PLEASE HELP!!! I WILL MARK BRAINLY AND ITS WORTH 15 POINTS!!!

Answer:

For statement 1 :

INPUT UNIT OF ITEM : Time of the year on Serengeti Desert

OUTPUT UNIT OF ITEM : Simba washes his clothes

For statement 2

INPUT UNIT OF ITEM : 1 capful of detergent

OUTPUT UNIT OF ITEM : each load of wash

Step-by-step explanation:

For statement 1 :

INPUT UNIT OF ITEM : Time of the year on Serengeti Desert

OUTPUT UNIT OF ITEM : Simba washes his clothes

For statement 2

INPUT UNIT OF ITEM : 1 capful of detergent

OUTPUT UNIT OF ITEM : each load of wash

From answers provided above the basis for the answers is that an input unit of item will have to result to a reaction which is an output unit of item hence the answers above

Answer:

a= (Z + 2b)/24

Step-by-step explanation:

given:

Z = 24a - 2b

to solve for a, we will try to move "a" to one side of the equation and all other terms to the other side:

Z = 24a - 2b    (add 2b to both sides)

Z + 2b = 24a -2b +2b

Z + 2b = 24a  (switch sides)

24a = Z + 2b (divide both sides by 24)

a/24 = (Z + 2b)/24

a= (Z + 2b)/24

Answer:y=x+3

Step-by-step explanation:

Answer:

y = 4/3 + 4

Step-by-step explanation:

4/3 comes from using rise over run. 4 comes from the y-intercept.

Answer:

y = [tex]\frac{4}{3}[/tex] x + 4

Step-by-step explanation:

