PLEASE HELP MEEEE HURRRY!!! :)

PLEASE HELP MEEEE HURRRY!!! :)

Answers

Answer 1

Answer:

Option D

Step-by-step explanation:

We are given the following equations -

[tex]\begin{bmatrix}-5x-12y-43z=-136\\ -4x-14y-52z=-146\\ 21x+72y+267z=756\end{bmatrix}[/tex]

It would be best to solve this equation in matrix form. Write down the coefficients of each terms, and reduce to " row echelon form " -

[tex]\begin{bmatrix}-5&-12&-43&-136\\ -4&-14&-52&-146\\ 21&72&267&756\end{bmatrix}[/tex]  First, I swapped the first and third rows.

[tex]\begin{bmatrix}21&72&267&756\\ -4&-14&-52&-146\\ -5&-12&-43&-136\end{bmatrix}[/tex]  Leading coefficient of row 2 canceled.  

[tex]\begin{bmatrix}21&72&267&756\\ 0&-\frac{2}{7}&-\frac{8}{7}&-2\\ -5&-12&-43&-136\end{bmatrix}[/tex]  The start value of row 3 was canceled.

[tex]\begin{bmatrix}21&72&267&756\\ 0&-\frac{2}{7}&-\frac{8}{7}&-2\\ 0&\frac{36}{7}&\frac{144}{7}&44\end{bmatrix}[/tex]       Matrix rows 2 and 3 were swapped.

[tex]\begin{bmatrix}21&72&267&756\\ 0&\frac{36}{7}&\frac{144}{7}&44\\ 0&-\frac{2}{7}&-\frac{8}{7}&-2\end{bmatrix}[/tex]      Leading coefficient in row 3 was canceled.

[tex]\begin{bmatrix}21&72&267&756\\ 0&\frac{36}{7}&\frac{144}{7}&44\\ 0&0&0&\frac{4}{9}\end{bmatrix}[/tex]

And at this point, I came to the conclusion that this system of equations had no solutions, considering it reduced to this -

[tex]\begin{bmatrix}1&0&-1&0\\ 0&1&4&0\\ 0&0&0&1\end{bmatrix}[/tex]

The positioning of the zeros indicated that there was no solution!

Hope that helps!


Related Questions

Which property of equality was used to solve this equation?

Answers

Answer:

Division property of equality

Step-by-step explanation:

They are dividing both sides.

If we transform the parabola y = (x + 1)2 + 2 by shifting 7 units to the right and 5 units down, what is the vertex of the resulting parabola? ( a0, a1)

Answers

Answer:

(6,-3)

Step-by-step explanation:

Translate into an algebraic expressions: a x is increased by 50% and decreased by 30% . What is the result?

Answers

Answer:

Step-by-step explanation:

If x is increased by 50%, it means that the amount by which x is increased is

50/100 × x = 0.5 × x = 0.5x

The new value of x would be

x + 0.5x = 1.5x

If the new value is further decreased by 30%, it means that the amount by which it was decreased is

30/100 × 1.5x = 0.3 × 1.5x = 0.45x

The new value of x would be

1.5x - 0.45x = 1.05x

Therefore, the result is 1.05x

The tread life of a particular brand of tire is a random variable best described by a normal distribution with a mean of 60,000 miles and a standard deviation of 2900 miles. What is the probability a particular tire of this brand will last longer than 57,100 miles

Answers

Answer:

84.13% probability a particular tire of this brand will last longer than 57,100 miles

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question, we have that:

[tex]\mu = 60000, \sigma = 2900[/tex]

What is the probability a particular tire of this brand will last longer than 57,100 miles

This is 1 subtracted by the pvalue of Z when X = 57100. So

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{57100 - 60000}{2900}[/tex]

[tex]Z = -1[/tex]

[tex]Z = -1[/tex] has a pvalue of 0.1587

1 - 0.1587 = 0.8413

84.13% probability a particular tire of this brand will last longer than 57,100 miles

