please helppp ill give brainliest the question is attached below

Answer:

12) 1/8 inch =  0.125 inch

    = 0.003175 m

    = 3.175 x 10-3 m

    = 0.3175 cm

13) 2 is rational and  π  is  irrattional.  π   is approximately   3.14 and is the bigger of two

14) C= 40,005,306.33 m

  = 4.0005 x 107 m

15)  12,615,800,000

= 1.26158 x 1010

=126158 x 105

16) Let's take speed of ant as 1Km/h=1000m/h. Then time 1666.875 days

Step-by-step explanation:

Answer:

a = 2, b = 0 , x = [tex]\frac{1}{2}[/tex]

Step-by-step explanation:

Given that x = 0 and x = 2 are zeros of p(x) , then

p(0) = 0 and p(2) = 0

p(0) = 2(0)³ - 5(0)² + a(0) + b = 0 , that is

0 - 0+ 0 + b = 0, then b = 0

p(2) = 2(2)³ - 5(2)² + 2a + b = 0 , that is

16 - 20 + 2a + 0 = 0

- 4 + 2a = 0 ( add 4 to both sides )

2a = 4 ( divide both sides by 2 )

a = 2

Then

p(x) = 2x³ - 5x² + 2x ← factor out x from each term

      = x(2x² - 5x + 2)

      = x(2x - 1)(x - 2)

To find zeros equate p(x) to zero

x(2x - 1)(x - 2) = 0

Equate each factor to zero and solve for x

x = 0

x - 2 = 0 ⇒ x = 2

These are the 2 zeros already known (given)

2x - 1 = 0 ⇒ 2x = 1 ⇒ x = [tex]\frac{1}{2}[/tex] ← third zero of p(x)

Answer:

318

Step-by-step explanation:

Bob=x

Marc=x+30

Donny=3(x+30)

x+x+30+3x+90=500

5x=500-120

5x=380

x=76

Bob has x = 76

Marc has x+30=106

Donny has 3*112=318

318+106+76=500

Answer:

The y-values repeat in various functions (for example: quadratic function: y=x²; y=4 for x=2 and for x=-2)  

Answer:

Step-by-step explanation:

y = - 5x + 30  and  x = 10  ⇒  y = -5•10 + 30 = -50 + 30 = -20

x = 10  and y = -20   ⇒  (10, -20)

Answer:

Its B. (10, –20)

Step-by-step explanation:

I just took the quiz on edge

Answer:

The equation which will give the value of x when solved is C. x + 20 = 120

x=100

Step-by-step explanation:

Total distance=120 miles

Distance covered=x miles

Distance remaining=20 miles

The equation is

Total distance=Distance covered + distance remaining

120 miles= x miles + 20 miles

120 miles - 20 miles = x miles

100 miles =x miles

Check:

Total distance=Distance covered + distance remaining

120 miles = 100 miles + 20 miles

120 miles =120 miles

The equation which will give the value of x when solved is C. x+20=120

Answer:

-38

Step-by-step explanation:

7-5(3)^2

PEMDAS

Since there are no parentheses to execute

Exponents next

7-5(3)^2

7-5*9

Multiply and divide next

7 - 45

-38

Answer:

r=-11

Step-by-step explanation:

7r+2=5(r-4)

7r+2=5r-20

2r=-22

r=-11

Answer:

216.

Step-by-step explanation:

These numbers are perfect cubes starting with 2^3.

2^3, 3^3,  4^3,  5^3 so the next one is 6^3, which is 216.

Answer: 1 U.S.dollar  = 0.85 euro.

1 euro = 1.18 dollars.

Step-by-step explanation:

The given equation: [tex]E=\dfrac{17}{20}D[/tex]

, where 'E' is the amount of euros that has the same value as 'D' U.S. Dollars.

At D= 1,

[tex]E=\dfrac{17}{20}=0.85\text{ euro}[/tex]

i.e. 1 U.S.dollar  = 0.85 euro.

