Please help will definitely say thanks

Answer:

Answer is below.

Step-by-step explanation:

Points R, S, T, Q on Circle O - Given

m (arc) RS + m (arc) ST = m (arc) RT , m (arc) RT + m (arc) TQ = m (arc) RQ - Arc addition

m (arc) RS + m (arc) ST + m (arc) TQ = m (arc) RQ - Substitution

Hope this helps.

The proofing is as follows:

Given that,

Now

m (arc) RS + m (arc) ST = m (arc) RT , m (arc) RT + m (arc) TQ = m (arc) RQ - Arc addition

And,

m (arc) RS + m (arc) ST + m (arc) TQ = m (arc) RQ - Substitution

learn more: https://brainly.com/question/7695753?referrer=searchResults

Answer:

Null and alternative hypothesis:

[tex]H_0: \mu=0.05\\\\H_a:\mu< 0.05[/tex]

The alternative hypothesis is the one that needs evidence to be supported, while the null hypothesis is the one that can be nullified (reject).

Only if there is enough evidence that thickness is less than 0.05 the null hypothesis will be rejected and the alternative hypothesis claim supported.

A Type I error happens when a true null hypothesis is rejected. In this case we will be purchase a order that is not fulfilling the thickness required.

A Type II error happens when a false null hypothesis is failed to be rejected. In this case, the order has a thickness significantly smaller than 0.05, but the sample gives no enough evidence and the order will not be purchased.

Step-by-step explanation:

A hypothesis test to see conclusive evidence that the true standard deviation of sheath thickness is less than 0.05 mm will have the following hypothesis:

[tex]H_0: \mu=0.05\\\\H_a:\mu< 0.05[/tex]

The alternative hypothesis Ha will state that the true mean is significantly smaller than 0.05, while the null hypothesis H0 will state the opposite: that the true mean is not significantly smaller than 0.05.

The alternative hypothesis is the one that needs evidence to be supported, while the null hypothesis is the one that can be nullified (reject).

Only if there is enough evidence that thickness is less than 0.05 the null hypothesis will be rejected and the alternative hypothesis claim supported.

Answer:

So each strawberry is 4 calories

Step-by-step explanation:

First find the slope of the line

Two points on the line are

(0,0) and (3,12)

m = (y2-y1)/(x2-x1)

    = (12-0)/(3-0)

     = 12/3

      = 4

So each strawberry is 4 calories

Let's raise i to various powers starting with 0,1,2,3...

i^0 = 1

i^1 = i

i^2 = ( sqrt(-1) )^2 = -1

i^3 = i^2*i = -1*i = -i

i^4 = (i^2)^2 = (-1)^2 = 1

i^5 = i^4*i = 1*i = i

i^6 = i^5*i = i*i = i^2 = -1

We see that the pattern repeats itself after 4 iterations. The four items to memorize are

i^0 = 1

i^1 = i

i^2 = -1

i^3 = -i

It bounces back and forth between 1 and i, alternating in sign as well. This could be one way to memorize the pattern.

To figure out something like i^25, we simply divide the exponent 25 over 4 to get the remainder. In this case, the remainder of 25/4 is 1 since 24/4 = 6, and 25 is one higher than 24.

This means i^25 = i^1 = i

Likewise,

i^5689 = i^1 = i

because 5689/4 = 1422 remainder 1. The quotient doesn't play a role at all so you can ignore it entirely

Answer:

a. A residual is how far off a point is from the expected value. For example, if I were to estimate the weight of my Southeastern Lubber Grasshopper, I would say it's maybe 5 ounces. But, in reality, it might be 4 ounces. So, the residual would be the reality minus the prediction, or 4 - 5, or -1 ounce.

b. The regression line is the line of predicted values for the points in the scatterplot. It tries to predict the points and make all the points be on the line.

Hope this helps!