Which is an expression in square units that represents the area of the shaded segment of C. Geometry

Answers

Answer:

[tex] \frac{1}{2} {r}^{2} ( \frac{1}{2}\pi - 1)[/tex]

option D is the right option.

solution,

Area of shaded region:

Area of sector-Area of

[tex] = \frac{90}{360} \times \pi {r}^{2} - \frac{1}{2} \times r \times r \\ = \frac{1}{4} \pi {r}^{2} - \frac{1}{2} {r}^{2} \\ = \frac{1}{2} {r}^{2} ( \frac{1}{2} \pi - 1)[/tex]

Hope this helps...

Good luck on your assignment..

The  expression in square units that represents the area of the shaded segment of C. Geometry is [tex]\frac{1}{2}r^2(\frac{1}{2}\pi - 1)[/tex]

Calculation of the expression:

Since we know that

The area of the shaded region = Area of the sector - an area of a triangle

So,

[tex]= \frac{90}{360} \times \pi r^2 - \frac{1}{2} \times r\times r\\\\ = \frac{1}{4}\pi r^2 - \frac{1}{2}r^2 \\\\= \frac{1}{2}r^2(\frac{1}{2}\pi - 1)[/tex]

hence, The  expression in square units that represents the area of the shaded segment of C. Geometry is [tex]\frac{1}{2}r^2(\frac{1}{2}\pi - 1)[/tex]

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A boy has 27 cubes, each with sides the length of 1cm. He uses these cubes to build one big cube. What is the volume of the big cube?

Answers

Answer:54

volume:side*side*side

side:1 cm*1 cm *1 cm      

answer=icm

When the factors of a trinomial are (x + p) and (x + 9) then the constant term
of the trinomial is:

Answers

Answer:

9p

Step-by-step explanation:

(x + p)(x + 9) =

= x^2 + 9x + px + 9p

= x^2 + (9 + p)x + 9p

The constant term is 9p.

A certain three​-cylinder combination lock has 65 numbers on it. To open​ it, you turn to a number on the first​ cylinder, then to a second number on the second​ cylinder, and then to a third number on the third cylinder and so on until a three​-number lock combination has been effected. Repetitions are​ allowed, and any of the 65 numbers can be used at each step to form the combination.​ What is the probability of guessing a lock combination on the first​ try?

Answers

Answer:

  1/275,625 ≈ 3.641×10^-6

Step-by-step explanation:

There are 65×65×65 = 274,625 possible combinations. The probability of guessing the correct one is 1/275,625 ≈ 3.641×10^-6.

A 50 gram sample of a substance that's

used to treat thyroid disorders has a k

value of 0.1137.

Answers

The question is incomplete. Here is the complete question.

A 50 gram sample of a substance that's used to treat thyroid disorders has a k-value of 0.1137. Find the substance's half-life, in days. Round your answer to the nearest tenth.

Answer: [tex]t_{1/2}[/tex] = 6.1 days

Step-by-step explanation: Half-life is the amount of time necessary for a substance to reduce to half of its initial value.

To determine half-life through mass of a substance:

[tex]N = N_{0}.e^{-kt_{1/2}}[/tex]

Initially, there are 50 grams. After 1 half-life, there are 25 grams:

[tex]25 = 50.e^{-0.1137.t_{1/2}}[/tex]

[tex]\frac{25}{50} = e^{-0.1137.t_{1/2}}[/tex]

[tex]\frac{1}{2} = e^{-0.1137.t_{1/2}}[/tex]

[tex]ln (\frac{1}{2} ) = ln (e^{-0.1137.t_{1/2}})[/tex]

ln(1) - ln(2) = -0.1137.[tex]t_{1/2}[/tex]

[tex]t_{1/2} = \frac{- ln(2)}{- 0.1137}[/tex]

[tex]t_{1/2} =[/tex] 6.1

The half-life of the sample substance is 6.1 days.

