Please help me with the question below! Thank you,Fine the domain and range of the graph

Answer:

A

Step-by-step explanation:

angle A is 90 and c and b have to be equal

Answer:

Step-by-step explanation:

45.10

Answer:

Answer attached

Answer: B C D

Step-by-step explanation:

just answered it for AP3X

Reasons used in the proof that the angle-bisector construction can be used to bisect any angle are as follows:

B. All of the radii of a circle are congruent

C .CPCTC

D. SSS triangle congruence postulate

" Angle bisector is defined as the ray which divides the angle into two equal parts."

According to the question,

A. Any Line segment can be extended indefinitely is not required to bisect any angle .

Therefore , it is not a correct option.

B. All of the radii of a circle are congruent : To bisect an angle draw an arc with same radii is used in constructing an angle bisector .

Therefore , Option B is a correct option.

C. CPCTC : Corresponding parts of a congruent triangle are congruent is required to proof angle bisector. As it proofs two triangles are congruent.

Therefore, Option C is the correct option.

D. SSS triangle congruence postulate : It is required an important step to prove that two triangles are congruent which imply proof of angle - bisector construction.

Therefore, Option D is the correct option.

Hence, Option B, Option C , Option D are the correct answer.

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Answer:

See below hot to plot.

Step-by-step explanation:

You did part a correctly and now have 3 points of this graph. For part b you need to plot the line by first plotting the points.

Plot the points on the graph and then connect them with a line.

The three points are (-5, -3), (0, 2), and (3, 5).

To plot (-5, -3):

Start at (0, 0), the origin, where the x-axis and y-axis intersect.

Go 5 units left to the -5. Now go 3 units down. That is point (-5, -3). Put a dot on it.

To plot (0, 2):

Start at (0, 0), the origin, where the x-axis and y-axis intersect.

Since the x-coordinate is 0, don't go right or left. Now go 2 units up to where you see a 2 on the y-axis. That is point (0, 2). Put a dot on it.

To plot (3, 5):

Start at (0, 0), the origin, where the x-axis and y-axis intersect.

Go 3 units right to the 3 on the x-axis. Now go 5 units up. That is point (3, 5). Put a dot on it.

Now connect the three dots with a line. Put arrow heads at both ends of the line.

Answer:

Hope this helps

Answer:

A. It is a series of points that fall in a straight line but are unconnected.

Step-by-step explanation:

Given variables y and x, and a proportional factor k, the proportional relationship is :

y/x = k or y = k*x

This means that points fall in a straight line.

Discrete data means that the function is also discrete, that is, points are not connected between them like in a continuous function.

Answer:

its a

Step-by-step explanation:

got it right

Answer:

I would say that it is A

Step-by-step explanation:

Answer:

C

Step-by-step explanation:

The number of buttons in C is 17 buttons

What is an Equation?

Equations are mathematical statements with two algebraic expressions flanking the equals (=) sign on either side.

It demonstrates the equality of the relationship between the expressions printed on the left and right sides.

Coefficients, variables, operators, constants, terms, expressions, and the equal to sign are some of the components of an equation. The "=" sign and terms on both sides must always be present when writing an equation.

Given data ,

Let the three tins be A , B and C respectively

The number of buttons in tin A = x

The number of buttons in tin B = 4 times the number of buttons in tin A

                                                   = 4x

The number of buttons in tin C = 7 fewer buttons than tin A

                                                    = x - 7

The total number of buttons in tin A , tin B and tin C together = 137 buttons

So , the total number of buttons =
number of buttons in tin A + number of buttons in tin B + number of buttons in tin C

So , the equation will be

Total number of buttons = x + 4x + ( x - 7 )

x + 4x + ( x - 7 ) = 137

6x - 7 = 137

Adding 7 on both sides , we get

6x = 144

Divide by 6 on both sides , we get

x = 24 buttons

So , the number of buttons in tin A is 24 buttons

So , number of buttons in tin B = 4 x 24

                                                   = 96 buttons

Therefore , the number of buttons in tin C = 17 buttons

Hence , the number of buttons in tin C is 17 buttons

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Answer:

(a) The probability that a male is selected, then two females is 0.4352.

(b) The probability that a female is selected, then two males is 0.3348.

(c) The probability that two females are selected, then one male is 0.4352.

(d) The probability that three males are selected is 0.0717.

(e) The probability that three females are selected is 0.1583.

Step-by-step explanation:

We are given that a math class consists of 25 students, 14 female and 11 male. Three students are selected at random to participate in a probability experiment.

