Please help !! *will mark correct answer as brainliest*

Problem:

The transformation is an isometry.

Answers:

True
False

Answer:

Volume of liquid which freezes to ice is 1620. 37 .

Expression to find this is 108x/100 = 1750

Step-by-step explanation:

Let the volume of liquid be x cubic inches

It is  given that volume of liquid increases by 8% when it freezes to ice

increase in volume of x  x cubic inches liquid = 8% of x = 8/100 * x = 8x/100

Total volume of ice = initial volume of liquid + increase in volume when it freezes to ice  = x + 8x/100 = (100x + 8x)/100 = 108x/100

Given that total volume of liquid which freezes is 1750

Thus,

108x/100 = 1750

108x = 1750*100

x = 1750*100/108 = 1620. 37

Volume of liquid which freezes to ice is 1620. 37 .

Expression to find this is 108x/100 = 1750

Answer:

(4, 3)

Step-by-step explanation:

Use the midpoint formula: [tex](\frac{x1+x2}{2}, \frac{y1+y2}{2} )[/tex]

Answer:

infinite solutions

Step-by-step explanation:

it means that all x are solution of this equation as 6=6 is always true

Answer:

0.0174 = 1.74% probability that the sample mean hardness for a random sample of 10 pins is at least 51

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

When the distribution is normal, we use the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this question, we have that:

[tex]\mu = 50, \sigma = 1.5, n = 10, s = \frac{1.5}{\sqrt{10}} = 0.4743[/tex]

What is the probability that the sample mean hardness for a random sample of 10 pins is at least 51

This is 1 subtracted by the pvalue of Z when X = 51. So

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

By the Central Limit Theorem

[tex]Z = \frac{X - \mu}{s}[/tex]

[tex]Z = \frac{51 - 50}{0.4743}[/tex]

[tex]Z = 2.11[/tex]

[tex]Z = 2.11[/tex] has a pvalue of 0.9826

1 - 0.9826 = 0.0174

0.0174 = 1.74% probability that the sample mean hardness for a random sample of 10 pins is at least 51

Answer:

21/55

Step-by-step explanation:

Simply multiply the top 2 together:

3 x 7 = 21

And the bottom 2 together:

5 x 11 = 55

21/55 is your answer!

Answer:

Step-by-step explanation:

given a field of the form F = (P(x,y),Q(x,y) and a simple closed curve positively oriented, then

[tex]\int_{C} F \cdot dr = \int_A \frac{dQ}{dx} - \frac{dP}{dy} dA[/tex] where A is the area of the region enclosed by C.

In this case, by the description we can assume that C starts at (0,0). Then it goes the point (pi,0) on the path giben by y = sin(x) and then return to (0,0) along the straigth line that connects both points. Note that in this way, the interior the region enclosed by C is always on the right side of the point. This means that the curve is negatively oriented. Consider the path C' given by going from (0,0) to (pi,0) in a straight line and the going from (pi,0) to (0,0) over the curve y = sin(x). This path is positively oriented and we have that

[tex] \int_{C} F\cdot dr = - \int_{C'} F\cdot dr[/tex]

We use the green theorem applied to the path C'. Taking [tex] P = x+4y^3, Q = 4x^2+y[/tex] we get

[tex] \int_{C'} F\cdot dr = \int_{A} 8x-12y^2dA[/tex]

A is the region enclosed by the curves y =sin(x) and the x axis between the points (0,0) and (pi,0). So, we can describe this region as follows

[tex]0\leq x \leq \pi, 0\leq y \leq \sin(x)[/tex]

This gives use the integral

[tex] \int_{A} 8x-12y^2dA = \int_{0}^{\pi}\int_{0}^{\sin(x)} 8x-12y^2 dydx[/tex]

Integrating accordingly, we get that [tex]\int_{C'} F\cdot dr = 8\pi - \frac{16}{3}[/tex]

So

[tex] \int_{C} F cdot dr = - (8\pi - \frac{16}{3}) = \frac{16}{3} - 8\pi [/tex]

Answer:

-10

Step-by-step explanation:

Use the Order of Operations - PEMDAS

Do what is in parentheses first - (4-2) = 2

Next multiply 3 and 4 = 12

Last, perform 2 - 12; which equals -10

Answer:

It is vertically stretched by a factor of 200 and shifted 10 units right

Step-by-step explanation:

Suppose we have a function f(x).

a*f(x), a > 1, is vertically stretching f(x) a units. Otherwise, if a < 1, we are vertically compressing f(x) by a units.

f(x - a) is shifting f(x) a units to the right.

f(x + a) is shifting f(x) a units to the left.