If other factors are held constant, which set of sample characteristics is most likely to reject a null hypothesis stating that m

Answers

Answer:

M = 90 for a sample of n = 100

Step-by-step explanation:

The correct order of the steps of a hypothesis test is given following  

1. Determine the null and alternative hypothesis.

2. Select a sample and compute the z - score for the sample mean.

3. Determine the probability at which you will conclude that the sample outcome is very unlikely.

4. Make a decision about the unknown population.

These steps are performed in the given sequence to test a hypothesis.

The null hypothesis is rejected or accepted on the basis of level of significance. When the p-value is greater than level of significance we fail to reject the null hypothesis and null hypothesis is then accepted. It is not necessary that all null hypothesis will be rejected at 10% level of significance or M = 90 with s sample of n = 100. To determine the criteria for accepting or rejecting a null hypothesis we should also consider p-value.

Select the equation that most accurately depicts the word problem. One-half of a certain number is 95. - n = 95 + n = 95 • n = 95 ÷ n = 95

Answers

Answer:

[tex] n * \frac{1}{2} = 95 [/tex]

Step-by-step explanation:

Required:

Select the equation that most accurately depicts the word problem

One-half of a certain number is 95.

Take the certain number to be n.

This statement in equation form will be:[tex] n * \frac{1}{2} = 95 [/tex]

Therefore, the equation that most accurately depicts the word problem is [tex] n * \frac{1}{2} = 95 [/tex]

Although your options are incomplete, but this answer is correct.

The * symbol can be replaced with a dot sign

Answer:

up up up up

Step-by-step explanation:

How many ways can you distribute $4$ identical balls among $4$ identical boxes?

Answers

Answer:

5 ways

Step-by-step explanation:

We have to name the cases.

1. 4 - 0 - 0 - 0

2. 3 - 1 - 0 - 0

3. 2 - 2 - 0 - 0

4. 2 - 1 - 1 - 0

5. 1 - 1 - 1 - 1

We don't name 0 - 0 - 1 - 3 or 0 - 1 - 1 - 2 etc. because it is the same thing.

There are 35 ways to distribute 4 identical balls among 4 identical boxes

How to determine the number of ways?

The given parameters are:

Balls, n = 4

Boxes, r = 4

The number of ways is then calculated as:

(n + r - 1)C(r - 1)

This gives

(4 + 4 - 1)C(4 - 1)

Evaluate

7C3

Apply the combination formula

7C3 = 7!/((7 - 3)! * 3!)

Evaluate the difference

7C3 = 7!/(4! * 3!)

Evaluate the expression

7C3 = 35

Hence, the number of ways is 35

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can you answer with explanation how its answer is 0.63?? Aja's favorite cereal is running a promotion that says 1-in-4 boxes of the cereal contain a prize. Suppose that Aja is going to buy 5 boxes of this cereal, and let X represent the number of prizes she wins in these boxes. Assume that these boxes represent a random sample, and assume that prizes are independent between boxes. What is the probability that she wins at most 1 prize in the 5 boxes

Answers

Let n = total boxes (5)

Probability (p) = 1 out of 4 = 1/4 = 0.25

Probability she wins at most 1 out of 5 is p(x <=1) Which is also = p (x =0) + p(x=1)

Probability of not winning would be 0.75 ( 1-0.25)

No prizes in 5 boxes = 0.75^5

1 prize in 5 boxes = 5 x 0.25 x 0.75^4

Total probability = 0.75^5 + 5 x 0.25 x 0.75^4 = 0.63

Answer: 0.63

Step-by-step explanation:

True or False?
2+3x=5
If x is 1.1?

Answers

Answer:

False

Step-by-step explanation:

2 + 3x = 5

Put x as 1.1.

2 + 3(1.1) = 5

2 + 3.3 = 5

5.3 = 5

False.

