Please help me I really need this

Answer:

Step-by-step explanation:

its about 263.08!

====================================================

Explanation:

We'll use this formula

S = (x/360)*A

where,

We'll plug in S = 85.5 and x = 117 to find solve for A.

S = (x/360)*A

85.5 = (117/360)*A

85.5*(360/117) = A

A = 85.5*(360/117)

A = 263.076923076923 which is approximate

A = 263.08 square meters (choice C)

------------

Side note: As the formula suggests, the x/360 portion is the fractional portion of the full area A. For example, if x = 180 degrees, then x/360 = 180/360 = 1/2, meaning we'll take half of the full circle area to get S.

Answer:  sorry i dont know this

Step-by-step explanation:

Answer:

74,310

Hope this helped! ^^

Answer:

[tex] = 74,310[/tex]

step by step explanation:

Answer:

C=89.2

Step-by-step explanation:

The formula of the circumference of a circle is C=2piR (or C=piD). Now, when calculating, plug in the numbers, giving you C=2pi14.2. Multiply everything, you get a super long irrational number; just round. You will get 89.2.

Answer:

7.96 cm

Step-by-step explanation:

radius of bottom: 19/2 = 9.5

area of bottom = pi * r^2 = 283.53

height * base area = volume

Answer:

16

Step-by-step explanation:

AB = BC    

32[tex]\sqrt{2}[/tex] = [tex]\sqrt{2 *AB^{2} } \\ => AB = 32 = BC\\x= BC/2 => x = 32/ 2 = 16[/tex]

Answer:

F'

Your answer is correct

Step-by-step explanation:

The image most of the time we will put ' prime on it to let the other know that this is the image

Answer:

I only know this much.....

A) Deepthi has won the election.

B) Rashmi got minimum number of votes.

Answer:

Step-by-step explanation:

take theta as reference angle

using sin rule

sin theta=opposite/hypotenuse

sin theta=3/5

sin theta=0.60

theta=sin 37 degree

therefore the value of theta is 37 degree.

Answer:

C) 150

Step-by-step explanation:

Answer:

(1, -2)

Step-by-step explanation:

The dilation that has a center of (0, 0) means that you would multiply each number in your coordinate point by your given scale factor.

For your given point (2, -4) with a scale factor of 0.5:

2 times 0.5 = 1

-4 times 0.5 = -2

Therefore your new point will be (1, -2).

Answer:

65 cm

Step-by-step explanation:

16^2 x 63^2 = 65^2

Answer:

43.9823

Step-by-step explanation:

[tex]Arc length = 2\pi r(\frac{0}{360} )\\ = 2\pi 12(\frac{210}{360} )[/tex]

Answer:

3(p - 5) + 2s should be the correct answer!

Step-by-step explanation:

3 henna powder, and you get $5 off each henna powder so equation is 3(p - 5)

2 bottle so, 2s

add them up and get the answer

Anyways, hope this helped!

Answer:

256

Step-by-step explanation:

4^4^4 = 4^(4^4) = 4^256

so written in base 4, there will be 256 zeroes after a 1.

This translates to approximately 154 digits in decimal.

Just like 2^2^2 =  2^4

there will be four zeroes after a 1.

2^2^2=2^(2^2) = 2^4 = 16 = 10000 (16 in base 2).

Answer:

4  Hope that helped

Answer:

a=9

c= 17.5

angles: a =31, b =59, c =90

Step-by-step explanation:

a:

tan (31) = a/15 *cross multiply*

a = 15 (tan (31))

a = 9

c:

*use pythagorean theorum*

9^2 + 15^2 = c^2

81 + 225 = c^2

306 = c^2

17.5 = c

Answer:

B = 59

a = 9.01

c = 17.49

Step-by-step explanation:

Angle B

180 - 90 - 31 = 59

c

The sine of an angle is equal to the ratio of the opposite side to the hypotenuse.

sin(B)=opp/hyp

sin(B)=15/c

sin(59)=15/c

c=15/sin(59)

c=17.49

Find the last side of the triangle using the Pythagorean theorem.

[tex]a^{2} +b^{2} =c^{2} \\a^{2} +15^{2} =17.49^{2} \\\\a^{2} =17.49^{2} -15^{2}\\a=9.01[/tex]

Answer:113

Step-by-step explanation:

Answer:

x=34[tex]\sqrt{2}[/tex]

y=34[tex]\sqrt{3}[/tex]

Step-by-step explanation:

Answer:

To make a "clean getaway"

Step-by-step explanation:

haha, nice one :D

The interquartile range(IQR) of the recorded weight of ken is calculated as 17 pounds.

The interquartile range(IQR) = third quartile(Q3) - first quartile(Q1)

The third quartile of in the box plot given is : 56 pounds

The third quartile of the data as represented in the box plot given :

39 pounds

The interquartile range(IQR) of ken's data = 56 - 39

= 17 pounds

Hence, The interquartile range(IQR) of the recorded weight of ken is calculated as 17 pounds.

Find more information about the interquartile range here

https://brainly.com/question/4102829

#SPJ2