Please help I will give extra points

Answer:

huh

Explanation:

I like ribs too eat lamfoaoa

Answer:

(8.3×40)+(8.3×71)

921.3grames

Answer:

[tex]\Large \boxed{\sf 921.3 \ g}[/tex]

Explanation:

Use formula

[tex]\displaystyle moles=\frac{mass}{M_r}[/tex]

[tex]M_r=40+35.5 \times 2 = 111[/tex]

Solve for mass

[tex]mass=8.3 \times 111=921.3[/tex]

the answer is 375 joules

Answer:

I believe it would be D, to enhance the survival rate.

Explanation:

Answer:

D

Explanation:

to enhance the survival

Answer:

C2H2

Explanation:

Answer: D, notify instructor .

Explanation: common sense love

Answer:

12.6 g of H₂O can be produced in the combustion

Explanation:

This excersise involves an easy combustion reaction:

2C₄H₁₀  +  13O₂  →   8CO₂  +  10H₂O

First step: calculate moles of reactants in order to find out the limiting.

23 g . 1mol / 58g = 0.396 moles of butane

29.1 g . 1mol /32g = 0.909 moles of O₂

2 moles of butane react to 13 moles of oxygen

Then, 0.396 moles of butane may react to (0.396 . 13) / 2 = 2.574 moles

Certainly we do not have enough oxygen, so O₂ becomes the limiting reactant

13 moles of O₂ can produce 10 moles of water

Then 0.909 moles may produce (0.909 . 10) /13 = 0.699 moles H₂O

We convert moles to mass → 0.699 mol . 18 g/mol = 12.6 g

Answer:

pls answer this link for the answer :D

Explanation:

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Answer: i could be incorrect but im pretty sure the answer is, Gas surface with no rings.

Explanation:

s-s-s-science!

Answer:

Gas surface with no rings.

Explanation:

Answer:

Hydrogen is the limiting reactant.

Explanation:

Hello!

In this case, for the identification of the limiting reactant, it is necessary to compute the yielded moles of ammonia via both hydrogen and nitrogen in agreement to the 3:2 and 1:2 mole ratios respectively:

[tex]n_{NH_3}^{by\ H_2}=5molH_2*\frac{2molNH_3}{3molH_2}=3.33molNH_3\\\\n_{NH_3}^{by\ N_2}=2molN_2*\frac{2molNH_3}{1molN_2}=4molNH_3[/tex]

Thus, since hydrogen yields the fewest moles of ammonia we infer it is the limiting reactant.

Best regards!

Answer:

Sep 23, 2019 — It's in everyone's benefit if physicians participate in research. By Mukesh K. Jain, Tadataka Yamada and Robert Lefkowitz. Drs. Jain, Yamada ...

Explanation:

Answer:

Nucleus

Explanation:

they originate in the nucleus

This question is incomplete, the complete question is;

The purification of hydrogen gas by diffusion through a palladium sheet was discussed in Section 5.3. Compute the number of kilograms of hydrogen that pass per hour through a 5-mm-thick sheet of palladium having an area of 0.20 m² at 500C.

Assume a diffusion coefficient of 1.0 × 10⁻⁸ m²/s, that the concentrations at the high- and low-pressure sides of the plate are 2.4 and 0.6 kg of hydrogen per cubic meter of palladium, and that steady-state conditions have been attained

Answer:

the number of kilograms of hydrogen that pass per hour through is 2.592 × 10⁻³ kg

Explanation:

Given the data in the question;

thickness of sheet t = 5 mm

Area A = 0.20 m²

Temperature T = 500°C

diffusion coefficient ∝ = 1.0 × 10⁻⁸ m²/s

concentration high pressure side C[tex]_A[/tex] = 2.4

concentration low pressure side C[tex]_B[/tex] = 0.6 kg

from the question, we calculate the concentration gradient

dc/dx = (C[tex]_A[/tex] -  C[tex]_B[/tex])/dt

so we substitute

dc/dx = (2.4 - 0.6) / ( - 5 × 10⁻³ )

dc/dx = -360

now, mass of hydrogen per hour that diffuse through a pd sheet

M = -∝AT(dc/dx)

where time t is 1 hour ( 3600 sec )

we substitute

M = -(1.0 × 10⁻⁸) × 0.20 × 3600 (-360)