(a) The probability that a male is selected, then two females is given by;

Number of ways of selecting a male from a total of 11 male = [tex]^{11}C_1[/tex]

Number of ways of selecting two female from a total of 14 female = [tex]^{14}C_2[/tex]

Total number of ways of selecting 3 students from a total of 25 = [tex]^{25}C_3[/tex]

So, the required probability =  [tex]\frac{^{11}C_1 \times ^{14}C_2}{^{25}C_3}[/tex]

                                           =  [tex]\frac{\frac{11!}{1! \times 10!} \times \frac{14!}{2! \times 12!} }{\frac{25!}{3! \times 22!} }[/tex]     {[tex]\because ^{n}C_r = \frac{n!}{r! \times (n-r)!}[/tex] }

                                           =  [tex]\frac{1001}{2300}[/tex]  =  0.4352

(b) The probability that a female is selected, then two males is given by;

Number of ways of selecting a female from a total of 14 female = [tex]^{14}C_1[/tex]

Number of ways of selecting two males from a total of 11 male = [tex]^{11}C_2[/tex]

Total number of ways of selecting 3 students from a total of 25 = [tex]^{25}C_3[/tex]

So, the required probability =  [tex]\frac{^{14}C_1 \times ^{11}C_2}{^{25}C_3}[/tex]

                                           =  [tex]\frac{\frac{14!}{1! \times 13!} \times \frac{11!}{2! \times 9!} }{\frac{25!}{3! \times 22!} }[/tex]     {[tex]\because ^{n}C_r = \frac{n!}{r! \times (n-r)!}[/tex] }

                                           =  [tex]\frac{770}{2300}[/tex]  =  0.3348

(c) The probability that two females is selected, then one male is given by;

Number of ways of selecting two females from a total of 14 female = [tex]^{14}C_2[/tex]

Number of ways of selecting one male from a total of 11 male = [tex]^{11}C_1[/tex]

Total number of ways of selecting 3 students from a total of 25 = [tex]^{25}C_3[/tex]

So, the required probability =  [tex]\frac{^{14}C_2 \times ^{11}C_1}{^{25}C_3}[/tex]

                                           =  [tex]\frac{\frac{14!}{2! \times 12!} \times \frac{11!}{1! \times 10!} }{\frac{25!}{3! \times 22!} }[/tex]     {[tex]\because ^{n}C_r = \frac{n!}{r! \times (n-r)!}[/tex] }

                                           =  [tex]\frac{1001}{2300}[/tex]  =  0.4352

(d) The probability that three males are selected is given by;

Number of ways of selecting three males from a total of 11 male = [tex]^{11}C_3[/tex]

Total number of ways of selecting 3 students from a total of 25 = [tex]^{25}C_3[/tex]

So, the required probability =  [tex]\frac{^{11}C_3}{^{25}C_3}[/tex]

                                           =  [tex]\frac{ \frac{11!}{3! \times 8!} }{\frac{25!}{3! \times 22!} }[/tex]     {[tex]\because ^{n}C_r = \frac{n!}{r! \times (n-r)!}[/tex] }

                                           =  [tex]\frac{165}{2300}[/tex]  =  0.0717

(e) The probability that three females are selected is given by;

Number of ways of selecting three females from a total of 14 female = [tex]^{14}C_3[/tex]

Total number of ways of selecting 3 students from a total of 25 = [tex]^{25}C_3[/tex]

So, the required probability =  [tex]\frac{^{14}C_3}{^{25}C_3}[/tex]

                                           =  [tex]\frac{ \frac{14!}{3! \times 11!} }{\frac{25!}{3! \times 22!} }[/tex]     {[tex]\because ^{n}C_r = \frac{n!}{r! \times (n-r)!}[/tex] }

                                           =  [tex]\frac{364}{2300}[/tex]  =  0.1583

(a) The probability that a male is selected, then two females is 0.4352.

(b) The probability that a female is selected, then two males is 0.3348.

(c) The probability that two females are selected, then one male is 0.4352.

(d) The probability that three males are selected is 0.0717.

(e) The probability that three females are selected is 0.1583.

Answer:

a)3/6 and 4/6

b)15/20 and 12/20

c)4/6 and 5/6

d)15/20 and 14/20

Step-by-step explanation:

Change the demonimator to the lowest common demonimator. What ever you do to the bottom number to get to the lowest common denominator, multiply the numerator by the same number.

