PLEASE HELP!!!!!!!!!!!!!
a. A light wave travels through glass (n=1.5) at an angle of 28°. What angle does it have when
it passes from the glass into water (n = 1.33)?
B. Draw a ray diagram to locate the image of the object below. Write one or two sentences to describe the type of image, it’s size relative to the object, and it’s position with respect to the lens.
C. An object is located 94.0 cm from a concave mirror. The focal length is 34.0 cm. What is the image distance? Is the image real or virtual??
D. An Object is located 65.0 cm from a concave lens. The image distance is -11.8 cm. What is the magnification?
E. For a person who is nearsighted, seeing objects that are far away is difficult. The light from these objects does not get focused far enough back in the eye. Write one or two sentences to identify the type of lens that can be used to correct nearsightedness and describe why it works.
PLEAAAASE HELP MEEE
Answers
Answer:
A. The angle with which the light passes from glass into water is approximately 31.97°
B. The image formed is, real, inverted, and smaller than the object
C. The image distance is 53.2[tex]\overline 6[/tex] cm
The image is real
D. The magnification is approximately 0.182
E. The type of lens required is a concave lens which corrects the focus of a powerful eye lens or a long eyeball
Explanation:
The given parameters for the light wave are;
The refractive index of the glass medium, n₁ = 1.5
The angle of incidence of the light, θ₁ = 28°
The refractive index of water, n₂ = 1.33
A. Let θ₂ represent the angle with which the light passes from glass into water
Snell's law is mathematically stated as follows;
n₁·sin(θ₁) = n₂·sin(θ₂)
According to Snell's law, we have;
1.5 × sin(28°) = 1.33 × sin(θ₂)
sin(θ) = (1.5 × sin(28°))/1.33 = 0.52947920615
∴ θ₂ = arcsin(0.52947920615) ≈ 31.97°
The angle with which the light passes from glass into water, θ₂ ≈ 31.97°
B. Please find attached the drawing of the image created with Microsoft Visio
From the drawing, we have that the image formed is real inverted smaller than the object and between the focus and radius of curvature
C. The location of the object from the mirror, u = 94.0 cm
The focal length of the mirror, f = +34.0 cm
The mirror formula for a concave mirror is given as follows;
[tex]\dfrac{1}{f} = \dfrac{1}{u} + \dfrac{1}{v}[/tex]
Therefore, we have;
[tex]\dfrac{1}{34.0} = \dfrac{1}{94.0} + \dfrac{1}{v}[/tex]
[tex]\dfrac{1}{v} = \dfrac{1}{34.0} - \dfrac{1}{94.0} = \dfrac{15}{799}[/tex]
[tex]\therefore \dfrac{v}{1} = v =\dfrac{799}{15} = 56.2\overline 6[/tex]
The image distance, v = 799/15 = 53.2[tex]\overline 6[/tex] cm
Therefore the image is in front of the mirror, which is a real image
The image is real
D. The given parameters of the object and lens are;
The distance of the object from the lens, u = 65.0 cm
The distance of the image formed from the lens, i = -18 cm
The magnification, M, is given as follows;
[tex]M = \dfrac{-v}{u}[/tex]
Therefore;
[tex]M = \dfrac{-(-11.8)}{65.0} = \dfrac{59}{325} \approx 0.18153846153[/tex]
The magnification, M ≈ 0.182
E. For a person who is near sighted, the light from objects from distant location are almost parallel and are brought to a focus in front of the retina and therefore, they appear blurred
The use of a concave lens is required to correct nearsightedness as it causes the light to appear come from a point before the focus such that the divergent rays of the object refracted through the concave lens comes to a focus at the.
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Answer:
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Explanation:
When two monochromatic light waves of the same wavelength and same amplitude undergo destructive interference, means that the peak of one of the waves coincides with the trough of the other, so the waves "cancel" each other in that point in space.
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Answers
Answer:
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Explanation/ Explanation / Example:
Provided an object traveled 500 meters in 3 minutes , to calculate the average velocity you should take the following steps: Change minutes into seconds (so that the final result would be in meters per second). 3 minutes = 3 * 60 = 180 seconds , Divide the distance by time: velocity = 500 / 180 = 2.77 m/s .
If this doesn't help let me know!