y = mx + b

m = [tex]\frac{rise}{run}[/tex] ; "b" is y-intercept

~~~~~~~~~~~

m = [tex]\frac{4}{3}[/tex] and b = 4

y = [tex]\frac{4}{3}[/tex] x + 4

Answer:

The solution is too long. So, I included them in the explanation

Step-by-step explanation:

This question has missing details. However, I've corrected each question before solving them

Required: Determine the inverse

1:

[tex]f(x) = 25x - 18[/tex]

Replace f(x) with y

[tex]y = 25x - 18[/tex]

Swap y & x

[tex]x = 25y - 18[/tex]

[tex]x + 18 = 25y - 18 + 18[/tex]

[tex]x + 18 = 25y[/tex]

Divide through by 25

[tex]\frac{x + 18}{25} = y[/tex]

[tex]y = \frac{x + 18}{25}[/tex]

Replace y with f'(x)

[tex]f'(x) = \frac{x + 18}{25}[/tex]

2. [tex]g(x) = \frac{12x - 1}{7}[/tex]

Replace g(x) with y

[tex]y = \frac{12x - 1}{7}[/tex]

Swap y & x

[tex]x = \frac{12y - 1}{7}[/tex]

[tex]7x = 12y - 1[/tex]

Add 1 to both sides

[tex]7x +1 = 12y - 1 + 1[/tex]

[tex]7x +1 = 12y[/tex]

Make y the subject

[tex]y = \frac{7x + 1}{12}[/tex]

[tex]g'(x) = \frac{7x + 1}{12}[/tex]

3: [tex]h(x) = -\frac{9x}{4} - \frac{1}{3}[/tex]

Replace h(x) with y

[tex]y = -\frac{9x}{4} - \frac{1}{3}[/tex]

Swap y & x

[tex]x = -\frac{9y}{4} - \frac{1}{3}[/tex]

Add [tex]\frac{1}{3}[/tex] to both sides

[tex]x + \frac{1}{3}= -\frac{9y}{4} - \frac{1}{3} + \frac{1}{3}[/tex]

[tex]x + \frac{1}{3}= -\frac{9y}{4}[/tex]

Multiply through by -4

[tex]-4(x + \frac{1}{3})= -4(-\frac{9y}{4})[/tex]

[tex]-4x - \frac{4}{3}= 9y[/tex]

Divide through by 9

[tex](-4x - \frac{4}{3})/9= y[/tex]

[tex]-4x * \frac{1}{9} - \frac{4}{3} * \frac{1}{9} = y[/tex]

[tex]\frac{-4x}{9} - \frac{4}{27}= y[/tex]

[tex]y = \frac{-4x}{9} - \frac{4}{27}[/tex]

[tex]h'(x) = \frac{-4x}{9} - \frac{4}{27}[/tex]

4:

[tex]f(x) = x^9[/tex]

Replace f(x) with y

[tex]y = x^9[/tex]

Swap y with x

[tex]x = y^9[/tex]

Take 9th root

[tex]x^{\frac{1}{9}} = y[/tex]

[tex]y = x^{\frac{1}{9}}[/tex]

Replace y with f'(x)

[tex]f'(x) = x^{\frac{1}{9}}[/tex]

5:

[tex]f(a) = a^3 + 8[/tex]

Replace f(a) with y

[tex]y = a^3 + 8[/tex]

Swap a with y

[tex]a = y^3 + 8[/tex]

Subtract 8

[tex]a - 8 = y^3 + 8 - 8[/tex]

[tex]a - 8 = y^3[/tex]

Take cube root

[tex]\sqrt[3]{a-8} = y[/tex]

[tex]y = \sqrt[3]{a-8}[/tex]

Replace y with f'(a)

[tex]f'(a) = \sqrt[3]{a-8}[/tex]

6:

[tex]g(a) = a^2 + 8a- 7[/tex]

Replace g(a) with y

[tex]y = a^2 + 8a - 7[/tex]

Swap positions of y and a

[tex]a = y^2 + 8y - 7[/tex]

[tex]y^2 + 8y - 7 - a = 0[/tex]

Solve using quadratic formula:

[tex]y = \frac{-b\±\sqrt{b^2 - 4ac}}{2a}[/tex]

[tex]a = 1[/tex] ; [tex]b = 8[/tex]; [tex]c = -7 - a[/tex]

[tex]y = \frac{-b\±\sqrt{b^2 - 4ac}}{2a}[/tex] becomes

[tex]y = \frac{-8 \±\sqrt{8^2 - 4 * 1 * (-7-a)}}{2 * 1}[/tex]

[tex]y = \frac{-8 \±\sqrt{64 + 28 + 4a}}{2 * 1}[/tex]

[tex]y = \frac{-8 \±\sqrt{92 + 4a}}{2 * 1}[/tex]

[tex]y = \frac{-8 \±\sqrt{92 + 4a}}{2 }[/tex]

Factorize

[tex]y = \frac{-8 \±\sqrt{4(23 + a)}}{2 }[/tex]

[tex]y = \frac{-8 \±2\sqrt{(23 + a)}}{2 }[/tex]

[tex]y = -4 \±\sqrt{(23 + a)}[/tex]

[tex]g'(a) = -4 \±\sqrt{(23 + a)}[/tex]

7:

[tex]f(b) = (b + 6)(b - 2)[/tex]

Replace f(b) with y

[tex]y = (b + 6)(b - 2)[/tex]

Swap y and b