In this question:

Initially: [tex]f(x) = \frac{1}{x}[/tex]

Then, first we shift, end up with:

[tex]f(x+10) = \frac{1}{x + 10}[/tex]

f was shifted 10 units to the left.

Finally,

[tex]200f(x+10) = \frac{200}{x + 100}[/tex]

It was vertically stretched by a factor of 200.

So the correct answer is:

It is vertically stretched by a factor of 200 and shifted 10 units right

Answer:

the answer is D

Step-by-step explanation:

Step-by-step explanation:

40 x $10.12/hr = $404.80

5 x $15.18/hr = $ 75.90

over time = $10.12 + $5.06 ( half of $10.12) = $15.18/hr

$404.80 + $75.90 = $480.70/weekly pay

assuming she works 52 weeks a year

$480.70 × 52 weeks = $24,996.40/yr

Answer:

20 4/5

Step-by-step explanation:

13/5 times 8/1

104/5

which is simplify

to 20 4/5\

hope this helps

Answer:

Step-by-step explanation:

This is a poisson distribution. Let x be a random representing the number of calls in a given time interval.

a) the expected number of calls in one hour is the same as the mean score in 60 minutes. Thus,

Mean score = 60/2 = 30 calls

b) The interval of interest is 5 minutes.

µ = 5/2 = 2.5

We want to determine P(x = 3)

Using the Poisson probability calculator,

P(x = 3) = 0.21

c) µ = 5/2 = 2.5

We want to determine P(x = 0)

Using the Poisson probability calculator,

P(x = 0) = 0.08

Answer:

0.6%

Step-by-step explanation:

We have a standard deck of 52 playing cards, which is made up of 13 cards of each type (hearts, diamonds, spades, clubs)

Therefore there are one nine hearts, one nine diamonds, one nine spades and one nine clubs, that is to say that in total there are 4. Therefore the probability of drawing a nine is:

4/52

In the second card it is the same, an eight, that is, there are 4 eight cards, but there is already one less card in the whole deck, since it is not replaced, therefore the probability is:

4/51

So the final probability would be:

(4/52) * (4/51) = 0.006

Which means that the probability of the event is 0.6%

Answer:

AC = 11 cm , CB = 22 cm

Step-by-step explanation:

let AC = x then BC = 2x , then

AC + BC = 33, that is

x + 2x = 33

3x = 33 ( divide both sides by 3 )

x = 11

Thus

AC = x = 11 cm and CB = 2x = 2 × 11 = 22 cm

Answer:

41

Step-by-step explanation:

[tex]24*2-7=\\48-7=\\41[/tex]

Answer:

[tex] 211600 = 225000 -k*6700[/tex]

[tex] k = \frac{225000-211600}{6700}= 2[/tex]

[tex] 238400 = 225000 +k*6700[/tex]

[tex] k = \frac{238400-225000}{6700}= 2[/tex]

So then the % expected would be:

[tex] 1- \frac{1}{2^2}= 1- 0.25 =0.75[/tex]

So then the answer would be 75%

Step-by-step explanation:

For this case we have the following info given:

[tex] \mu = 225000[/tex] represent the true mean

[tex]\sigma =6700[/tex] represent the true deviation

And for this case we want to find the minimum percentage of sold homes between $211,600 and $238,400.

From the chebysev theorem we know that we have [tex]1 -\frac{1}{k^2}[/tex] % of values within [tex]\mu \pm k\sigma[/tex] if we use this formula and the limit given we have:

[tex] 211600 = 225000 -k*6700[/tex]

[tex] k = \frac{225000-211600}{6700}= 2[/tex]

[tex] 238400 = 225000 +k*6700[/tex]

[tex] k = \frac{238400-225000}{6700}= 2[/tex]

So then the % expected would be:

[tex] 1- \frac{1}{2^2}= 1- 0.25 =0.75[/tex]

So then the answer would be 75%

Answer:

96 degrees

Step-by-step explanation:

Since x is half of 168, its angle measure is 84 degrees. Since x and y are a linear pair, their angle measures must add to 180 degrees, meaning that:

y+84=180

y=180-84=96

Hope this helps!