Answer:

False

Solution,

X=1.1

[tex]2 + 3x = 5 \\ 2 + 3 \times 1.1 = 5 \\ 2 + 3.3 = 5 \\ 5.3 = 5 \: \: \\ hence \: it \: is \: false[/tex]

The Ericsson method is one of several methods claimed to increase the likelihood of a baby girl. In a clinical​ trial, results could be analyzed with a formal hypothesis test with the alternative hypothesis of pgreater than​0.5,which corresponds to the claim that the method increases the likelihood of having a​ girl, so that the proportion of girls is greater than 0.5. If you have an interest in establishing the success of the​ method, which of the following​ P-values would you​ prefer: 0.999,​ 0.5, 0.95,​ 0.05, 0.01,​ 0.001? Why?

Answers

Answer:

0.001

Step-by-step explanation:

Here, the aim is to support the null hypothesis, Ha. Where Ha: p > 0.5. Which means we are to reject null hypothesis H0. Where H0: p = 0.5.

The higher the pvalue, the higher the evidence of success. We know If the pvalue is less than level of significance, the null hypothesis H0 is rejected.

Hence the smallest possible value 0.001 is preferred as the pvalue because it corresponds to the sample evidence that most strongly supports the alternative hypothesis that the method is effective

Express as a ratio in the lowest term
1. 360 metres to 3 kilometres
2. 2 minutes to 14 seconds​

Answers

Answer:

1. 3:25

2. 60:7

Step-by-step explanation:

To express the ratio in the lowest terms:

1. 360 metres to 3 kilometres

First of all, we need to convert both the terms in same unit.

Let us convert kilometres to metres for simplicity.

We know that 1 km = 1000 m

So, 3 km = 3000 m

Hence, the ratio can be represented as:

[tex]360\ m: 3000\ m\\\Rightarrow \dfrac{360}{3000}\\ \\\text{Dividing by 10:}\\\Rightarrow \dfrac{36}{300}\\\\\text{Dividing by 12:}\\\Rightarrow \dfrac{3}{25}\\\Rightarrow 3:25[/tex]

So, the simplest ratio is 3:25.

2. 2 minutes to 14 seconds​

Converting minutes to seconds.

1 minute = 60 seconds

2 minutes = 120 seconds

So, the ratio can be written as:

120 seconds : 14 seconds

Dividing by 2:

60:7

So, the simplest form is 60:7.

The answers are:

1. 3:25

2. 60:7

Subtracting polynomials

Answers

Answer:

The other polynomial is 11x^2 -3x

Step-by-step explanation:

12x^2 -5x  - ( x^2 -2x) = other polynomial

Distribute the minus sign

12x^2 -5x  -  x^2 +2x

Combine terms

11x^2 -3x

The other polynomial is 11x^2 -3x

Option 3

As we should subtract the polynomials with same power

So 12x^2-x^2= 11x^2

And same for x term

Hope it help

Plz rate

6.1.3
What requirements are necessary for a normal probability distribution to be a standard normal probability distribution?

Answers

Answer:

The requirements that are necessary for a normal probability distribution to be a standard normal probability distribution are µ = 0 and σ = 1.

Step-by-step explanation:

A normal-distribution is an accurate symmetric-distribution of experimental data-values.  

If we create a histogram on data-values that are normally distributed, the figure of columns form a symmetrical bell shape.  

If X [tex]\sim[/tex] N (µ, σ²), then [tex]Z=\frac{X-\mu}{\sigma}[/tex], is a standard normal variate with mean, E (Z) = 0 and Var (Z) = 1. That is, Z [tex]\sim[/tex] N (0, 1).

The distribution of these z-variates is known as the standard normal distribution.

Thus, the requirements that are necessary for a normal probability distribution to be a standard normal probability distribution are µ = 0 and σ = 1.


Fill in the green box.