Answer:

The coordinates of the point on a circle with radius 4 at an angle of [tex]\frac{2\pi}{3}[/tex] radians are x = -2 and y = 3.464.

Step-by-step explanation:

This problem ask us to determine the rectangular coordinates from polar coordinates. The polar coordinates of the point in rectangular form is expressed by the following expression:

[tex](x,y) = (r\cdot \cos \theta, r\cdot \sin \theta)[/tex]

Where [tex]r[/tex] and [tex]\theta[/tex] are the radius of the circle and the angle of inclination of the point with respect to horizontal, measured in radians. If [tex]r = 4[/tex] and [tex]\theta = \frac{2\pi}{3}\,rad[/tex], the coordinates of the point are:

[tex](x,y) = \left(4\cdot \cos \frac{2\pi}{3},4\cdot \sin \frac{2\pi}{3} \right)[/tex]

[tex](x,y) = (-2, 3.464)[/tex]

The coordinates of the point on a circle with radius 4 at an angle of [tex]\frac{2\pi}{3}[/tex] radians are x = -2 and y = 3.464.

Answer:

6/5, 7/6

Step-by-step explanation:

The nth term is (n+1)/n

2/1, 3/2, 4/3, 5/4

Put n as 5 and 6.

(5+1)/5

= 6/5

(6+1)/6

= 7/6

Answer: a) 503.2m

b) 621.6m

Step-by-step explanation:

The diagram representing the scenario is shown in the attached photo.

A represents her starting point.

CD = x = how far east she is from her starting point

BC = y = how far south she is from her starting point

Angle BAC = 180 - 129 = 51°

Angle ACD = angle BAC = 51° because they are alternate angles

To determine x, we would apply the cosine trigonometric ratio

Cos 51 = x /800

x = 800Cos51 = 800 × 0.629 = 503.2m

To determine y, we would apply the sine trigonometric ratio

Sin 51 = y /800

y = 800Sin51 = 800 × 0.777 = 621.6m

Answer:

largets area is 32 feet cubed

Step-by-step explanation:

8=4  foot 2 for each  side w and e and 32feet n and s  16 each side

Answer:

-12

Step-by-step explanation:

Edge 2021

Answer:

not sure how to really answer this question.

Answer:

4.56,  4.65, 5.46, 5.64, 6.45, 6.54

Step-by-step explanation:

First we have to compare the first digits in each number as less is this digit as less is the number. So the least off all are

4.56 and 4.65

which of these two numbers is least ? Now we have to look to the 2-nd digits of these numbers:

they are 5 and 6 . 5<6 so 4.56<4.65

Lets select next numbers whicj first digit is 5. They are:

5.46 and 5.64. However the second digit of the number 5.64 -6 is bigger than the second digit of number 5.46 -4. That is why 5.46<5.64

Similarly 6.45< 6.54

Answer:

The sequence converges. The limit DNE.

Step-by-step explanation:

Find the limit of n as n tends to infinity (in other words, positive infinity) in {Ln(n)/ Ln(3n)}

Positive infinity values for n start from 1,2,3,4,5,6,7,8,9,10,11,12,13,14,...,infinity

So I solved for values of n, up to n=20. All values are rounded up to 3 decimal places; for better accuracy.

When n is 1, the function is equal to 0.000

When n is 2, the function is = 0.387

When n is 3, the function = 0.500

When n is 4, the function = 0.558

When n is 5, the function = 0.594

When n is 6, the function = 0.619

When n is 7, the function = 0.639

When n is 8, the function = 0.654

When n is 9, the function = 0.667

When n is 10, the function = 0.677

When n is 11, the function = 0.686

When n is 12, the function = 0.693

When n is 13, the function = 0.700

When n is 14, the function = 0.706

When n is 15, the function = 0.711

When n is 16, the function = 0.716

When n is 17, the function = 0.721

When n is 18, the function = 0.725

When n is 19, the function = 0.728

When n is 20, the function = 0.732

We say there is a convergence because the space between the values of n gets smaller and smaller as n tends to infinity and there is no definite limit. Limit DNE.