Answer:

y-intercept: (0, 2.5)

x-intercept: (1.67, 0)

Step-by-step explanation:

Right now, you have 3x + 2y = 5. You want to change it into slope-intercept form to make the problem easier to solve.

2y = -3x + 5

y = -3/2x + 5/2

From here, you can see that the y-intercept is (0, 5/2). You can also say that the y-intercept is (0, 2.5).

To get the x-intercept, substitute 0 for y.

0 = -3/2x + 5/2

3/2x = 5/2

3x = 5

x = 5/3

So, the x-intercept is (5/3, 0). You can also say that the x-intercept is (1.67, 0).

Hope this helps!

Answer:

Step-by-step explanation:

To find the x-intercept, let y = 0.  Then 3x = 5 and x = 5/3, or x = 1.667, and the x-intercept is (1.667, 0).

To find the y-intercept, let x = 0.  Then 2y = 5 and y = 5/2 or 2.5.  Then the y-intercept is (0, 2.5).

Problem 9, part a)

Compass bearings always have north as the starting point. This is where 0 degrees is situated, and 360 degrees as well. As the bearing angle increases, you'll turn to the right toward the eastward direction. Effectively you're sweeping out a clockwise rotation. The bearing 322 degrees is in a northwest position as the diagram shows (place the ship at the bottom right corner of the triangle). The bottom right acute angle of the triangle is 322 - 270 = 52 degrees. This is the reference angle we'll use for finding the distance d.

With respect to the reference angle of 52 degrees, the side 18.5 is the opposite side and d is the adjacent side. Use the tangent ratio to get...

tan(angle) = opposite/adjacent

tan(52) = 18.5/d

d*tan(52) = 18.5

d = 18.5/tan(52)

d = 14.4537840903742

The approximate value of d is 14.4537840903742 km

This rounds to 14.5 when rounding to one decimal place.

=======================================================

Problem 9, part b)

Recall that

distance = rate*time

where "rate" is another term for "speed" or "velocity"

We can solve this for the time to get

time = distance/rate

------

We found the distance back in part a) above. We are given the rate of 48 km/h

So,

time = distance/rate

time = 14.4537840903742/48

time = 0.3011205018828

This is the time it takes in hours. Multiply by 60 to convert to minutes

0.3011205018828 hours = 60*0.3011205018828 = 18.067230112968 minutes

This rounds to the whole number 18

Answer:

Tash scores 40 baskets

Step-by-step explanation:

Rani = R

Layla = L

Tash = T

R = 4L

T = 4L-8

As L + R + T = 100

L + 4L + 4L-8 = 100

Collect like terms

9L - 8 = 100

+ 8 both sides

9L = 108

divide by 9 both sides

L = 108 / 9

L = 12

Now..... T = 4L-8 substitute L with 12

T = 48 - 8

T = 40

Answer:

Step-by-step explanation:

[tex]5 - 8x = - 1[/tex]

Move constant to R.H.S and change its sign:

[tex] - 8x = - 1 - 5[/tex]

Calculate

[tex] - 8x = - 6[/tex]

The difference sign (-) will be cancelled in both sides

[tex]8x = 6[/tex]

Divide both sides of the equation by 8

[tex] \frac{8x}{8} = \frac{6}{8} [/tex]

Calculate

[tex]x = \frac{3}{4} [/tex]

Hope this helps...

Good luck on your assignment...

Answer:

Hey there!

5-8x=-1

-8x=-6

x=3/4

Hope this helps!

Answer:

3200000

Step-by-step explanation:

multiply the volume value by 1000

Answer: 2(y + 6)(-y + 6)

Step-by-step explanation: Factor 72 - 2y^2

                                             -2y^2 + 72

                                             = 2(y + 6)(-y + 6)

Answer:

[tex]-2\left(y+6\right)\left(y-6\right)[/tex]

Step-by-step explanation:

[tex]72-2y^2[/tex]

[tex]-2y^2+72[/tex]

Factor out GCF.

[tex]2(-y^2+36)[/tex]

Apply difference of two squares formula.

[tex]-2\left(y+6\right)\left(y-6\right)[/tex]

Answer:

225

Step-by-step explanation:

Answer:

B. 13 quarters

Step-by-step explanation:

Let:

quarters = x = $0.25

dimes = y = $0.10

Get the set of equation:

x + y = 20

0.10y + 0.25x = 3.95

First, solve for x. Use the first equation. Isolate the x by subtracting y from both sides:

x + y (-y) = 20 (-y)

x = 20 - y

Plug in 20 - y for x in the second equation:

0.10y + 0.25(2020  - y) = 3.95

Simplify. Remember to follow PEMDAS. Isolate the variable, y.