[tex]b = (y + 6)(y - 2)[/tex]

Open Brackets

[tex]b = y^2 + 6y - 2y - 12[/tex]

[tex]b = y^2 + 4y - 12[/tex]

[tex]y^2 + 4y - 12 - b = 0[/tex]

Solve using quadratic formula:

[tex]y = \frac{-b\±\sqrt{b^2 - 4ac}}{2a}[/tex]

[tex]a = 1[/tex] ; [tex]b = 4[/tex]; [tex]c = -12 - b[/tex]

[tex]y = \frac{-b\±\sqrt{b^2 - 4ac}}{2a}[/tex] becomes

[tex]y = \frac{-4\±\sqrt{4^2 - 4 * 1 * (-12-b)}}{2*1}[/tex]

[tex]y = \frac{-4\±\sqrt{4^2 - 4 *(-12-b)}}{2}[/tex]

Factorize:

[tex]y = \frac{-4\±\sqrt{4(4 - (-12-b))}}{2}[/tex]

[tex]y = \frac{-4\±2\sqrt{(4 - (-12-b))}}{2}[/tex]

[tex]y = \frac{-4\±2\sqrt{(4 +12+b)}}{2}[/tex]

[tex]y = \frac{-4\±2\sqrt{16+b}}{2}[/tex]

[tex]y = -2\±\sqrt{16+b}[/tex]

Replace y with f'(b)

[tex]f'(b) = -2\±\sqrt{16+b}[/tex]

8:

[tex]h(x) = \frac{2x+17}{3x+1}[/tex]

Replace h(x) with y

[tex]y = \frac{2x+17}{3x+1}[/tex]

Swap x and y

[tex]x = \frac{2y+17}{3y+1}[/tex]

Cross Multiply

[tex](3y + 1)x = 2y + 17[/tex]

[tex]3yx + x = 2y + 17[/tex]

Subtract x from both sides:

[tex]3yx + x -x= 2y + 17-x[/tex]

[tex]3yx = 2y + 17-x[/tex]

Subtract 2y from both sides

[tex]3yx-2y =17-x[/tex]

Factorize:

[tex]y(3x-2) =17-x[/tex]

Make y the subject

[tex]y = \frac{17 - x}{3x - 2}[/tex]

Replace y with h'(x)

[tex]h'(x) = \frac{17 - x}{3x - 2}[/tex]

9:

[tex]h(c) = \sqrt{2c + 2}[/tex]

Replace h(c) with y

[tex]y = \sqrt{2c + 2}[/tex]

Swap positions of y and c

[tex]c = \sqrt{2y + 2}[/tex]

Square both sides

[tex]c^2 = 2y + 2[/tex]

Subtract 2 from both sides

[tex]c^2 - 2= 2y[/tex]

Make y the subject

[tex]y = \frac{c^2 - 2}{2}[/tex]

[tex]h'(c) = \frac{c^2 - 2}{2}[/tex]

10:

[tex]f(x) = \frac{x + 10}{9x - 1}[/tex]

Replace f(x) with y

[tex]y = \frac{x + 10}{9x - 1}[/tex]

Swap positions of x and y

[tex]x = \frac{y + 10}{9y - 1}[/tex]

Cross Multiply

[tex]x(9y - 1) = y + 10[/tex]

[tex]9xy - x = y + 10[/tex]

Subtract y from both sides

[tex]9xy - y - x = y - y+ 10[/tex]

[tex]9xy - y - x = 10[/tex]

Add x to both sides

[tex]9xy - y - x + x= 10 + x[/tex]

[tex]9xy - y = 10 + x[/tex]

Factorize

[tex]y(9x - 1) = 10 + x[/tex]

Make y the subject

[tex]y = \frac{10 + x}{9x - 1}[/tex]

Replace y with f'(x)

[tex]f'(x) = \frac{10 + x}{9x -1}[/tex]

Answer:           0.875

Step-by-step explanation:

Answer:-1/2

Step-by-step explanation:

Look at the points

If 8% of students were absent on Tuesday no. of students that were absent was 50.

A percentage is a value per hundredth. Percentages can be converted into decimals and fractions by dividing the percentage value by a hundred.

Given, There are 625 students at Median middle school and 8% of the students were absent on Tuesday.

∴ No. of students that were absent on Tuesday is 8% of 625 which is,

= (8/100)×625.

= 50.

Learn more about percentages here :

https://brainly.com/question/24159063

#SPJ2

Answer:

59/6

Step-by-step explanation:

9x6=54

54+5= 59

put the denominator of the fraction to the denominator to the new fraction. I hope this helps.

Answer:

Required equations in standard form are:

1. 3x+4y=12

2. -5x+2y = 10

Step-by-step explanation:

Standard form of equation is given as:

[tex]Ax+By = C[/tex]

1. x – intercept is 4 and y – intercept is 3.