At E= 1 , we have

[tex]1=\dfrac{17}{20}D\\\\\Rightarrow\ D= 20/17\approx1.18\text{ dollars}[/tex]

Hence, 1 euro = 1.18 dollars.

Answer:

AB = 72°

Step-by-step explanation:

The inscribed angle ADC is half the measure of its intercepted arc, thus

56° = [tex]\frac{1}{2}[/tex] ( m ABC ) ← multiply both sides by 2

112° = ABC

ABC = AB + BC = AB + 40, so

AB + 40 = 112 ( subtract 40 from both sides )

AB = 72°

Try this

(x^2 + x - 12) + (x^2 - 8x + 16)

2y - 1

√36

i wanted to help you! :)

Answer:

[tex]\frac{3}{3}[/tex] = 1   (everything basically cancels)

Step-by-step explanation:

Answer:

Step-by-step explanation:

A "difference" indicates subtraction is being used. The difference between these 2 numbers is found the same way we find the distance between 2 points on a number line. Since both the difference and the distance have to be positive numbers, the formula to find it is

|a - b| which is the absolute value of a - b.

If a = -52 and b = -79:

| -52 - (-79) | = | -52 + 79 | = 27 OR

If a = -79 and b = -52:

| -79 - (-52) | = | -79 + 52 | = | -27 | = 27

The probability that neither of them draws the Leeks card is P = 4/6 = 0.667

Here we can assume that all the cards have the same probability of being randomly drawn.

The cards are:

So we have 6 cards. We want to find the probability that neither contestant draws the "Leeks" card.

Sammy draws first, the probability of drawing the Leeks card will be equal to the quotient between the number of Leeks cards (one) and the total number of cards (6).

Then the probability of drawing the leeks card is p = 1/6

This means that the probability of NOT drawing the leeks card is:

q = 1 - 1/6 = 5/6.

Now draws Hanna, now there are 5 cards in the deck (because one was already drawn). With the same approach as before, the probability of drawing the Leeks card is p = 1/5, then the probability of NOT drawing the card is:

q = 1 - 1/5 = 4/5.

The joint probability (this is, the probability of both of these events to happen together) is just the product of the individual probabilities.

Then the probability that neither of them draws the Leeks card is:

P = (4/5)*(5/6) = 4/6 = 0.667

If you want to learn more about probability, you can read:

https://brainly.com/question/24349426

Answer:

1-10, -3, 2, 7

im sorry if i give a wrong answer

Answer: P≈2.4×10 power5

Step-by-step Explanation: P=4a=4·60025=2.401×10 power5

Answer:

[tex]\huge \boxed{\mathrm{980 \ m}}[/tex]

Step-by-step explanation:

The formula for the area of a square is:

[tex]A=s^2[/tex]

The area is given as 60025 m².

We need to find the length of each side.

[tex]60025=s^2[/tex]

Take the square root of both sides.

[tex]s=245[/tex]

The side length is 245 m.

The formula for the perimeter of a square is:

[tex]P=4s[/tex]

Plug in the value for the side length.

[tex]P=4(245)[/tex]

[tex]P=980[/tex]

The perimeter of the field is 980 m.

Answer:

-3

Step-by-step explanation:

-5 = -8 - (- 3)

Step-by-step explanation:

It is read thus Y^3+X^2-7

The equation form from the given statement would be Y^3 + X^2 - 7.

You can represent the unknown amounts by the use of variables. Follow whatever the description is and convert it one by one mathematically.

For example if it is asked to increase some item by 4 , then you can add 4 in that item to increase it by 4.

We have been given a statement as;

"A number y cubed plus x squared decreased by 7".

So, the equation form would be

Y^3 + X^2 - 7

Learn more about expression here;

https://brainly.com/question/14083225

#SPJ2

The complete question is

"A number y cubed plus x squared decreased by 7". write the expression.