Answers

Answer:

y=6

solution,

Similar Right triangles:

[tex] \frac{c}{h} = \frac{h}{d} \\ {h}^{2} = cd \\ {y}^{2} = 4 \times 9 \\ {y = 36 }^{2} \\ y = \sqrt{ {(6)}^{2} } \\ y = 6[/tex]

Hope this helps..

Good luck on your assignment..

Answer:whats the measure of x i really need help

Step-by-step explanation:

Find the sum of the positive divisors of 18.

Answers

Answer:

39

Step-by-step explanation:

factors of 18= 1, 2, 3, 6, 9, 18

1+2+3+6+9+18=39

Answer:

  39

Step-by-step explanation:

The divisors of 18 are ...

  1, 2, 3, 6, 9, 18

Their sum is ...

  1 + 2 + 3 + 6 + 9 + 18 = 39

The International Air Transport Association surveys business travelers to develop quality ratings for transatlantic gateway airports. The maximum possible rating is 10. Suppose a simple random sample of 50 business travelers is selected and each traveler is asked to provide a rating for the Miami International Airport. The ratings obtained from the sample of 50 business travelers follow.
Click on the datafile logo to reference the data.
6 4 6 8 7 7 6 3 3 8 10 4 8
7 8 7 5 9 5 8 4 3 8 5 5 4
4 4 8 4 5 6 2 5 9 9 8 4 8
9 9 5 9 7 8 3 10 8 9 6
Develop a 95% confidence interval estimate of the population mean rating for Miami. If required, round your answers to two decimal places. Do not round intermediate calculations.

Answers

Answer:

The 95% confidence interval estimate of the population mean rating for Miami is (5.7, 7.0).

Step-by-step explanation:

The (1 - α)% confidence interval for the population mean, when the population standard deviation is not provided is:

[tex]CI=\bar x\pm t_{\alpha/2, (n-1)}\cdot\ \frac{s}{\sqrt{n}}[/tex]

The sample selected is of size, n = 50.

The critical value of t for 95% confidence level and (n - 1) = 49 degrees of freedom is:

[tex]t_{\alpha/2, (n-1)}=t_{0.05/2, 49}=2.000[/tex]

*Use a t-table.

Compute the sample mean and sample standard deviation as follows:

[tex]\bar x=\frac{1}{n}\sum {x}=\frac{1}{50}\times [6+4+6+...+9+6]=6.34\\\\s=\sqrt{\frac{1}{n-1}\sum (x-\bar x)^{2}}=\sqrt{\frac{1}{50-1}\times 229.22}=2.163[/tex]

Compute the 95% confidence interval estimate of the population mean rating for Miami as follows:

[tex]CI=\bar x\pm t_{\alpha/2, (n-1)}\cdot\ \frac{s}{\sqrt{n}}[/tex]

     [tex]=6.34\pm 2.00\times\frac{2.163}{\sqrt{50}}\\\\=6.34\pm 0.612\\\\=(5.728, 6.952)\\\\\approx(5.7, 7.0)[/tex]

Thus, the 95% confidence interval estimate of the population mean rating for Miami is (5.7, 7.0).



Write an expression:
You bought four
sandwiches that cost
$2.50 each and two
drinks that cost d
dollars each.

Answers

Answer:

2d + 10.

Step-by-step explanation:

If four sandwiches cost $2.50 each, you have 4 * 2.5.

If two drinks cost $d each, you have 2 * d.

4 * 2.5 + 2 * d

= 10 + 2d

= 2d + 10.

Hope this helps!

Suppose that the relationship between the tax rate t on imported shoes and the total sales S (in millions of dollars) is given by the function below. Find the tax rate t that maximizes revenue for the government. (Round your answer to three decimal places.)