Answer:

The period is of [tex]\frac{\pi}{3}[/tex] units.

The horizontal shift is of 30 units to the left.

Step-by-step explanation:

The secant function has the following general format:

[tex]y = A\sec{(Bx + C)}[/tex]

A represents the vertical shift.

C represents the horizontal shift. If C is positive, the shift is to the right. If it is negative, it is to the left.

The period is [tex]P = \frac{2\pi}{B}[/tex]

In this question:

[tex]y = 7\sec{6x - 30}[/tex]

So [tex]B = 6, C = -30[/tex]

Then [tex]P = \frac{2\pi}{6} = \frac{\pi}{3}[/tex]

The period is of [tex]\frac{\pi}{3}[/tex] units.

The horizontal shift is of 30 units to the left.

Answer:

We want to find the usual limits using the rule of thumb and for this case rule states that we have most of the values within 2 deviations from the mean so then we can find the usual limits like this:

[tex] \mu -2*\sigma = 80.9 -2*10.7= 59.5[/tex]

[tex] \mu +2*\sigma = 80.9 -2*10.7= 102.3[/tex]

And for this case a value of 142.3 is higher than the upper limti so then we can conclude that would be significantly high with the rule of thumb criteria

Step-by-step explanation:

For this case we have the follwing info given:

[tex] \mu = 80.9[/tex] represent the mean

[tex]\sigma = 10.7[/tex] represent the deviation

We want to find the usual limits using the rule of thumb and for this case rule states that we have most of the values within 2 deviations from the mean so then we can find the usual limits like this:

[tex] \mu -2*\sigma = 80.9 -2*10.7= 59.5[/tex]

[tex] \mu +2*\sigma = 80.9 -2*10.7= 102.3[/tex]

And for this case a value of 142.3 is higher than the upper limti so then we can conclude that would be significantly high with the rule of thumb criteria

Answer:

Step-by-step explanation:

The point slope form of a straight line is expressed as

y - y1 = m(x - x1)

Where

m represents slope of the line

y1 represents the initial value of y

x1 represents the initial value of x

If two lines are parallel, it means that they have the same slope. From the equation of the given line, slope = 1/2

Therefore,

m = 1/2

x1 = - 3

y1 = - 2

Substituting into the point slope equation, it becomes

y - - 2 = 1/2(x - - 3)

y + 2 = 1/2(x + 3)

The equation is

y + 2 = 1/2(x + 3)

Answer: The point slope form of a straight line is expressed as y - y1 = m(x - x1)Wherem represents slope of the liney1 represents the initial value of yx1 represents the initial value of xIf two lines are parallel, it means that they have the same slope. From the equation of the given line, slope = 1/2Therefore,m = 1/2x1 = - 3y1 = - 2Substituting into the point slope equation, it becomesy - - 2 = 1/2(x - - 3)y + 2 = 1/2(x + 3)The equation is y + 2 = 1/2(x + 3)

Step-by-step explanation:

Answer:

2) 43

4) 65

Step-by-step explanation:

The first and third quartile of the data can be found by calculating the median of the first and second halves of the data.  For example, the first quartile of the data can be calculated thus:

40,41,43,50,56

41,43,50

43

and the third quartile thus:

62,63,65,78,97

63,65,78

65

Hope it helps <3

Answer:

A) 43

B) 65

Step-by-step explanation:

A) First Quartile = [tex](N+1)\frac{1}{4}[/tex]

Where N is the number of observations

=> 1st Quartile = (11+1)(1/4)

=> 1st Quartile = (12)(1/4)

=> 1st Quartile = 3rd number

B) Third Quartile = [tex](N+1)\frac{3}{4}[/tex]

=> 3rd Quartile = (11+1)(3/4)

=> 3rd Quartile = (12)(3/4)