Answer:

Step-by-step explanation:

It should be:

Step-by-step explanation:

denominator

add numerator

Answer:

F. 1/2

Step-by-step explanation:

If the ratio of team assistants to players are 1/6 and there are 36 players that means that there are 6 team assistants. If we do the ratio of coaches to assistant that would be 3/6 or F. 1/2

Answer:

13. [tex]\frac{\sqrt[5]{x^4} }{x}[/tex].

14. [tex]v = \pm3\sqrt{5}[/tex]

15. 2.

Step-by-step explanation:

13. [tex]x^{1/5} * x^{-2/5}[/tex]

= [tex]x^{1/5 + (-2/5)}[/tex]

= [tex]x^{1/5 - 2/5}[/tex]

= [tex]x^{-1/5}[/tex]

= [tex]\frac{1}{x^{1/5}}[/tex]

= [tex]\frac{x^{4/5}}{x^{1/5 + 4/5}}[/tex]

= [tex]\frac{x^{4/5}}{x}[/tex]

= [tex]\frac{\sqrt[5]{x^4} }{x}[/tex].

14. [tex]v^2 - 45 = 0[/tex]

[tex]v^2 = 45[/tex]

[tex]\sqrt{v^2} = \pm\sqrt{45}[/tex]

[tex]\sqrt{v^2} = \pm\sqrt{3^2 * 5}[/tex]

[tex]v = \pm3\sqrt{5}[/tex].

15. [tex]\sqrt[3]{2} * \sqrt[3]{4}[/tex]

= [tex]\sqrt[3]{2 * 4}[/tex]

= [tex]\sqrt[3]{2 * 2 * 2}[/tex]

= [tex]\sqrt[3]{2 ^3}[/tex]

= 2.

Hope this helps!

Answer:

62

Step-by-step explanation:

add 24 to the smaller number to get the greater one

Answer:

62

Step-by-step explanation:

let, the greater number be 'x' and smaller number be 'y'

x-y=24 i.e. x-38=24

or, X=24+38

X= 62

Answer:

The lower quartile is 23.4

Step-by-step explanation:

The given data are;

47.2, 33.8, 43, 62, 5.8, 9, 61.4, 30.8, 68.2, 51.6, 13.2, 17.4, 64.2, 50.6, 29.4, 40.4

Rearranging the data, we have;

5.8, 9, 13.2, 17.4, 29.4, 30.8, 33.8, 40.4, 43, 47.2, 50.6, 51.6, 61.4, 62, 64.2, 68.2

The lower quartile, Q₁, is the (n + 1)/4 th term which is (16 +1)/4 = 4.25th term

However since we have an even set of numbers, we place a separator at the middle and we look for the median of the left half as follows

5.8, 9, 13.2, 17.4, 29.4, 30.8, 33.8, 40.4║ 43, 47.2, 50.6, 51.6, 61.4, 62, 64.2, 68.2

We have two numbers (17.4 + 29.4) at the median of the left set of numbers, we find the average of the two numbers to get the lower quartile

The lower quartile is therefore = (17.4 + 29.4)/2 = 23.4.

Answer:

2520

Step-by-step explanation:

The n th term of an AP is

[tex]a_{n}[/tex] = a₁ + (n - 1)d

where a₁ is the first term and d the common difference.

To find the number of terms given [tex]a_{n}[/tex] = - 10 , d = - 2 and a₁ = 100, then

100 - 2(n - 1) = - 10 ( subtract 100 from both sides )

- 2(n - 1) = - 110 ( divide both sides by - 2 )

n - 1 = 55 ( add 1 to both sides )

n = 56 ← number of terms

Given n, a₁ and a₅₆ , then the sun of the terms is

[tex]S_{56}[/tex] = [tex]\frac{n}{2}[/tex] (a₁ + a₅₆ )

      = [tex]\frac{56}{2}[/tex] (100 - 10) = 28 × 90 = 2520

Answer:

( 0,0) and (3,0)

Step-by-step explanation:

y=(2x(x-3))/(x-1)

Set y = 0

0 =(2x(x-3))/(x-1)

Multiply each side by x-1, which makes x not equal to 1

0 =(2x(x-3))

Using the zero product property

2x=0  x-3 =0

x=0   x= 3

The x intercepts are x=0   x= 3

( 0,0) and (3,0)

Answer: Hi!

