please help with this math problem ​

Answer:

4

Step-by-step explanation:

2 cookies + 2 cookies = 4 cookies!

The more cookies the better!

Answer:

maybe u should have paid attention in class buddy

Step-by-step explanation:

L

Answer:

2 11/12 cups of flour

Step-by-step explanation:

2 recipes are 2 1/2 cups of flour  

1/3 is 1/3 x 1 1/4= 1/3 + 1/12= 5/12  

So, 2 11/12 cups of flour

Answer:

45% Of the cars are there

because it says 45% so I am pretty sure that is it

Answer: The answer is B

Step-by-step explanation:

Answer:

[tex]g'(n) = -\frac{n+1}{3}[/tex]

Step-by-step explanation:

Given

[tex]g(n) = -3n - 1[/tex]

Required

Determine the inverse

[tex]g(n) = -3n - 1[/tex]

Replace g(n) with y

[tex]y = -3n - 1[/tex]

Swap positions of x and y

[tex]n = -3y - 1[/tex]

Make y the subject

[tex]3y = -n - 1[/tex]

[tex]3y = -(n + 1)[/tex]

[tex]y = -\frac{n+1}{3}[/tex]

Replace y with g'(n)

[tex]g'(n) = -\frac{n+1}{3}[/tex]

Answer:

4 7/15

Step-by-step explanation:

Hope this helps :)

Answer:

here is a videos look it up on you tube and it might help

Step-by-step explanation:

search this

Interpreting graphs of proportional relationships

Answer:

Step-by-step explanation:

Given that:

[tex]\int^2_0 \int^2_x \ sin (y^2) \ dy dx \\ \\ \text{Using backward equation; we have:} \\ \\ \int^2_0\int^2_0 sin(y^2) \ dy \ dx = \int \int_o \ sin(y^2) \ dA \\ \\ where; \\ \\ D= \Big\{ (x,y) | }0 \le x \le 2, x \le y \le 2 \Big\}[/tex]

[tex]\text{Sketching this region; the alternative description of D is:} \\ D= \Big\{ (x,y) | }0 \le y \le 2, 0 \le x \le y \Big\}[/tex]

[tex]\text{Now, above equation gives room for double integral in reverse order;}[/tex]

[tex]\int^2_0 \int^2_0 \ sin (y^2) dy dx = \int \int _o \ sin (y^2) \ dA \\ \\ = \int^2_o \int^y_o \ sin (y^2) \ dx \ dy \\ \\ = \int^2_o \Big [x sin (y^2) \Big] ^{x=y}_{x=o} \ dy \\ \\= \int^2_0 ( y -0) \ sin (y^2) \ dy \\ \\ = \int^2_0 y \ sin (y^2) \ dy \\ \\ y^2 = U \\ \\ 2y \ dy = du \\ \\ = \dfrac{1}{2} \int ^2 _ 0 \ sin (U) \ du \\ \\ = - \dfrac{1}{2} \Big [cos \ U \Big]^2_o \\ \\ = - \dfrac{1}{2} \Big [cos \ (y^2) \Big]^2_o \\ \\ = - \dfrac{1}{2} cos (4) + \dfrac{1}{2} cos (0) \\ \\[/tex]

[tex]= - \dfrac{1}{2} cos (4) + \dfrac{1}{2} (1) \\ \\ = \dfrac{1}{2}\Big [1- cos (4) \Big] \\ \\ = \mathbf{0.82682}[/tex]

Answer:

288.68 square millimeters

288.68 square millimeters or  1703.12 square millimeters

Answer:

Step-by-step explanation:

Divide the pentagon radially into 5 congruent, isosceles triangles.

Area of one triangle = ½×7.2×4.955 = 17.838 mm²

area of pentagon = 5×17.838 mm ≅ 89.2 mm²

Answer:

x = 4

Step-by-step explanation:

6(+4)=48

6+24=48

6+24=48

6+24−24=48−24

6=24

6=24

6/6=24

...

Answer:

3 6 520; 6 235; 6 250.

