going so I’m scared to sleep lol I’m just messing with you I don’t have to wake up early tomorrow I have a headache I’m so sore and sore sore but sore sore from sore and I’m sore sore and sore sore throat sore sore and sore sore throat sore sore I

1. Drill press size is determined by the largest__

Answers

Drill press size is determined by the largest piece of stock


Your welcome

What cell type has no membrane-bound organelles, has DNA that is found in an area called the
nucleoid, and is very small?
A. Eukaryotic cell
B. Prokaryotic cell
C. Animal cell
D. Plant cell

Answers

Prokaryotic cell is the correct answer. A good way to remember is Eukaryotic cell is a you cell since that is the kind of cell that makes up your body

Answer:

Prokaryotic cell

Explanation:

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