=> 3rd Quartile = 3*3

=> 3rd Quatile = 9th number

Answer:

x = 2.2

Step-by-step explanation:

-0.45x + 0.33 = -0.66

Subtract .33 from each side

-0.45x + 0.33-.33 = -0.66-.33

-.45x = -.99

Divide each side by -.45

-.45x./-.45 = -.99/-.45

x = 11/5

x = 2.2

Answer:

E. The parameter is μmale - μfemale and the statistic is xmale - xfemale.

Step-by-step explanation:

The sample statistic is a piece of information about the individuals or objects that were selected from a given population. The sample is just a fraction of the total population. Since it is a herculean task studying an entire population, the sample forms a manageable size that allows us to have an insight into the entire population. The sample statistics are now the piece of information about the sample being studied such as the average, mean, median, or mode.  The sample statistics have to be as specific as possible of the factors being measured. In the question, we would have to obtain the mean of both the male and female genders. This gives us an insight into the population under study.

The parameter, on the other hand, is a description of the entire population being studied. For example, we might want to determine the population mean. That is the factor we seek to measure. It is represented by the sign mu (μ).  

Answer:

1. Test statistic t=1.581.

2. The null hypothesis H0 failed to be rejected.

There is not enough evidence to support the claim that the mean number of calls per salesperson per week is significantly more than 41.

NOTE: if the null hypothesis is µ = 40, there is enough evidence to support the claim that the mean number of calls per salesperson per week is significantly more than 40 (test statistic t=3.161).

Step-by-step explanation:

This is a hypothesis test for the population mean.

The claim is that the mean number of calls per salesperson per week is significantly more than 41.

Then, the null and alternative hypothesis are:

[tex]H_0: \mu=41\\\\H_a:\mu> 41[/tex]

The significance level is 0.025.

The sample has a size n=38.

The sample mean is M=42.

As the standard deviation of the population is not known, we estimate it with the sample standard deviation, that has a value of s=3.9.

The estimated standard error of the mean is computed using the formula:

[tex]s_M=\dfrac{s}{\sqrt{n}}=\dfrac{3.9}{\sqrt{38}}=0.633[/tex]

Then, we can calculate the t-statistic as:

[tex]t=\dfrac{M-\mu}{s/\sqrt{n}}=\dfrac{42-41}{0.633}=\dfrac{1}{0.633}=1.581[/tex]

The degrees of freedom for this sample size are:

[tex]df=n-1=38-1=37[/tex]

This test is a right-tailed test, with 37 degrees of freedom and t=1.581, so the P-value for this test is calculated as (using a t-table):

[tex]\text{P-value}=P(t>1.581)=0.061[/tex]

As the P-value (0.061) is bigger than the significance level (0.025), the effect is not significant.

The null hypothesis failed to be rejected.

There is not enough evidence to support the claim that the mean number of calls per salesperson per week is significantly more than 41.

For µ = 40:

This is a hypothesis test for the population mean.

The claim is that the mean number of calls per salesperson per week is significantly more than 40.

Then, the null and alternative hypothesis are:

[tex]H_0: \mu=40\\\\H_a:\mu> 40[/tex]

The significance level is 0.025.

The sample has a size n=38.

The sample mean is M=42.

As the standard deviation of the population is not known, we estimate it with the sample standard deviation, that has a value of s=3.9.

The estimated standard error of the mean is computed using the formula:

[tex]s_M=\dfrac{s}{\sqrt{n}}=\dfrac{3.9}{\sqrt{38}}=0.633[/tex]

Then, we can calculate the t-statistic as:

[tex]t=\dfrac{M-\mu}{s/\sqrt{n}}=\dfrac{42-40}{0.633}=\dfrac{2}{0.633}=3.161[/tex]

The degrees of freedom for this sample size are:

[tex]df=n-1=38-1=37[/tex]

This test is a right-tailed test, with 37 degrees of freedom and t=3.161, so the P-value for this test is calculated as (using a t-table):

[tex]\text{P-value}=P(t>3.161)=0.002[/tex]

As the P-value (0.002) is smaller than the significance level (0.025), the effect is significant.