Answer: X= 4

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

18=3(3x−6)

18=(3)(3x)+(3)(−6)(Distribute)

18=9x+−18

18=9x−18

Step 2: Flip the equation.

9x−18=18

Step 3: Add 18 to both sides.

9x−18+18=18+18

9x=36

Step 4: Divide both sides by 9.

9x

9

=

36

9

Answer:

X=4

Step-by-step explanation:

18=3(3X-6)

18=3><(3X-6)

18=9X-18

9X=-18-18

9X=36

X=36/9

X=4

Hope this helps

Brainliest please

Answer:  $2 or $9

Step-by-step explanation:

Revenue (R) = $1800 , x = 1100 - 100p

R = xp

1800 = (1100 - 100p)p             substituted x with 1100 - 100p

1800 = 1100p - 100p²             distributed p into 1100 - 100p

100p² - 1100p + 1800 = 0       added 100p² & subtracted 1100p on both sides

     p² - 11p + 18 = 0                divided both sides by 100

(p - 2) (p - 9) = 0                     factored quadratic equation

p = 2  p = 9                         applied Zero Product Property to solve for p

Answer: 18 cm

Step-by-step explanation:

We know the circumference formula is C=2πr. Since our circumference is given in terms of π, we can easily figure out what the radius is.

36π=2πr                   [divide both sides by π to cancel out]

36=2r                        [divide both sides by 2]

r=18 cm

Answer:

18cm

Step-by-step explanation:

because i found it lol

Answer:

Center, radius, chord, diameter... are Words related to circle

[tex]\displaystyle\bf\\\textbf{At any translation of a quadrilateral the sides remain the same,}\\\\\textbf{the angles remain the same.}\\\\\textbf{It turns out that the quadrilateral remains the same.}\\\\P_{A'B'C'D'}=P_{ABCD}=AB+BC+CD+DA=\\\\~~~~~~~~~~~~~~=2.2+4.5+6.1+1.4=\boxed{\bf14.2}[/tex]

Answer:

The 95% confidence interval for the difference between the proportion of women who drink alcohol and the proportion of men who drink alcohol is (-0.102, -0.014) or (-10.2%, -1.4%).

Step-by-step explanation:

We want to calculate the bounds of a 95% confidence interval of the difference between proportions.

For a 95% CI, the critical value for z is z=1.96.

The sample 1 (women), of size n1=1000 has a proportion of p1=0.494.

[tex]p_1=X_1/n_1=494/1000=0.494[/tex]

The sample 2 (men), of size n2=1000 has a proportion of p2=0.552.

[tex]p_2=X_2/n_2=552/1000=0.552[/tex]

The difference between proportions is (p1-p2)=-0.058.

[tex]p_d=p_1-p_2=0.494-0.552=-0.058[/tex]

The pooled proportion, needed to calculate the standard error, is:

[tex]p=\dfrac{X_1+X_2}{n_1+n_2}=\dfrac{494+552}{1000+1000}=\dfrac{1046}{2000}=0.523[/tex]

The estimated standard error of the difference between means is computed using the formula:

[tex]s_{p1-p2}=\sqrt{\dfrac{p(1-p)}{n_1}+\dfrac{p(1-p)}{n_2}}=\sqrt{\dfrac{0.523*0.477}{1000}+\dfrac{0.523*0.477}{1000}}\\\\\\s_{p1-p2}=\sqrt{0.000249+0.000249}=\sqrt{0.000499}=0.022[/tex]

Then, the margin of error is:

[tex]MOE=z \cdot s_{p1-p2}=1.96\cdot 0.022=0.0438[/tex]

Then, the lower and upper bounds of the confidence interval are:

[tex]LL=(p_1-p_2)-z\cdot s_{p1-p2} = -0.058-0.0438=-0.102\\\\UL=(p_1-p_2)+z\cdot s_{p1-p2}= -0.058+0.0438=-0.014[/tex]

The 95% confidence interval for the difference between proportions is (-0.102, -0.014).