Answer:1

Step-by-step explanation:it is right

The mistake is in the first step. You seem to want to divide through by 7, but you only did it correctly with the x ² term. What you should have after doing this is

7x ² + 9x + 2 = 0

→   x ² + 9/7 x + 2/7 = 0

This step isn't actually necessary to begin with since the starting quadratic is easily factorized:

7x ² + 9x + 2 = (7x + 2) (x + 1) = 0

Then

7x + 2 = 0   or   x + 1 = 0

7x = -2   or   x = -1

x = -2/7   or   x = -1

Answer:

rrir

Step-by-step explanation:

e8

Answer:

Im pretty sure it is 48 but it could be 96

Step-by-step explanation:

I just found the area and halved that.

Answer:

What???

Step-by-step explanation:

Answer:

????

Step-by-step explanation:

Answer:

B

Step-by-step explanation:

Yes.

Providing FI is a straight line, then FGH + HGI = 180. The angles are supplementary.

If one of them is 89 then the other one must be 180 - 89 = 91

B is the correct answer.

1/4 / 5 is equal to 4x5, or 20.

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hope it helps

Answer:

The area of Alison's pizza would be 30 in.

Answer:

Don't worry I will help to solve this problem OK.Sorry I don't understand please ask with other OK .

Step-by-step explanation:

base = 40

height = 16

Area of parallelogram = b×h = 40× 16= 640

Answer:

the area of the shaded area is 160 cm ²

Step-by-step explanation:

Hey There!

so the first step in solving this problem is to find the area of the whole shape

This is a trapezoid and the formula for area of a trapezoid is

[tex]A=\frac{a=b}{2} h[/tex]

a = base 1 (20)

b = base 2  (40)

h = height (16)

now we plug in the values

[tex]A=\frac{40+20}{2} 16\\40+20=60\\\frac{60}{2} =30\\30*16=480[/tex]

so the area of the trapezoid is 480

The next step is to find the area of the triangle

To do so we use this formula

[tex]A=\frac{hb}{2}[/tex]

h = height (16)

b = base (20)

now we just plug in the values

[tex]A=\frac{16*20}{2} \\16*20=320\\\frac{320}{2}=160\\[/tex]

The area of the triangle is 160

Answer:

can you give us the whole sheet?

Step-by-step explanation:

Answer:

Step-by-step explanation:

x/50 = 12/24

24x = 600

x= 25

Answer:

132 ft³

Step-by-step explanation:

L=11    W=3   H=4

V=LWH

V=(11)(3)(4)

V=132 ft³

Answer:

E(X) = 38.9346

Var(X) = 25.588

E(Y) = 38.25

Var(Y) = 26.1875

Step-by-step explanation:

Given - Four buses carrying 153 high school students arrive to Montreal. The buses carry, respectively, 36, 46, 32, and 39 students. One of the students is randomly selected.One of the 4 bus drivers is also randomly selected.

To find - Compute the expectations and variances of X and Y.

Proof -

Let us assume that,

X be The number of students that were on the bus carrying this randomly selected student.

Y denote the number of students on his bus.

Now,

E(X) =  [tex]\frac{36(36) + 46(46) + 32(32) + 39(39)}{153}[/tex]

       = [tex]\frac{5957}{153}[/tex]

       = 38.9346

⇒E(X) = 38.9346

Now,

E(Y) = [tex]\frac{36 + 46 + 32 + 39}{4}[/tex]

      =  [tex]\frac{153}{4}[/tex]

      = 38.25

⇒E(Y) = 38.25

Now,

Var(X) = [tex]\frac{36(36 - 38.9346)^{2} + 46(46 - 38.9346)^{2} + 32(32 - 38.9346)^{2} + 39(39 - 38.9346)^{2}}{153}[/tex]

          = [tex]\frac{310.0276 + 2296.3144 + 1308.5091 + 0.1668}{153}[/tex]

          = [tex]\frac{3915.0179}{153}[/tex]

          = 25.588

⇒Var(X) = 25.588

Now,

Var(Y) = E(Y²) - [E(Y)]²

          = [tex]\frac{36^{2} + 46^{2} + 32^{2} + 39^{2} }{4} - (38.25)^{2}[/tex]

          = [tex]\frac{5957}{4} - 1463.0625[/tex]

          = 1489.25 - 1463.0625

          = 26.1875

⇒Var(Y) = 26.1875