M = 0.002592

M = 2.592 × 10⁻³ kg per one hour

Therefore, the number of kilograms of hydrogen that pass per hour through is 2.592 × 10⁻³ kg

The number of kilograms of hydrogen that pass per hour through a 5-mm-thick sheet of palladium having an area of 0.20 m² at 500°C is 2.592 × 10⁻³ kg.

Purification: It refers to the process of removing impurities or contaminants from a substance in order to make it cleaner, purer, or more refined. It also involves the elimination or reduction of unwanted substances or components that may be present in the original material.

According to the question, given data is:

Thickness of sheet t = 5 mm

Area A = 0.20 m²

Temperature T = 500°C

Diffusion coefficient ∝ = 1.0 × 10⁻⁸ m²/s

Concentration high pressure side [tex]C_A[/tex] = 2.4

Concentration low pressure side[tex]C_B[/tex]= 0.6 kg

from the question, we calculate the concentration gradient,

[tex]dc/dx = (C _A- C_B)/dt[/tex]

so, we substitute the values,

[tex]dc/dx[/tex] = (2.4 - 0.6)/ ( - 5 × 10⁻³)

[tex]dc/dx = -360[/tex]

Now, mass of hydrogen per hour that diffuse through a Palladium sheet,

M = -∝[tex]AT(dc/dx)[/tex]

where time t is 1 hour (3600 sec)

We substitute,

M = -(1.0 × 10⁻⁸) × 0.20 × 3600 (-360)

M = 0.002592

M = 2.592 × 10⁻³ kg per hour.

Therefore, the number of kilograms of hydrogen that pass per hour through a palladium sheet is approximately 2.592 × 10⁻³ kg.

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This question is incomplete, the complete question is;

The purification of hydrogen gas by diffusion through a palladium sheet was discussed in Section 5.3. Compute the number of kilograms of hydrogen that pass per hour through a 5-mm-thick sheet of palladium having an area of 0.20 m² at 500C.

Assume a diffusion coefficient of 1.0 × 10⁻⁸ m²/s, that the concentrations at the high- and low-pressure sides of the plate are 2.4 and 0.6 kg of hydrogen per cubic meter of palladium, and that steady-state conditions have been attained.

Answer:

D.

the father parent shares his genetic information with the mother during sexual intercourse( the sperm and egg)

Answer: Ammonia Ice

Explanation: Like Jupiter, Saturn boasts layers of clouds. The upper layers of clouds are made up of ammonia ice. Traveling toward the core, clouds of water ice form, with bands of ammonium hydrosulfide ice intermixed. The lower layers of Saturn see higher temperatures and pressures.

Answer:

B

Explanation:

Answer:

B

Explanation:

Edge 2022

Answer:

3 moles of NH₄Cl

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

NH₃(g) + HCl(g) → NH₄Cl(s) ΔH = –176 kJ

From the balanced equation above,

1 mole of NH₄Cl where obtained when the change in enthalphy (ΔH) was –176 kJ.

Finally, we shall determine the number of mole of NH₄Cl produced when the change in enthalphy (ΔH) is –528 kJ. This can be obtained as follow:

From the balanced equation above,

1 mole of NH₄Cl where obtained when the change in enthalphy (ΔH) was –176 kJ.

Therefore, Xmol of NH₄Cl will be obtained when the change in enthalphy (ΔH) is –528 kJ i.e

Xmol of NH₄Cl = –528 / –176

Xmol of NH₄Cl = 3 moles

Thus, 3 moles of NH₄Cl where obtained from the reaction.

The third picture has only one type of combination of atoms so it represents a pure compound. Therefore, option (c) is correct.