Row A: 7, 11, 15, 19, 23

Row B: 51, 42, 33, 24, 15

Row C: 4, 8, 16, 32, 64

Row D: 64, 32, 16, 8, 4

(If you notice, Row C and Row D are just swapped in order!)

Hope this helps!

Hi there! Hopefully this helps!

--------------------------------------------------------------------------------------------------------------

A's rule, add 4: 7, 11, 15, 19, 23

B's rule, Subtract 9: 51, 42, 33, 24, 15

C's rule, Multiply by 2: 4, 8, 16, 32, 64

D's rule, Divide by 2: 64, 32, 16, 8, 4

Answer:

1. x²-2x+15

This can't be factored, I've tried multiple ways now, but it just can't be factored.

2. y²-19y+90​

Let's factor y^2−19y+90

y^2−19y+90

The middle number is -19 and the last number is 90.

Factoring means we want something like

(y+_)(y+_)

Which numbers go in the blanks?

We need two numbers that...

   Add together to get -19

   Multiply together to get 90

Can you think of the two numbers?

Try -9 and -10:

   -9+-10 = -19

   -9*-10 = 90

Fill in the blanks in

(y+_)(y+_)

with -9 and -10 to get...

(y-9)(y-10)

Answer:

(y−9) (y−10)

Answer:

4 and 16 units²

Step-by-step explanation:

The perimeter of a square of side s = 4s and area = s² , equating gives

s² = 4s ( subtract 4s from both sides )

s² - 4s = 0 ( factor out s from each term on the left )

s(s - 4) = 0

Equate each factor to zero and solve for s

s = 0

s - 4 = 0 ⇒ s = 4

However, s > 0, thus s= 4

That is side = 4 units and area = 4² = 16 units²

Step-by-step explanation:

Hi there!

Please see the answer in the picture.

Hope it helps!

1. Approach

One is given a trigonometric equation with and one is asked to prove that it is true. Using the attached image, combined with the knowledge of trigonometry, one can evaluate each trigonometric function. Then one can simplify each ratio to solve. To yield the most accurate result, one has to each of the ratios in a fractional form, rather than simplifying it into a decimal form. Remember the right angle trigonometric ratios, these ratios describe the relationship between the sides and angles in a right triangle. Such ratios are as follows,

[tex]sin(\theta)=\frac{opposite}{hypotenuse}\\\\cos(\theta)=\frac{adjacent}{hypotenuse}\\\\tan(\theta)=\frac{opposite}{adjacent}\\\\csc(\theta)=\frac{hypotenuse}{opposite}\\\\sec(\theta)=\frac{hypotenuse}{adjacent}\\\\cot(\theta)=\frac{adjacent}{opposite}[/tex]

Please note that the terms (opposite) and (adjacent) are relative to the angle uses in the ratio, however the term (hypotenuse) refers to the side opposite the right angle, this side never changes its name. Use these ratios to evaluate the trigonometric functions. Then simplify to prove the identity.

2. Problem (9)

[tex]\frac{sin(60)+cos(30)}{1+sin(30)+cos(60)}=sin(60)[/tex]

As per the attached image, the following statements regarding the value of each ratio can be made:

[tex]sin(60)=\frac{\sqrt{3}}{2}\\\\cos(30)=\frac{\sqrt{3}}{2}\\\\sin(30)=\frac{1}{2}\\\\cos(60)=\frac{1}{2}[/tex]

Substitute,

[tex]\frac{sin(60)+cos(30)}{1+sin(30)+cos(60)}=sin(60)[/tex]