If the mass of each ball is 12 kg and they experience a gravitational force of magnitude 2.00
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Answer:
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Answer:
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Answer:
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Explanation:
Initial speed=2 m/s
mv=Ft
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v=5.7 m/s
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Answer:
238.09 cm^3
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Answer:
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This is a pretty vague question, but I'll answer as best I can.
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Answers
Answer:
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Given that the force applied to the smaller piston, F₂ = 4,000 N
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Answers
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Answers
Answer:
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work and power!!
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Answer:
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Don't scroll down. Help pls 22 POINTS!!
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Answer:
I don't know if these are all right but these are my best answers. good luck and I hope you do well.
1. true
2. true
3. false
4. true
5. true
6. true
7. true
8. true
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10. false
13. it stimulates the heart through chest compressions
14. on bare skin upper right shoulder and lower left ribs
15. no CPR
Explanation:
What is the transfer of energy that occurs when a force causes an object to move?
O Energy
Force
Power
O Work
Answers
Answer:
huh? I think it's Power.....
A 2kg rock is dropped from a height of 10m and hits the ground going 11m/s. How much work was done by air resistance as it fell?
Answers
Answer: 0.24 kg/m
Explanation: use k = ρ * A * C / 2 as the formulaIf a motor is rated at 5.6KW, work done in 20minutes is equal to:
Answers
Answer:
given Power= 5.6×1000=5600watt
t=20min=20×60=1200sec. work done=?
P=w/t
w=pt=5600×1200=672×10^4Joule
The amount of work done by the motor is equal to 6.72 Megajoules.
Given the following data:
Time = 20 minutesPower = 5.6 Kilowatt = 5600 Watts.Conversion:
1 minute = 60 seconds20 minutes = [tex]20 \times 60 = 1200[/tex] seconds.To determine the amount of work done by the motor:
Mathematically, the work done by an object with respect to power and time is given by the formula:
[tex]Work\;done = power \times time[/tex]
Substituting the given parameters into the formula, we have;
[tex]Work\;done = 5600 \times 1200[/tex]
Work done = 6,720,000 Joules
Note: 1,000,000 Joules = 1 Megajoules.
Work done = 6.72 Megajoules.
Read more on work done here: https://brainly.com/question/13818347
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Answers
Answer:
Newton's First Law of Motion.
Explanation:
Newton's First Law of Motion states that a body continues its state of motion untill and unless an external force acts on it. Here, the truck moves forward even after the breaks are applied in order to maintain its State of motion.
A particle was moving in a straight line at 172.8 km/hr. If it decelerated over 120 meters to come to rest, find the time taken to cover this distance.
Answers
Answer:
v=s/t
s=vt
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t=(120×10‐³)/172.8
(the distance meters has been changed to kilometres)
t=1/1440 hrs
Given ,
Helppppp meeeeee pleaseeeeeeeee
Answers
If I keep F constant in F=ma, what is the relationship between m and a?
Answers
Answer:
If F is a constant, we can take f = 1
f = m×a
ma = 1
therefore we can say that force is hence proportinal to the product of mass and acceleration.
The tuning fork has a frequency of 426.7 is found to cause resonance in a closed column of air measuring 0.186 (the diameter of the tube is 0.015m) find the velocity of the sound produced by the tuning fork.
Answers
Answer:
The velocity of the tuning fork sound is 317.4648 m/s
Explanation:
The given parameters are;
The frequency of the fork, f = 426.7 Hz
The length of the closed air column, L = 0.186 m
The diameter of the tube, d = 0.15 m
At the fundamental frequency in a closed tube, we have;
λ = 4·L
Where;
λ = The wavelength of the wave
L = The length of the tube
From the equation for the velocity of a wave, we have;
v = f·λ
Where;
v = The velocity of the (sound) wave
f = The frequency of the wave = 426.7 Hz
λ = 4·L = 4 × 0.186 m = 0.744 m
∴ v = 426.7 Hz × 0.744 m = 317.4648 m/s
Therefore, the velocity of the sound produced by the tuning fork, v = 317.4648 m/s
a car travels at a constant speed of 30km/h for .80h what is the total distance
Answers
Answer:
2400 km
Explanation:
30km for 1hr
Need up to 80 hrs , multiply both 80 and 30
So its 2400km