The points will be:

(4,0) and (0,3)

Slope: m = [tex]\frac{y_2-y_1}{x_2-x_1}[/tex]

[tex]m = \frac{3-0}{0-4}\\m = -\frac{3}{4}[/tex]

Slope intercept form of line is:

[tex]y = mx+b[/tex]

Putting the values of m and b(y-intercept)

[tex]y = -\frac{3}{4}x+3[/tex]

Multiplying whole equation by 4

[tex]4y = -3x+12\\3x+4y = 12[/tex]

2. x – intercept is -2 and y – intercept is 5

The points will be:

(-2,0) and (0,5)

Now

[tex]m = \frac{5-0}{0+2}\\m = \frac{5}{2}[/tex]

Putting the values of m and b in slope intercept form

[tex]y = \frac{5}{2}x+5[/tex]

Multiplying the equation by 2

[tex]2y = 5x+10[/tex]

[tex]-5x+2y=10[/tex]

Hence,

Required equations in standard form are:

1. 3x+4y=12

2. -5x+2y = 10

Step-by-step explanation:

the regular form of r=8

Answer:

Step-by-step explanation:

Y= -6

X=-2

Answer:

5/2

Step-by-step explanation:

25 and 10 so 25/10 or 5/2 or 2 1/2

Answer:

A

Step-by-step explanation:

Point slope form

x, y

[tex](y-x)= (slope)(x-y)[/tex]

So its

[tex]y-6=\frac{1}{2}(x+3)[/tex]

So option 1.

Hope this helps plz hit the crown :D

Answer:

B

Step-by-step explanation:

y=mx +b

y= 1/2x = b

y intercept (0,-6)

Answer:

5/8

Step-by-step explanation:

1/4=2/8

7/8-2/8=5/8

Answer:

niwebfasfbjsdfb

Step-by-step explanation:

jsdfhsdbfjhadsjbdsfhb

102 is 60% 170. Divide 102 by 0.6, which results in 102. Hope this helps! Have an amazing rest of your day and please mark brainliest! xx

Answer:My suggestion is practice what you learned after each class for like 10-20 min and pay close attention in class. Wish you the best of luck.

Step-by-step explanation:

Answer:

d=25 or d=2

Step-by-step explanation:

hope that helps!

Answer:

d=2/5 or d=2

Step-by-step explanation:

Step 1: Subtract -6d^2 from both sides.

−d2−12d+4−−6d2=−6d2−−6d2

5d2−12d+4=0

Step 2: Factor left side of equation.

(5d−2)(d−2)=0

Step 3: Set factors equal to 0.

5d−2=0 or d−2=0

d= 2/5 or d=2

Answer:

a=5

Step-by-step explanation:

18-2a=8

-18     -18

-2a=-10

/-2  /-2

a=5

Answer:

x=19/4

Step-by-step explanation:

The product of 5 and a number x is 1/4

Answer:

Option 4: 45 units is the correct answer

Step-by-step explanation:

Let [tex]P_1[/tex] be the perimeter of Pentagon and

Let P2 be the perimeter of Triangle

So,

[tex]P_1 = 5(\frac{1}{2}x-1)\\P_2 = 3(x-5)[/tex]

In order to find the perimeter of each figure we have to put both the expressions equal so that the value of x can be found and then perimeter.

So,

[tex]P_1 = P_2\\5(\frac{1}{2}x-1) = 3(x-5)\\\frac{5}{2}x-5 = 3x-15\\\frac{5}{2}x-3x = -15+5\\\frac{5x-6x}{2} = -10\\-\frac{x}{2} = -10\\-x = -10 * 2\\-x = -20\\x = 20[/tex]

Putting x = 20 in 2nd perimeter

[tex]P_2 = 3(x-5) \\= 3(20-5)\\= 3(15)\\=45[/tex]

As both the perimeters are same, the perimeter of pentagon will also be 45 units.

Hence,

Option 4: 45 units is the correct answer

Answer:

Step-by-step explanation:

3(4x-5)-3x+2 work the ()

12x-15-3x+2 combine like terms

9x-13

Answer:

Step-by-step explanation:

1. use the slope formula --> (y2-y1)/(x2-x1)

2. (8 - 4)/(13 -(-3))

3. 4/16

4. m = 1/4

Answer:

option D is the answer

Step-by-step explanation:

3n + 5

_______

n² + 5