First, multiply 0.25 to all terms within the parenthesis:

0.10y + (0.25 * 20) + (0.25 * -y) = 3.95

0.10y + 5 - 0.25y = 3.95

Combine like terms:

(-0.25y + 0.10y) + 5 = 3.95

(-0.15y) + 5 = 3.95

Isolate the variable, y. Do the opposite of PEMDAS. First, subtract 5 from both sides:

(-0.15y) + 5 (-5) = 3.95 (-5)

(-0.15y) = 3.95 - 5

-0.15y = -1.05

Isolate the variable, y. Divide -0.15 from both sides:

(-0.15y)/-0.15 = (-1.05)/-0.15

y = 1.05/0.15 = 7

y = 7

There are 7 dimes.

Plug in 7 to one of the equations in the operation for y (dimes):

x + y = 20

x + (7) = 20

Isolate the variable, x. Note the equal sign, what you do to one side, you do to the other. Subtract 7 from both sides:

x + 7 (-7) = 20 (-7)

x = 20 - 7

x = 13

There are 13 quarters.

Check: Plug in 13 for x, and 7 for y in the second equation:

0.10y + 0.25x = 3.95

0.10(7) + 0.25(13) = 3.95

0.70 + 3.25 = 3.95

3.95 = 3.95

~

Note that you are solving only for quarters. In this case, your answer will be B. 13.

~

Answer:

B. 13 Quarters

Step-by-step explanation:

So since we don't have an amt. specified like e.g there are 10 more quarters than dimes, we can only rely on guess and check.

First we can try 10 quarters --> 10 x 25 = 250 --> 395 - 250 = 145 = 14.5 dimes

=> 10 is not equal to 14.5 so we know that the amt. of quarters must be more than 10 and must be an odd amt. => so now we can try 13

13 x 25 = 325 --> 395 - 325 = 70 => 70/10= 7 --> 13 + 7 = 20

Thus, we have our answer of 13

Hope this helps!

Explanation:

The x+d portion indicates we'll have either a left or right shift of d units. Since d is positive, we shift d units to the left. The value of d would have to be negative to have a right shift of d units.

This means that the junction point or turning point must be in the negative x territory. The parent function y = x^(1/5) has its turning point at the origin. So y = (x+d)^(1/5) will have its turning point at (-d,0) for some positive number d.

The exponent 1/5 is in the form 1/n with n = 5 being odd. The odd number tells us we have something like a cube root where it forms an S shape of sorts. Each branch extends on forever to the left and right. Therefore, the domain is the set of all real numbers. We don't have to worry about negative values because we aren't dealing with square roots, fourth roots, sixth roots, etc.

All of these facts point to graph C being the answer.

Answer:

c

Step-by-step explanation:

i think

Answer: 8/7 And simplified simplified 1 1/7

Step-by-step explanation:

[tex]\mathfrak{\huge{\pink{\underline{\underline{AnSwEr:-}}}}}[/tex]

Actually Welcome to the Concept of the Slopes and Tangents.

Basically the above data is the representation of the linear equation.

Thus the slope of linear equation is given as,

m = (y2-y1) / (x2-x1)

so taking any randoms numbers from the given table, we get as,

m = (14-7)/(16-8)

m= (7)/(8)

slope = m = 0.875

Answer:

x = [tex]10^{120}[/tex].

Step-by-step explanation:

logx - 116 = 4

log(x) = 4 + 116

log(x) = 120

10^120 = x

x = [tex]10^{120}[/tex]

Hope this helps!

Answer: the answer is 3

Step-by-step explanation: i took the test and thats the answer

Answer:

49. to the left two spaces (place values)

50. 4.35 m

51. to the right three spaces (place values)

52. 12,000 mL

53. to the right six spaces (place values)

54. 3,000,000

Step-by-step explanation:

49. 1 centimeter is equal to [tex]\frac{1}{100}[/tex] of a meter. In other words, there are 100 cm in 1 meter. To convert from cm to m, you would move the decimal to the left because meters are larger than centimeters meaning a large number of centimeters would convert to a smaller number of meters. The decimal will move two places because there are 100 cm in 1 meter. (look at the number of zeros to determine how many spaces to move)