S(t) = 7 â 6(cubedroot(t))

Answers

Answer:

66.992%

Step-by-step explanation:

[tex]Sales, S(t)=7-6\sqrt[3]{t}[/tex]

Since we want to maximize revenue for the government

Government's Revenue= Sales X Tax Rate

[tex]R(t)=t \cdot S(t)\\R(t)=t(7-6\sqrt[3]{t})\\=7t-6t^{1+1/3}\\R(t)=7t-6t^{4/3}[/tex]

To maximize revenue, we differentiate R(t) and equate it to zero to solve for its critical points. Then we test that this critical point is a relative maximum for R(t) using the second derivative test.

Now:

[tex]R'(t)=7-6*\frac{4}{3} t^{4/3-1}\\=7-8t^{1/3}[/tex]

Setting the derivative equal to zero

[tex]7-8t^{1/3}=0\\7=8t^{1/3}\\t^{1/3}=\dfrac{7}{8} \\t=(\frac{7}{8})^3\\t=0.66992[/tex]

Next, we determine that t=0.6692 is a relative maximum for R(t) using the second derivative test.

[tex]R''(t)=-8*\frac{1}{3} t^{1/3-1}\\R''(t)=-\frac{8}{3} t^{-2/3}[/tex]

R''(0.6692)=-3.48 (which is negative)

Therefore, t=0.66992 is a relative maximum for R(t).

The tax rate, t that maximizes revenue for the government is:

=0.66992 X 100

t=66.992% (correct to 3 decimal places)

In the study of a nonlinear spring with periodic​ forcing, the equation y prime prime plus ky plus ry cubedy′′+ky+ry3equals=Upper A cosine omega tAcosωt arises. Let kequals=44​, requals=33​, Aequals=77​, and omegaωequals=88. Find the first three nonzero terms in the Taylor polynomial approximation to the solution with initial values ​y(0)equals=​0, y prime (0 )y′(0)equals=1.

Answers

Answer:

[tex]\mathbf{y(t) = t + \dfrac{7}{2}t^2 - \dfrac{2}{3}t^3+ ...}[/tex]

Step-by-step explanation:

THe interpretation of the given question is as follows:

y'' + ky +  ry³ = A cos ωt

Let k = 4, r = 3, A = 7 and ω = 8

The objective is to find the first three non zero terms in the Taylor polynomial approximation to the solution with initial values y(0) = 0 ; y' (0) = 1

SO;

y'' + ky " ry³ = A cos ωt

where;

k = 4, r = 3, A = 7 and ω = 8

y(0) = 0 ; y' (0) = 1

y'' + 4y + 3y³ = 7 cos 8t

y'' = - 4y - 3y³ + 7 cos 8t     ---- (1)

y'' (0) = -4y(0) - 3y³(0) + 7 cos (0)

y'' (0) = - 4 × 0 - 3 × 0 + 7

y'' (0) = 7

Differentiating equation (1) with respect to  t ; we have:

y''' = - 4y' - 9y² × y¹ - 56 sin 8t

y''' (0) = -4y'(0) - 9y²(0)× y¹ (0) - 56 sin (0)

y''' (0) = - 4 × 1  - 9 × 0 × 1 - 56 × 0

y''' (0) = - 4

Thus; we have :

y(0) = 0  ; y'(0) = 1  ; y'' (0) = 7 ; y'''(0) = -4

Therefore; the Taylor polynomial approximation to the first three nonzero terms is :

[tex]y(t) = y(0) + y'(0) t + y''(0) \dfrac{t^2}{2!} + y'''(0) \dfrac{t^3}{3!}+...[/tex]

[tex]y(t) = 0 + t + 7 \dfrac{t^2}{2!} + \dfrac{-4}{3!} {t^3}+ ...[/tex]

[tex]\mathbf{y(t) = t + \dfrac{7}{2}t^2 - \dfrac{2}{3}t^3+ ...}[/tex]

cube root of 99 is 4.626 find the cube root of 792​

Answers

Answer:

the answer is: 9.25

Step-by-step explanation:

the cube root of 792 is approximately 9.252.