The null hypothesis is rejected.

There is enough evidence to support the claim that the mean number of calls per salesperson per week is significantly more than 40.  

Answer: (d) 88/ 2π

Step-by-step explanation:

Perimeter = 88m

Perimeter of a circle = 2πr

88 = 2π x r

r = 88 / 2π

Answer:

88/2π​ = r

Step-by-step explanation:

The circumference is 88 m

The circumference is given by

C = 2*pi*r

88 = 2 * pi *r

Divide each side by 2 pi

88 / 2pi = 2 * pi *r / 2 * pi

88 / 2 pi = r

Answer:

45 premium tickets were sold

Step-by-step explanation:

p = premium

d = deluxe

r = regular

p+d+r = 273

6p+4d + 2r = 836

118+d = r

Replace r with 118+d

p+d+118+d = 273

p +2d = 273-118

p+2d = 155

6p+4d + 2(118+d) = 836

6p+4d + 236+2d = 836

6p +6d = 836-236

6p + 6d = 600

Divide by 6

p+d = 100

d = 100-p

Replace d in p +2d= 155

p +2(100-p) = 155

p+200-2p = 155

-p = 155-200

-p =-45

p =45

45 premium tickets were sold

Answer:

Step-by-step explanation

We get three linear equations from the information given, where

p= number of premium tickets

d = number of deluxe tickets

r = number of regular tickets:

[tex]\left \{ {{p+d+r=273} \atop \\{6p+4d+2r=836} \right.[/tex]

and the applying third r=118+d, we get

[tex]\left \{ {p+d+118+d=273} \atop {6p+4d+2d+236=836}} \right.[/tex]

[tex]\left \{ {{p+2d=115} \atop {6p+6d=600}} \right.[/tex]

Now we get from the upper one

p=115-2d

solving the another equation gives us

6*115-12d+6d=600,

hence d=15

and by replacing

p=115-2*15=85.

85 premium tickets were sold

Answer:

Quad 1

Step-by-step explanation:

Answer:

a) Test statistic = 1.960

b) The critical values include -2.50 and 2.50.

The critical regions of rejection are thus

t < -2.50 or t > 2.50

c) The sketch of the curve is presented in the attached image to this solution. The shaded parents indicate the rejection regions.

d) The t-statistic obtained (1.96), lies within the acceptance region (-2.50 ≤ x ≤ 2.50), we fail to reject the null hypothesis.

Step-by-step explanation:

a) Test statistic is computed using the expression

t = (x - μ₀)/σₓ

x = Sample mean = 104.2

μ₀ = the standard we are comparing Against

σₓ = standard error of the mean = (σ/√n)

σ = 9.6

n = Sample size = 24

σₓ = (9.6/√24) =

t = (0.425 - 0.35) ÷ 0.07816

t = 1.9595917942 = 1.960

b) To obtain these critical values, we first find the degree of freedom

Degree of freedom = n - 1 = 24 - 1 = 23

The critical values for significance level of 0.01 and degree of freedom of 23 is given as

t(0.01, 23) = 2.50

So, since the test is two-tailled (we are testing in both directions; greater than or less than), the regions of rejection include

t < -2.50 and t > 2.50

c) since the test is two-tailled (we are testing in both directions; greater than or less than), the regions of rejection include

t < -2.50 and t > 2.50

The t-distribution curve is very similar to the normal distribution curve. The t-distribution curve is also a bell shaped curve, but it is heavier at the limits indicating that the t-distribution favours outliers more than the normal distribution.

The sketch of the curve is presented in the attached image with the shaded regions indicating the rejection region.

d) Since the t-statistic obtained (1.96), lies within the acceptance region (-2.50 ≤ x ≤ 2.50), we fail to reject the null hypothesis.