Answer:

See below in bold.

Step-by-step explanation:

We can write the equation as

y = a(x - 28)(x + 28)   as -28 and 28  ( +/- 1/2 * 56) are the zeros of the equation

y has coordinates (0, 32) at the top of the parabola so

32 = a(0 - 28)(0 + 28)

32 = a * (-28*28)

32 = -784 a

a = 32 / -784

a = -0.04082

So the equation is y = -0.04082(x - 28)(x + 28)

y = -0.04082x^2 + 32

The second part  is found by first finding the value of x corresponding to  y = 22

22 = -0.04082x^2 + 32

-0.04082x^2 = -10

x^2 = 245

x = 15.7 inches.

This is the distance from the centre of the door:

The distance from the edge = 28 - 15.7

= 12,3 inches.

Answer:

Height of tank = 50cm

Step-by-step explanation:

Volume of water from tank that the water is 10cm down is 84000cm³

Length = 60cm

Width = 35cm

Height of water = x

Volume = length* width* height

Volume= 84000cm³

84000 = 60*35*x

84000= 2100x

84000/2100= x

40 = x

Height of water= 40cm

Height of tank I = height of water+ 10cm

Height of tank= 40+10= 50cm

Height of tank = 50cm

Answer:

100 possible extensions

Step-by-step explanation:

we can calculated how many possible extensions they have to try using the rule of multiplication as:

___1_____*___10_____*___10_____*____1____ = 100

1st digit        2nd digit        3rd digit         4th digit

You know that the 1st and 4th digits of the extension are 5. it means that you just have 1 option for these places. On the other hand, you don't remember nothing about the 2nd and 3rd digit, it means that there are 10 possibles digits (from 0 to 9) for each digit.

So, There are 100 possibles extensions in which the 5 is the first and last digit.

Answer:

a=b

Step-by-step explanation:

When the denominator is zero, the expression is undefined

a-b=0

a=b

Answer:

The scale factor is 2/3

Step-by-step explanation:

The image of (6,9) under a dilation is (4,6).

As you might see, there is a ratio between the image after dilating and before dilating, which is 4/6 = 6/9 = 2/3.

=> The scale factor is 2/3.

Answer:

(a)[tex]D(t)=\dfrac{50000}{1.9t+9}[/tex]

(b)[tex]D'(115)=-1.8355[/tex]

Step-by-step explanation:

The demand function for a product is given by :

[tex]D(p)=\dfrac{50000}{p}[/tex]

Price, p is a function of time given by [tex]p=1.9t+9[/tex], where t is in days.

(a)We want to find the demand as a function of time t.

[tex]\text{If } D(p)=\dfrac{50000}{p},$ and p=1.9t+9\\Then:\\D(t)=\dfrac{50000}{1.9t+9}[/tex]

(b)Rate of change of the quantity demanded when t=115 days.

[tex]\text{If } D(t)=\dfrac{50000}{1.9t+9}[/tex]

[tex]\dfrac{\mathrm{d}}{\mathrm{d}t}\left[\dfrac{50000}{\frac{19t}{10}+9}\right]}}=50000\cdot \dfrac{\mathrm{d}}{\mathrm{d}t}\left[\dfrac{1}{\frac{19t}{10}+9}\right]}[/tex]

[tex]=-50000\cdot\dfrac{d}{dt} \dfrac{\left[\frac{19t}{10}+9\right]}{\left(\frac{19t}{10}+9\right)^2}}}[/tex]

[tex]=\dfrac{-50000(1.9\frac{d}{dt}t+\frac{d}{dt}9)}{\left(\frac{19t}{10}+9\right)^2}}}[/tex]

[tex]=-\dfrac{95000}{\left(\frac{19t}{10}+9\right)^2}\\$Simplify/rewrite to obtain:$\\\\D'(t)=-\dfrac{9500000}{\left(19t+90\right)^2}[/tex]

Therefore, when t=115 days

[tex]D'(115)=-\dfrac{9500000}{\left(19(115)+90\right)^2}\\D'(115)=-1.8355[/tex]