A pure compound is a compound that contains two or more elements combined chemically in a fixed ratio. These compounds can be broken down into separate or simple elements by chemical methods.

A pure compound is formed when elements are joined together by chemical bonds. Compounds such as water, crystals, and baking soda as pure.  

Water is a compound formed by the combination of oxygen and hydrogen in a fixed ratio. A pure substance is a substance that has only one kind of atom or molecule having a constant composition.

The first picture represents pure substance and the 2nd and 4th pictures represent mixed compounds. Therefore, the third picture represents a pure compound.

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Answer:

What are the options?

Explanation:

......

Answer:

d is right hope this helps:)

Answer:

The fourth one is correct ( D/ number 4).

Answer:

Sodium oxide

Explanation:

Answer: Sodium oxide

Answer: The correct answer is 2 moles.

Explanation:

The given question is incomplete. The complete question is:

Photosynthesis reactions in green plants use carbon dioxide and water to produce glucose (C6H12O6) and oxygen. A plant has 88.0 g of carbon dioxide and 64.0 g of water available for photosynthesis. Determine the mass of glucose (C6H1206) produced

Answer: 60.0 g of glucose

Explanation:

To calculate the moles, we use the equation:

[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}[/tex]

a) moles of [tex]CO_2[/tex]

[tex]\text{Number of moles}=\frac{88.0g}{44g/mol}=2.0moles[/tex]

b) moles of [tex]H_2O[/tex]

[tex]\text{Number of moles}=\frac{64.0g}{18g/mol}=3.5moles[/tex]

[tex]6CO_2+6H_2O\rightarrow C_{6}H_{12}O_6+6O_2[/tex]

According to stoichiometry :

6 moles of [tex]CO_2[/tex] require = 6 moles of [tex]H_2O[/tex]

Thus 2.0 moles of [tex]CO_2[/tex] require=[tex]\frac{6}{6}\times 2.0=2.0moles[/tex]  of [tex]H_2O[/tex]

Thus [tex]CO_2[/tex] is the limiting reagent as it limits the formation of product.

As 6 moles of [tex]CO_2[/tex] give =  1 moles of glucose

Thus 2.0 moles of [tex]CO_2[/tex] give =[tex]\frac{1}{6}\times 2.0=0.33moles[/tex]  of glucose

Mass of glucose = [tex]moles\times {\text {Molar mass}}=0.33moles\times 180g/mol=60g[/tex]

Thus 60.0 g of glucose will be produced from 88.0 g of carbon dioxide and 64.0 g of water  

In green plants use carbon dioxide and water to produce glucose (C6H12O6) and oxygen. A plant has 88.0 g of carbon dioxide and 64.0 g of water available for photosynthesis produces 60.0 g of glucose.

To calculate the moles, we use the equation:

Mole fraction is a unit of concentration, described to be same to the range of moles of a element divided via way of means of the entire range of moles of a solution.

Thus it is well explained.

To learn more about the photosynthesis refer to link ;

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Answer:

[tex]\boxed{\bold { \Large { \boxed {0.28 \ kg}}}}[/tex]

Explanation:

Use kinetic energy formula

[tex]\sf \displaystyle K.E=\frac{1}{2} mv^2[/tex]

Solve for m

[tex]\displaystyle 125=\frac{1}{2} m \times 30^2[/tex]

[tex]m=0.2777..[/tex]

A man has a kinetic energy of 125J when he runs at 30m/s.  0.2777  is the mass of the man.

Kinetic energy is the energy of motion, observable as the movement of an object, particle, or set of particles.

Use kinetic energy formula:

Given data:

K.E = 125J

V = 30m/s

K.E = [tex]\frac{1}{2} mv^2[/tex]

Solve for m

125J = [tex]\frac{1}{2} \;m \;{30m/s}^2[/tex]

m = 0.2777

Hence,  0.2777 is the mass of the man.

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Answer:

i think answer is B negative effects and benefits