Hope this Helps!!!

Answer:

-4x -11

Step-by-step explanation:

-(x + 5) - 3(x + 2)

Distribute

-x -5  -3x -6

Combine like terms

-x-3x   -5-6

-4x -11

Answer:

[tex] = - (4x + 11)[/tex]

Step-by-step explanation:

[tex]-(x + 5) - 3(x + 2) \\ -x - 5 - 3x - 6 \\ -x - 3x -5 - 6 \\ - 4x - 11 \\ = -(4x + 11)[/tex]

Answer:

Step-by-step explanation:

Hello friend

The answer is 5:15 in 12 hour clock

Answer:

5:15 PM

Step-by-step explanation:

12:00 + 5:00

17:00 in 12 hour clock is 5:00 PM.

15 minutes + 5:00 PM

⇒ 5:15 PM

Answer:

50%

Step-by-step explanation:

The numbers that are not odd are 2, 4, and 6 on a dice.

3 numbers out of 6.

3/6 = 1/2 = 0.5

P(not odd)= 50%

Answer:

4320 minutes

Step-by-step explanation:

Recall,

1 day --->  24 hours

but each hour has 60 minutes, hence 1 day can also be expressed:

1 day -----> 24 x 60 = 1440 minutes

3 days -----> 1440 min/day  x 3 days = 4320 minutes

Answer: 4,320 minutes

Step-by-step explanation: 1 day = 1440 days. 1440 * 3 = 4,320 minutes

Answer:

ln e = 1

ln e 2x = 2x

ln 1 = 0

Step-by-step explanation:

ln e

ln(2.718282) = 1

In e 2x

ln(2.718282)(2)x = 2x

ln 1 = 0

Answer:

(a) [tex]\frac{1}{13}[/tex]

(b) [tex]\frac{3}{13}[/tex]

(c) [tex]\frac{10}{13}[/tex]

Step-by-step explanation:

The probability of an event B occurring is given by;

P(B) =  [tex]\frac{n(E)}{n(S)}[/tex]

Where;

P(B) = probability of the event B

n(E) = number of favourable outcomes

n(S) = total number of events in the sampled space.

From the question, the card is drawn randomly from a standard 52-card deck. The probability of

(a) drawing a "king" card is analyzed as follows.

Let the event of drawing the "king" card be B.

In a standard 52-card deck, the number of cards that are of type king is 4. i.e 1 from the diamond pack, 1 from the spade pack, 1 from the heart pack and 1 from the club pack.

Therefore, the number of favourable outcomes is 4, while the total number of events in the sampled space is 52.

The probability of drawing a "king" card, P(B) is;

P(B) = [tex]\frac{4}{52}[/tex]

P(B) = [tex]\frac{1}{13}[/tex]

(b) drawing a "face" card is analyzed as follows.

Let the event of drawing the "face" card be B.

In a standard 52-card deck, a face card can either be a Jack, Queen or a King. There are 4 Jack cards, 4 Queen cards and 4 King cards in the deck.  The number of cards that are of type face is 12.

Therefore, the number of favourable outcomes is 12, while the total number of events in the sampled space is 52.

The probability of drawing a "face" card, P(B) is;

P(B) = [tex]\frac{12}{52}[/tex]

P(B) = [tex]\frac{3}{13}[/tex]

(c) drawing a card that is not a "face" is analyzed as follows;

The sum of the probability of drawing a face card and the probability of not drawing a face card is always 1.

Let the event of drawing a "face" card be B and the event of not drawing a "face" card be C.

P(B) + P(C) = 1

P(C) = 1 - P(B)

From (b) above, the P(B) = [tex]\frac{3}{13}[/tex]

Therefore,

P(C) = 1 - [tex]\frac{3}{13}[/tex]

P(C) = [tex]\frac{10}{13}[/tex]