[tex]\frac{\frac{\sqrt{3}}{2}+\frac{\sqrt{3}}{2}}{1+\frac{1}{2}+\frac{1}{2}}=\frac{\sqrt{3}}{2}[/tex]

Simplify,

[tex]\frac{\frac{\sqrt{3}}{2}+\frac{\sqrt{3}}{2}}{1+\frac{1}{2}+\frac{1}{2}}=\frac{\sqrt{3}}{2}[/tex]

[tex]\frac{\frac{2\sqrt{3}}{2}}{1+\frac{1}{2}+\frac{1}{2}}=\frac{\sqrt{3}}{2}[/tex]

[tex]\frac{\frac{2\sqrt{3}}{2}}{1+1}=\frac{\sqrt{3}}{2}[/tex]

[tex]\frac{\sqrt{3}}{1+1}=\frac{\sqrt{3}}{2}[/tex]

[tex]\frac{\sqrt{3}}{2}=\frac{\sqrt{3}}{2}[/tex]

Thus, this equation is true.

2. Problem (10)

Use a similar strategy to evaluate this equation,

[tex]\frac{1-cos(30)}{sin(30)}=\frac{1-cot(60)}{1+cot(60)}[/tex]

Use the attached image to evaluate the ratios.

[tex]cos(30)=\frac{\sqrt{3}}{2}\\\\sin(30)=\frac{1}{2}\\\\cot(60)=\frac{1}{\sqrt{3}}[/tex]

Substitute,

[tex]\frac{1-cos(30)}{sin(30)}=\frac{1-cot(60)}{1+cot(60)}[/tex]

[tex]\frac{1-\frac{\sqrt{3}}{2}}{\frac{1}{2}}=\frac{1-\frac{1}{\sqrt{3}}}{1+\frac{1}{\sqrt{3}}}[/tex]

Simplify,

[tex]\frac{1-\frac{\sqrt{3}}{2}}{\frac{1}{2}}=\frac{1-\frac{1}{\sqrt{3}}}{1+\frac{1}{\sqrt{3}}}[/tex]

[tex]\frac{\frac{2-\sqrt{3}}{2}}{\frac{1}{2}}=\frac{1-\frac{1}{\sqrt{3}}}{1+\frac{1}{\sqrt{3}}}[/tex]

[tex]\frac{\frac{2-\sqrt{3}}{2}}{\frac{1}{2}}=\frac{\frac{\sqrt{3}-1}{\sqrt{3}}}{1+\frac{1}{\sqrt{3}}}[/tex]

[tex]\frac{\frac{2-\sqrt{3}}{2}}{\frac{1}{2}}=\frac{\frac{\sqrt{3}-1}{\sqrt{3}}}{\frac{\sqrt{3}+1}{\sqrt{3}}}[/tex]

[tex]2-\sqrt{3}=\frac{\frac{\sqrt{3}-1}{\sqrt{3}}}{\frac{\sqrt{3}+1}{\sqrt{3}}}[/tex]

[tex]2-\sqrt{3}=\frac{\sqrt{3}-1}{\sqrt{3}}*\frac{\sqrt{3}}{\sqrt{3}+1}}[/tex]

[tex]2-\sqrt{3}=\frac{\sqrt{3}-1}{\sqrt{3}+1}[/tex]

Rationalize the denominator,

[tex]2-\sqrt{3}=\frac{\sqrt{3}-1}{\sqrt{3}+1}[/tex]

[tex]2-\sqrt{3}=\frac{\sqrt{3}-1}{\sqrt{3}+1}*\frac{\sqrt{3}-1}{\sqrt{3}-1}[/tex]

[tex]2-\sqrt{3}=\frac{(\sqrt{3}-1)^2}{3-1}[/tex]

[tex]2-\sqrt{3}=\frac{3-2\sqrt{3}+1}{2}[/tex]

[tex]2-\sqrt{3}=\frac{4-2\sqrt{3}}{2}[/tex]

[tex]2-\sqrt{3}=2-\sqrt{3}[/tex]

Therefore, this equation is also true.