50. Follow the rule from the 49:

435.00 → 4.35

51. 1 liter is equal to 1000 milliliters. This means the number will increase, moving the decimal to the right. The decimal will move three places because each place value equals 10x and 10 · 10 · 10 = 1000. (look at the number of zeros to determine how many spaces to move)

52. Follow the rule from 51:

12.00 → 12,000

53. 1 megameter is equal to 1,000,000 meters. This means the number will increase, moving the decimal to the right. The decimal will move six spaces because each place value equals 10x. 10 · 10 · 10 · 10 · 10 · 10 = 1,000,000 (look at the zeros to determine how many spaces to move)

54. Follow the rule from 53:

3.00 → 3,000,000

Answer: A. 3 red squares to 6 green squares

Step-by-step explanation:

Method 1) Find a common factor between 15 and 30. For this problem, I'll pick 5. Divide both numbers by this common factor.

15/5=3 red squares

30/5=6 green squares

3 red squares to 6 green squares

Method 2) Find the greatest common factor between 15 and 30. The GCF is 15. Divide both numbers by the GCF.

15/15=1

30/15=2

This leaves you with a ratio of 1 red square to 2 green squares. 1:2 is equivalent to 3:6

3 red squares to 6 green squares

Answer:

x=pm-rm

Step-by-step explanation:

[tex]\frac{x}{m}+r=p\\\\ \frac{x}{m}+r-r=p-r\\\\\frac{x}{m}=p-r\\\\\frac{x}{m}*m=(p-r)*m\\\\\boxed{x=pm-rm; m\neq 0}[/tex]

Answer:

A = ab

Step-by-step explanation:

The area of a rectangle is denoted by A = lw, where l is the length and w is the width.

Here, our length is a centimetres and our width is b centimetres. This means that l = a and w = b. Plug these into the formula:

A = lw

A = ab

The answer is thus A = ab.

~ an aesthetics lover

Answer:

ab cm^2

Step-by-step explanation:

The area of a rectangle is given by A = Length times Width.

Here the area is A = (a cm)*(b cm) = ab cm^2

Answer:

-17.5℃

Step-by-step explanation:

Current temperature = 0 ℃

Rate of falling per hour = -3.5 ℃

Temperature in 5 hours = -3.5 * 5 = -17.5 ℃  

Answer:

y intercept is -19/6

Step-by-step explanation:

The slope intercept form of a line is given by

y = mx+b where m is the slope and b is the y intercept

y = 16/13x - 19/6

The slope is 16/13 and the y intercept is -19/6

Answer:

[tex]\boxed{-\frac{19}{6} }[/tex]

Step-by-step explanation:

Use slope-intercept formula.

[tex]y=mx+b[/tex]

[tex]m[/tex] is the slope of the line.

[tex]b[/tex] is the y-intercept of the line.

The equation of the line is already in slope-intercept form.

[tex]y=\frac{16}{3} x+-\frac{19}{6}[/tex]

[tex]b= -\frac{19}{6}[/tex]

Answer:

B.

Step-by-step explanation:

Since we are moving the graph f(x) to the right 2 and down 1 with a reflection over the x-axis, we modify a, h, and k in f(x) = a(bx - h)² + k:

We would get f(x) = -(x - 2)² - 1 as our answer.

Answer:

I'm confused what's the question ?

Answer:

A. m∠2 + m∠3

Step-by-step explanation:

The exterior angle theorem states that the exterior angle formed when you extend the side of a triangle is equal to the sum of its non-adjacent angles.

So m∠4's non-adjacent angles are 2 and 3 NOT 1. Therefore, the measure of ∠4 = m∠2 + m∠3.

Hope this helps!

Answer:

A) m∠2 + m∠3

Step-by-step explanation:

Triangle Exterior Angle Theorem: The Sum of the outside angle is found using by adding the two opposite interior angles.

In the case of ∠4, the opposite interior angles are ∠2 & ∠3.

~

Hey there! :)

Answer:

x = 5, x = -i√7, x = i√7

Step-by-step explanation:

We can factor the equation x³ - 5x² + 7x - 35 = 0 by grouping:

x²(x - 5) + 7(x -5) = 0

We get:

(x² + 7)(x - 5) = 0

or

(x + i√7)(x - i√7)(x - 5) = 0

Use the Zero Product Property to solve for the solutions:

x - 5 = 0

x = 5.

-----------

x² + 7 = 0

x² = -7 (We will have imaginary solutions in this instance)

x = ±i√7

Therefore, the zeros of this equation are:

x = 5, x = -i√7, x = i√7