To find the cube root of 792, we can use the relationship between cube roots and cube numbers.

If the cube root of 99 is approximately 4.626, we can use this information to find the cube root of 792.

Let's calculate the cube root of 792 using the relationship:

(cube root of 792) = (cube root of 99) * (cube root of 8)

Since 792 is equal to 99 multiplied by 8 (792 = 99 * 8), we can rewrite the equation as:

(cube root of 792) = (4.626) * (cube root of 8)

Now, we need to find the cube root of 8:

(cube root of 8) = 2

Substituting this value back into the equation, we get:

(cube root of 792) = (4.626) * (2) = 9.252

Therefore, the cube root of 792 is approximately 9.252.

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Combine the like terms to create an equivalent expression: -12 - 6p - (-2)

Answers

Answer:

-6p -10

Step-by-step explanation:

-12 - 6p - (-2)

Subtracting a negative is like adding

-12 - 6p + (2)

Combine like terms

-6p -12+2

-6p -10

Answer:

-6p=10

Step-by-step explanation:

-12 - 6p - (-2)  to combine like expression

-12-6p+2

-6p-10 to create equivalent expression an equal sign is used

-6p=10

What is the domain of the relation graphed below?

Answers

Answer:

domain: (-4,4)

Step-by-step explanation:

i'm not sure if it has brackets because it doesn't have point that are on x-intervals -4 and 4

For a specific location in a particularly rainy city, the time a new thunderstorm begins to produce rain (first drop time) is uniformly distributed throughout the day and independent of this first drop time for the surrounding days. Given that it will rain at some point both of the next two days, what is the probability that the first drop of rain will be felt between 8:25 AM and 3:30 PM on both days? a) O 0.2951 b) 0.9137 c) 0.0871 d) 0.2938 e) 0.0863 f) None of the above.

Answers

Answer:

c) 0.0871

Step-by-step explanation:

An uniform probability is a case of probability in which each outcome is equally as likely.

For this situation, we have a lower limit of the distribution that we call a and an upper limit that we call b.

The probability that we find a value X between c and d is given by the following formula.

[tex]P(c \leq X \leq d) = \frac{d - c}{b - a}[/tex]

On a single day:

24 hours, so [tex]a = 0, b = 24[/tex]

8:25 P.M. is 8:25 = 8.4167h

3:30 P. M. is the equivalent to 12 + 3:30 = 15:30 = 15.5h

Probability of rain between these times:

[tex]P(8.4167 \leq X \leq 15.5) = \frac{15.5 - 8.4167}{24 - 0} = 0.2951[/tex]

On both days:

Two days, each with a 0.2951 probability

0.2951*0.2951 = 0.0871

The correct answer is:

c) 0.0871

Write the equation of each line in slope intercept form (If possible please show work)

Answers

Answer:

y= -2/3 x - 9

Step-by-step explanation:

The slope intercept form is

y = mx+b where m is the slope and b is the y intercept

y = -2/3 x+b

We have a point to substitute into the equation

-5 = -2/3(-6) +b

-5 = 4 +b

Subtract 4 from each side

-5-4 = 4-4+b

-9 = b

y= -2/3 x - 9

The sum of two intcgers is -6. If one of them is 2, then the other is
(a) 4
(b) 4
(c) 8
(d) -8​

Answers

Answer:

D) -8

Step-by-step explanation:

If you add a positive and a negative, you end up subtracting. If your sum is lower than any of the numbers you are adding together, then there is a negative. In this case, your only negative number is -8, but if there were others, you could find this equation by doing negative six minus two (because the equation was originally addition, it would still be subtraction to check your work or find the answer in this case.)

Hopefully you find this useful :)

Answer:   -8

Step-by-step explanation:    lets take the unknown number as x,

so we have, 2 + x= -6

                 by using transposition method, x= -6-2( positive becomes  

                                                                       negative when transpositioning)

      so, x= -8                      

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